Abstract constant in java












13















I would like to create a constant not implemented in super class in order to force subclasses to implement it. The best solution that I've found (on this topic) is to create an abstract method that will return the constant value. I assume that it is impossible to do something like:



abstract final static String Name;


But I still have hope because Java uses something like this in Serializable interface with the serialVersionUID. Did someone know how did they do this? Is it possible to reproduce it in my own class?










share|improve this question









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  • the question is how is this solved with serialVersionUID? So it's possible somehow...

    – Philipp Sander
    Mar 19 at 10:42






  • 4





    FYI, in the Serializable case it's the runtime that wants the serialVersionUID, not the compiler. A class that implements Serializable and doesn't have that field compiles just fine.

    – Federico klez Culloca
    Mar 19 at 10:42











  • Also, serialVersionUID is not mandatory for the runtime, either. If it doesn't exist, the serialization mechanism calculates it.

    – RealSkeptic
    Mar 19 at 10:47











  • Even if it is not mandatory, it still ask for it. The serialVersionIUD is not the exact solution that I want, but it come close to it.

    – Julien Maret
    Mar 19 at 10:54











  • @JulienMaret are you more concerned with emitting a warning if it is not there or do you want to get a default value if it is not? Or both?

    – Captain Man
    Mar 19 at 15:06
















13















I would like to create a constant not implemented in super class in order to force subclasses to implement it. The best solution that I've found (on this topic) is to create an abstract method that will return the constant value. I assume that it is impossible to do something like:



abstract final static String Name;


But I still have hope because Java uses something like this in Serializable interface with the serialVersionUID. Did someone know how did they do this? Is it possible to reproduce it in my own class?










share|improve this question









New contributor




Julien Maret is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





















  • the question is how is this solved with serialVersionUID? So it's possible somehow...

    – Philipp Sander
    Mar 19 at 10:42






  • 4





    FYI, in the Serializable case it's the runtime that wants the serialVersionUID, not the compiler. A class that implements Serializable and doesn't have that field compiles just fine.

    – Federico klez Culloca
    Mar 19 at 10:42











  • Also, serialVersionUID is not mandatory for the runtime, either. If it doesn't exist, the serialization mechanism calculates it.

    – RealSkeptic
    Mar 19 at 10:47











  • Even if it is not mandatory, it still ask for it. The serialVersionIUD is not the exact solution that I want, but it come close to it.

    – Julien Maret
    Mar 19 at 10:54











  • @JulienMaret are you more concerned with emitting a warning if it is not there or do you want to get a default value if it is not? Or both?

    – Captain Man
    Mar 19 at 15:06














13












13








13








I would like to create a constant not implemented in super class in order to force subclasses to implement it. The best solution that I've found (on this topic) is to create an abstract method that will return the constant value. I assume that it is impossible to do something like:



abstract final static String Name;


But I still have hope because Java uses something like this in Serializable interface with the serialVersionUID. Did someone know how did they do this? Is it possible to reproduce it in my own class?










share|improve this question









New contributor




Julien Maret is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












I would like to create a constant not implemented in super class in order to force subclasses to implement it. The best solution that I've found (on this topic) is to create an abstract method that will return the constant value. I assume that it is impossible to do something like:



abstract final static String Name;


But I still have hope because Java uses something like this in Serializable interface with the serialVersionUID. Did someone know how did they do this? Is it possible to reproduce it in my own class?







java






share|improve this question









New contributor




Julien Maret is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









New contributor




Julien Maret is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question








edited Mar 19 at 11:01









zb226

5,80232954




5,80232954






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asked Mar 19 at 10:37









Julien MaretJulien Maret

685




685




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New contributor





Julien Maret is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Julien Maret is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.













  • the question is how is this solved with serialVersionUID? So it's possible somehow...

    – Philipp Sander
    Mar 19 at 10:42






  • 4





    FYI, in the Serializable case it's the runtime that wants the serialVersionUID, not the compiler. A class that implements Serializable and doesn't have that field compiles just fine.

