Linearly change the step size in a table











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I am trying to create a table of points, where the size of the step would change linearly from a certain value to another. Bellow is a simple code to demonstrate a table of points with a constant step in X and Y direction.



MasterMesh=Flatten[Table[{XX , YY, 0}, {XX, -1/2, 1/2, 0.2}, {YY, -1/2, 1/2, 0.2}], 1];
ListPointPlot3D[MasterMesh]


enter image description here



My goal would ultimately be, to create a raster of point that is something like shown in the figure bellow (drawn clumsily), where the distances between the new points (marked red bellow) are supposed to change linearly in a way that L1:L2:L3:L4:L5=1:2:3:4:5.
enter image description here



Any help will be much appreciated!










share|improve this question


























    up vote
    4
    down vote

    favorite












    I am trying to create a table of points, where the size of the step would change linearly from a certain value to another. Bellow is a simple code to demonstrate a table of points with a constant step in X and Y direction.



    MasterMesh=Flatten[Table[{XX , YY, 0}, {XX, -1/2, 1/2, 0.2}, {YY, -1/2, 1/2, 0.2}], 1];
    ListPointPlot3D[MasterMesh]


    enter image description here



    My goal would ultimately be, to create a raster of point that is something like shown in the figure bellow (drawn clumsily), where the distances between the new points (marked red bellow) are supposed to change linearly in a way that L1:L2:L3:L4:L5=1:2:3:4:5.
    enter image description here



    Any help will be much appreciated!










    share|improve this question
























      up vote
      4
      down vote

      favorite









      up vote
      4
      down vote

      favorite











      I am trying to create a table of points, where the size of the step would change linearly from a certain value to another. Bellow is a simple code to demonstrate a table of points with a constant step in X and Y direction.



      MasterMesh=Flatten[Table[{XX , YY, 0}, {XX, -1/2, 1/2, 0.2}, {YY, -1/2, 1/2, 0.2}], 1];
      ListPointPlot3D[MasterMesh]


      enter image description here



      My goal would ultimately be, to create a raster of point that is something like shown in the figure bellow (drawn clumsily), where the distances between the new points (marked red bellow) are supposed to change linearly in a way that L1:L2:L3:L4:L5=1:2:3:4:5.
      enter image description here



      Any help will be much appreciated!










      share|improve this question













      I am trying to create a table of points, where the size of the step would change linearly from a certain value to another. Bellow is a simple code to demonstrate a table of points with a constant step in X and Y direction.



      MasterMesh=Flatten[Table[{XX , YY, 0}, {XX, -1/2, 1/2, 0.2}, {YY, -1/2, 1/2, 0.2}], 1];
      ListPointPlot3D[MasterMesh]


      enter image description here



      My goal would ultimately be, to create a raster of point that is something like shown in the figure bellow (drawn clumsily), where the distances between the new points (marked red bellow) are supposed to change linearly in a way that L1:L2:L3:L4:L5=1:2:3:4:5.
      enter image description here



      Any help will be much appreciated!







      list-manipulation table data






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked 2 days ago









      marko

      756




      756






















          3 Answers
          3






          active

          oldest

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          up vote
          4
          down vote



          accepted










          g1 = Prepend[Accumulate@Range[5], 0]
          (* {0, 1, 3, 6, 10, 15} *)

          g2 = Prepend[Accumulate@Reverse@Range[5], 0]
          (* {0, 5, 9, 12, 14, 15} *)

          Join @@ MapIndexed[{First[#2], #1, 0} &,
          Subdivide[g1, g2, 5],
          {2}
          ] // ListPointPlot3D


          enter image description here






          share|improve this answer





















          • Thank you for this answer. In a way, this code does what I asked in the question. The only drawback is that I need the distance between the first and last point in X or Y direction to be controlled independently and not related to the number of subdivisions. As is stands now, if I want 5 subdivisions in Y direction, I get the min and max Y coordinate of 1 and 6 respectively. Changing the number of subdivisions to 10, makes them 1 and 11.
            – marko
            2 days ago










          • @marko I don't understand your comment. In my code, the mesh size is set independently in the two directions. I also do not understand which direction you are referring to as $x$ and $y$.
            – Szabolcs
            2 days ago












          • Sorry for the unclear comment. As it stands now, the number of subdivisions (set to 5) defined in Subdivide[g1, g2, 5] defines also the length of the mesh in this direction (the direction I called "Y"). Setting the number of divisions to 10, will change the length of the mesh to 10. Is there a way to keep this constant? Similarly, I wish to keep the length of the mesh in the other direction constant (now it is 15), regardless of the number of divisions. Let's say that I wish the mesh to be of length 10 in both directions. Hopefully this is more clear.
            – marko
            2 days ago










