How to extract filenames from a chunk of code
I want to extract all the filenames which are coming in a piece of code like
a=`cut -d: -f 3 /etc/passwd | sort | uniq` | awk `{print $2}`
"if [ -n "$a" ];",
"then for i in `echo "$a"`; do awk -F:
...
;done; else echo "error";fi" cat /etc/issue ...
/etc/pam.d/system-auth
(/deny=/)
Like in this code, I want to fetch these files -
/etc/passwd, /etc/issue and /etc/pam.d/system-auth
regex linux bash
add a comment |
I want to extract all the filenames which are coming in a piece of code like
a=`cut -d: -f 3 /etc/passwd | sort | uniq` | awk `{print $2}`
"if [ -n "$a" ];",
"then for i in `echo "$a"`; do awk -F:
...
;done; else echo "error";fi" cat /etc/issue ...
/etc/pam.d/system-auth
(/deny=/)
Like in this code, I want to fetch these files -
/etc/passwd, /etc/issue and /etc/pam.d/system-auth
regex linux bash
1
what have you tried so far?
– oguzismail
Nov 23 '18 at 5:38
There are many valid filenames in your sample data:a,cut,/etc/passwd,sort,uniq,awk,printin the first line alone. You will need to be more specific about what you want to extract.
– Nick
Nov 23 '18 at 5:48
Welcome to SO. Stack Overflow is a question and answer page for professional and enthusiastic programmers. Add your own code to your question. You are expected to show at least the amount of research you have put into solving this question yourself.
– Cyrus
Nov 23 '18 at 5:48
Please take a look at: What should I do when someone answers my question?
– Cyrus
Nov 23 '18 at 6:03
add a comment |
I want to extract all the filenames which are coming in a piece of code like
a=`cut -d: -f 3 /etc/passwd | sort | uniq` | awk `{print $2}`
"if [ -n "$a" ];",
"then for i in `echo "$a"`; do awk -F:
...
;done; else echo "error";fi" cat /etc/issue ...
/etc/pam.d/system-auth
(/deny=/)
Like in this code, I want to fetch these files -
/etc/passwd, /etc/issue and /etc/pam.d/system-auth
regex linux bash
I want to extract all the filenames which are coming in a piece of code like
a=`cut -d: -f 3 /etc/passwd | sort | uniq` | awk `{print $2}`
"if [ -n "$a" ];",
"then for i in `echo "$a"`; do awk -F:
...
;done; else echo "error";fi" cat /etc/issue ...
/etc/pam.d/system-auth
(/deny=/)
Like in this code, I want to fetch these files -
/etc/passwd, /etc/issue and /etc/pam.d/system-auth
regex linux bash
regex linux bash
asked Nov 23 '18 at 5:32
user6219266
1
what have you tried so far?
– oguzismail
Nov 23 '18 at 5:38
There are many valid filenames in your sample data:a,cut,/etc/passwd,sort,uniq,awk,printin the first line alone. You will need to be more specific about what you want to extract.
– Nick
Nov 23 '18 at 5:48
Welcome to SO. Stack Overflow is a question and answer page for professional and enthusiastic programmers. Add your own code to your question. You are expected to show at least the amount of research you have put into solving this question yourself.
– Cyrus
Nov 23 '18 at 5:48
Please take a look at: What should I do when someone answers my question?
– Cyrus
Nov 23 '18 at 6:03
add a comment |
1
what have you tried so far?
– oguzismail
Nov 23 '18 at 5:38
There are many valid filenames in your sample data:a,cut,/etc/passwd,sort,uniq,awk,printin the first line alone. You will need to be more specific about what you want to extract.
– Nick
Nov 23 '18 at 5:48
Welcome to SO. Stack Overflow is a question and answer page for professional and enthusiastic programmers. Add your own code to your question. You are expected to show at least the amount of research you have put into solving this question yourself.
– Cyrus
Nov 23 '18 at 5:48
Please take a look at: What should I do when someone answers my question?
– Cyrus
Nov 23 '18 at 6:03
1
1
what have you tried so far?
– oguzismail
Nov 23 '18 at 5:38
what have you tried so far?
– oguzismail
Nov 23 '18 at 5:38
There are many valid filenames in your sample data:
a, cut, /etc/passwd, sort, uniq, awk, print in the first line alone. You will need to be more specific about what you want to extract.– Nick
Nov 23 '18 at 5:48
There are many valid filenames in your sample data:
a, cut, /etc/passwd, sort, uniq, awk, print in the first line alone. You will need to be more specific about what you want to extract.– Nick
Nov 23 '18 at 5:48
Welcome to SO. Stack Overflow is a question and answer page for professional and enthusiastic programmers. Add your own code to your question. You are expected to show at least the amount of research you have put into solving this question yourself.