    – Federico klez Culloca
    Mar 19 at 10:42











  • Also, serialVersionUID is not mandatory for the runtime, either. If it doesn't exist, the serialization mechanism calculates it.

    – RealSkeptic
    Mar 19 at 10:47











  • Even if it is not mandatory, it still ask for it. The serialVersionIUD is not the exact solution that I want, but it come close to it.

    – Julien Maret
    Mar 19 at 10:54











  • @JulienMaret are you more concerned with emitting a warning if it is not there or do you want to get a default value if it is not? Or both?

    – Captain Man
    Mar 19 at 15:06



















  • the question is how is this solved with serialVersionUID? So it's possible somehow...

    – Philipp Sander
    Mar 19 at 10:42






  • 4





    FYI, in the Serializable case it's the runtime that wants the serialVersionUID, not the compiler. A class that implements Serializable and doesn't have that field compiles just fine.

    – Federico klez Culloca
    Mar 19 at 10:42











  • Also, serialVersionUID is not mandatory for the runtime, either. If it doesn't exist, the serialization mechanism calculates it.

    – RealSkeptic
    Mar 19 at 10:47











  • Even if it is not mandatory, it still ask for it. The serialVersionIUD is not the exact solution that I want, but it come close to it.

    – Julien Maret
    Mar 19 at 10:54











  • @JulienMaret are you more concerned with emitting a warning if it is not there or do you want to get a default value if it is not? Or both?

    – Captain Man
    Mar 19 at 15:06

















the question is how is this solved with serialVersionUID? So it's possible somehow...

– Philipp Sander
Mar 19 at 10:42





the question is how is this solved with serialVersionUID? So it's possible somehow...

– Philipp Sander
Mar 19 at 10:42




4




4





FYI, in the Serializable case it's the runtime that wants the serialVersionUID, not the compiler. A class that implements Serializable and doesn't have that field compiles just fine.

– Federico klez Culloca
Mar 19 at 10:42





FYI, in the Serializable case it's the runtime that wants the serialVersionUID, not the compiler. A class that implements Serializable and doesn't have that field compiles just fine.

– Federico klez Culloca
Mar 19 at 10:42













Also, serialVersionUID is not mandatory for the runtime, either. If it doesn't exist, the serialization mechanism calculates it.

– RealSkeptic
Mar 19 at 10:47





Also, serialVersionUID is not mandatory for the runtime, either. If it doesn't exist, the serialization mechanism calculates it.

– RealSkeptic
Mar 19 at 10:47













Even if it is not mandatory, it still ask for it. The serialVersionIUD is not the exact solution that I want, but it come close to it.

– Julien Maret
Mar 19 at 10:54





Even if it is not mandatory, it still ask for it. The serialVersionIUD is not the exact solution that I want, but it come close to it.

– Julien Maret
Mar 19 at 10:54













@JulienMaret are you more concerned with emitting a warning if it is not there or do you want to get a default value if it is not? Or both?

– Captain Man
Mar 19 at 15:06





@JulienMaret are you more concerned with emitting a warning if it is not there or do you want to get a default value if it is not? Or both?

– Captain Man
Mar 19 at 15:06












5 Answers
5






active

oldest

votes


















10














serialVersionUID field presence is not enforced by the Serializable interface because interface can't enforce presence of a field. You can declare a class which implements Serializable, it will compile just fine without serialVersionUID field being there.



The check for serialVersionUID field is hardcoded in the tools. One example is JDK java.io.ObjectStreamClass.getSerialVersionUID() methods that loads the serialVersionUID value with reflection:



/**
* Returns explicit serial version UID value declared by given class, or
* null if none.
*/
private static Long getDeclaredSUID(Class<?> cl) {
try {
Field f = cl.getDeclaredField("serialVersionUID");
int mask = Modifier.STATIC | Modifier.FINAL;
if ((f.getModifiers() & mask) == mask) {
f.setAccessible(true);
return Long.valueOf(f.getLong(null));
}
} catch (Exception ex) {
}
return null;
}





share|improve this answer

































    12














    Such constant cannot be static because static fields are shared among all instances of the class, including instances of all subclasses.
    Here is how to implement this as non-static constant:



    public abstract class Foo {
    public final String name; // Particular value to be defined in subclass

    protected Foo (String name) {
    this.name = name;
    }
    }

    public class Bar extends Foo {
    public Bar () {
    super ("Zoo"); // Here we define particular value for the constant
    }
    }