          • @marko You can scale the mesh by inserting the required scaling factor in front of the first or second element of {First[#2], #1, 0} in MapIndexed. A bit inconvenient, as you'd need to sync the factor with the value in Range and Subdivide, but it will work :-)
            – Szabolcs
            2 days ago












          • Thank you. I managed to get it working, using the code bellow, where I define number of elements in both directions and the length (for a hyperbolic paraboloid) NumElements1 = 16; NumElements2 = 10; len = 2; g1 = Prepend[Accumulate@Range[NumElements2], 0]; g2 = Prepend[Accumulate@Reverse@Range[NumElements2], 0]; Flatten[MapIndexed[{len/ Last[g1]*#1, (len/(NumElements1 + 1))*(First[#2] - 1), (len/Last[g1]*#1 - len/2)^2 - ((len/(NumElements1 + 1))*(First[#2] - 1) - len/2)^2} &, Subdivide[g1, g2, NumElements1], {2}], 1] // ListPointPlot3D
            – marko
            2 days ago




















          up vote
          2
          down vote













          MasterMesh =
          Flatten[Table[{1.7^x, 1.7^y, 0},
          {x, 1, 2, .1},
          {y, 1, 2, .1}], 1];
          ListPointPlot3D[MasterMesh]





          share|improve this answer





















          • Your code indeed produces something similar to what I would need, but the step length is not increasing in a way that I wish. For the set of data that you provided, it goes: L1=0.19, L2=0.21, L3=0.24. Also the max distance in X or Y direction, location of the first point and the step change seem to be all dependable on each other.
            – marko
            2 days ago


















          up vote
          2
          down vote













          You can change n and range



          n = 5
          range = .5
          d = 2 range/n
          x = FoldList[# + 1/(n*(n + 1)/2)*#2*2 range &, -range, Range@n];
          h = Table[{x[[i]], j, 0}, {i, n + 1}, {j, -range, range, d}];
          g = Table[Diagonal@Table[{i, k, 0}, {i, x[[j]], -x[[-j]],
          Abs[x[[j]] + x[[-j]]]/(n + 1)}, {k, -range, range, d}], {j, 2, n}];
          ListPointPlot3D[Join[{h[[1]]}, g, {h[[n + 1]]}],PlotStyle -> PointSize[Large]]


          enter image description here



          n=12 and range=2     


          enter image description here






          share|improve this answer























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            3 Answers
            3






            active

            oldest

            votes








            3 Answers
            3






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes








            up vote
            4
            down vote



            accepted










            g1 = Prepend[Accumulate@Range[5], 0]
            (* {0, 1, 3, 6, 10, 15} *)

            g2 = Prepend[Accumulate@Reverse@Range[5], 0]
            (* {0, 5, 9, 12, 14, 15} *)

            Join @@ MapIndexed[{First[#2], #1, 0} &,
            Subdivide[g1, g2, 5],
            {2}
            ] // ListPointPlot3D


            enter image description here






            share|improve this answer





















            • Thank you for this answer. In a way, this code does what I asked in the question. The only drawback is that I need the distance between the first and last point in X or Y direction to be controlled independently and not related to the number of subdivisions. As is stands now, if I want 5 subdivisions in Y direction, I get the min and max Y coordinate of 1 and 6 respectively. Changing the number of subdivisions to 10, makes them 1 and 11.
              – marko
              2 days ago










            • @marko I don't understand your comment. In my code, the mesh size is set independently in the two directions. I also do not understand which direction you are referring to as $x$ and $y$.
              – Szabolcs
              2 days ago












            • Sorry for the unclear comment. As it stands now, the number of subdivisions (set to 5) defined in Subdivide[g1, g2, 5] defines also the length of the mesh in this direction (the direction I called "Y"). Setting the number of divisions to 10, will change the length of the mesh to 10. Is there a way to keep this constant? Similarly, I wish to keep the length of the mesh in the other direction constant (now it is 15), regardless of the number of divisions. Let's say that I wish the mesh to be of length 10 in both directions. Hopefully this is more clear.
              – marko
              2 days ago










            • @marko You can scale the mesh by inserting the required scaling factor in front of the first or second element of {First[#2], #1, 0} in MapIndexed. A bit inconvenient, as you'd need to sync the factor with the value in Range and Subdivide, but it will work :-)
              – Szabolcs
              2 days ago












