get second element by class name if it exists
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}
I'm trying to get the ID of an element by class name like this
var prod_id2 = document.getElementsByClassName('select-selected')[1].id
document.getElementById('hidden-input-2').value = prod_id2;
This works fine, but my issue is that if there's only one element with that class it breaks the functionality, so I need some sort of if statement to only define this var if there is a second div with that class.
Any ideas?
javascript
asked Nov 23 '18 at 17:11
MariaLMariaL
355325
add a comment |
I'm trying to get the ID of an element by class name like this
var prod_id2 = document.getElementsByClassName('select-selected')[1].id
document.getElementById('hidden-input-2').value = prod_id2;
This works fine, but my issue is that if there's only one element with that class it breaks the functionality, so I need some sort of if statement to only define this var if there is a second div with that class.
Any ideas?
javascript
asked Nov 23 '18 at 17:11
MariaLMariaL
355325
1
Get the node list and verify that.lengthis at least 2.
– Pointy
Nov 23 '18 at 17:12
add a comment |
I'm trying to get the ID of an element by class name like this
var prod_id2 = document.getElementsByClassName('select-selected')[1].id
document.getElementById('hidden-input-2').value = prod_id2;
This works fine, but my issue is that if there's only one element with that class it breaks the functionality, so I need some sort of if statement to only define this var if there is a second div with that class.
Any ideas?
javascript
asked Nov 23 '18 at 17:11
MariaLMariaL
355325
I'm trying to get the ID of an element by class name like this
var prod_id2 = document.getElementsByClassName('select-selected')[1].id
document.getElementById('hidden-input-2').value = prod_id2;
This works fine, but my issue is that if there's only one element with that class it breaks the functionality, so I need some sort of if statement to only define this var if there is a second div with that class.
Any ideas?
javascript
javascript
asked Nov 23 '18 at 17:11
MariaLMariaL
355325
asked Nov 23 '18 at 17:11
MariaLMariaL
355325
asked Nov 23 '18 at 17:11
MariaLMariaL
355325
asked Nov 23 '18 at 17:11
MariaLMariaL
355325
asked Nov 23 '18 at 17:11
MariaLMariaL
355325
355325
1
Get the node list and verify that.lengthis at least 2.
– Pointy
Nov 23 '18 at 17:12
add a comment |
1
Get the node list and verify that.lengthis at least 2.
– Pointy
Nov 23 '18 at 17:12
1
1
Get the node list and verify that
.length is at least 2.– Pointy
Nov 23 '18 at 17:12
Get the node list and verify that
.length is at least 2.– Pointy
Nov 23 '18 at 17:12
add a comment |
3 Answers
3
active
oldest
votes
Try this:
const elements = document.querySelectorAll('.test');
if (elements[1]) {
elements[1].innerText = 'Hithere';
}<div class="test">hi</div>
<div class="test">hi</div>
<div class="test">hi</div>
document.querySelectorAll('.test');selects all elements with the class test and returns a nodelist.- Then we can access the second element via of the nodelist with elements[1].
answered Nov 23 '18 at 17:15
Willem van der VeenWillem van der Veen
5,61333139
add a comment |
Here is how to check for the second element.
You can also set another fallback , different to null:
document.addEventListener("DOMContentLoaded", function(event) {
var selectedElements = document.querySelectorAll('.selected-selected'),
prod_id2 = selectedElements[1] || null;
alert(prod_id2)
});<div id="test" class="selected-selected"></div>You can also check that value then:
if (prod_id2) { // do some other stuff with the set value }
answered Nov 23 '18 at 17:20
GutelaunetypGutelaunetyp
17510
add a comment |
It breaks the functionality I think because you are grabbing the 2nd element specifically. You can do:
const prod_id2 = document.querySelectorAll('.select-selected');
and loop over the elements and grab the ID
prod_id2.forEach((prod, index) => {
if(index === 2) {
document.getElementById('hidden-input-2').value = prod.id;
}
})
answered Nov 23 '18 at 17:18
DmitriyDmitriy
633316
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
Try this:
const elements = document.querySelectorAll('.test');
if (elements[1]) {
elements[1].innerText = 'Hithere';
}<div class="test">hi</div>
<div class="test">hi</div>
<div class="test">hi</div>
document.querySelectorAll('.test');selects all elements with the class test and returns a nodelist.- Then we can access the second element via of the nodelist with elements[1].
answered Nov 23 '18 at 17:15
Willem van der VeenWillem van der Veen
5,61333139
add a comment |
Try this:
const elements = document.querySelectorAll('.test');
if (elements[1]) {
elements[1].innerText = 'Hithere';
}<div class="test">hi</div>
<div class="test">hi</div>
<div class="test">hi</div>
document.querySelectorAll('.test');selects all elements with the class test and returns a nodelist.- Then we can access the second element via of the nodelist with elements[1].
answered Nov 23 '18 at 17:15
Willem van der VeenWillem van der Veen
5,61333139
add a comment |
Try this:
const elements = document.querySelectorAll('.test');
if (elements[1]) {
elements[1].innerText = 'Hithere';
}<div class="test">hi</div>
<div class="test">hi</div>
<div class="test">hi</div>
document.querySelectorAll('.test');selects all elements with the class test and returns a nodelist.- Then we can access the second element via of the nodelist with elements[1].
answered Nov 23 '18 at 17:15
Willem van der VeenWillem van der Veen
5,61333139
Try this:
const elements = document.querySelectorAll('.test');
if (elements[1]) {
elements[1].innerText = 'Hithere';
}<div class="test">hi</div>
<div class="test">hi</div>
<div class="test">hi</div>
document.querySelectorAll('.test');selects all elements with the class test and returns a nodelist.- Then we can access the second element via of the nodelist with elements[1].