    BTW, serialVersionUID is not a part of Serializable interface.






    share|improve this answer

































      2














      I wouldn't recommend it but if you need it so much you could create a regex check in Checkstyle and force people to implement the static variable






      share|improve this answer


























      • @JulienMaret Checkstyle is not just an Eclipse plugin. It can also be part of your build process like Maven. I don't think this is a good solution but just want to point out it is not actually IDE specific.

        – Captain Man
        Mar 19 at 15:07



















      1














      When a class implementing Serializable does not have a serialVersionUID the little message you see in your IDE and while compiling is a warning emitted by javac. If you want to create something like that you can but the process seems complicated. The solution is here in this answer.



      They go into detail but the general idea is to create an annotation and annotation processor and use the annotation processor during compilation. I'm guessing you could use reflection (or... not reflection since it is compile time?) to see if the annotated class contains the field you want.






      share|improve this answer































        0














        Here the best way I found to simulate it. Javadoc prevent prevent a bit to bad extends... but id subclass dont have NAME it will just fail to execute



        public abstract class Foo {
        protected final String NAME;
        public Foo() {
        String name="";
        try {
        name = (String) this.getClass().getDeclaredField("NAME").get(name);
        } catch (NoSuchFieldException
        | SecurityException
        | IllegalArgumentException
        | IllegalAccessException e) {
        e.printStackTrace();
        }
        NAME = name;
        }
        }

        public class Bar extends Foo {
        public static final String NAME = "myName";
        }





        share|improve this answer










        New contributor




        Julien Maret is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.





















        • Are you sure the code will not compile? Your code looks like it will not only compile, but also run without error since you catch the exception ?

          – Falco
          Mar 19 at 14:28











        • I think you would want to set NAME to Foo.NAME in the catch block, right? That way if they don't "override" it it will use the "default"?

          – Captain Man
          Mar 19 at 15:11











        • Why are you passing the empty String referenced by name to the get method declared by your (sub)class? That’s obviously never the right object for this operation. And when you have checked that NAME does exist, what do you gain from that? Are you aware that this code will break when you create a subclass of Bar?

          – Holger
          Mar 19 at 16:06











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        5 Answers
        5






        active

        oldest

        votes








        5 Answers
        5






        active

        oldest

        votes









        active

        oldest

        votes






        active

        oldest

        votes









        10














        serialVersionUID field presence is not enforced by the Serializable interface because interface can't enforce presence of a field. You can declare a class which implements Serializable, it will compile just fine without serialVersionUID field being there.



        The check for serialVersionUID field is hardcoded in the tools. One example is JDK java.io.ObjectStreamClass.getSerialVersionUID() methods that loads the serialVersionUID value with reflection:



        /**
        * Returns explicit serial version UID value declared by given class, or
        * null if none.
        */
        private static Long getDeclaredSUID(Class<?> cl) {
        try {
        Field f = cl.getDeclaredField("serialVersionUID");
        int mask = Modifier.STATIC | Modifier.FINAL;
        if ((f.getModifiers() & mask) == mask) {
        f.setAccessible(true);
        return Long.valueOf(f.getLong(null));
        }
        } catch (Exception ex) {
        }
        return null;
        }





        share|improve this answer






























          10














          serialVersionUID field presence is not enforced by the Serializable interface because interface can't enforce presence of a field. You can declare a class which implements Serializable, it will compile just fine without serialVersionUID field being there.



