Give an example of subset $B$ of the real line $mathbb{R}$ so the subsets $A$, $Int(A)$, $overline{A}$, dont...











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What is an example of a subset $A$ of the real line $mathbb{R}$ (equipped with the standard metric topology), such that
the subsets $A$, $Int(A)$, $overline{A}$, $overline{Int(A)}$ and Int($overline{A}$) are pairwise different?










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put on hold as off-topic by amWhy, Brahadeesh, DRF, Lord_Farin, KReiser Dec 4 at 1:24


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    Welcome to mathSE. What have you tried? Where did you get stuck? Please add some information about your work done. As is the question will be closed.
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What is an example of a subset $A$ of the real line $mathbb{R}$ (equipped with the standard metric topology), such that
the subsets $A$, $Int(A)$, $overline{A}$, $overline{Int(A)}$ and Int($overline{A}$) are pairwise different?










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put on hold as off-topic by amWhy, Brahadeesh, DRF, Lord_Farin, KReiser Dec 4 at 1:24


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, Brahadeesh, DRF, Lord_Farin, KReiser

If this question can be reworded to fit the rules in the help center, please edit the question.









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    Welcome to mathSE. What have you tried? Where did you get stuck? Please add some information about your work done. As is the question will be closed.
    – DRF
    Dec 3 at 14:12













up vote
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down vote

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up vote
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down vote

favorite











What is an example of a subset $A$ of the real line $mathbb{R}$ (equipped with the standard metric topology), such that
the subsets $A$, $Int(A)$, $overline{A}$, $overline{Int(A)}$ and Int($overline{A}$) are pairwise different?










share|cite|improve this question









New contributor




Esteban Cambiasso is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











What is an example of a subset $A$ of the real line $mathbb{R}$ (equipped with the standard metric topology), such that
the subsets $A$, $Int(A)$, $overline{A}$, $overline{Int(A)}$ and Int($overline{A}$) are pairwise different?







general-topology






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edited 21 hours ago





















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asked Dec 3 at 11:35









Esteban Cambiasso

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103




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Esteban Cambiasso is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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Esteban Cambiasso is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




put on hold as off-topic by amWhy, Brahadeesh, DRF, Lord_Farin, KReiser Dec 4 at 1:24


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, Brahadeesh, DRF, Lord_Farin, KReiser

If this question can be reworded to fit the rules in the help center, please edit the question.




put on hold as off-topic by amWhy, Brahadeesh, DRF, Lord_Farin, KReiser Dec 4 at 1:24


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, Brahadeesh, DRF, Lord_Farin, KReiser

If this question can be reworded to fit the rules in the help center, please edit the question.








  • 1




    Welcome to mathSE. What have you tried? Where did you get stuck? Please add some information about your work done. As is the question will be closed.
    – DRF
    Dec 3 at 14:12














  • 1




    Welcome to mathSE. What have you tried? Where did you get stuck? Please add some information about your work done. As is the question will be closed.
    – DRF
    Dec 3 at 14:12








1




1




Welcome to mathSE. What have you tried? Where did you get stuck? Please add some information about your work done. As is the question will be closed.
– DRF
Dec 3 at 14:12




Welcome to mathSE. What have you tried? Where did you get stuck? Please add some information about your work done. As is the question will be closed.
– DRF
Dec 3 at 14:12










2 Answers
2






active

oldest

votes

















up vote
3
down vote



accepted










Let $B=Bbb Qcap(1,2),$ and let $A=(0,1)cup B.$






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  • ok, we got the same idea ahah (Typing latex with a phone is harder though)
    – Antonio Alfieri
    Dec 3 at 12:01












  • True! Hence my brevity. ;-)
    – Cameron Buie
    Dec 3 at 12:21


















up vote
2
down vote













Take $A=((0,1) cap mathbb{Q}) cup (2,3)$. The interior of A is $(2,3)$, the closure of A is $[0,1] cup [2,3]$, the closure of the interior of A is $[2,3]$, and the interior of the closure of A is $(0,1) cup (2,3)$.






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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    3
    down vote



    accepted










    Let $B=Bbb Qcap(1,2),$ and let $A=(0,1)cup B.$






    share|cite|improve this answer





















    • ok, we got the same idea ahah (Typing latex with a phone is harder though)
      – Antonio Alfieri
      Dec 3 at 12:01












    • True! Hence my brevity. ;-)
      – Cameron Buie
      Dec 3 at 12:21















    up vote
    3
    down vote



    accepted










    Let $B=Bbb Qcap(1,2),$ and let $A=(0,1)cup B.$






    share|cite|improve this answer





















    • ok, we got the same idea ahah (Typing latex with a phone is harder though)
      – Antonio Alfieri
      Dec 3 at 12:01












    • True! Hence my brevity. ;-)
      – Cameron Buie
      Dec 3 at 12:21













    up vote
    3
    down vote



    accepted







    up vote
    3
    down vote



    accepted






    Let $B=Bbb Qcap(1,2),$ and let $A=(0,1)cup B.$






    share|cite|improve this answer












    Let $B=Bbb Qcap(1,2),$ and let $A=(0,1)cup B.$







    share|cite|improve this answer












    share|cite|improve this answer



    share|cite|improve this answer










    answered Dec 3 at 11:39









    Cameron Buie

    84.6k771155




    84.6k771155












    • ok, we got the same idea ahah (Typing latex with a phone is harder though)
      – Antonio Alfieri
      Dec 3 at 12:01












    • True! Hence my brevity. ;-)
      – Cameron Buie
      Dec 3 at 12:21


















    • ok, we got the same idea ahah (Typing latex with a phone is harder though)
      – Antonio Alfieri
      Dec 3 at 12:01












    • True! Hence my brevity. ;-)
      – Cameron Buie
      Dec 3 at 12:21
















    ok, we got the same idea ahah (Typing latex with a phone is harder though)
    – Antonio Alfieri
    Dec 3 at 12:01






    ok, we got the same idea ahah (Typing latex with a phone is harder though)
    – Antonio Alfieri
    Dec 3 at 12:01














    True! Hence my brevity. ;-)
    – Cameron Buie
    Dec 3 at 12:21




    True! Hence my brevity. ;-)
    – Cameron Buie
    Dec 3 at 12:21










    up vote
    2
    down vote













    Take $A=((0,1) cap mathbb{Q}) cup (2,3)$. The interior of A is $(2,3)$, the closure of A is $[0,1] cup [2,3]$, the closure of the interior of A is $[2,3]$, and the interior of the closure of A is $(0,1) cup (2,3)$.






    share|cite|improve this answer

























      up vote
      2
      down vote













      Take $A=((0,1) cap mathbb{Q}) cup (2,3)$. The interior of A is $(2,3)$, the closure of A is $[0,1] cup [2,3]$, the closure of the interior of A is $[2,3]$, and the interior of the closure of A is $(0,1) cup (2,3)$.






      share|cite|improve this answer























        up vote
        2
        down vote










        up vote
        2
        down vote









        Take $A=((0,1) cap mathbb{Q}) cup (2,3)$. The interior of A is $(2,3)$, the closure of A is $[0,1] cup [2,3]$, the closure of the interior of A is $[2,3]$, and the interior of the closure of A is $(0,1) cup (2,3)$.






        share|cite|improve this answer












        Take $A=((0,1) cap mathbb{Q}) cup (2,3)$. The interior of A is $(2,3)$, the closure of A is $[0,1] cup [2,3]$, the closure of the interior of A is $[2,3]$, and the interior of the closure of A is $(0,1) cup (2,3)$.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Dec 3 at 11:59









        Antonio Alfieri

        1,162412




        1,162412















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