How map stream to immutable java class?












2















Consider a piece of code:



imnport reactor.util.context.Context

public Context addAll (Context ctx, Map.Entry<String, Object> hashMap) {
Context ctxVar = ctx;
for (Map.Entry<String, Object> e : hashMap.entrySet()) {
if (e.getValue() != null) {
ctxVar = ctxVar.put(e.getKey(), e.getValue());
}
}
return ctxVar;
}


reactor.util.context.Context is immutable class. So put merges old context with new added value and returns new
context.



The question is - is there more compact way to "combine" HashMap into immutable object using java 8 streams? (Not for Context class only)



Note: I have read about java stream collect and it seems that does not work because I have to supply initial Context
and combine several contexts after map but recreate entire context for combine operations I think is too much.










share|improve this question























  • Shouldn't Map.Entry<String, Object> hashMap be Map<String, Object> hashMap? You use that variable as if it's a Map.

    – Eran
    Nov 22 '18 at 7:46
















2















Consider a piece of code:



imnport reactor.util.context.Context

public Context addAll (Context ctx, Map.Entry<String, Object> hashMap) {
Context ctxVar = ctx;
for (Map.Entry<String, Object> e : hashMap.entrySet()) {
if (e.getValue() != null) {
ctxVar = ctxVar.put(e.getKey(), e.getValue());
}
}
return ctxVar;
}


reactor.util.context.Context is immutable class. So put merges old context with new added value and returns new
context.



The question is - is there more compact way to "combine" HashMap into immutable object using java 8 streams? (Not for Context class only)



Note: I have read about java stream collect and it seems that does not work because I have to supply initial Context
and combine several contexts after map but recreate entire context for combine operations I think is too much.










share|improve this question























  • Shouldn't Map.Entry<String, Object> hashMap be Map<String, Object> hashMap? You use that variable as if it's a Map.

    – Eran
    Nov 22 '18 at 7:46














2












2








2








Consider a piece of code:



imnport reactor.util.context.Context

public Context addAll (Context ctx, Map.Entry<String, Object> hashMap) {
Context ctxVar = ctx;
for (Map.Entry<String, Object> e : hashMap.entrySet()) {
if (e.getValue() != null) {
ctxVar = ctxVar.put(e.getKey(), e.getValue());
}
}
return ctxVar;
}


reactor.util.context.Context is immutable class. So put merges old context with new added value and returns new
context.



The question is - is there more compact way to "combine" HashMap into immutable object using java 8 streams? (Not for Context class only)



Note: I have read about java stream collect and it seems that does not work because I have to supply initial Context
and combine several contexts after map but recreate entire context for combine operations I think is too much.










share|improve this question














Consider a piece of code:



imnport reactor.util.context.Context

public Context addAll (Context ctx, Map.Entry<String, Object> hashMap) {
Context ctxVar = ctx;
for (Map.Entry<String, Object> e : hashMap.entrySet()) {
if (e.getValue() != null) {
ctxVar = ctxVar.put(e.getKey(), e.getValue());
}
}
return ctxVar;
}


reactor.util.context.Context is immutable class. So put merges old context with new added value and returns new
context.



The question is - is there more compact way to "combine" HashMap into immutable object using java 8 streams? (Not for Context class only)



Note: I have read about java stream collect and it seems that does not work because I have to supply initial Context
and combine several contexts after map but recreate entire context for combine operations I think is too much.







java java-8 java-stream






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 22 '18 at 7:27









CherryCherry

9,4292597178




9,4292597178













  • Shouldn't Map.Entry<String, Object> hashMap be Map<String, Object> hashMap? You use that variable as if it's a Map.

    – Eran
    Nov 22 '18 at 7:46



















  • Shouldn't Map.Entry<String, Object> hashMap be Map<String, Object> hashMap? You use that variable as if it's a Map.

    – Eran
    Nov 22 '18 at 7:46

















Shouldn't Map.Entry<String, Object> hashMap be Map<String, Object> hashMap? You use that variable as if it's a Map.

