Some numbers are more equivalent than others
$begingroup$
ALL ANIMALS ARE EQUAL
BUT SOME ANIMALS ARE MORE EQUAL THAN OTHERS
— from
Animal Farm
by George Orwell
A contrived simple
equivalence
rule applies neatly to numbers 0 through 99
but not to any other numbers.
Equivalences of numbers 0 through 19 are listed below,
accounting for almost all other eligible numbers as well,
where ‘=’ means “is equivalent to.”
(Each number is
reflexively
equivalent to itself.)
0 = no others
10 = no others
1 = no others
11 = 29 = 31 = 49 = 51 = 69 = 71 = 89 = 91
2 = no others
12 = 28 = 32 = 48 = 52 = 68 = 72 = 88 = 92
3 = no others
13 = 27 = 33 = 47 = 53 = 67 = 73 = 87 = 93
4 = no others
14 = 26 = 34 = 46 = 54 = 66 = 74 = 86 = 94
5 = no others
15 = 25 = 35 = 45 = 55 = 65 = 75 = 85 = 95
6 = no others
16 = 24 = 36 = 44 = 56 = 64 = 76 = 84 = 96
7 = no others
17 = 23 = 37 = 43 = 57 = 63 = 77 = 83 = 97
8 = no others
18 = 22 = 38 = 42 = 58 = 62 = 78 = 82 = 98
9 = no others
19 = 21 = 39 = 41 = 59 = 61 = 79 = 81 = 99
What would be the entry for 20 in this list?
20 = ___ . . . ?
Please use and explain the simplest possible rule,
not purely mathematical,
that accounts for every equivalence from 0 to 99.
lateral-thinking
asked Mar 24 at 18:07
humnhumn
14.8k442133
$endgroup$
add a comment |
$begingroup$
ALL ANIMALS ARE EQUAL
BUT SOME ANIMALS ARE MORE EQUAL THAN OTHERS
— from
Animal Farm
by George Orwell
A contrived simple
equivalence
rule applies neatly to numbers 0 through 99
but not to any other numbers.
Equivalences of numbers 0 through 19 are listed below,
accounting for almost all other eligible numbers as well,
where ‘=’ means “is equivalent to.”
(Each number is
reflexively
equivalent to itself.)
0 = no others
10 = no others
1 = no others
11 = 29 = 31 = 49 = 51 = 69 = 71 = 89 = 91
2 = no others
12 = 28 = 32 = 48 = 52 = 68 = 72 = 88 = 92
3 = no others
13 = 27 = 33 = 47 = 53 = 67 = 73 = 87 = 93
4 = no others
14 = 26 = 34 = 46 = 54 = 66 = 74 = 86 = 94
5 = no others
15 = 25 = 35 = 45 = 55 = 65 = 75 = 85 = 95
6 = no others
16 = 24 = 36 = 44 = 56 = 64 = 76 = 84 = 96
7 = no others
17 = 23 = 37 = 43 = 57 = 63 = 77 = 83 = 97
8 = no others
18 = 22 = 38 = 42 = 58 = 62 = 78 = 82 = 98
9 = no others
19 = 21 = 39 = 41 = 59 = 61 = 79 = 81 = 99
What would be the entry for 20 in this list?
20 = ___ . . . ?
Please use and explain the simplest possible rule,
not purely mathematical,
that accounts for every equivalence from 0 to 99.
lateral-thinking
asked Mar 24 at 18:07
humnhumn
14.8k442133
$endgroup$
2
$begingroup$
Apology for the lack of more specific tags: They would give away the solution.
$endgroup$
– humn
Mar 24 at 18:08
6
$begingroup$
Hurray, a humn puzzle! It's been a while.
$endgroup$
– Rand al'Thor
Mar 24 at 19:06
1
$begingroup$
Is there a way to "watch" a question so that I'm notified of new or accepted answers? I've already starred it.
$endgroup$
– MooseBoys
Mar 27 at 1:04
1
$begingroup$
To be clear, is the relation really only meaningful for numbers 0 thru 99, or are you just saying all numbers outside that range would be "no others"?
$endgroup$
– MooseBoys
Mar 27 at 1:07
$begingroup$
Thank you, @MooseBoys. Yes the relation only has relevance to numbers 0 through 99. "No others" would indeed be a great catch-all for other numbers.
$endgroup$
– humn
Mar 27 at 12:17
add a comment |
$begingroup$
ALL ANIMALS ARE EQUAL
BUT SOME ANIMALS ARE MORE EQUAL THAN OTHERS
— from
Animal Farm
by George Orwell
A contrived simple
equivalence
rule applies neatly to numbers 0 through 99
but not to any other numbers.
Equivalences of numbers 0 through 19 are listed below,
accounting for almost all other eligible numbers as well,
where ‘=’ means “is equivalent to.”
(Each number is
reflexively
equivalent to itself.)
