InvocableMethod Through anonymous APEX
I have an invocablemethod that runs from a process builder that got broken for a few months I had a mapping issue and some fields didn't populate or create for various reasons. In the process builder you only need to pass the Opportunity Id and a string variable and it does the work.
I want to fix my error and pass in Opportunity Ids directly to the method however, I can't figure out how to populate the data to do it.
Example:
@InvocableMethod(label='Perform Mapping' description='Performs a ConvertAnything mapping given a list of records.')
global static void generateAndInsertAllRecords(List<ContextRecord> contextRecords)
{
// do stuff
}
ContextRecord is defined here:
global class SL_Mapping_Handler extends SL_Mapping_Handler_Helper {
// used for determining which records to perform the mapping from
global class ContextRecord {
@InvocableVariable(label='Id' required=true)
global Id Id;
@InvocableVariable(label='Custom Mapping Identifier')
global String customMappingIdentifier;
}
I'm in anon apex trying to do something like this:
SL_Mapping_Handler.ContextRecord cr = new SL_MApping_Handler.ContextRecord();
cr.Id = '006A000000YN0gd';
cr.customMappingIdentifier = 'Opp Auto Renewal';
List<ContextRecord> l = new List<ContextRecord>();
l.add(cr);
SL_Mapping_Handler.generateAndInsertAllRecords(l);
But I get an error:
Line: 3, Column: 1 Invalid type: ContextRecord
Is this possible to do? Is it just a syntax error?
apex invocable-method
edited 11 hours ago
Adrian Larson♦
108k19115243
asked 11 hours ago
Dan WoodingDan Wooding
1,9671137
add a comment |
I have an invocablemethod that runs from a process builder that got broken for a few months I had a mapping issue and some fields didn't populate or create for various reasons. In the process builder you only need to pass the Opportunity Id and a string variable and it does the work.
I want to fix my error and pass in Opportunity Ids directly to the method however, I can't figure out how to populate the data to do it.
Example:
@InvocableMethod(label='Perform Mapping' description='Performs a ConvertAnything mapping given a list of records.')
global static void generateAndInsertAllRecords(List<ContextRecord> contextRecords)
{
// do stuff
}
ContextRecord is defined here:
global class SL_Mapping_Handler extends SL_Mapping_Handler_Helper {
// used for determining which records to perform the mapping from
global class ContextRecord {
@InvocableVariable(label='Id' required=true)
global Id Id;
@InvocableVariable(label='Custom Mapping Identifier')
global String customMappingIdentifier;
}
I'm in anon apex trying to do something like this:
SL_Mapping_Handler.ContextRecord cr = new SL_MApping_Handler.ContextRecord();
cr.Id = '006A000000YN0gd';
cr.customMappingIdentifier = 'Opp Auto Renewal';
List<ContextRecord> l = new List<ContextRecord>();
l.add(cr);
SL_Mapping_Handler.generateAndInsertAllRecords(l);
But I get an error:
Line: 3, Column: 1 Invalid type: ContextRecord
Is this possible to do? Is it just a syntax error?
apex invocable-method
edited 11 hours ago
Adrian Larson♦
108k19115243
asked 11 hours ago
Dan WoodingDan Wooding
1,9671137
add a comment |
I have an invocablemethod that runs from a process builder that got broken for a few months I had a mapping issue and some fields didn't populate or create for various reasons. In the process builder you only need to pass the Opportunity Id and a string variable and it does the work.
I want to fix my error and pass in Opportunity Ids directly to the method however, I can't figure out how to populate the data to do it.
Example:
@InvocableMethod(label='Perform Mapping' description='Performs a ConvertAnything mapping given a list of records.')
global static void generateAndInsertAllRecords(List<ContextRecord> contextRecords)
{
// do stuff
}
ContextRecord is defined here:
global class SL_Mapping_Handler extends SL_Mapping_Handler_Helper {
// used for determining which records to perform the mapping from
global class ContextRecord {
@InvocableVariable(label='Id' required=true)
global Id Id;
@InvocableVariable(label='Custom Mapping Identifier')
global String customMappingIdentifier;
}
I'm in anon apex trying to do something like this:
SL_Mapping_Handler.ContextRecord cr = new SL_MApping_Handler.ContextRecord();
cr.Id = '006A000000YN0gd';
cr.customMappingIdentifier = 'Opp Auto Renewal';
List<ContextRecord> l = new List<ContextRecord>();
l.add(cr);
SL_Mapping_Handler.generateAndInsertAllRecords(l);
But I get an error:
Line: 3, Column: 1 Invalid type: ContextRecord
Is this possible to do? Is it just a syntax error?
apex invocable-method
edited 11 hours ago
Adrian Larson♦
108k19115243
asked 11 hours ago
Dan WoodingDan Wooding
1,9671137
I have an invocablemethod that runs from a process builder that got broken for a few months I had a mapping issue and some fields didn't populate or create for various reasons. In the process builder you only need to pass the Opportunity Id and a string variable and it does the work.
I want to fix my error and pass in Opportunity Ids directly to the method however, I can't figure out how to populate the data to do it.