– Eran
Nov 22 '18 at 7:46





Shouldn't Map.Entry<String, Object> hashMap be Map<String, Object> hashMap? You use that variable as if it's a Map.

– Eran
Nov 22 '18 at 7:46












2 Answers
2






active

oldest

votes


















0














You can use reduce:



Context ctxVar = hashMap.entrySet()
.stream()
.filter(e -> e.getValue() != null)
.reduce(ctx,
(c, e) -> c.put(e.getKey(), e.getValue()),
(c1, c2) -> c1.putAll(c2));


It does seem wasteful, though (in the same way your original loop is wasteful), since it creates multiple Context instances when only the last one is needed.



It would make more sense if you write a static method of the Context class (or a constructor) that accepts a Map and only creates a single Context instance for the entries of the Map. However, I now noticed that you didn't write this Context class, so you can't change it.






share|improve this answer


























  • It's a bit long winded but... you could implement a mutable version of Context which accumulates (key, value) pairs, build it up while streaming the map and then hand it over to the provided context with context.addAll( myMutableContext)

    – David Soroko
    Nov 22 '18 at 15:52













  • @DavidSoroko Your approach will iteratively create a new Context for each entry from Context(containing previous entries) provided as a parameter to Context.putAll.

    – ETO
    Nov 23 '18 at 1:58





















0














Your question interested me. I researched the subject.



Here is what I came up with:



package reactor.util.context;

import java.util.Map;
import java.util.Map.Entry;
import static java.util.stream.Collectors.toMap;

public class ContextUtils {
public static Context putAll(Context context, Map map) {
if (map.isEmpty()) {
return context;
} else {
Map contextMap = context.stream()
.filter(e -> e.getValue() != null)
.collect(toMap(Entry::getKey, Entry::getValue));
return new ContextN(contextMap, map);
}
}
}


This utility method creates a new Context containing the entries from both initial context and provided map.



This solution may still look not optimal, as it creates a new HashMap with initiaCapacity = 0 and loadFactor = 0.75f. In fact, this is not a problem, since ContextN itself is a subclass of HashMap with precise capacity and loadFactor = 1. The data from intermediary map will be copied to the context and later it will be collected by GC.



Note: the utility class has to be in package reactor.util.context. ContextN is package-private so it is not accessible from other packages.






share|improve this answer

























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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    0














    You can use reduce:



    Context ctxVar = hashMap.entrySet()
    .stream()
    .filter(e -> e.getValue() != null)
    .reduce(ctx,
    (c, e) -> c.put(e.getKey(), e.getValue()),
    (c1, c2) -> c1.putAll(c2));


    It does seem wasteful, though (in the same way your original loop is wasteful), since it creates multiple Context instances when only the last one is needed.



    It would make more sense if you write a static method of the Context class (or a constructor) that accepts a Map and only creates a single Context instance for the entries of the Map. However, I now noticed that you didn't write this Context class, so you can't change it.






    share|improve this answer


























    • It's a bit long winded but... you could implement a mutable version of Context which accumulates (key, value) pairs, build it up while streaming the map and then hand it over to the provided context with context.addAll( myMutableContext)

      – David Soroko
      Nov 22 '18 at 15:52













    • @DavidSoroko Your approach will iteratively create a new Context for each entry from Context(containing previous entries) provided as a parameter to Context.putAll.

      – ETO
      Nov 23 '18 at 1:58


















    0














    You can use reduce:



    Context ctxVar = hashMap.entrySet()
    .stream()
    .filter(e -> e.getValue() != null)
    .reduce(ctx,
    (c, e) -> c.put(e.getKey(), e.getValue()),
    (c1, c2) -> c1.putAll(c2));


    It does seem wasteful, though (in the same way your original loop is wasteful), since it creates multiple Context instances when only the last one is needed.