0 = no others
10 = no others
1 = no others
11 = 29 = 31 = 49 = 51 = 69 = 71 = 89 = 91
2 = no others
12 = 28 = 32 = 48 = 52 = 68 = 72 = 88 = 92
3 = no others
13 = 27 = 33 = 47 = 53 = 67 = 73 = 87 = 93
4 = no others
14 = 26 = 34 = 46 = 54 = 66 = 74 = 86 = 94
5 = no others
15 = 25 = 35 = 45 = 55 = 65 = 75 = 85 = 95
6 = no others
16 = 24 = 36 = 44 = 56 = 64 = 76 = 84 = 96
7 = no others
17 = 23 = 37 = 43 = 57 = 63 = 77 = 83 = 97
8 = no others
18 = 22 = 38 = 42 = 58 = 62 = 78 = 82 = 98
9 = no others
19 = 21 = 39 = 41 = 59 = 61 = 79 = 81 = 99
What would be the entry for 20 in this list?
20 = ___ . . . ?
Please use and explain the simplest possible rule,
not purely mathematical,
that accounts for every equivalence from 0 to 99.
lateral-thinking
asked Mar 24 at 18:07
humnhumn
14.8k442133
$endgroup$
ALL ANIMALS ARE EQUAL
BUT SOME ANIMALS ARE MORE EQUAL THAN OTHERS
— from
Animal Farm
by George Orwell
A contrived simple
equivalence
rule applies neatly to numbers 0 through 99
but not to any other numbers.
Equivalences of numbers 0 through 19 are listed below,
accounting for almost all other eligible numbers as well,
where ‘=’ means “is equivalent to.”
(Each number is
reflexively
equivalent to itself.)
0 = no others
10 = no others
1 = no others
11 = 29 = 31 = 49 = 51 = 69 = 71 = 89 = 91
2 = no others
12 = 28 = 32 = 48 = 52 = 68 = 72 = 88 = 92
3 = no others
13 = 27 = 33 = 47 = 53 = 67 = 73 = 87 = 93
4 = no others
14 = 26 = 34 = 46 = 54 = 66 = 74 = 86 = 94
5 = no others
15 = 25 = 35 = 45 = 55 = 65 = 75 = 85 = 95
6 = no others
16 = 24 = 36 = 44 = 56 = 64 = 76 = 84 = 96
7 = no others
17 = 23 = 37 = 43 = 57 = 63 = 77 = 83 = 97
8 = no others
18 = 22 = 38 = 42 = 58 = 62 = 78 = 82 = 98
9 = no others
19 = 21 = 39 = 41 = 59 = 61 = 79 = 81 = 99
What would be the entry for 20 in this list?
20 = ___ . . . ?
Please use and explain the simplest possible rule,
not purely mathematical,
that accounts for every equivalence from 0 to 99.
lateral-thinking
lateral-thinking
asked Mar 24 at 18:07
humnhumn
14.8k442133
asked Mar 24 at 18:07
humnhumn
14.8k442133
asked Mar 24 at 18:07
humnhumn
14.8k442133
asked Mar 24 at 18:07
humnhumn
14.8k442133
asked Mar 24 at 18:07
humnhumn
14.8k442133
14.8k442133
2
$begingroup$
Apology for the lack of more specific tags: They would give away the solution.
$endgroup$
– humn
Mar 24 at 18:08
6
$begingroup$
Hurray, a humn puzzle! It's been a while.
$endgroup$
– Rand al'Thor
Mar 24 at 19:06
1
$begingroup$
Is there a way to "watch" a question so that I'm notified of new or accepted answers? I've already starred it.
$endgroup$
– MooseBoys
Mar 27 at 1:04
1
$begingroup$
To be clear, is the relation really only meaningful for numbers 0 thru 99, or are you just saying all numbers outside that range would be "no others"?
$endgroup$
– MooseBoys
Mar 27 at 1:07
$begingroup$
Thank you, @MooseBoys. Yes the relation only has relevance to numbers 0 through 99. "No others" would indeed be a great catch-all for other numbers.
$endgroup$
– humn
Mar 27 at 12:17
add a comment |
2
$begingroup$
Apology for the lack of more specific tags: They would give away the solution.
$endgroup$
– humn
Mar 24 at 18:08
6
$begingroup$
Hurray, a humn puzzle! It's been a while.
$endgroup$
– Rand al'Thor
Mar 24 at 19:06
1
$begingroup$
Is there a way to "watch" a question so that I'm notified of new or accepted answers? I've already starred it.
$endgroup$
– MooseBoys
Mar 27 at 1:04
1
$begingroup$
To be clear, is the relation really only meaningful for numbers 0 thru 99, or are you just saying all numbers outside that range would be "no others"?
$endgroup$
– MooseBoys
Mar 27 at 1:07
$begingroup$
Thank you, @MooseBoys. Yes the relation only has relevance to numbers 0 through 99. "No others" would indeed be a great catch-all for other numbers.
$endgroup$
– humn
Mar 27 at 12:17
2
2
$begingroup$
Apology for the lack of more specific tags: They would give away the solution.
$endgroup$
– humn
Mar 24 at 18:08
$begingroup$
Apology for the lack of more specific tags: They would give away the solution.
$endgroup$
– humn
Mar 24 at 18:08
6
6
$begingroup$
Hurray, a humn puzzle! It's been a while.
