What number comes next in this sequence?











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$4, 15, 13, 7, 22, -1, 31, -9, 40, -17, 49$.



What comes next? The answer is $-25$, but why?










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  • 16




    My answer is 42. The reason is that I like the number 42. And there is no one who can prove me wrong. That being said, if I were to try to read the mind of whoever made this problem, I would look at every other term.
    – Arthur
    Nov 24 at 21:52








  • 3




    Any finite sequence of integers can be continued any way you like. Sometimes there are patterns that suggest that one continuation is more natural than another. I see no such pattern here. If you [edit' the question to tell us where the sequence comes from we may be able to hlep. Otherwise the question will probably be closed.
    – Ethan Bolker
    Nov 24 at 21:53






  • 1




    wolframalpha.com/input/…
    – AccidentalFourierTransform
    Nov 25 at 0:11















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$4, 15, 13, 7, 22, -1, 31, -9, 40, -17, 49$.



What comes next? The answer is $-25$, but why?










share|cite|improve this question


















  • 16




    My answer is 42. The reason is that I like the number 42. And there is no one who can prove me wrong. That being said, if I were to try to read the mind of whoever made this problem, I would look at every other term.
    – Arthur
    Nov 24 at 21:52








  • 3




    Any finite sequence of integers can be continued any way you like. Sometimes there are patterns that suggest that one continuation is more natural than another. I see no such pattern here. If you [edit' the question to tell us where the sequence comes from we may be able to hlep. Otherwise the question will probably be closed.
    – Ethan Bolker
    Nov 24 at 21:53






  • 1




    wolframalpha.com/input/…
    – AccidentalFourierTransform
    Nov 25 at 0:11













up vote
0
down vote

favorite
1









up vote
0
down vote

favorite
1






1





$4, 15, 13, 7, 22, -1, 31, -9, 40, -17, 49$.



What comes next? The answer is $-25$, but why?










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$4, 15, 13, 7, 22, -1, 31, -9, 40, -17, 49$.



What comes next? The answer is $-25$, but why?







sequences-and-series pattern-recognition






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asked Nov 24 at 21:49









stackofhay42

1393




1393








  • 16




    My answer is 42. The reason is that I like the number 42. And there is no one who can prove me wrong. That being said, if I were to try to read the mind of whoever made this problem, I would look at every other term.
    – Arthur
    Nov 24 at 21:52








  • 3




    Any finite sequence of integers can be continued any way you like. Sometimes there are patterns that suggest that one continuation is more natural than another. I see no such pattern here. If you [edit' the question to tell us where the sequence comes from we may be able to hlep. Otherwise the question will probably be closed.
    – Ethan Bolker
    Nov 24 at 21:53






  • 1




    wolframalpha.com/input/…
    – AccidentalFourierTransform
    Nov 25 at 0:11














  • 16




    My answer is 42. The reason is that I like the number 42. And there is no one who can prove me wrong. That being said, if I were to try to read the mind of whoever made this problem, I would look at every other term.
    – Arthur
    Nov 24 at 21:52








  • 3




    Any finite sequence of integers can be continued any way you like. Sometimes there are patterns that suggest that one continuation is more natural than another. I see no such pattern here. If you [edit' the question to tell us where the sequence comes from we may be able to hlep. Otherwise the question will probably be closed.
    – Ethan Bolker
    Nov 24 at 21:53






  • 1




    wolframalpha.com/input/…
    – AccidentalFourierTransform
    Nov 25 at 0:11








16




16




My answer is 42. The reason is that I like the number 42. And there is no one who can prove me wrong. That being said, if I were to try to read the mind of whoever made this problem, I would look at every other term.
– Arthur
Nov 24 at 21:52






My answer is 42. The reason is that I like the number 42. And there is no one who can prove me wrong. That being said, if I were to try to read the mind of whoever made this problem, I would look at every other term.
– Arthur
Nov 24 at 21:52






3




3




Any finite sequence of integers can be continued any way you like. Sometimes there are patterns that suggest that one continuation is more natural than another. I see no such pattern here. If you [edit' the question to tell us where the sequence comes from we may be able to hlep. Otherwise the question will probably be closed.
– Ethan Bolker
Nov 24 at 21:53




Any finite sequence of integers can be continued any way you like. Sometimes there are patterns that suggest that one continuation is more natural than another. I see no such pattern here. If you [edit' the question to tell us where the sequence comes from we may be able to hlep. Otherwise the question will probably be closed.
– Ethan Bolker
Nov 24 at 21:53