          The check for serialVersionUID field is hardcoded in the tools. One example is JDK java.io.ObjectStreamClass.getSerialVersionUID() methods that loads the serialVersionUID value with reflection:



          /**
          * Returns explicit serial version UID value declared by given class, or
          * null if none.
          */
          private static Long getDeclaredSUID(Class<?> cl) {
          try {
          Field f = cl.getDeclaredField("serialVersionUID");
          int mask = Modifier.STATIC | Modifier.FINAL;
          if ((f.getModifiers() & mask) == mask) {
          f.setAccessible(true);
          return Long.valueOf(f.getLong(null));
          }
          } catch (Exception ex) {
          }
          return null;
          }





          share|improve this answer




























            10












            10








            10







            serialVersionUID field presence is not enforced by the Serializable interface because interface can't enforce presence of a field. You can declare a class which implements Serializable, it will compile just fine without serialVersionUID field being there.



            The check for serialVersionUID field is hardcoded in the tools. One example is JDK java.io.ObjectStreamClass.getSerialVersionUID() methods that loads the serialVersionUID value with reflection:



            /**
            * Returns explicit serial version UID value declared by given class, or
            * null if none.
            */
            private static Long getDeclaredSUID(Class<?> cl) {
            try {
            Field f = cl.getDeclaredField("serialVersionUID");
            int mask = Modifier.STATIC | Modifier.FINAL;
            if ((f.getModifiers() & mask) == mask) {
            f.setAccessible(true);
            return Long.valueOf(f.getLong(null));
            }
            } catch (Exception ex) {
            }
            return null;
            }





            share|improve this answer















            serialVersionUID field presence is not enforced by the Serializable interface because interface can't enforce presence of a field. You can declare a class which implements Serializable, it will compile just fine without serialVersionUID field being there.



            The check for serialVersionUID field is hardcoded in the tools. One example is JDK java.io.ObjectStreamClass.getSerialVersionUID() methods that loads the serialVersionUID value with reflection:



            /**
            * Returns explicit serial version UID value declared by given class, or
            * null if none.
            */
            private static Long getDeclaredSUID(Class<?> cl) {
            try {
            Field f = cl.getDeclaredField("serialVersionUID");
            int mask = Modifier.STATIC | Modifier.FINAL;
            if ((f.getModifiers() & mask) == mask) {
            f.setAccessible(true);
            return Long.valueOf(f.getLong(null));
            }
            } catch (Exception ex) {
            }
            return null;
            }






            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Mar 19 at 13:08

























            answered Mar 19 at 10:38









            Karol DowbeckiKarol Dowbecki

            24.8k93759




            24.8k93759

























                12














                Such constant cannot be static because static fields are shared among all instances of the class, including instances of all subclasses.
                Here is how to implement this as non-static constant:



                public abstract class Foo {
                public final String name; // Particular value to be defined in subclass

                protected Foo (String name) {
                this.name = name;
                }
                }

                public class Bar extends Foo {
                public Bar () {
                super ("Zoo"); // Here we define particular value for the constant
                }
                }


                BTW, serialVersionUID is not a part of Serializable interface.






                share|improve this answer






























                  12














                  Such constant cannot be static because static fields are shared among all instances of the class, including instances of all subclasses.
                  Here is how to implement this as non-static constant:



                  public abstract class Foo {
                  public final String name; // Particular value to be defined in subclass

                  protected Foo (String name) {
                  this.name = name;
                  }
                  }

                  public class Bar extends Foo {
                  public Bar () {
                  super ("Zoo"); // Here we define particular value for the constant
                  }
                  }


                  BTW, serialVersionUID is not a part of Serializable interface.






                  share|improve this answer




























                    12












                    12








                    12







                    Such constant cannot be static because static fields are shared among all instances of the class, including instances of all subclasses.
                    Here is how to implement this as non-static constant:



                    public abstract class Foo {
                    public final String name; // Particular value to be defined in subclass

                    protected Foo (String name) {
                    this.name = name;
                    }
                    }

                    public class Bar extends Foo {
                    public Bar () {
                    super ("Zoo"); // Here we define particular value for the constant
                    }
                    }


                    BTW, serialVersionUID is not a part of Serializable interface.






                    share|improve this answer















                    Such constant cannot be static because static fields are shared among all instances of the class, including instances of all subclasses.
                    Here is how to implement this as non-static constant:



                    public abstract class Foo {
                    public final String name; // Particular value to be defined in subclass

                    protected Foo (String name) {
                    this.name = name;
                    }
                    }

                    public class Bar extends Foo {
                    public Bar () {
                    super ("Zoo"); // Here we define particular value for the constant
                    }
                    }