$endgroup$
– Rand al'Thor
Mar 24 at 19:06
$begingroup$
Hurray, a humn puzzle! It's been a while.
$endgroup$
– Rand al'Thor
Mar 24 at 19:06
1
1
$begingroup$
Is there a way to "watch" a question so that I'm notified of new or accepted answers? I've already starred it.
$endgroup$
– MooseBoys
Mar 27 at 1:04
$begingroup$
Is there a way to "watch" a question so that I'm notified of new or accepted answers? I've already starred it.
$endgroup$
– MooseBoys
Mar 27 at 1:04
1
1
$begingroup$
To be clear, is the relation really only meaningful for numbers 0 thru 99, or are you just saying all numbers outside that range would be "no others"?
$endgroup$
– MooseBoys
Mar 27 at 1:07
$begingroup$
To be clear, is the relation really only meaningful for numbers 0 thru 99, or are you just saying all numbers outside that range would be "no others"?
$endgroup$
– MooseBoys
Mar 27 at 1:07
$begingroup$
Thank you, @MooseBoys. Yes the relation only has relevance to numbers 0 through 99. "No others" would indeed be a great catch-all for other numbers.
$endgroup$
– humn
Mar 27 at 12:17
$begingroup$
Thank you, @MooseBoys. Yes the relation only has relevance to numbers 0 through 99. "No others" would indeed be a great catch-all for other numbers.
$endgroup$
– humn
Mar 27 at 12:17
add a comment |
3 Answers
3
active
oldest
votes
$begingroup$
Answer:
20 = no others
Reason: (humn has told me that this is wrong but it's my favorite guess of mine)
Because you gave us a list of equivalences which are more equal than others. So we can assume the remaining numbers are less equal and therefore only equal to themselves.
Other guesses:
Xilpex's rule applies if no digits are zero. If any digit is zero (
2can be written as02) then there are no equivalents
Because the rules are contrived so I can simply invent whatever I want for the rules that aren't given to me.
answered Mar 24 at 23:29
ferretferret
2,0151828
$endgroup$
$begingroup$
Correct answer, @ferret! But the reasoning is more complicated than necessary.
$endgroup$
– humn
Mar 25 at 2:02
1
$begingroup$
@humn edited with a new "lateral thinking" attempt
$endgroup$
– ferret
Mar 25 at 3:04
1
$begingroup$
You're on the way, @ferret, and gave me an idea for another puzzle. Still missing the essential ingredient.
$endgroup$
– humn
Mar 25 at 4:06
1
$begingroup$
@humn is it because they are rot13 pbagevirq?
$endgroup$
– ferret
Mar 25 at 5:31
1
$begingroup$
Thank you for playing along, @ferret. Pleasure to have met you.
$endgroup$
– humn
Mar 25 at 17:06
|
show 4 more comments
$begingroup$
20 would be:
20 = 20 = 40 = 40 = 60 = 60 = 80 = 80 = 100
Explanation:
The rule (vertically) is: Line 1 + 1, then Line 2 - 1, and so on.
answered Mar 24 at 18:19
XilpexXilpex
272111
$endgroup$
3
$begingroup$
Thank you for taking the bait, Xilpex. Not quite the solution, though. For instance, it doesn't explain the entry for 10.
$endgroup$
– humn
Mar 24 at 18:23
1
$begingroup$
@humn Ok. I'll see if there is any other answer... :D
$endgroup$
– Xilpex
Mar 24 at 18:25
1
$begingroup$
Plus there is no $100$.
$endgroup$
– Arnaud Mortier
Mar 24 at 18:36
add a comment |
$begingroup$
0 = no others 10 = no others 20 = no others
1 = no others 1 1 = 2 9 = 3 1 = 4 9 = 5 1 = 69 = 71 = 89 = 91
2 = no others 1 2 = 2 8 = 3 2 = 4 8 = 5 2 = 68 = 72 = 88 = 92
3 = no others 1 3 = 2 7 = 3 3 = 4 7 = 5 3 = 67 = 73 = 87 = 93
4 = no others 1 4 = 2 6 = 3 4 = 4 6 = 5 4 = 66 = 74 = 86 = 94
5 = no others 1 5 = 2 5 = 3 5 = 4 5 = 5 5 = 65 = 75 = 85 = 95
6 = no others 1 6 = 2 4 = 3 6 = 4 4 = 5 6 = 64 = 76 = 84 = 96
7 = no others 1 7 = 2 3 = 3 7 = 4 3 = 5 7 = 63 = 77 = 83 = 97
8 = no others 1 8 = 2 2 = 3 8 = 4 2 = 5 8 = 62 = 78 = 82 = 98
9 = no others 1 9 = 2 1 = 3 9 = 4 1 = 5 9 = 61 = 79 = 81 = 99
Delete the tens digit, like follow:
0 = no others 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9
1 = no others 1 = 9 = 1 = 9 = 1 = 9 = 1 = 9 = 1
2 = no others 2 = 8 = 2 = 8 = 2 = 8 = 2 = 8 = 2
3 = no others 3 = 7 = 3 = 7 = 3 = 7 = 3 = 7 = 3
4 = no others 4 = 6 = 4 = 6 = 4 = 6 = 4 = 6 = 4
5 = no others 5 = 5 = 5 = 5 = 5 = 5 = 5 = 5 = 5
6 = no others 6 = 4 = 6 = 4 = 6 = 4 = 6 = 4 = 6
7 = no others 7 = 3 = 7 = 3 = 7 = 3 = 7 = 3 = 7
8 = no others 8 = 2 = 8 = 2 = 8 = 2 = 8 = 2 = 8
9 = no others 9 = 1 = 9 = 1 = 9 = 1 = 9 = 1 = 9
So there is no rules to 0,
20 = no others
answered Mar 25 at 6:10
user58107user58107
212
$endgroup$
1
$begingroup$
Keep going, @user58107! It's simpler than that.