            • Thank you. I managed to get it working, using the code bellow, where I define number of elements in both directions and the length (for a hyperbolic paraboloid) NumElements1 = 16; NumElements2 = 10; len = 2; g1 = Prepend[Accumulate@Range[NumElements2], 0]; g2 = Prepend[Accumulate@Reverse@Range[NumElements2], 0]; Flatten[MapIndexed[{len/ Last[g1]*#1, (len/(NumElements1 + 1))*(First[#2] - 1), (len/Last[g1]*#1 - len/2)^2 - ((len/(NumElements1 + 1))*(First[#2] - 1) - len/2)^2} &, Subdivide[g1, g2, NumElements1], {2}], 1] // ListPointPlot3D
              – marko
              2 days ago

















            up vote
            4
            down vote



            accepted










            g1 = Prepend[Accumulate@Range[5], 0]
            (* {0, 1, 3, 6, 10, 15} *)

            g2 = Prepend[Accumulate@Reverse@Range[5], 0]
            (* {0, 5, 9, 12, 14, 15} *)

            Join @@ MapIndexed[{First[#2], #1, 0} &,
            Subdivide[g1, g2, 5],
            {2}
            ] // ListPointPlot3D


            enter image description here






            share|improve this answer





















            • Thank you for this answer. In a way, this code does what I asked in the question. The only drawback is that I need the distance between the first and last point in X or Y direction to be controlled independently and not related to the number of subdivisions. As is stands now, if I want 5 subdivisions in Y direction, I get the min and max Y coordinate of 1 and 6 respectively. Changing the number of subdivisions to 10, makes them 1 and 11.
              – marko
              2 days ago










            • @marko I don't understand your comment. In my code, the mesh size is set independently in the two directions. I also do not understand which direction you are referring to as $x$ and $y$.
              – Szabolcs
              2 days ago












            • Sorry for the unclear comment. As it stands now, the number of subdivisions (set to 5) defined in Subdivide[g1, g2, 5] defines also the length of the mesh in this direction (the direction I called "Y"). Setting the number of divisions to 10, will change the length of the mesh to 10. Is there a way to keep this constant? Similarly, I wish to keep the length of the mesh in the other direction constant (now it is 15), regardless of the number of divisions. Let's say that I wish the mesh to be of length 10 in both directions. Hopefully this is more clear.
              – marko
              2 days ago










            • @marko You can scale the mesh by inserting the required scaling factor in front of the first or second element of {First[#2], #1, 0} in MapIndexed. A bit inconvenient, as you'd need to sync the factor with the value in Range and Subdivide, but it will work :-)
              – Szabolcs
              2 days ago












            • Thank you. I managed to get it working, using the code bellow, where I define number of elements in both directions and the length (for a hyperbolic paraboloid) NumElements1 = 16; NumElements2 = 10; len = 2; g1 = Prepend[Accumulate@Range[NumElements2], 0]; g2 = Prepend[Accumulate@Reverse@Range[NumElements2], 0]; Flatten[MapIndexed[{len/ Last[g1]*#1, (len/(NumElements1 + 1))*(First[#2] - 1), (len/Last[g1]*#1 - len/2)^2 - ((len/(NumElements1 + 1))*(First[#2] - 1) - len/2)^2} &, Subdivide[g1, g2, NumElements1], {2}], 1] // ListPointPlot3D
              – marko
              2 days ago















            up vote
            4
            down vote



            accepted







            up vote
            4
            down vote



            accepted






            g1 = Prepend[Accumulate@Range[5], 0]
            (* {0, 1, 3, 6, 10, 15} *)

            g2 = Prepend[Accumulate@Reverse@Range[5], 0]
            (* {0, 5, 9, 12, 14, 15} *)

            Join @@ MapIndexed[{First[#2], #1, 0} &,
            Subdivide[g1, g2, 5],
            {2}
            ] // ListPointPlot3D


            enter image description here






            share|improve this answer












            g1 = Prepend[Accumulate@Range[5], 0]
            (* {0, 1, 3, 6, 10, 15} *)

            g2 = Prepend[Accumulate@Reverse@Range[5], 0]
            (* {0, 5, 9, 12, 14, 15} *)

            Join @@ MapIndexed[{First[#2], #1, 0} &,
            Subdivide[g1, g2, 5],
            {2}
            ] // ListPointPlot3D


            enter image description here







            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered 2 days ago









            Szabolcs

            157k13430917




            157k13430917












            • Thank you for this answer. In a way, this code does what I asked in the question. The only drawback is that I need the distance between the first and last point in X or Y direction to be controlled independently and not related to the number of subdivisions. As is stands now, if I want 5 subdivisions in Y direction, I get the min and max Y coordinate of 1 and 6 respectively. Changing the number of subdivisions to 10, makes them 1 and 11.
              – marko
              2 days ago










            • @marko I don't understand your comment. In my code, the mesh size is set independently in the two directions. I also do not understand which direction you are referring to as $x$ and $y$.
              – Szabolcs
              2 days ago