                    BTW, serialVersionUID is not a part of Serializable interface.







                    share|improve this answer














                    share|improve this answer



                    share|improve this answer








                    edited Mar 19 at 10:50

























                    answered Mar 19 at 10:43









                    Mikhail VladimirovMikhail Vladimirov

                    11.1k12631




                    11.1k12631























                        2














                        I wouldn't recommend it but if you need it so much you could create a regex check in Checkstyle and force people to implement the static variable






                        share|improve this answer


























                        • @JulienMaret Checkstyle is not just an Eclipse plugin. It can also be part of your build process like Maven. I don't think this is a good solution but just want to point out it is not actually IDE specific.

                          – Captain Man
                          Mar 19 at 15:07
















                        2














                        I wouldn't recommend it but if you need it so much you could create a regex check in Checkstyle and force people to implement the static variable






                        share|improve this answer


























                        • @JulienMaret Checkstyle is not just an Eclipse plugin. It can also be part of your build process like Maven. I don't think this is a good solution but just want to point out it is not actually IDE specific.

                          – Captain Man
                          Mar 19 at 15:07














                        2












                        2








                        2







                        I wouldn't recommend it but if you need it so much you could create a regex check in Checkstyle and force people to implement the static variable






                        share|improve this answer















                        I wouldn't recommend it but if you need it so much you could create a regex check in Checkstyle and force people to implement the static variable







                        share|improve this answer














                        share|improve this answer



                        share|improve this answer








                        edited Mar 19 at 15:08









                        Captain Man

                        3,28532755




                        3,28532755










                        answered Mar 19 at 10:52









                        ave4496ave4496

                        1,47531436




                        1,47531436













                        • @JulienMaret Checkstyle is not just an Eclipse plugin. It can also be part of your build process like Maven. I don't think this is a good solution but just want to point out it is not actually IDE specific.

                          – Captain Man
                          Mar 19 at 15:07



















                        • @JulienMaret Checkstyle is not just an Eclipse plugin. It can also be part of your build process like Maven. I don't think this is a good solution but just want to point out it is not actually IDE specific.

                          – Captain Man
                          Mar 19 at 15:07

















                        @JulienMaret Checkstyle is not just an Eclipse plugin. It can also be part of your build process like Maven. I don't think this is a good solution but just want to point out it is not actually IDE specific.

                        – Captain Man
                        Mar 19 at 15:07





                        @JulienMaret Checkstyle is not just an Eclipse plugin. It can also be part of your build process like Maven. I don't think this is a good solution but just want to point out it is not actually IDE specific.

                        – Captain Man
                        Mar 19 at 15:07











                        1














                        When a class implementing Serializable does not have a serialVersionUID the little message you see in your IDE and while compiling is a warning emitted by javac. If you want to create something like that you can but the process seems complicated. The solution is here in this answer.



                        They go into detail but the general idea is to create an annotation and annotation processor and use the annotation processor during compilation. I'm guessing you could use reflection (or... not reflection since it is compile time?) to see if the annotated class contains the field you want.






                        share|improve this answer




























                          1














                          When a class implementing Serializable does not have a serialVersionUID the little message you see in your IDE and while compiling is a warning emitted by javac. If you want to create something like that you can but the process seems complicated. The solution is here in this answer.



                          They go into detail but the general idea is to create an annotation and annotation processor and use the annotation processor during compilation. I'm guessing you could use reflection (or... not reflection since it is compile time?) to see if the annotated class contains the field you want.






                          share|improve this answer


























                            1












                            1








                            1







                            When a class implementing Serializable does not have a serialVersionUID the little message you see in your IDE and while compiling is a warning emitted by javac. If you want to create something like that you can but the process seems complicated. The solution is here in this answer.



                            They go into detail but the general idea is to create an annotation and annotation processor and use the annotation processor during compilation. I'm guessing you could use reflection (or... not reflection since it is compile time?) to see if the annotated class contains the field you want.