$endgroup$
– humn
Mar 25 at 6:42
2
$begingroup$
look the column, my English very poor, can't explain clarification.
$endgroup$
– user58107
Mar 25 at 6:46
$begingroup$
Oh, oh oh oh, @user58107, this puzzle relies on English. (Big give-away.) Thank you for hitching the ride.
$endgroup$
– humn
Mar 25 at 6:52
add a comment |
Your Answer
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Answer:
20 = no others
Reason: (humn has told me that this is wrong but it's my favorite guess of mine)
Because you gave us a list of equivalences which are more equal than others. So we can assume the remaining numbers are less equal and therefore only equal to themselves.
Other guesses:
Xilpex's rule applies if no digits are zero. If any digit is zero (
2can be written as02) then there are no equivalents
Because the rules are contrived so I can simply invent whatever I want for the rules that aren't given to me.
answered Mar 24 at 23:29
ferretferret
2,0151828
$endgroup$
$begingroup$
Correct answer, @ferret! But the reasoning is more complicated than necessary.
$endgroup$
– humn
Mar 25 at 2:02
1
$begingroup$
@humn edited with a new "lateral thinking" attempt
$endgroup$
– ferret
Mar 25 at 3:04
1
$begingroup$
You're on the way, @ferret, and gave me an idea for another puzzle. Still missing the essential ingredient.
$endgroup$
– humn
Mar 25 at 4:06
1
$begingroup$
@humn is it because they are rot13 pbagevirq?
$endgroup$
– ferret
Mar 25 at 5:31
1
$begingroup$
Thank you for playing along, @ferret. Pleasure to have met you.
$endgroup$
– humn
Mar 25 at 17:06
|
show 4 more comments
$begingroup$
Answer:
20 = no others
Reason: (humn has told me that this is wrong but it's my favorite guess of mine)
Because you gave us a list of equivalences which are more equal than others. So we can assume the remaining numbers are less equal and therefore only equal to themselves.
Other guesses:
Xilpex's rule applies if no digits are zero. If any digit is zero (
2can be written as02) then there are no equivalents
Because the rules are contrived so I can simply invent whatever I want for the rules that aren't given to me.
answered Mar 24 at 23:29
ferretferret
2,0151828
$endgroup$
$begingroup$
Correct answer, @ferret! But the reasoning is more complicated than necessary.
$endgroup$
– humn
Mar 25 at 2:02
1
$begingroup$
@humn edited with a new "lateral thinking" attempt
$endgroup$
– ferret
Mar 25 at 3:04
1
$begingroup$
You're on the way, @ferret, and gave me an idea for another puzzle. Still missing the essential ingredient.
$endgroup$
– humn
Mar 25 at 4:06
1
$begingroup$
@humn is it because they are rot13 pbagevirq?
$endgroup$
– ferret
Mar 25 at 5:31
1
$begingroup$
Thank you for playing along, @ferret. Pleasure to have met you.
$endgroup$
– humn
Mar 25 at 17:06
|
show 4 more comments
$begingroup$
Answer:
20 = no others
Reason: (humn has told me that this is wrong but it's my favorite guess of mine)
Because you gave us a list of equivalences which are more equal than others. So we can assume the remaining numbers are less equal and therefore only equal to themselves.
Other guesses:
Xilpex's rule applies if no digits are zero. If any digit is zero (
2can be written as02) then there are no equivalents
Because the rules are contrived so I can simply invent whatever I want for the rules that aren't given to me.
answered Mar 24 at 23:29
ferretferret
2,0151828
$endgroup$
Answer:
20 = no others
Reason: (humn has told me that this is wrong but it's my favorite guess of mine)
Because you gave us a list of equivalences which are more equal than others. So we can assume the remaining numbers are less equal and therefore only equal to themselves.
Other guesses:
Xilpex's rule applies if no digits are zero. If any digit is zero (
2can be written as02) then there are no equivalents
Because the rules are contrived so I can simply invent whatever I want for the rules that aren't given to me.
answered Mar 24 at 23:29
ferretferret
2,0151828
edited Mar 25 at 17:07
answered Mar 24 at 23:29
ferretferret
2,0151828
answered Mar 24 at 23:29
ferretferret
2,0151828
answered Mar 24 at 23:29
ferretferret
2,0151828
2,0151828
$begingroup$
Correct answer, @ferret! But the reasoning is more complicated than necessary.