const elements = document.querySelectorAll('.test');
if (elements[1]) {
elements[1].innerText = 'Hithere';
}<div class="test">hi</div>
<div class="test">hi</div>
<div class="test">hi</div>const elements = document.querySelectorAll('.test');
if (elements[1]) {
elements[1].innerText = 'Hithere';
}<div class="test">hi</div>
<div class="test">hi</div>
<div class="test">hi</div>answered Nov 23 '18 at 17:15
Willem van der VeenWillem van der Veen
5,61333139
answered Nov 23 '18 at 17:15
Willem van der VeenWillem van der Veen
5,61333139
answered Nov 23 '18 at 17:15
Willem van der VeenWillem van der Veen
5,61333139
answered Nov 23 '18 at 17:15
Willem van der VeenWillem van der Veen
5,61333139
5,61333139
add a comment |
add a comment |
Here is how to check for the second element.
You can also set another fallback , different to null:
document.addEventListener("DOMContentLoaded", function(event) {
var selectedElements = document.querySelectorAll('.selected-selected'),
prod_id2 = selectedElements[1] || null;
alert(prod_id2)
});<div id="test" class="selected-selected"></div>You can also check that value then:
if (prod_id2) { // do some other stuff with the set value }
answered Nov 23 '18 at 17:20
GutelaunetypGutelaunetyp
17510
add a comment |
Here is how to check for the second element.
You can also set another fallback , different to null:
document.addEventListener("DOMContentLoaded", function(event) {
var selectedElements = document.querySelectorAll('.selected-selected'),
prod_id2 = selectedElements[1] || null;
alert(prod_id2)
});<div id="test" class="selected-selected"></div>You can also check that value then:
if (prod_id2) { // do some other stuff with the set value }
answered Nov 23 '18 at 17:20
GutelaunetypGutelaunetyp
17510
add a comment |
Here is how to check for the second element.
You can also set another fallback , different to null:
document.addEventListener("DOMContentLoaded", function(event) {
var selectedElements = document.querySelectorAll('.selected-selected'),
prod_id2 = selectedElements[1] || null;
alert(prod_id2)
});<div id="test" class="selected-selected"></div>You can also check that value then:
if (prod_id2) { // do some other stuff with the set value }
answered Nov 23 '18 at 17:20
GutelaunetypGutelaunetyp
17510
Here is how to check for the second element.
You can also set another fallback , different to null:
document.addEventListener("DOMContentLoaded", function(event) {
var selectedElements = document.querySelectorAll('.selected-selected'),
prod_id2 = selectedElements[1] || null;
alert(prod_id2)
});<div id="test" class="selected-selected"></div>You can also check that value then:
if (prod_id2) { // do some other stuff with the set value }
document.addEventListener("DOMContentLoaded", function(event) {
var selectedElements = document.querySelectorAll('.selected-selected'),
prod_id2 = selectedElements[1] || null;
alert(prod_id2)
});<div id="test" class="selected-selected"></div>document.addEventListener("DOMContentLoaded", function(event) {
var selectedElements = document.querySelectorAll('.selected-selected'),
prod_id2 = selectedElements[1] || null;
alert(prod_id2)
});<div id="test" class="selected-selected"></div>answered Nov 23 '18 at 17:20
GutelaunetypGutelaunetyp
17510
answered Nov 23 '18 at 17:20
GutelaunetypGutelaunetyp
17510
answered Nov 23 '18 at 17:20
GutelaunetypGutelaunetyp
17510
answered Nov 23 '18 at 17:20
GutelaunetypGutelaunetyp
17510
17510
add a comment |
add a comment |
It breaks the functionality I think because you are grabbing the 2nd element specifically. You can do:
const prod_id2 = document.querySelectorAll('.select-selected');
and loop over the elements and grab the ID
prod_id2.forEach((prod, index) => {
if(index === 2) {
document.getElementById('hidden-input-2').value = prod.id;
}
})
answered Nov 23 '18 at 17:18
DmitriyDmitriy
633316
add a comment |
It breaks the functionality I think because you are grabbing the 2nd element specifically. You can do:
const prod_id2 = document.querySelectorAll('.select-selected');
and loop over the elements and grab the ID
prod_id2.forEach((prod, index) => {
if(index === 2) {
document.getElementById('hidden-input-2').value = prod.id;
}
})
answered Nov 23 '18 at 17:18
DmitriyDmitriy
633316
add a comment |
It breaks the functionality I think because you are grabbing the 2nd element specifically. You can do:
const prod_id2 = document.querySelectorAll('.select-selected');
and loop over the elements and grab the ID
prod_id2.forEach((prod, index) => {
if(index === 2) {
document.getElementById('hidden-input-2').value = prod.id;
}
})
answered Nov 23 '18 at 17:18
DmitriyDmitriy
633316
It breaks the functionality I think because you are grabbing the 2nd element specifically. You can do:
const prod_id2 = document.querySelectorAll('.select-selected');
and loop over the elements and grab the ID
prod_id2.forEach((prod, index) => {
if(index === 2) {
document.getElementById('hidden-input-2').value = prod.id;
}
})
answered Nov 23 '18 at 17:18
DmitriyDmitriy
633316
edited Nov 23 '18 at 17:23
answered Nov 23 '18 at 17:18
DmitriyDmitriy
633316
answered Nov 23 '18 at 17:18
DmitriyDmitriy
633316
answered Nov 23 '18 at 17:18
DmitriyDmitriy
633316
633316
add a comment |
add a comment |
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1
Get the node list and verify that
.lengthis at least 2.– Pointy
Nov 23 '18 at 17:12