                            share|improve this answer













                            When a class implementing Serializable does not have a serialVersionUID the little message you see in your IDE and while compiling is a warning emitted by javac. If you want to create something like that you can but the process seems complicated. The solution is here in this answer.



                            They go into detail but the general idea is to create an annotation and annotation processor and use the annotation processor during compilation. I'm guessing you could use reflection (or... not reflection since it is compile time?) to see if the annotated class contains the field you want.







                            share|improve this answer












                            share|improve this answer



                            share|improve this answer










                            answered Mar 19 at 15:04









                            Captain ManCaptain Man

                            3,28532755




                            3,28532755























                                0














                                Here the best way I found to simulate it. Javadoc prevent prevent a bit to bad extends... but id subclass dont have NAME it will just fail to execute



                                public abstract class Foo {
                                protected final String NAME;
                                public Foo() {
                                String name="";
                                try {
                                name = (String) this.getClass().getDeclaredField("NAME").get(name);
                                } catch (NoSuchFieldException
                                | SecurityException
                                | IllegalArgumentException
                                | IllegalAccessException e) {
                                e.printStackTrace();
                                }
                                NAME = name;
                                }
                                }

                                public class Bar extends Foo {
                                public static final String NAME = "myName";
                                }





                                share|improve this answer










                                New contributor




                                Julien Maret is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                Check out our Code of Conduct.





















                                • Are you sure the code will not compile? Your code looks like it will not only compile, but also run without error since you catch the exception ?

                                  – Falco
                                  Mar 19 at 14:28











                                • I think you would want to set NAME to Foo.NAME in the catch block, right? That way if they don't "override" it it will use the "default"?

                                  – Captain Man
                                  Mar 19 at 15:11











                                • Why are you passing the empty String referenced by name to the get method declared by your (sub)class? That’s obviously never the right object for this operation. And when you have checked that NAME does exist, what do you gain from that? Are you aware that this code will break when you create a subclass of Bar?

                                  – Holger
                                  Mar 19 at 16:06
















                                0














                                Here the best way I found to simulate it. Javadoc prevent prevent a bit to bad extends... but id subclass dont have NAME it will just fail to execute



                                public abstract class Foo {
                                protected final String NAME;
                                public Foo() {
                                String name="";
                                try {
                                name = (String) this.getClass().getDeclaredField("NAME").get(name);
                                } catch (NoSuchFieldException
                                | SecurityException
                                | IllegalArgumentException
                                | IllegalAccessException e) {
                                e.printStackTrace();
                                }
                                NAME = name;
                                }
                                }

                                public class Bar extends Foo {
                                public static final String NAME = "myName";
                                }





                                share|improve this answer










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                                • Are you sure the code will not compile? Your code looks like it will not only compile, but also run without error since you catch the exception ?

                                  – Falco
                                  Mar 19 at 14:28











                                • I think you would want to set NAME to Foo.NAME in the catch block, right? That way if they don't "override" it it will use the "default"?

                                  – Captain Man
                                  Mar 19 at 15:11











                                • Why are you passing the empty String referenced by name to the get method declared by your (sub)class? That’s obviously never the right object for this operation. And when you have checked that NAME does exist, what do you gain from that? Are you aware that this code will break when you create a subclass of Bar?

                                  – Holger
                                  Mar 19 at 16:06














                                0












                                0








                                0







                                Here the best way I found to simulate it. Javadoc prevent prevent a bit to bad extends... but id subclass dont have NAME it will just fail to execute



                                public abstract class Foo {
                                protected final String NAME;
                                public Foo() {
                                String name="";
                                try {
                                name = (String) this.getClass().getDeclaredField("NAME").get(name);
                                } catch (NoSuchFieldException
                                | SecurityException
                                | IllegalArgumentException
                                | IllegalAccessException e) {
                                e.printStackTrace();
                                }
                                NAME = name;
                                }
                                }

                                public class Bar extends Foo {
                                public static final String NAME = "myName";
                                }





                                share|improve this answer










                                New contributor




                                Julien Maret is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                Check out our Code of Conduct.










