Best way to format a chart for any length of string without using excel












1














I am trying to create a chart for my names, but it doesn't align correctly if the name is too short or too long. I want to know if there is way I can align the names no matter the length of the string. Below is the align method I used



public static final String FORMAT = "%st%s,%st%s%n";



public static void print() {
for(int i = 0; i < n; i++)
System.out.printf(FORMAT, name[i], last[i], first[i], formatName[i]);


output:



Nirvana Narayan Narayan,Nirvana Nirvana--Narayan
Kim Do Do,Kim Kim--Do
Kiri Wood Wood,Kiri Kiri--Wood
Quinn Hume Hume,Quinn Quinn--Hume









share|improve this question


















  • 1




    Use .length, take the maximum and print the missing spaces for shorter strings. In C you have %n, that gives you the number of characters printed so far, but I'm pretty sure Java does not have a similar format specifier.
    – KaeptnNemo
    Nov 19 at 22:09
















1














I am trying to create a chart for my names, but it doesn't align correctly if the name is too short or too long. I want to know if there is way I can align the names no matter the length of the string. Below is the align method I used



public static final String FORMAT = "%st%s,%st%s%n";



public static void print() {
for(int i = 0; i < n; i++)
System.out.printf(FORMAT, name[i], last[i], first[i], formatName[i]);


output:



Nirvana Narayan Narayan,Nirvana Nirvana--Narayan
Kim Do Do,Kim Kim--Do
Kiri Wood Wood,Kiri Kiri--Wood
Quinn Hume Hume,Quinn Quinn--Hume









share|improve this question


















  • 1




    Use .length, take the maximum and print the missing spaces for shorter strings. In C you have %n, that gives you the number of characters printed so far, but I'm pretty sure Java does not have a similar format specifier.
    – KaeptnNemo
    Nov 19 at 22:09














1












1








1







I am trying to create a chart for my names, but it doesn't align correctly if the name is too short or too long. I want to know if there is way I can align the names no matter the length of the string. Below is the align method I used



public static final String FORMAT = "%st%s,%st%s%n";



public static void print() {
for(int i = 0; i < n; i++)
System.out.printf(FORMAT, name[i], last[i], first[i], formatName[i]);


output:



Nirvana Narayan Narayan,Nirvana Nirvana--Narayan
Kim Do Do,Kim Kim--Do
Kiri Wood Wood,Kiri Kiri--Wood
Quinn Hume Hume,Quinn Quinn--Hume









share|improve this question













I am trying to create a chart for my names, but it doesn't align correctly if the name is too short or too long. I want to know if there is way I can align the names no matter the length of the string. Below is the align method I used



public static final String FORMAT = "%st%s,%st%s%n";



public static void print() {
for(int i = 0; i < n; i++)
System.out.printf(FORMAT, name[i], last[i], first[i], formatName[i]);


output:



Nirvana Narayan Narayan,Nirvana Nirvana--Narayan
Kim Do Do,Kim Kim--Do
Kiri Wood Wood,Kiri Kiri--Wood
Quinn Hume Hume,Quinn Quinn--Hume






java string






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asked Nov 19 at 22:03









James P

102




102








  • 1




    Use .length, take the maximum and print the missing spaces for shorter strings. In C you have %n, that gives you the number of characters printed so far, but I'm pretty sure Java does not have a similar format specifier.
    – KaeptnNemo
    Nov 19 at 22:09














  • 1




    Use .length, take the maximum and print the missing spaces for shorter strings. In C you have %n, that gives you the number of characters printed so far, but I'm pretty sure Java does not have a similar format specifier.
    – KaeptnNemo
    Nov 19 at 22:09








1




1




Use .length, take the maximum and print the missing spaces for shorter strings. In C you have %n, that gives you the number of characters printed so far, but I'm pretty sure Java does not have a similar format specifier.
– KaeptnNemo
Nov 19 at 22:09




Use .length, take the maximum and print the missing spaces for shorter strings. In C you have %n, that gives you the number of characters printed so far, but I'm pretty sure Java does not have a similar format specifier.
– KaeptnNemo
Nov 19 at 22:09












1 Answer
1






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oldest

votes


















1














As described by KaeptnNemo in a comment:




Use .length, take the maximum and print the missing spaces for shorter strings.




The easiest way to print missing spaces is to use the printf method with a format string using e.g. the %-10s format to print at least 10 characters, left-justified, filling with spaces as needed.