$endgroup$
– humn
Mar 25 at 2:02
1
$begingroup$
@humn edited with a new "lateral thinking" attempt
$endgroup$
– ferret
Mar 25 at 3:04
1
$begingroup$
You're on the way, @ferret, and gave me an idea for another puzzle. Still missing the essential ingredient.
$endgroup$
– humn
Mar 25 at 4:06
1
$begingroup$
@humn is it because they are rot13 pbagevirq?
$endgroup$
– ferret
Mar 25 at 5:31
1
$begingroup$
Thank you for playing along, @ferret. Pleasure to have met you.
$endgroup$
– humn
Mar 25 at 17:06
|
show 4 more comments
$begingroup$
Correct answer, @ferret! But the reasoning is more complicated than necessary.
$endgroup$
– humn
Mar 25 at 2:02
1
$begingroup$
@humn edited with a new "lateral thinking" attempt
$endgroup$
– ferret
Mar 25 at 3:04
1
$begingroup$
You're on the way, @ferret, and gave me an idea for another puzzle. Still missing the essential ingredient.
$endgroup$
– humn
Mar 25 at 4:06
1
$begingroup$
@humn is it because they are rot13 pbagevirq?
$endgroup$
– ferret
Mar 25 at 5:31
1
$begingroup$
Thank you for playing along, @ferret. Pleasure to have met you.
$endgroup$
– humn
Mar 25 at 17:06
$begingroup$
Correct answer, @ferret! But the reasoning is more complicated than necessary.
$endgroup$
– humn
Mar 25 at 2:02
$begingroup$
Correct answer, @ferret! But the reasoning is more complicated than necessary.
$endgroup$
– humn
Mar 25 at 2:02
1
1
$begingroup$
@humn edited with a new "lateral thinking" attempt
$endgroup$
– ferret
Mar 25 at 3:04
$begingroup$
@humn edited with a new "lateral thinking" attempt
$endgroup$
– ferret
Mar 25 at 3:04
1
1
$begingroup$
You're on the way, @ferret, and gave me an idea for another puzzle. Still missing the essential ingredient.
$endgroup$
– humn
Mar 25 at 4:06
$begingroup$
You're on the way, @ferret, and gave me an idea for another puzzle. Still missing the essential ingredient.
$endgroup$
– humn
Mar 25 at 4:06
1
1
$begingroup$
@humn is it because they are rot13 pbagevirq?
$endgroup$
– ferret
Mar 25 at 5:31
$begingroup$
@humn is it because they are rot13 pbagevirq?
$endgroup$
– ferret
Mar 25 at 5:31
1
1
$begingroup$
Thank you for playing along, @ferret. Pleasure to have met you.
$endgroup$
– humn
Mar 25 at 17:06
$begingroup$
Thank you for playing along, @ferret. Pleasure to have met you.
$endgroup$
– humn
Mar 25 at 17:06
|
show 4 more comments
$begingroup$
20 would be:
20 = 20 = 40 = 40 = 60 = 60 = 80 = 80 = 100
Explanation:
The rule (vertically) is: Line 1 + 1, then Line 2 - 1, and so on.
answered Mar 24 at 18:19
XilpexXilpex
272111
$endgroup$
3
$begingroup$
Thank you for taking the bait, Xilpex. Not quite the solution, though. For instance, it doesn't explain the entry for 10.
$endgroup$
– humn
Mar 24 at 18:23
1
$begingroup$
@humn Ok. I'll see if there is any other answer... :D
$endgroup$
– Xilpex
Mar 24 at 18:25
1
$begingroup$
Plus there is no $100$.
$endgroup$
– Arnaud Mortier
Mar 24 at 18:36
add a comment |
$begingroup$
20 would be:
20 = 20 = 40 = 40 = 60 = 60 = 80 = 80 = 100
Explanation:
The rule (vertically) is: Line 1 + 1, then Line 2 - 1, and so on.
answered Mar 24 at 18:19
XilpexXilpex
272111
$endgroup$
3
$begingroup$
Thank you for taking the bait, Xilpex. Not quite the solution, though. For instance, it doesn't explain the entry for 10.
$endgroup$
– humn
Mar 24 at 18:23
1
$begingroup$
@humn Ok. I'll see if there is any other answer... :D
$endgroup$
– Xilpex
Mar 24 at 18:25
1
$begingroup$
Plus there is no $100$.
$endgroup$
– Arnaud Mortier
Mar 24 at 18:36
add a comment |
$begingroup$
20 would be:
20 = 20 = 40 = 40 = 60 = 60 = 80 = 80 = 100
Explanation:
The rule (vertically) is: Line 1 + 1, then Line 2 - 1, and so on.
answered Mar 24 at 18:19
XilpexXilpex
272111
$endgroup$
20 would be:
20 = 20 = 40 = 40 = 60 = 60 = 80 = 80 = 100
Explanation:
The rule (vertically) is: Line 1 + 1, then Line 2 - 1, and so on.
answered Mar 24 at 18:19
XilpexXilpex
272111
answered Mar 24 at 18:19
XilpexXilpex
272111
answered Mar 24 at 18:19
XilpexXilpex
272111
answered Mar 24 at 18:19
XilpexXilpex
272111
272111
3
$begingroup$
Thank you for taking the bait, Xilpex. Not quite the solution, though. For instance, it doesn't explain the entry for 10.