                                Here the best way I found to simulate it. Javadoc prevent prevent a bit to bad extends... but id subclass dont have NAME it will just fail to execute



                                public abstract class Foo {
                                protected final String NAME;
                                public Foo() {
                                String name="";
                                try {
                                name = (String) this.getClass().getDeclaredField("NAME").get(name);
                                } catch (NoSuchFieldException
                                | SecurityException
                                | IllegalArgumentException
                                | IllegalAccessException e) {
                                e.printStackTrace();
                                }
                                NAME = name;
                                }
                                }

                                public class Bar extends Foo {
                                public static final String NAME = "myName";
                                }






                                share|improve this answer










                                New contributor




                                Julien Maret is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                Check out our Code of Conduct.









                                share|improve this answer



                                share|improve this answer








                                edited Mar 19 at 14:29





















                                New contributor




                                Julien Maret is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                Check out our Code of Conduct.









                                answered Mar 19 at 13:26









                                Julien MaretJulien Maret

                                685




                                685




                                New contributor




                                Julien Maret is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                Check out our Code of Conduct.





                                New contributor





                                Julien Maret is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                Check out our Code of Conduct.






                                Julien Maret is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                Check out our Code of Conduct.













                                • Are you sure the code will not compile? Your code looks like it will not only compile, but also run without error since you catch the exception ?

                                  – Falco
                                  Mar 19 at 14:28











                                • I think you would want to set NAME to Foo.NAME in the catch block, right? That way if they don't "override" it it will use the "default"?

                                  – Captain Man
                                  Mar 19 at 15:11











                                • Why are you passing the empty String referenced by name to the get method declared by your (sub)class? That’s obviously never the right object for this operation. And when you have checked that NAME does exist, what do you gain from that? Are you aware that this code will break when you create a subclass of Bar?

                                  – Holger
                                  Mar 19 at 16:06



















                                • Are you sure the code will not compile? Your code looks like it will not only compile, but also run without error since you catch the exception ?

                                  – Falco
                                  Mar 19 at 14:28











                                • I think you would want to set NAME to Foo.NAME in the catch block, right? That way if they don't "override" it it will use the "default"?

                                  – Captain Man
                                  Mar 19 at 15:11











                                • Why are you passing the empty String referenced by name to the get method declared by your (sub)class? That’s obviously never the right object for this operation. And when you have checked that NAME does exist, what do you gain from that? Are you aware that this code will break when you create a subclass of Bar?

                                  – Holger
                                  Mar 19 at 16:06

















                                Are you sure the code will not compile? Your code looks like it will not only compile, but also run without error since you catch the exception ?

                                – Falco
                                Mar 19 at 14:28





                                Are you sure the code will not compile? Your code looks like it will not only compile, but also run without error since you catch the exception ?

                                – Falco
                                Mar 19 at 14:28













                                I think you would want to set NAME to Foo.NAME in the catch block, right? That way if they don't "override" it it will use the "default"?

                                – Captain Man
                                Mar 19 at 15:11





                                I think you would want to set NAME to Foo.NAME in the catch block, right? That way if they don't "override" it it will use the "default"?

                                – Captain Man
                                Mar 19 at 15:11













                                Why are you passing the empty String referenced by name to the get method declared by your (sub)class? That’s obviously never the right object for this operation. And when you have checked that NAME does exist, what do you gain from that? Are you aware that this code will break when you create a subclass of Bar?

                                – Holger
                                Mar 19 at 16:06





                                Why are you passing the empty String referenced by name to the get method declared by your (sub)class? That’s obviously never the right object for this operation. And when you have checked that NAME does exist, what do you gain from that? Are you aware that this code will break when you create a subclass of Bar?

                                – Holger
                                Mar 19 at 16:06










                                Julien Maret is a new contributor. Be nice, and check out our Code of Conduct.










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                                Julien Maret is a new contributor. Be nice, and check out our Code of Conduct.












                                Julien Maret is a new contributor. Be nice, and check out our Code of Conduct.
















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