    It would make more sense if you write a static method of the Context class (or a constructor) that accepts a Map and only creates a single Context instance for the entries of the Map. However, I now noticed that you didn't write this Context class, so you can't change it.






    share|improve this answer


























    • It's a bit long winded but... you could implement a mutable version of Context which accumulates (key, value) pairs, build it up while streaming the map and then hand it over to the provided context with context.addAll( myMutableContext)

      – David Soroko
      Nov 22 '18 at 15:52













    • @DavidSoroko Your approach will iteratively create a new Context for each entry from Context(containing previous entries) provided as a parameter to Context.putAll.

      – ETO
      Nov 23 '18 at 1:58
















    0












    0








    0







    You can use reduce:



    Context ctxVar = hashMap.entrySet()
    .stream()
    .filter(e -> e.getValue() != null)
    .reduce(ctx,
    (c, e) -> c.put(e.getKey(), e.getValue()),
    (c1, c2) -> c1.putAll(c2));


    It does seem wasteful, though (in the same way your original loop is wasteful), since it creates multiple Context instances when only the last one is needed.



    It would make more sense if you write a static method of the Context class (or a constructor) that accepts a Map and only creates a single Context instance for the entries of the Map. However, I now noticed that you didn't write this Context class, so you can't change it.






    share|improve this answer















    You can use reduce:



    Context ctxVar = hashMap.entrySet()
    .stream()
    .filter(e -> e.getValue() != null)
    .reduce(ctx,
    (c, e) -> c.put(e.getKey(), e.getValue()),
    (c1, c2) -> c1.putAll(c2));


    It does seem wasteful, though (in the same way your original loop is wasteful), since it creates multiple Context instances when only the last one is needed.



    It would make more sense if you write a static method of the Context class (or a constructor) that accepts a Map and only creates a single Context instance for the entries of the Map. However, I now noticed that you didn't write this Context class, so you can't change it.







    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Nov 22 '18 at 7:41

























    answered Nov 22 '18 at 7:35









    EranEran

    289k37473561




    289k37473561













    • It's a bit long winded but... you could implement a mutable version of Context which accumulates (key, value) pairs, build it up while streaming the map and then hand it over to the provided context with context.addAll( myMutableContext)

      – David Soroko
      Nov 22 '18 at 15:52













    • @DavidSoroko Your approach will iteratively create a new Context for each entry from Context(containing previous entries) provided as a parameter to Context.putAll.

      – ETO
      Nov 23 '18 at 1:58





















    • It's a bit long winded but... you could implement a mutable version of Context which accumulates (key, value) pairs, build it up while streaming the map and then hand it over to the provided context with context.addAll( myMutableContext)

      – David Soroko
      Nov 22 '18 at 15:52













    • @DavidSoroko Your approach will iteratively create a new Context for each entry from Context(containing previous entries) provided as a parameter to Context.putAll.

      – ETO
      Nov 23 '18 at 1:58



















    It's a bit long winded but... you could implement a mutable version of Context which accumulates (key, value) pairs, build it up while streaming the map and then hand it over to the provided context with context.addAll( myMutableContext)

    – David Soroko
    Nov 22 '18 at 15:52







    It's a bit long winded but... you could implement a mutable version of Context which accumulates (key, value) pairs, build it up while streaming the map and then hand it over to the provided context with context.addAll( myMutableContext)

    – David Soroko
    Nov 22 '18 at 15:52















    @DavidSoroko Your approach will iteratively create a new Context for each entry from Context(containing previous entries) provided as a parameter to Context.putAll.

    – ETO
    Nov 23 '18 at 1:58







    @DavidSoroko Your approach will iteratively create a new Context for each entry from Context(containing previous entries) provided as a parameter to Context.putAll.

    – ETO
    Nov 23 '18 at 1:58















    0














    Your question interested me. I researched the subject.



    Here is what I came up with:



    package reactor.util.context;

    import java.util.Map;
    import java.util.Map.Entry;
    import static java.util.stream.Collectors.toMap;

    public class ContextUtils {
    public static Context putAll(Context context, Map map) {
    if (map.isEmpty()) {
    return context;
    } else {
    Map contextMap = context.stream()
    .filter(e -> e.getValue() != null)
    .collect(toMap(Entry::getKey, Entry::getValue));
    return new ContextN(contextMap, map);
    }
    }
    }


    This utility method creates a new Context containing the entries from both initial context and provided map.



