2D array size specified by the user












2















So, I have a code when I prompt the user to enter a number, I want the size of the 2D array to be changed according to what the user entered, for example:



Enter a number between 1 and 12:
3



The 2D array then will change according to that size to become a 3x3 2D array, I hope I am as clear as I could be, I would really appreciate it if someone can please guide me to a solution, Thank you everyone !!



#include <iostream>
#include <cstdio>
#include <cmath>
#include <cstdlib>

using namespace std;

double Atemp = 0;
double Utemp = 0;
double Working = 0;
double Total = 0;
char Answer = 'x';
int Umain;



void displayOverview ();

void playOrQuit();

void promptNumber();

void fillUserArray(char grid);

int main(){

displayOverview();

playOrQuit();

promptNumber();


return 0;
}

void displayOverview(){

}

void playOrQuit(){

string playOrNot;

cout << "If you want to play please press 'p' for play, and 'q' if you wish to quitn";
cin >> playOrNot;

if(playOrNot == "p"){
cout << "Awesome, lets start playing !!! n";

}if(playOrNot == "q"){
cout << "Alright then, see you soon !!n";
exit(0);
}if(playOrNot != "p" && playOrNot != "q"){
cout << "Invalid entry !!n";
exit(0);
}
}


void promptNumber(){

do{
cout << "Please Enter numbers between 1 and 12: ";
cin >> Umain;
if(Umain <= 12){
for (Utemp = Umain; Utemp > 0; Utemp--){
cout << "Please enter a number: ";
cin >> Atemp;
}
}else{
cout << "Not within limit :(n";
}
}while (Answer == 'y');
}

void fillUserGrid (char grid){

for( int row = 0; row < Umain; row++ ) {
for(int col = 0; col < Umain; col++){
grid[row][col] = userInput.at( row * Umain + col );
}
}
}

void outputUserGrid(char grid){

for (int row = 0; row < Umain; row++){
for(int col = 0; col < Umain; col++){
cout << grid[row][col]<<" ";
}
cout << endl;
}
}









share|improve this question




















  • 1





    Possible duplicate of How do I declare a 2d array in C++ using new?

    – Ken Y-N
    Nov 21 '18 at 4:47











  • @KenY-N I don't agree because OP didn't explicitly ask for new.

    – Swordfish
    Nov 21 '18 at 4:59






  • 1





    If you want an array-like thingy that you can resize, please use std::vector<char> grid;, set its size to rows * columns and access it using grid[y * columns + x];. Thanks.

    – Swordfish
    Nov 21 '18 at 5:01













  • @Swordfish and neither did they ask for a 1D std::vector - they have grid[row][col] (although that function's parameter is wrong...).

    – Ken Y-N
    Nov 21 '18 at 5:03













  • This feels like XY Problem. I've answered accordingly. If it turns out you absolutely need a data structure that is the exact size you need, then the duplicate question mentioned earlier provides solutions... But scroll down to some of the lesser-voted answers to find the good solutions.

    – paddy
    Nov 21 '18 at 5:18


















2















So, I have a code when I prompt the user to enter a number, I want the size of the 2D array to be changed according to what the user entered, for example:



Enter a number between 1 and 12:
3



The 2D array then will change according to that size to become a 3x3 2D array, I hope I am as clear as I could be, I would really appreciate it if someone can please guide me to a solution, Thank you everyone !!



#include <iostream>
#include <cstdio>
#include <cmath>
#include <cstdlib>

using namespace std;

double Atemp = 0;
double Utemp = 0;
double Working = 0;
double Total = 0;
char Answer = 'x';
int Umain;



void displayOverview ();

void playOrQuit();

void promptNumber();

void fillUserArray(char grid);

int main(){

displayOverview();

playOrQuit();

promptNumber();


return 0;
}

void displayOverview(){

}

void playOrQuit(){

string playOrNot;

cout << "If you want to play please press 'p' for play, and 'q' if you wish to quitn";
cin >> playOrNot;

if(playOrNot == "p"){
cout << "Awesome, lets start playing !!! n";