E.g. since the longest text for the first column is 23, a format string such as "%-23s %s%n" can be used. Now just write the code to build the format string automatically:



String input = { { "Nirvana Narayan Narayan", "Nirvana Nirvana--Narayan" },
{ "Kim Do Do", "Kim Kim--Do" },
{ "Kiri Wood Wood", "Kiri Kiri--Wood" },
{ "Quinn Hume Hume", "Quinn Quinn--Hume" } };

// Find column widths
int widths = new int[input[0].length];
for (String row : input)
for (int i = 0; i < widths.length; i++)
widths[i] = Math.max(widths[i], row[i].length());

// Build format string
StringBuilder buf = new StringBuilder();
for (int i = 0; i < widths.length - 1; i++)
buf.append("%-").append(widths[i]).append("s ");
String fmt = buf.append("%s%n").toString();

// Print table
for (String row : input)
System.out.printf(fmt, (Object) row);


Output



Nirvana Narayan Narayan Nirvana Nirvana--Narayan
Kim Do Do Kim Kim--Do
Kiri Wood Wood Kiri Kiri--Wood
Quinn Hume Hume Quinn Quinn--Hume




If you like, you can even add column-separators.



// Build format string
StringBuilder buf = new StringBuilder("|");
for (int i = 0; i < widths.length; i++)
buf.append(" %-").append(widths[i]).append("s |");
String fmt = buf.append("%n").toString();


Output



| Nirvana Narayan Narayan | Nirvana Nirvana--Narayan |
| Kim Do Do | Kim Kim--Do |
| Kiri Wood Wood | Kiri Kiri--Wood |
| Quinn Hume Hume | Quinn Quinn--Hume |





share|improve this answer























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    1 Answer
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    active

    oldest

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    1 Answer
    1






    active

    oldest

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    active

    oldest

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    active

    oldest

    votes









    1














    As described by KaeptnNemo in a comment:




    Use .length, take the maximum and print the missing spaces for shorter strings.




    The easiest way to print missing spaces is to use the printf method with a format string using e.g. the %-10s format to print at least 10 characters, left-justified, filling with spaces as needed.



    E.g. since the longest text for the first column is 23, a format string such as "%-23s %s%n" can be used. Now just write the code to build the format string automatically:



    String input = { { "Nirvana Narayan Narayan", "Nirvana Nirvana--Narayan" },
    { "Kim Do Do", "Kim Kim--Do" },
    { "Kiri Wood Wood", "Kiri Kiri--Wood" },
    { "Quinn Hume Hume", "Quinn Quinn--Hume" } };

    // Find column widths
    int widths = new int[input[0].length];
    for (String row : input)
    for (int i = 0; i < widths.length; i++)
    widths[i] = Math.max(widths[i], row[i].length());

    // Build format string
    StringBuilder buf = new StringBuilder();
    for (int i = 0; i < widths.length - 1; i++)
    buf.append("%-").append(widths[i]).append("s ");
    String fmt = buf.append("%s%n").toString();

    // Print table
    for (String row : input)
    System.out.printf(fmt, (Object) row);


    Output



    Nirvana Narayan Narayan Nirvana Nirvana--Narayan
    Kim Do Do Kim Kim--Do
    Kiri Wood Wood Kiri Kiri--Wood
    Quinn Hume Hume Quinn Quinn--Hume




    If you like, you can even add column-separators.



    // Build format string
    StringBuilder buf = new StringBuilder("|");
    for (int i = 0; i < widths.length; i++)
    buf.append(" %-").append(widths[i]).append("s |");
    String fmt = buf.append("%n").toString();


    Output



    | Nirvana Narayan Narayan | Nirvana Nirvana--Narayan |
    | Kim Do Do | Kim Kim--Do |
    | Kiri Wood Wood | Kiri Kiri--Wood |
    | Quinn Hume Hume | Quinn Quinn--Hume |





    share|improve this answer




























      1














      As described by KaeptnNemo in a comment:




      Use .length, take the maximum and print the missing spaces for shorter strings.




      The easiest way to print missing spaces is to use the printf method with a format string using e.g. the %-10s format to print at least 10 characters, left-justified, filling with spaces as needed.



      E.g. since the longest text for the first column is 23, a format string such as "%-23s %s%n" can be used. Now just write the code to build the format string automatically:



      String input = { { "Nirvana Narayan Narayan", "Nirvana Nirvana--Narayan" },
      { "Kim Do Do", "Kim Kim--Do" },
      { "Kiri Wood Wood", "Kiri Kiri--Wood" },
      { "Quinn Hume Hume", "Quinn Quinn--Hume" } };

      // Find column widths
      int widths = new int[input[0].length];
      for (String row : input)
      for (int i = 0; i < widths.length; i++)
      widths[i] = Math.max(widths[i], row[i].length());

      // Build format string
      StringBuilder buf = new StringBuilder();
      for (int i = 0; i < widths.length - 1; i++)
      buf.append("%-").append(widths[i]).append("s ");
      String fmt = buf.append("%s%n").toString();

      // Print table
      for (String row : input)
      System.out.printf(fmt, (Object) row);


      Output



      Nirvana Narayan Narayan Nirvana Nirvana--Narayan
      Kim Do Do Kim Kim--Do
      Kiri Wood Wood Kiri Kiri--Wood
      Quinn Hume Hume Quinn Quinn--Hume




      If you like, you can even add column-separators.