    This solution may still look not optimal, as it creates a new HashMap with initiaCapacity = 0 and loadFactor = 0.75f. In fact, this is not a problem, since ContextN itself is a subclass of HashMap with precise capacity and loadFactor = 1. The data from intermediary map will be copied to the context and later it will be collected by GC.



    Note: the utility class has to be in package reactor.util.context. ContextN is package-private so it is not accessible from other packages.






    share|improve this answer






























      0














      Your question interested me. I researched the subject.



      Here is what I came up with:



      package reactor.util.context;

      import java.util.Map;
      import java.util.Map.Entry;
      import static java.util.stream.Collectors.toMap;

      public class ContextUtils {
      public static Context putAll(Context context, Map map) {
      if (map.isEmpty()) {
      return context;
      } else {
      Map contextMap = context.stream()
      .filter(e -> e.getValue() != null)
      .collect(toMap(Entry::getKey, Entry::getValue));
      return new ContextN(contextMap, map);
      }
      }
      }


      This utility method creates a new Context containing the entries from both initial context and provided map.



      This solution may still look not optimal, as it creates a new HashMap with initiaCapacity = 0 and loadFactor = 0.75f. In fact, this is not a problem, since ContextN itself is a subclass of HashMap with precise capacity and loadFactor = 1. The data from intermediary map will be copied to the context and later it will be collected by GC.



      Note: the utility class has to be in package reactor.util.context. ContextN is package-private so it is not accessible from other packages.






      share|improve this answer




























        0












        0








        0







        Your question interested me. I researched the subject.



        Here is what I came up with:



        package reactor.util.context;

        import java.util.Map;
        import java.util.Map.Entry;
        import static java.util.stream.Collectors.toMap;

        public class ContextUtils {
        public static Context putAll(Context context, Map map) {
        if (map.isEmpty()) {
        return context;
        } else {
        Map contextMap = context.stream()
        .filter(e -> e.getValue() != null)
        .collect(toMap(Entry::getKey, Entry::getValue));
        return new ContextN(contextMap, map);
        }
        }
        }


        This utility method creates a new Context containing the entries from both initial context and provided map.



        This solution may still look not optimal, as it creates a new HashMap with initiaCapacity = 0 and loadFactor = 0.75f. In fact, this is not a problem, since ContextN itself is a subclass of HashMap with precise capacity and loadFactor = 1. The data from intermediary map will be copied to the context and later it will be collected by GC.



        Note: the utility class has to be in package reactor.util.context. ContextN is package-private so it is not accessible from other packages.






        share|improve this answer















        Your question interested me. I researched the subject.



        Here is what I came up with:



        package reactor.util.context;

        import java.util.Map;
        import java.util.Map.Entry;
        import static java.util.stream.Collectors.toMap;

        public class ContextUtils {
        public static Context putAll(Context context, Map map) {
        if (map.isEmpty()) {
        return context;
        } else {
        Map contextMap = context.stream()
        .filter(e -> e.getValue() != null)
        .collect(toMap(Entry::getKey, Entry::getValue));
        return new ContextN(contextMap, map);
        }
        }
        }


        This utility method creates a new Context containing the entries from both initial context and provided map.



        This solution may still look not optimal, as it creates a new HashMap with initiaCapacity = 0 and loadFactor = 0.75f. In fact, this is not a problem, since ContextN itself is a subclass of HashMap with precise capacity and loadFactor = 1. The data from intermediary map will be copied to the context and later it will be collected by GC.



        Note: the utility class has to be in package reactor.util.context. ContextN is package-private so it is not accessible from other packages.







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Nov 23 '18 at 2:01

























        answered Nov 22 '18 at 22:49









        ETOETO

        2,7161629




        2,7161629






























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