$endgroup$
– humn
Mar 24 at 18:23
1
$begingroup$
@humn Ok. I'll see if there is any other answer... :D
$endgroup$
– Xilpex
Mar 24 at 18:25
1
$begingroup$
Plus there is no $100$.
$endgroup$
– Arnaud Mortier
Mar 24 at 18:36
add a comment |
3
$begingroup$
Thank you for taking the bait, Xilpex. Not quite the solution, though. For instance, it doesn't explain the entry for 10.
$endgroup$
– humn
Mar 24 at 18:23
1
$begingroup$
@humn Ok. I'll see if there is any other answer... :D
$endgroup$
– Xilpex
Mar 24 at 18:25
1
$begingroup$
Plus there is no $100$.
$endgroup$
– Arnaud Mortier
Mar 24 at 18:36
3
3
$begingroup$
Thank you for taking the bait, Xilpex. Not quite the solution, though. For instance, it doesn't explain the entry for 10.
$endgroup$
– humn
Mar 24 at 18:23
$begingroup$
Thank you for taking the bait, Xilpex. Not quite the solution, though. For instance, it doesn't explain the entry for 10.
$endgroup$
– humn
Mar 24 at 18:23
1
1
$begingroup$
@humn Ok. I'll see if there is any other answer... :D
$endgroup$
– Xilpex
Mar 24 at 18:25
$begingroup$
@humn Ok. I'll see if there is any other answer... :D
$endgroup$
– Xilpex
Mar 24 at 18:25
1
1
$begingroup$
Plus there is no $100$.
$endgroup$
– Arnaud Mortier
Mar 24 at 18:36
$begingroup$
Plus there is no $100$.
$endgroup$
– Arnaud Mortier
Mar 24 at 18:36
add a comment |
$begingroup$
0 = no others 10 = no others 20 = no others
1 = no others 1 1 = 2 9 = 3 1 = 4 9 = 5 1 = 69 = 71 = 89 = 91
2 = no others 1 2 = 2 8 = 3 2 = 4 8 = 5 2 = 68 = 72 = 88 = 92
3 = no others 1 3 = 2 7 = 3 3 = 4 7 = 5 3 = 67 = 73 = 87 = 93
4 = no others 1 4 = 2 6 = 3 4 = 4 6 = 5 4 = 66 = 74 = 86 = 94
5 = no others 1 5 = 2 5 = 3 5 = 4 5 = 5 5 = 65 = 75 = 85 = 95
6 = no others 1 6 = 2 4 = 3 6 = 4 4 = 5 6 = 64 = 76 = 84 = 96
7 = no others 1 7 = 2 3 = 3 7 = 4 3 = 5 7 = 63 = 77 = 83 = 97
8 = no others 1 8 = 2 2 = 3 8 = 4 2 = 5 8 = 62 = 78 = 82 = 98
9 = no others 1 9 = 2 1 = 3 9 = 4 1 = 5 9 = 61 = 79 = 81 = 99
Delete the tens digit, like follow:
0 = no others 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9
1 = no others 1 = 9 = 1 = 9 = 1 = 9 = 1 = 9 = 1
2 = no others 2 = 8 = 2 = 8 = 2 = 8 = 2 = 8 = 2
3 = no others 3 = 7 = 3 = 7 = 3 = 7 = 3 = 7 = 3
4 = no others 4 = 6 = 4 = 6 = 4 = 6 = 4 = 6 = 4
5 = no others 5 = 5 = 5 = 5 = 5 = 5 = 5 = 5 = 5
6 = no others 6 = 4 = 6 = 4 = 6 = 4 = 6 = 4 = 6
7 = no others 7 = 3 = 7 = 3 = 7 = 3 = 7 = 3 = 7
8 = no others 8 = 2 = 8 = 2 = 8 = 2 = 8 = 2 = 8
9 = no others 9 = 1 = 9 = 1 = 9 = 1 = 9 = 1 = 9
So there is no rules to 0,
20 = no others
answered Mar 25 at 6:10
user58107user58107
212
$endgroup$
1
$begingroup$
Keep going, @user58107! It's simpler than that.
$endgroup$
– humn
Mar 25 at 6:42
2
$begingroup$
look the column, my English very poor, can't explain clarification.
$endgroup$
– user58107
Mar 25 at 6:46
$begingroup$
Oh, oh oh oh, @user58107, this puzzle relies on English. (Big give-away.) Thank you for hitching the ride.
