Haskell transfer between monadic functions





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Feel I am never going to fully grasp Haskell now. Two functions: one that counts records in a SQlite DB, so it can produce incremental IDs (checkUniqueID). The other one to make the records, calling on checkUniqueID. I just need the value over to taskEntry as an Int. I guess I am missing the knowledge to stay in the monadic realm. Code below.



-- checkUniqueID :: IO ()
checkUniqueID = do
conn <- open "taglist.db"
len <- query_ conn "SELECT (id) FROM task" :: IO [Only Int]
let showLength = Data.List.length $ len
close conn
return (showLength + 1) -- for testing purposes

-- fieldnames: id, task, date_in, date_out
taskEntry :: IO ()
taskEntry = do
putStrLn "Provide task and date due: "
let taskIDInt = checkUniqueID -- issue here!
task <- getLine
date_out <- getLine
let date_in = "today"
conn <- open "taglist.db"
execute conn "INSERT INTO task (id, task, date_in, date_out) VALUES (?,?,?,?)"
(taskIDInt :: Int , task :: String , date_in :: String , date_out :: String)
close conn
return ()









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  • 3





    for starters, the type should probably be checkUniqueID :: IO Int - you actually want to return something of type Int, besides executing an IO action. Then: taskIDInt <- checkUniqueID, because checkUniqueID is in IO.

    – mb21
    Nov 23 '18 at 16:04


















-1















Feel I am never going to fully grasp Haskell now. Two functions: one that counts records in a SQlite DB, so it can produce incremental IDs (checkUniqueID). The other one to make the records, calling on checkUniqueID. I just need the value over to taskEntry as an Int. I guess I am missing the knowledge to stay in the monadic realm. Code below.



-- checkUniqueID :: IO ()
checkUniqueID = do
conn <- open "taglist.db"
len <- query_ conn "SELECT (id) FROM task" :: IO [Only Int]
let showLength = Data.List.length $ len
close conn
return (showLength + 1) -- for testing purposes

-- fieldnames: id, task, date_in, date_out
taskEntry :: IO ()
taskEntry = do
putStrLn "Provide task and date due: "
let taskIDInt = checkUniqueID -- issue here!
task <- getLine
date_out <- getLine
let date_in = "today"
conn <- open "taglist.db"
execute conn "INSERT INTO task (id, task, date_in, date_out) VALUES (?,?,?,?)"
(taskIDInt :: Int , task :: String , date_in :: String , date_out :: String)
close conn
return ()









share|improve this question


















  • 3





    for starters, the type should probably be checkUniqueID :: IO Int - you actually want to return something of type Int, besides executing an IO action. Then: taskIDInt <- checkUniqueID, because checkUniqueID is in IO.

    – mb21
    Nov 23 '18 at 16:04














-1












-1








-1








Feel I am never going to fully grasp Haskell now. Two functions: one that counts records in a SQlite DB, so it can produce incremental IDs (checkUniqueID). The other one to make the records, calling on checkUniqueID. I just need the value over to taskEntry as an Int. I guess I am missing the knowledge to stay in the monadic realm. Code below.



-- checkUniqueID :: IO ()
checkUniqueID = do
conn <- open "taglist.db"
len <- query_ conn "SELECT (id) FROM task" :: IO [Only Int]
let showLength = Data.List.length $ len
close conn
return (showLength + 1) -- for testing purposes

-- fieldnames: id, task, date_in, date_out
taskEntry :: IO ()
taskEntry = do
putStrLn "Provide task and date due: "
let taskIDInt = checkUniqueID -- issue here!
task <- getLine
date_out <- getLine
let date_in = "today"
conn <- open "taglist.db"
execute conn "INSERT INTO task (id, task, date_in, date_out) VALUES (?,?,?,?)"
(taskIDInt :: Int , task :: String , date_in :: String , date_out :: String)
close conn
return ()









share|improve this question














Feel I am never going to fully grasp Haskell now. Two functions: one that counts records in a SQlite DB, so it can produce incremental IDs (checkUniqueID). The other one to make the records, calling on checkUniqueID. I just need the value over to taskEntry as an Int. I guess I am missing the knowledge to stay in the monadic realm. Code below.



-- checkUniqueID :: IO ()
checkUniqueID = do
conn <- open "taglist.db"
len <- query_ conn "SELECT (id) FROM task" :: IO [Only Int]
let showLength = Data.List.length $ len
close conn
return (showLength + 1) -- for testing purposes

-- fieldnames: id, task, date_in, date_out
taskEntry :: IO ()
taskEntry = do
putStrLn "Provide task and date due: "
let taskIDInt = checkUniqueID -- issue here!
task <- getLine
date_out <- getLine
let date_in = "today"
conn <- open "taglist.db"
execute conn "INSERT INTO task (id, task, date_in, date_out) VALUES (?,?,?,?)"
(taskIDInt :: Int , task :: String , date_in :: String , date_out :: String)
close conn
return ()






sqlite haskell io monads






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asked Nov 23 '18 at 16:00









MadderoteMadderote

352211




352211








  • 3





    for starters, the type should probably be checkUniqueID :: IO Int - you actually want to return something of type Int, besides executing an IO action. Then: taskIDInt <- checkUniqueID, because checkUniqueID is in IO.