}if(playOrNot == "q"){
cout << "Alright then, see you soon !!n";
exit(0);
}if(playOrNot != "p" && playOrNot != "q"){
cout << "Invalid entry !!n";
exit(0);
}
}


void promptNumber(){

do{
cout << "Please Enter numbers between 1 and 12: ";
cin >> Umain;
if(Umain <= 12){
for (Utemp = Umain; Utemp > 0; Utemp--){
cout << "Please enter a number: ";
cin >> Atemp;
}
}else{
cout << "Not within limit :(n";
}
}while (Answer == 'y');
}

void fillUserGrid (char grid){

for( int row = 0; row < Umain; row++ ) {
for(int col = 0; col < Umain; col++){
grid[row][col] = userInput.at( row * Umain + col );
}
}
}

void outputUserGrid(char grid){

for (int row = 0; row < Umain; row++){
for(int col = 0; col < Umain; col++){
cout << grid[row][col]<<" ";
}
cout << endl;
}
}









share|improve this question




















  • 1





    Possible duplicate of How do I declare a 2d array in C++ using new?

    – Ken Y-N
    Nov 21 '18 at 4:47











  • @KenY-N I don't agree because OP didn't explicitly ask for new.

    – Swordfish
    Nov 21 '18 at 4:59






  • 1





    If you want an array-like thingy that you can resize, please use std::vector<char> grid;, set its size to rows * columns and access it using grid[y * columns + x];. Thanks.

    – Swordfish
    Nov 21 '18 at 5:01













  • @Swordfish and neither did they ask for a 1D std::vector - they have grid[row][col] (although that function's parameter is wrong...).

    – Ken Y-N
    Nov 21 '18 at 5:03













  • This feels like XY Problem. I've answered accordingly. If it turns out you absolutely need a data structure that is the exact size you need, then the duplicate question mentioned earlier provides solutions... But scroll down to some of the lesser-voted answers to find the good solutions.

    – paddy
    Nov 21 '18 at 5:18
















2












2








2








So, I have a code when I prompt the user to enter a number, I want the size of the 2D array to be changed according to what the user entered, for example:



Enter a number between 1 and 12:
3



The 2D array then will change according to that size to become a 3x3 2D array, I hope I am as clear as I could be, I would really appreciate it if someone can please guide me to a solution, Thank you everyone !!



#include <iostream>
#include <cstdio>
#include <cmath>
#include <cstdlib>

using namespace std;

double Atemp = 0;
double Utemp = 0;
double Working = 0;
double Total = 0;
char Answer = 'x';
int Umain;



void displayOverview ();

void playOrQuit();

void promptNumber();

void fillUserArray(char grid);

int main(){

displayOverview();

playOrQuit();

promptNumber();


return 0;
}

void displayOverview(){

}

void playOrQuit(){

string playOrNot;

cout << "If you want to play please press 'p' for play, and 'q' if you wish to quitn";
cin >> playOrNot;

if(playOrNot == "p"){
cout << "Awesome, lets start playing !!! n";

}if(playOrNot == "q"){
cout << "Alright then, see you soon !!n";
exit(0);
}if(playOrNot != "p" && playOrNot != "q"){
cout << "Invalid entry !!n";
exit(0);
}
}


void promptNumber(){

do{
cout << "Please Enter numbers between 1 and 12: ";
cin >> Umain;
if(Umain <= 12){
for (Utemp = Umain; Utemp > 0; Utemp--){
cout << "Please enter a number: ";
cin >> Atemp;
}
}else{
cout << "Not within limit :(n";
}
}while (Answer == 'y');
}

void fillUserGrid (char grid){

for( int row = 0; row < Umain; row++ ) {
for(int col = 0; col < Umain; col++){
grid[row][col] = userInput.at( row * Umain + col );
}
}
}

void outputUserGrid(char grid){

for (int row = 0; row < Umain; row++){
for(int col = 0; col < Umain; col++){
cout << grid[row][col]<<" ";
}
cout << endl;
}
}









share|improve this question
















So, I have a code when I prompt the user to enter a number, I want the size of the 2D array to be changed according to what the user entered, for example:



Enter a number between 1 and 12:
3



The 2D array then will change according to that size to become a 3x3 2D array, I hope I am as clear as I could be, I would really appreciate it if someone can please guide me to a solution, Thank you everyone !!