$endgroup$
– humn
Mar 25 at 6:52
add a comment |
$begingroup$
0 = no others 10 = no others 20 = no others
1 = no others 1 1 = 2 9 = 3 1 = 4 9 = 5 1 = 69 = 71 = 89 = 91
2 = no others 1 2 = 2 8 = 3 2 = 4 8 = 5 2 = 68 = 72 = 88 = 92
3 = no others 1 3 = 2 7 = 3 3 = 4 7 = 5 3 = 67 = 73 = 87 = 93
4 = no others 1 4 = 2 6 = 3 4 = 4 6 = 5 4 = 66 = 74 = 86 = 94
5 = no others 1 5 = 2 5 = 3 5 = 4 5 = 5 5 = 65 = 75 = 85 = 95
6 = no others 1 6 = 2 4 = 3 6 = 4 4 = 5 6 = 64 = 76 = 84 = 96
7 = no others 1 7 = 2 3 = 3 7 = 4 3 = 5 7 = 63 = 77 = 83 = 97
8 = no others 1 8 = 2 2 = 3 8 = 4 2 = 5 8 = 62 = 78 = 82 = 98
9 = no others 1 9 = 2 1 = 3 9 = 4 1 = 5 9 = 61 = 79 = 81 = 99
Delete the tens digit, like follow:
0 = no others 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9
1 = no others 1 = 9 = 1 = 9 = 1 = 9 = 1 = 9 = 1
2 = no others 2 = 8 = 2 = 8 = 2 = 8 = 2 = 8 = 2
3 = no others 3 = 7 = 3 = 7 = 3 = 7 = 3 = 7 = 3
4 = no others 4 = 6 = 4 = 6 = 4 = 6 = 4 = 6 = 4
5 = no others 5 = 5 = 5 = 5 = 5 = 5 = 5 = 5 = 5
6 = no others 6 = 4 = 6 = 4 = 6 = 4 = 6 = 4 = 6
7 = no others 7 = 3 = 7 = 3 = 7 = 3 = 7 = 3 = 7
8 = no others 8 = 2 = 8 = 2 = 8 = 2 = 8 = 2 = 8
9 = no others 9 = 1 = 9 = 1 = 9 = 1 = 9 = 1 = 9
So there is no rules to 0,
20 = no others
answered Mar 25 at 6:10
user58107user58107
212
$endgroup$
1
$begingroup$
Keep going, @user58107! It's simpler than that.
$endgroup$
– humn
Mar 25 at 6:42
2
$begingroup$
look the column, my English very poor, can't explain clarification.
$endgroup$
– user58107
Mar 25 at 6:46
$begingroup$
Oh, oh oh oh, @user58107, this puzzle relies on English. (Big give-away.) Thank you for hitching the ride.
$endgroup$
– humn
Mar 25 at 6:52
add a comment |
$begingroup$
0 = no others 10 = no others 20 = no others
1 = no others 1 1 = 2 9 = 3 1 = 4 9 = 5 1 = 69 = 71 = 89 = 91
2 = no others 1 2 = 2 8 = 3 2 = 4 8 = 5 2 = 68 = 72 = 88 = 92
3 = no others 1 3 = 2 7 = 3 3 = 4 7 = 5 3 = 67 = 73 = 87 = 93
4 = no others 1 4 = 2 6 = 3 4 = 4 6 = 5 4 = 66 = 74 = 86 = 94
5 = no others 1 5 = 2 5 = 3 5 = 4 5 = 5 5 = 65 = 75 = 85 = 95
6 = no others 1 6 = 2 4 = 3 6 = 4 4 = 5 6 = 64 = 76 = 84 = 96
7 = no others 1 7 = 2 3 = 3 7 = 4 3 = 5 7 = 63 = 77 = 83 = 97
8 = no others 1 8 = 2 2 = 3 8 = 4 2 = 5 8 = 62 = 78 = 82 = 98
9 = no others 1 9 = 2 1 = 3 9 = 4 1 = 5 9 = 61 = 79 = 81 = 99
Delete the tens digit, like follow:
0 = no others 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9
1 = no others 1 = 9 = 1 = 9 = 1 = 9 = 1 = 9 = 1
2 = no others 2 = 8 = 2 = 8 = 2 = 8 = 2 = 8 = 2
3 = no others 3 = 7 = 3 = 7 = 3 = 7 = 3 = 7 = 3
4 = no others 4 = 6 = 4 = 6 = 4 = 6 = 4 = 6 = 4
5 = no others 5 = 5 = 5 = 5 = 5 = 5 = 5 = 5 = 5
6 = no others 6 = 4 = 6 = 4 = 6 = 4 = 6 = 4 = 6
7 = no others 7 = 3 = 7 = 3 = 7 = 3 = 7 = 3 = 7
8 = no others 8 = 2 = 8 = 2 = 8 = 2 = 8 = 2 = 8
9 = no others 9 = 1 = 9 = 1 = 9 = 1 = 9 = 1 = 9
So there is no rules to 0,
20 = no others
answered Mar 25 at 6:10
user58107user58107
212
$endgroup$
0 = no others 10 = no others 20 = no others
1 = no others 1 1 = 2 9 = 3 1 = 4 9 = 5 1 = 69 = 71 = 89 = 91
2 = no others 1 2 = 2 8 = 3 2 = 4 8 = 5 2 = 68 = 72 = 88 = 92
3 = no others 1 3 = 2 7 = 3 3 = 4 7 = 5 3 = 67 = 73 = 87 = 93
4 = no others 1 4 = 2 6 = 3 4 = 4 6 = 5 4 = 66 = 74 = 86 = 94
5 = no others 1 5 = 2 5 = 3 5 = 4 5 = 5 5 = 65 = 75 = 85 = 95
6 = no others 1 6 = 2 4 = 3 6 = 4 4 = 5 6 = 64 = 76 = 84 = 96