– Cyrus
Nov 23 '18 at 5:48
Welcome to SO. Stack Overflow is a question and answer page for professional and enthusiastic programmers. Add your own code to your question. You are expected to show at least the amount of research you have put into solving this question yourself.
– Cyrus
Nov 23 '18 at 5:48
Please take a look at: What should I do when someone answers my question?
– Cyrus
Nov 23 '18 at 6:03
Please take a look at: What should I do when someone answers my question?
– Cyrus
Nov 23 '18 at 6:03
add a comment |
1 Answer
1
active
oldest
votes
Assuming you are interested in absolute paths that start with a slash, you can use following regex to capture,
/[w+./-]+(?= |$)
Demo
You may put your text in a file say myfile and then run this command,
cat myfile|grep -oP '/[w+./-]+(?= |$)'
OR
grep -oP '/[w+./-]+(?= |$)' myfile
This prints following output as the way you want,
/etc/passwd
/etc/issue
/etc/pam.d/system-auth
answered Nov 23 '18 at 9:37
Pushpesh Kumar RajwanshiPushpesh Kumar Rajwanshi
10.1k21229
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Assuming you are interested in absolute paths that start with a slash, you can use following regex to capture,
/[w+./-]+(?= |$)
Demo
You may put your text in a file say myfile and then run this command,
cat myfile|grep -oP '/[w+./-]+(?= |$)'
OR
grep -oP '/[w+./-]+(?= |$)' myfile
This prints following output as the way you want,
/etc/passwd
/etc/issue
/etc/pam.d/system-auth
answered Nov 23 '18 at 9:37
Pushpesh Kumar RajwanshiPushpesh Kumar Rajwanshi
10.1k21229
add a comment |
Assuming you are interested in absolute paths that start with a slash, you can use following regex to capture,
/[w+./-]+(?= |$)
Demo
You may put your text in a file say myfile and then run this command,
cat myfile|grep -oP '/[w+./-]+(?= |$)'
OR
grep -oP '/[w+./-]+(?= |$)' myfile
This prints following output as the way you want,
/etc/passwd
/etc/issue
/etc/pam.d/system-auth
answered Nov 23 '18 at 9:37
Pushpesh Kumar RajwanshiPushpesh Kumar Rajwanshi
10.1k21229
add a comment |
Assuming you are interested in absolute paths that start with a slash, you can use following regex to capture,
/[w+./-]+(?= |$)
Demo
You may put your text in a file say myfile and then run this command,
cat myfile|grep -oP '/[w+./-]+(?= |$)'
OR
grep -oP '/[w+./-]+(?= |$)' myfile
This prints following output as the way you want,
/etc/passwd
/etc/issue
/etc/pam.d/system-auth
answered Nov 23 '18 at 9:37
Pushpesh Kumar RajwanshiPushpesh Kumar Rajwanshi
10.1k21229
Assuming you are interested in absolute paths that start with a slash, you can use following regex to capture,
/[w+./-]+(?= |$)
Demo
You may put your text in a file say myfile and then run this command,
cat myfile|grep -oP '/[w+./-]+(?= |$)'
OR
grep -oP '/[w+./-]+(?= |$)' myfile
This prints following output as the way you want,
/etc/passwd
/etc/issue
/etc/pam.d/system-auth
answered Nov 23 '18 at 9:37
Pushpesh Kumar RajwanshiPushpesh Kumar Rajwanshi
10.1k21229
edited Nov 23 '18 at 10:17
answered Nov 23 '18 at 9:37
Pushpesh Kumar RajwanshiPushpesh Kumar Rajwanshi
10.1k21229
answered Nov 23 '18 at 9:37
Pushpesh Kumar RajwanshiPushpesh Kumar Rajwanshi
10.1k21229
answered Nov 23 '18 at 9:37
Pushpesh Kumar RajwanshiPushpesh Kumar Rajwanshi
10.1k21229
10.1k21229
add a comment |
add a comment |
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1
what have you tried so far?
– oguzismail
Nov 23 '18 at 5:38
There are many valid filenames in your sample data:
a,cut,/etc/passwd,sort,uniq,awk,printin the first line alone. You will need to be more specific about what you want to extract.– Nick
Nov 23 '18 at 5:48
Welcome to SO. Stack Overflow is a question and answer page for professional and enthusiastic programmers. Add your own code to your question. You are expected to show at least the amount of research you have put into solving this question yourself.
– Cyrus
Nov 23 '18 at 5:48
Please take a look at: What should I do when someone answers my question?
– Cyrus
Nov 23 '18 at 6:03