      // Build format string
      StringBuilder buf = new StringBuilder("|");
      for (int i = 0; i < widths.length; i++)
      buf.append(" %-").append(widths[i]).append("s |");
      String fmt = buf.append("%n").toString();


      Output



      | Nirvana Narayan Narayan | Nirvana Nirvana--Narayan |
      | Kim Do Do | Kim Kim--Do |
      | Kiri Wood Wood | Kiri Kiri--Wood |
      | Quinn Hume Hume | Quinn Quinn--Hume |





      share|improve this answer


























        1












        1








        1






        As described by KaeptnNemo in a comment:




        Use .length, take the maximum and print the missing spaces for shorter strings.




        The easiest way to print missing spaces is to use the printf method with a format string using e.g. the %-10s format to print at least 10 characters, left-justified, filling with spaces as needed.



        E.g. since the longest text for the first column is 23, a format string such as "%-23s %s%n" can be used. Now just write the code to build the format string automatically:



        String input = { { "Nirvana Narayan Narayan", "Nirvana Nirvana--Narayan" },
        { "Kim Do Do", "Kim Kim--Do" },
        { "Kiri Wood Wood", "Kiri Kiri--Wood" },
        { "Quinn Hume Hume", "Quinn Quinn--Hume" } };

        // Find column widths
        int widths = new int[input[0].length];
        for (String row : input)
        for (int i = 0; i < widths.length; i++)
        widths[i] = Math.max(widths[i], row[i].length());

        // Build format string
        StringBuilder buf = new StringBuilder();
        for (int i = 0; i < widths.length - 1; i++)
        buf.append("%-").append(widths[i]).append("s ");
        String fmt = buf.append("%s%n").toString();

        // Print table
        for (String row : input)
        System.out.printf(fmt, (Object) row);


        Output



        Nirvana Narayan Narayan Nirvana Nirvana--Narayan
        Kim Do Do Kim Kim--Do
        Kiri Wood Wood Kiri Kiri--Wood
        Quinn Hume Hume Quinn Quinn--Hume




        If you like, you can even add column-separators.



        // Build format string
        StringBuilder buf = new StringBuilder("|");
        for (int i = 0; i < widths.length; i++)
        buf.append(" %-").append(widths[i]).append("s |");
        String fmt = buf.append("%n").toString();


        Output



        | Nirvana Narayan Narayan | Nirvana Nirvana--Narayan |
        | Kim Do Do | Kim Kim--Do |
        | Kiri Wood Wood | Kiri Kiri--Wood |
        | Quinn Hume Hume | Quinn Quinn--Hume |





        share|improve this answer














        As described by KaeptnNemo in a comment:




        Use .length, take the maximum and print the missing spaces for shorter strings.




        The easiest way to print missing spaces is to use the printf method with a format string using e.g. the %-10s format to print at least 10 characters, left-justified, filling with spaces as needed.



        E.g. since the longest text for the first column is 23, a format string such as "%-23s %s%n" can be used. Now just write the code to build the format string automatically:



        String input = { { "Nirvana Narayan Narayan", "Nirvana Nirvana--Narayan" },
        { "Kim Do Do", "Kim Kim--Do" },
        { "Kiri Wood Wood", "Kiri Kiri--Wood" },
        { "Quinn Hume Hume", "Quinn Quinn--Hume" } };

        // Find column widths
        int widths = new int[input[0].length];
        for (String row : input)
        for (int i = 0; i < widths.length; i++)
        widths[i] = Math.max(widths[i], row[i].length());

        // Build format string
        StringBuilder buf = new StringBuilder();
        for (int i = 0; i < widths.length - 1; i++)
        buf.append("%-").append(widths[i]).append("s ");
        String fmt = buf.append("%s%n").toString();

        // Print table
        for (String row : input)
        System.out.printf(fmt, (Object) row);


        Output



        Nirvana Narayan Narayan Nirvana Nirvana--Narayan
        Kim Do Do Kim Kim--Do
        Kiri Wood Wood Kiri Kiri--Wood
        Quinn Hume Hume Quinn Quinn--Hume




        If you like, you can even add column-separators.



        // Build format string
        StringBuilder buf = new StringBuilder("|");
        for (int i = 0; i < widths.length; i++)
        buf.append(" %-").append(widths[i]).append("s |");
        String fmt = buf.append("%n").toString();


        Output



        | Nirvana Narayan Narayan | Nirvana Nirvana--Narayan |
        | Kim Do Do | Kim Kim--Do |
        | Kiri Wood Wood | Kiri Kiri--Wood |
        | Quinn Hume Hume | Quinn Quinn--Hume |






        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Nov 19 at 22:36

























        answered Nov 19 at 22:30









        Andreas

        74.7k458122




        74.7k458122






























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