7 = no others 1 7 = 2 3 = 3 7 = 4 3 = 5 7 = 63 = 77 = 83 = 97
8 = no others 1 8 = 2 2 = 3 8 = 4 2 = 5 8 = 62 = 78 = 82 = 98
9 = no others 1 9 = 2 1 = 3 9 = 4 1 = 5 9 = 61 = 79 = 81 = 99
Delete the tens digit, like follow:
0 = no others 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9
1 = no others 1 = 9 = 1 = 9 = 1 = 9 = 1 = 9 = 1
2 = no others 2 = 8 = 2 = 8 = 2 = 8 = 2 = 8 = 2
3 = no others 3 = 7 = 3 = 7 = 3 = 7 = 3 = 7 = 3
4 = no others 4 = 6 = 4 = 6 = 4 = 6 = 4 = 6 = 4
5 = no others 5 = 5 = 5 = 5 = 5 = 5 = 5 = 5 = 5
6 = no others 6 = 4 = 6 = 4 = 6 = 4 = 6 = 4 = 6
7 = no others 7 = 3 = 7 = 3 = 7 = 3 = 7 = 3 = 7
8 = no others 8 = 2 = 8 = 2 = 8 = 2 = 8 = 2 = 8
9 = no others 9 = 1 = 9 = 1 = 9 = 1 = 9 = 1 = 9
So there is no rules to 0,
20 = no others
answered Mar 25 at 6:10
user58107user58107
212
edited Mar 25 at 6:36
answered Mar 25 at 6:10
user58107user58107
212
answered Mar 25 at 6:10
user58107user58107
212
answered Mar 25 at 6:10
user58107user58107
212
212
1
$begingroup$
Keep going, @user58107! It's simpler than that.
$endgroup$
– humn
Mar 25 at 6:42
2
$begingroup$
look the column, my English very poor, can't explain clarification.
$endgroup$
– user58107
Mar 25 at 6:46
$begingroup$
Oh, oh oh oh, @user58107, this puzzle relies on English. (Big give-away.) Thank you for hitching the ride.
$endgroup$
– humn
Mar 25 at 6:52
add a comment |
1
$begingroup$
Keep going, @user58107! It's simpler than that.
$endgroup$
– humn
Mar 25 at 6:42
2
$begingroup$
look the column, my English very poor, can't explain clarification.
$endgroup$
– user58107
Mar 25 at 6:46
$begingroup$
Oh, oh oh oh, @user58107, this puzzle relies on English. (Big give-away.) Thank you for hitching the ride.
$endgroup$
– humn
Mar 25 at 6:52
1
1
$begingroup$
Keep going, @user58107! It's simpler than that.
$endgroup$
– humn
Mar 25 at 6:42
$begingroup$
Keep going, @user58107! It's simpler than that.
$endgroup$
– humn
Mar 25 at 6:42
2
2
$begingroup$
look the column, my English very poor, can't explain clarification.
$endgroup$
– user58107
Mar 25 at 6:46
$begingroup$
look the column, my English very poor, can't explain clarification.
$endgroup$
– user58107
Mar 25 at 6:46
$begingroup$
Oh, oh oh oh, @user58107, this puzzle relies on English. (Big give-away.) Thank you for hitching the ride.
$endgroup$
– humn
Mar 25 at 6:52
$begingroup$
Oh, oh oh oh, @user58107, this puzzle relies on English. (Big give-away.) Thank you for hitching the ride.
$endgroup$
– humn
Mar 25 at 6:52
add a comment |
Thanks for contributing an answer to Puzzling Stack Exchange!
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2
$begingroup$
Apology for the lack of more specific tags: They would give away the solution.
$endgroup$
– humn
Mar 24 at 18:08
6
$begingroup$
Hurray, a humn puzzle! It's been a while.
$endgroup$
– Rand al'Thor
Mar 24 at 19:06
1
$begingroup$
Is there a way to "watch" a question so that I'm notified of new or accepted answers? I've already starred it.
$endgroup$
– MooseBoys
Mar 27 at 1:04
1
$begingroup$
To be clear, is the relation really only meaningful for numbers 0 thru 99, or are you just saying all numbers outside that range would be "no others"?
$endgroup$
– MooseBoys
Mar 27 at 1:07
$begingroup$
Thank you, @MooseBoys. Yes the relation only has relevance to numbers 0 through 99. "No others" would indeed be a great catch-all for other numbers.
$endgroup$
– humn
Mar 27 at 12:17