    – mb21
    Nov 23 '18 at 16:04














  • 3





    for starters, the type should probably be checkUniqueID :: IO Int - you actually want to return something of type Int, besides executing an IO action. Then: taskIDInt <- checkUniqueID, because checkUniqueID is in IO.

    – mb21
    Nov 23 '18 at 16:04








3




3





for starters, the type should probably be checkUniqueID :: IO Int - you actually want to return something of type Int, besides executing an IO action. Then: taskIDInt <- checkUniqueID, because checkUniqueID is in IO.

– mb21
Nov 23 '18 at 16:04





for starters, the type should probably be checkUniqueID :: IO Int - you actually want to return something of type Int, besides executing an IO action. Then: taskIDInt <- checkUniqueID, because checkUniqueID is in IO.

– mb21
Nov 23 '18 at 16:04












1 Answer
1






active

oldest

votes


















2














First, checkUniqueID returns an Int, so its type should be IO Int, not IO ():



checkUniqueID :: IO Int


Second, within the do notation, the left arrow <- is what binds result of a monadic function to a name. You're already using it with getLine, so I'm not entirely sure why you would fail to use it with checkUniqueID as well:



taskIDInt <- checkUniqueID





share|improve this answer
























  • I am not failing with your suggestion. I have a hard time seeing the forrest through the trees. You put me on the right track and it works! Sorry for this... Sometimes I feel a bit stupid trying monoids, applicatives, functors etc while the only thing I need to do is a simple bind of two monadic functions! Thanks

    – Madderote
    Nov 23 '18 at 19:02












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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









2














First, checkUniqueID returns an Int, so its type should be IO Int, not IO ():



checkUniqueID :: IO Int


Second, within the do notation, the left arrow <- is what binds result of a monadic function to a name. You're already using it with getLine, so I'm not entirely sure why you would fail to use it with checkUniqueID as well:



taskIDInt <- checkUniqueID





share|improve this answer
























  • I am not failing with your suggestion. I have a hard time seeing the forrest through the trees. You put me on the right track and it works! Sorry for this... Sometimes I feel a bit stupid trying monoids, applicatives, functors etc while the only thing I need to do is a simple bind of two monadic functions! Thanks

    – Madderote
    Nov 23 '18 at 19:02
















2














First, checkUniqueID returns an Int, so its type should be IO Int, not IO ():



checkUniqueID :: IO Int


Second, within the do notation, the left arrow <- is what binds result of a monadic function to a name. You're already using it with getLine, so I'm not entirely sure why you would fail to use it with checkUniqueID as well:



taskIDInt <- checkUniqueID





share|improve this answer
























  • I am not failing with your suggestion. I have a hard time seeing the forrest through the trees. You put me on the right track and it works! Sorry for this... Sometimes I feel a bit stupid trying monoids, applicatives, functors etc while the only thing I need to do is a simple bind of two monadic functions! Thanks

    – Madderote
    Nov 23 '18 at 19:02














2












2








2







First, checkUniqueID returns an Int, so its type should be IO Int, not IO ():



checkUniqueID :: IO Int


Second, within the do notation, the left arrow <- is what binds result of a monadic function to a name. You're already using it with getLine, so I'm not entirely sure why you would fail to use it with checkUniqueID as well:



taskIDInt <- checkUniqueID





share|improve this answer













First, checkUniqueID returns an Int, so its type should be IO Int, not IO ():



checkUniqueID :: IO Int


Second, within the do notation, the left arrow <- is what binds result of a monadic function to a name. You're already using it with getLine, so I'm not entirely sure why you would fail to use it with checkUniqueID as well:



taskIDInt <- checkUniqueID






share|improve this answer












share|improve this answer



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answered Nov 23 '18 at 16:20









Fyodor SoikinFyodor Soikin

43.8k569102




43.8k569102













  • I am not failing with your suggestion. I have a hard time seeing the forrest through the trees. You put me on the right track and it works! Sorry for this... Sometimes I feel a bit stupid trying monoids, applicatives, functors etc while the only thing I need to do is a simple bind of two monadic functions! Thanks

    – Madderote
    Nov 23 '18 at 19:02



















  • I am not failing with your suggestion. I have a hard time seeing the forrest through the trees. You put me on the right track and it works! Sorry for this... Sometimes I feel a bit stupid trying monoids, applicatives, functors etc while the only thing I need to do is a simple bind of two monadic functions! Thanks

    – Madderote
    Nov 23 '18 at 19:02

















I am not failing with your suggestion. I have a hard time seeing the forrest through the trees. You put me on the right track and it works! Sorry for this... Sometimes I feel a bit stupid trying monoids, applicatives, functors etc while the only thing I need to do is a simple bind of two monadic functions! Thanks

– Madderote
Nov 23 '18 at 19:02





I am not failing with your suggestion. I have a hard time seeing the forrest through the trees. You put me on the right track and it works! Sorry for this... Sometimes I feel a bit stupid trying monoids, applicatives, functors etc while the only thing I need to do is a simple bind of two monadic functions! Thanks

– Madderote
Nov 23 '18 at 19:02




















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