1




1




wolframalpha.com/input/…
– AccidentalFourierTransform
Nov 25 at 0:11




wolframalpha.com/input/…
– AccidentalFourierTransform
Nov 25 at 0:11










3 Answers
3






active

oldest

votes

















up vote
14
down vote



accepted










Break up the sequence into the even ordered terms and odd ordered.






share|cite|improve this answer

















  • 2




    Wow! I was looking for some very complicated patterns, and it is actually so easy.
    – Mark
    Nov 24 at 21:55


















up vote
3
down vote














  • Firs observation, first term and second term add up to 19, third and fourth add to 20, fifth and sixth add to 21 and so on..


According to that, the the next number is $49+x = 24 implies x = -25$




  • Second observation, second and third terms add to 28, the fourth and fifth add to 29 and so on...


Therefore, you can generate the next number using these two observations anywhere in the sequence.



I know this is not the best way to predict the next number. However, it is not a bad try.



:)






share|cite|improve this answer






























    up vote
    0
    down vote













    As a general rule, the simplest kind of sequences of numbers are linear recurrence sequences. It is a matter of finding the recurrence relation. Using the first $10$ terms of the sequence, and linear algebra, the generating function appears to be



    $$ A(x) := frac{-23 x^4 + 5 x^3 + 15 x^2 + 4 x}{(x^2 - 1)^2} = 4 x + 15x^2 + 13x^3 +dots $$



    with the $11$th term $49$ being consistent with the generating function.



    The $12$th term is then $-25$ as you stated. The polynomial numerator and denominator coefficients can be found using linear algebra in the general case. In your case, by looking at every other term, you can find that they are both arithmetic progressions with constant differences $9$ and $-8$.






    share|cite|improve this answer





















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      3 Answers
      3






      active

      oldest

      votes








      3 Answers
      3






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes








      up vote
      14
      down vote



      accepted










      Break up the sequence into the even ordered terms and odd ordered.






      share|cite|improve this answer

















      • 2




        Wow! I was looking for some very complicated patterns, and it is actually so easy.
        – Mark
        Nov 24 at 21:55















      up vote
      14
      down vote



      accepted










      Break up the sequence into the even ordered terms and odd ordered.






      share|cite|improve this answer

















      • 2




        Wow! I was looking for some very complicated patterns, and it is actually so easy.
        – Mark
        Nov 24 at 21:55













      up vote
      14
      down vote



      accepted







      up vote
      14
      down vote



      accepted






      Break up the sequence into the even ordered terms and odd ordered.






      share|cite|improve this answer












      Break up the sequence into the even ordered terms and odd ordered.







      share|cite|improve this answer












      share|cite|improve this answer



      share|cite|improve this answer










      answered Nov 24 at 21:53









      TurlocTheRed

      788211




      788211








      • 2




        Wow! I was looking for some very complicated patterns, and it is actually so easy.
        – Mark
        Nov 24 at 21:55














      • 2




        Wow! I was looking for some very complicated patterns, and it is actually so easy.
        – Mark
        Nov 24 at 21:55








      2




      2




      Wow! I was looking for some very complicated patterns, and it is actually so easy.
      – Mark
      Nov 24 at 21:55




      Wow! I was looking for some very complicated patterns, and it is actually so easy.
      – Mark
      Nov 24 at 21:55










      up vote
      3
      down vote














      • Firs observation, first term and second term add up to 19, third and fourth add to 20, fifth and sixth add to 21 and so on..


      According to that, the the next number is $49+x = 24 implies x = -25$




      • Second observation, second and third terms add to 28, the fourth and fifth add to 29 and so on...


      Therefore, you can generate the next number using these two observations anywhere in the sequence.



      I know this is not the best way to predict the next number. However, it is not a bad try.



      :)






      share|cite|improve this answer



























        up vote
        3
        down vote














        • Firs observation, first term and second term add up to 19, third and fourth add to 20, fifth and sixth add to 21 and so on..


        According to that, the the next number is $49+x = 24 implies x = -25$




        • Second observation, second and third terms add to 28, the fourth and fifth add to 29 and so on...


        Therefore, you can generate the next number using these two observations anywhere in the sequence.



        I know this is not the best way to predict the next number. However, it is not a bad try.