#include <iostream>
#include <cstdio>
#include <cmath>
#include <cstdlib>

using namespace std;

double Atemp = 0;
double Utemp = 0;
double Working = 0;
double Total = 0;
char Answer = 'x';
int Umain;



void displayOverview ();

void playOrQuit();

void promptNumber();

void fillUserArray(char grid);

int main(){

displayOverview();

playOrQuit();

promptNumber();


return 0;
}

void displayOverview(){

}

void playOrQuit(){

string playOrNot;

cout << "If you want to play please press 'p' for play, and 'q' if you wish to quitn";
cin >> playOrNot;

if(playOrNot == "p"){
cout << "Awesome, lets start playing !!! n";

}if(playOrNot == "q"){
cout << "Alright then, see you soon !!n";
exit(0);
}if(playOrNot != "p" && playOrNot != "q"){
cout << "Invalid entry !!n";
exit(0);
}
}


void promptNumber(){

do{
cout << "Please Enter numbers between 1 and 12: ";
cin >> Umain;
if(Umain <= 12){
for (Utemp = Umain; Utemp > 0; Utemp--){
cout << "Please enter a number: ";
cin >> Atemp;
}
}else{
cout << "Not within limit :(n";
}
}while (Answer == 'y');
}

void fillUserGrid (char grid){

for( int row = 0; row < Umain; row++ ) {
for(int col = 0; col < Umain; col++){
grid[row][col] = userInput.at( row * Umain + col );
}
}
}

void outputUserGrid(char grid){

for (int row = 0; row < Umain; row++){
for(int col = 0; col < Umain; col++){
cout << grid[row][col]<<" ";
}
cout << endl;
}
}






c++ arrays multidimensional-array






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 21 '18 at 4:49







DanielAA9

















asked Nov 21 '18 at 4:40









DanielAA9DanielAA9

375




375








  • 1





    Possible duplicate of How do I declare a 2d array in C++ using new?

    – Ken Y-N
    Nov 21 '18 at 4:47











  • @KenY-N I don't agree because OP didn't explicitly ask for new.

    – Swordfish
    Nov 21 '18 at 4:59






  • 1





    If you want an array-like thingy that you can resize, please use std::vector<char> grid;, set its size to rows * columns and access it using grid[y * columns + x];. Thanks.

    – Swordfish
    Nov 21 '18 at 5:01













  • @Swordfish and neither did they ask for a 1D std::vector - they have grid[row][col] (although that function's parameter is wrong...).

    – Ken Y-N
    Nov 21 '18 at 5:03













  • This feels like XY Problem. I've answered accordingly. If it turns out you absolutely need a data structure that is the exact size you need, then the duplicate question mentioned earlier provides solutions... But scroll down to some of the lesser-voted answers to find the good solutions.

    – paddy
    Nov 21 '18 at 5:18
















  • 1





    Possible duplicate of How do I declare a 2d array in C++ using new?

    – Ken Y-N
    Nov 21 '18 at 4:47











  • @KenY-N I don't agree because OP didn't explicitly ask for new.

    – Swordfish
    Nov 21 '18 at 4:59






  • 1





    If you want an array-like thingy that you can resize, please use std::vector<char> grid;, set its size to rows * columns and access it using grid[y * columns + x];. Thanks.

    – Swordfish
    Nov 21 '18 at 5:01













  • @Swordfish and neither did they ask for a 1D std::vector - they have grid[row][col] (although that function's parameter is wrong...).

    – Ken Y-N
    Nov 21 '18 at 5:03













  • This feels like XY Problem. I've answered accordingly. If it turns out you absolutely need a data structure that is the exact size you need, then the duplicate question mentioned earlier provides solutions... But scroll down to some of the lesser-voted answers to find the good solutions.

    – paddy
    Nov 21 '18 at 5:18










1




1





Possible duplicate of How do I declare a 2d array in C++ using new?

– Ken Y-N
Nov 21 '18 at 4:47





Possible duplicate of How do I declare a 2d array in C++ using new?