Example:
@InvocableMethod(label='Perform Mapping' description='Performs a ConvertAnything mapping given a list of records.')
global static void generateAndInsertAllRecords(List<ContextRecord> contextRecords)
{
// do stuff
}
ContextRecord is defined here:
global class SL_Mapping_Handler extends SL_Mapping_Handler_Helper {
// used for determining which records to perform the mapping from
global class ContextRecord {
@InvocableVariable(label='Id' required=true)
global Id Id;
@InvocableVariable(label='Custom Mapping Identifier')
global String customMappingIdentifier;
}
I'm in anon apex trying to do something like this:
SL_Mapping_Handler.ContextRecord cr = new SL_MApping_Handler.ContextRecord();
cr.Id = '006A000000YN0gd';
cr.customMappingIdentifier = 'Opp Auto Renewal';
List<ContextRecord> l = new List<ContextRecord>();
l.add(cr);
SL_Mapping_Handler.generateAndInsertAllRecords(l);
But I get an error:
Line: 3, Column: 1 Invalid type: ContextRecord
Is this possible to do? Is it just a syntax error?
apex invocable-method
apex invocable-method
edited 11 hours ago
Adrian Larson♦
108k19115243
asked 11 hours ago
Dan WoodingDan Wooding
1,9671137
edited 11 hours ago
Adrian Larson♦
108k19115243
asked 11 hours ago
Dan WoodingDan Wooding
1,9671137
edited 11 hours ago
Adrian Larson♦
108k19115243
edited 11 hours ago
Adrian Larson♦
108k19115243
edited 11 hours ago
Adrian Larson♦
108k19115243
108k19115243
asked 11 hours ago
Dan WoodingDan Wooding
1,9671137
asked 11 hours ago
Dan WoodingDan Wooding
1,9671137
asked 11 hours ago
Dan WoodingDan Wooding
1,9671137
1,9671137
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
You will need to declare the list in your snippet as:
List<SL_Mapping_Handler.ContextRecord> l = new List<SL_Mapping_Handler.ContextRecord>();
Replaces:
List<ContextRecord> l = new List<ContextRecord>();
edited 11 hours ago
Daniel Ballinger
73k15149394
answered 11 hours ago
Jayant DasJayant Das
14.3k2824
1
Beat me to it. The issue was that OP was trying to reference an inner class outside of its containing class. Unless you're insideSL_Mapping_Handler, you need to prepend the name of the outer class to be able to use the inner class.
– Derek F
11 hours ago
add a comment |
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1 Answer
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1 Answer
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active
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votes
You will need to declare the list in your snippet as:
List<SL_Mapping_Handler.ContextRecord> l = new List<SL_Mapping_Handler.ContextRecord>();
Replaces:
List<ContextRecord> l = new List<ContextRecord>();
edited 11 hours ago
Daniel Ballinger
73k15149394
answered 11 hours ago
Jayant DasJayant Das
14.3k2824
1
Beat me to it. The issue was that OP was trying to reference an inner class outside of its containing class. Unless you're insideSL_Mapping_Handler, you need to prepend the name of the outer class to be able to use the inner class.
– Derek F
11 hours ago
add a comment |
You will need to declare the list in your snippet as:
List<SL_Mapping_Handler.ContextRecord> l = new List<SL_Mapping_Handler.ContextRecord>();
Replaces:
List<ContextRecord> l = new List<ContextRecord>();
edited 11 hours ago
Daniel Ballinger
73k15149394
answered 11 hours ago
Jayant DasJayant Das
14.3k2824
1
Beat me to it. The issue was that OP was trying to reference an inner class outside of its containing class. Unless you're insideSL_Mapping_Handler, you need to prepend the name of the outer class to be able to use the inner class.
– Derek F
11 hours ago
add a comment |
You will need to declare the list in your snippet as:
List<SL_Mapping_Handler.ContextRecord> l = new List<SL_Mapping_Handler.ContextRecord>();
Replaces:
List<ContextRecord> l = new List<ContextRecord>();
edited 11 hours ago
Daniel Ballinger
73k15149394
answered 11 hours ago
Jayant DasJayant Das
14.3k2824
You will need to declare the list in your snippet as:
List<SL_Mapping_Handler.ContextRecord> l = new List<SL_Mapping_Handler.ContextRecord>();
Replaces:
List<ContextRecord> l = new List<ContextRecord>();
edited 11 hours ago
Daniel Ballinger
73k15149394
answered 11 hours ago
Jayant DasJayant Das
14.3k2824
edited 11 hours ago
Daniel Ballinger
73k15149394
edited 11 hours ago
Daniel Ballinger
73k15149394
edited 11 hours ago
Daniel Ballinger
73k15149394
73k15149394
answered 11 hours ago
Jayant DasJayant Das
14.3k2824
answered 11 hours ago
Jayant DasJayant Das
14.3k2824
answered 11 hours ago
Jayant DasJayant Das
14.3k2824
14.3k2824
1
Beat me to it. The issue was that OP was trying to reference an inner class outside of its containing class. Unless you're insideSL_Mapping_Handler, you need to prepend the name of the outer class to be able to use the inner class.
– Derek F
11 hours ago
add a comment |
1
Beat me to it. The issue was that OP was trying to reference an inner class outside of its containing class. Unless you're insideSL_Mapping_Handler, you need to prepend the name of the outer class to be able to use the inner class.
– Derek F
11 hours ago
1
1
Beat me to it. The issue was that OP was trying to reference an inner class outside of its containing class. Unless you're inside
SL_Mapping_Handler, you need to prepend the name of the outer class to be able to use the inner class.– Derek F
11 hours ago
Beat me to it. The issue was that OP was trying to reference an inner class outside of its containing class. Unless you're inside
SL_Mapping_Handler, you need to prepend the name of the outer class to be able to use the inner class.– Derek F
11 hours ago
add a comment |
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