        :)






        share|cite|improve this answer

























          up vote
          3
          down vote










          up vote
          3
          down vote










          • Firs observation, first term and second term add up to 19, third and fourth add to 20, fifth and sixth add to 21 and so on..


          According to that, the the next number is $49+x = 24 implies x = -25$




          • Second observation, second and third terms add to 28, the fourth and fifth add to 29 and so on...


          Therefore, you can generate the next number using these two observations anywhere in the sequence.



          I know this is not the best way to predict the next number. However, it is not a bad try.



          :)






          share|cite|improve this answer















          • Firs observation, first term and second term add up to 19, third and fourth add to 20, fifth and sixth add to 21 and so on..


          According to that, the the next number is $49+x = 24 implies x = -25$




          • Second observation, second and third terms add to 28, the fourth and fifth add to 29 and so on...


          Therefore, you can generate the next number using these two observations anywhere in the sequence.



          I know this is not the best way to predict the next number. However, it is not a bad try.



          :)







          share|cite|improve this answer














          share|cite|improve this answer



          share|cite|improve this answer








          edited Nov 24 at 22:21

























          answered Nov 24 at 21:59









          Maged Saeed

          530315




          530315






















              up vote
              0
              down vote













              As a general rule, the simplest kind of sequences of numbers are linear recurrence sequences. It is a matter of finding the recurrence relation. Using the first $10$ terms of the sequence, and linear algebra, the generating function appears to be



              $$ A(x) := frac{-23 x^4 + 5 x^3 + 15 x^2 + 4 x}{(x^2 - 1)^2} = 4 x + 15x^2 + 13x^3 +dots $$



              with the $11$th term $49$ being consistent with the generating function.



              The $12$th term is then $-25$ as you stated. The polynomial numerator and denominator coefficients can be found using linear algebra in the general case. In your case, by looking at every other term, you can find that they are both arithmetic progressions with constant differences $9$ and $-8$.






              share|cite|improve this answer

























                up vote
                0
                down vote













                As a general rule, the simplest kind of sequences of numbers are linear recurrence sequences. It is a matter of finding the recurrence relation. Using the first $10$ terms of the sequence, and linear algebra, the generating function appears to be



                $$ A(x) := frac{-23 x^4 + 5 x^3 + 15 x^2 + 4 x}{(x^2 - 1)^2} = 4 x + 15x^2 + 13x^3 +dots $$



                with the $11$th term $49$ being consistent with the generating function.



                The $12$th term is then $-25$ as you stated. The polynomial numerator and denominator coefficients can be found using linear algebra in the general case. In your case, by looking at every other term, you can find that they are both arithmetic progressions with constant differences $9$ and $-8$.






                share|cite|improve this answer























                  up vote
                  0
                  down vote










                  up vote
                  0
                  down vote









                  As a general rule, the simplest kind of sequences of numbers are linear recurrence sequences. It is a matter of finding the recurrence relation. Using the first $10$ terms of the sequence, and linear algebra, the generating function appears to be



                  $$ A(x) := frac{-23 x^4 + 5 x^3 + 15 x^2 + 4 x}{(x^2 - 1)^2} = 4 x + 15x^2 + 13x^3 +dots $$



                  with the $11$th term $49$ being consistent with the generating function.



                  The $12$th term is then $-25$ as you stated. The polynomial numerator and denominator coefficients can be found using linear algebra in the general case. In your case, by looking at every other term, you can find that they are both arithmetic progressions with constant differences $9$ and $-8$.






                  share|cite|improve this answer












                  As a general rule, the simplest kind of sequences of numbers are linear recurrence sequences. It is a matter of finding the recurrence relation. Using the first $10$ terms of the sequence, and linear algebra, the generating function appears to be



                  $$ A(x) := frac{-23 x^4 + 5 x^3 + 15 x^2 + 4 x}{(x^2 - 1)^2} = 4 x + 15x^2 + 13x^3 +dots $$



                  with the $11$th term $49$ being consistent with the generating function.



                  The $12$th term is then $-25$ as you stated. The polynomial numerator and denominator coefficients can be found using linear algebra in the general case. In your case, by looking at every other term, you can find that they are both arithmetic progressions with constant differences $9$ and $-8$.







                  share|cite|improve this answer












                  share|cite|improve this answer



                  share|cite|improve this answer










                  answered Nov 25 at 3:21









                  Somos

                  12.7k11034




                  12.7k11034






























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