– Ken Y-N
Nov 21 '18 at 4:47













@KenY-N I don't agree because OP didn't explicitly ask for new.

– Swordfish
Nov 21 '18 at 4:59





@KenY-N I don't agree because OP didn't explicitly ask for new.

– Swordfish
Nov 21 '18 at 4:59




1




1





If you want an array-like thingy that you can resize, please use std::vector<char> grid;, set its size to rows * columns and access it using grid[y * columns + x];. Thanks.

– Swordfish
Nov 21 '18 at 5:01







If you want an array-like thingy that you can resize, please use std::vector<char> grid;, set its size to rows * columns and access it using grid[y * columns + x];. Thanks.

– Swordfish
Nov 21 '18 at 5:01















@Swordfish and neither did they ask for a 1D std::vector - they have grid[row][col] (although that function's parameter is wrong...).

– Ken Y-N
Nov 21 '18 at 5:03







@Swordfish and neither did they ask for a 1D std::vector - they have grid[row][col] (although that function's parameter is wrong...).

– Ken Y-N
Nov 21 '18 at 5:03















This feels like XY Problem. I've answered accordingly. If it turns out you absolutely need a data structure that is the exact size you need, then the duplicate question mentioned earlier provides solutions... But scroll down to some of the lesser-voted answers to find the good solutions.

– paddy
Nov 21 '18 at 5:18







This feels like XY Problem. I've answered accordingly. If it turns out you absolutely need a data structure that is the exact size you need, then the duplicate question mentioned earlier provides solutions... But scroll down to some of the lesser-voted answers to find the good solutions.

– paddy
Nov 21 '18 at 5:18














1 Answer
1






active

oldest

votes


















2














It's quite legitimate to just use a 12x12 array for your game. When the user wants to play on a smaller grid, you can just use part of it.



The only times this might be an issue are if you're running into L1/L2 cache issues for performance-critical programs, or if you're storing lots of these grids and need to reduce memory use. I would be surprised if either of these scenarios applies to you.






share|improve this answer
























  • I see, thank you for helping me out

    – DanielAA9
    Nov 21 '18 at 5:17











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









2














It's quite legitimate to just use a 12x12 array for your game. When the user wants to play on a smaller grid, you can just use part of it.



The only times this might be an issue are if you're running into L1/L2 cache issues for performance-critical programs, or if you're storing lots of these grids and need to reduce memory use. I would be surprised if either of these scenarios applies to you.






share|improve this answer
























  • I see, thank you for helping me out

    – DanielAA9
    Nov 21 '18 at 5:17
















2














It's quite legitimate to just use a 12x12 array for your game. When the user wants to play on a smaller grid, you can just use part of it.



The only times this might be an issue are if you're running into L1/L2 cache issues for performance-critical programs, or if you're storing lots of these grids and need to reduce memory use. I would be surprised if either of these scenarios applies to you.






share|improve this answer
























  • I see, thank you for helping me out

    – DanielAA9
    Nov 21 '18 at 5:17














2












2








2







It's quite legitimate to just use a 12x12 array for your game. When the user wants to play on a smaller grid, you can just use part of it.



The only times this might be an issue are if you're running into L1/L2 cache issues for performance-critical programs, or if you're storing lots of these grids and need to reduce memory use. I would be surprised if either of these scenarios applies to you.






share|improve this answer













It's quite legitimate to just use a 12x12 array for your game. When the user wants to play on a smaller grid, you can just use part of it.



The only times this might be an issue are if you're running into L1/L2 cache issues for performance-critical programs, or if you're storing lots of these grids and need to reduce memory use. I would be surprised if either of these scenarios applies to you.







share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 21 '18 at 5:08









paddypaddy

42.7k53176




42.7k53176













  • I see, thank you for helping me out

    – DanielAA9
    Nov 21 '18 at 5:17



















  • I see, thank you for helping me out

    – DanielAA9
    Nov 21 '18 at 5:17

















I see, thank you for helping me out

– DanielAA9
Nov 21 '18 at 5:17





I see, thank you for helping me out

– DanielAA9
Nov 21 '18 at 5:17


















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