            • Sorry for the unclear comment. As it stands now, the number of subdivisions (set to 5) defined in Subdivide[g1, g2, 5] defines also the length of the mesh in this direction (the direction I called "Y"). Setting the number of divisions to 10, will change the length of the mesh to 10. Is there a way to keep this constant? Similarly, I wish to keep the length of the mesh in the other direction constant (now it is 15), regardless of the number of divisions. Let's say that I wish the mesh to be of length 10 in both directions. Hopefully this is more clear.
              – marko
              2 days ago










            • @marko You can scale the mesh by inserting the required scaling factor in front of the first or second element of {First[#2], #1, 0} in MapIndexed. A bit inconvenient, as you'd need to sync the factor with the value in Range and Subdivide, but it will work :-)
              – Szabolcs
              2 days ago












            • Thank you. I managed to get it working, using the code bellow, where I define number of elements in both directions and the length (for a hyperbolic paraboloid) NumElements1 = 16; NumElements2 = 10; len = 2; g1 = Prepend[Accumulate@Range[NumElements2], 0]; g2 = Prepend[Accumulate@Reverse@Range[NumElements2], 0]; Flatten[MapIndexed[{len/ Last[g1]*#1, (len/(NumElements1 + 1))*(First[#2] - 1), (len/Last[g1]*#1 - len/2)^2 - ((len/(NumElements1 + 1))*(First[#2] - 1) - len/2)^2} &, Subdivide[g1, g2, NumElements1], {2}], 1] // ListPointPlot3D
              – marko
              2 days ago




















            • Thank you for this answer. In a way, this code does what I asked in the question. The only drawback is that I need the distance between the first and last point in X or Y direction to be controlled independently and not related to the number of subdivisions. As is stands now, if I want 5 subdivisions in Y direction, I get the min and max Y coordinate of 1 and 6 respectively. Changing the number of subdivisions to 10, makes them 1 and 11.
              – marko
              2 days ago










            • @marko I don't understand your comment. In my code, the mesh size is set independently in the two directions. I also do not understand which direction you are referring to as $x$ and $y$.
              – Szabolcs
              2 days ago












            • Sorry for the unclear comment. As it stands now, the number of subdivisions (set to 5) defined in Subdivide[g1, g2, 5] defines also the length of the mesh in this direction (the direction I called "Y"). Setting the number of divisions to 10, will change the length of the mesh to 10. Is there a way to keep this constant? Similarly, I wish to keep the length of the mesh in the other direction constant (now it is 15), regardless of the number of divisions. Let's say that I wish the mesh to be of length 10 in both directions. Hopefully this is more clear.
              – marko
              2 days ago










            • @marko You can scale the mesh by inserting the required scaling factor in front of the first or second element of {First[#2], #1, 0} in MapIndexed. A bit inconvenient, as you'd need to sync the factor with the value in Range and Subdivide, but it will work :-)
              – Szabolcs
              2 days ago












            • Thank you. I managed to get it working, using the code bellow, where I define number of elements in both directions and the length (for a hyperbolic paraboloid) NumElements1 = 16; NumElements2 = 10; len = 2; g1 = Prepend[Accumulate@Range[NumElements2], 0]; g2 = Prepend[Accumulate@Reverse@Range[NumElements2], 0]; Flatten[MapIndexed[{len/ Last[g1]*#1, (len/(NumElements1 + 1))*(First[#2] - 1), (len/Last[g1]*#1 - len/2)^2 - ((len/(NumElements1 + 1))*(First[#2] - 1) - len/2)^2} &, Subdivide[g1, g2, NumElements1], {2}], 1] // ListPointPlot3D
              – marko
              2 days ago


















            Thank you for this answer. In a way, this code does what I asked in the question. The only drawback is that I need the distance between the first and last point in X or Y direction to be controlled independently and not related to the number of subdivisions. As is stands now, if I want 5 subdivisions in Y direction, I get the min and max Y coordinate of 1 and 6 respectively. Changing the number of subdivisions to 10, makes them 1 and 11.
            – marko
            2 days ago




            Thank you for this answer. In a way, this code does what I asked in the question. The only drawback is that I need the distance between the first and last point in X or Y direction to be controlled independently and not related to the number of subdivisions. As is stands now, if I want 5 subdivisions in Y direction, I get the min and max Y coordinate of 1 and 6 respectively. Changing the number of subdivisions to 10, makes them 1 and 11.
            – marko
            2 days ago












            @marko I don't understand your comment. In my code, the mesh size is set independently in the two directions. I also do not understand which direction you are referring to as $x$ and $y$.
            – Szabolcs
            2 days ago






            @marko I don't understand your comment. In my code, the mesh size is set independently in the two directions. I also do not understand which direction you are referring to as $x$ and $y$.
            – Szabolcs
            2 days ago














            Sorry for the unclear comment. As it stands now, the number of subdivisions (set to 5) defined in Subdivide[g1, g2, 5] defines also the length of the mesh in this direction (the direction I called "Y"). Setting the number of divisions to 10, will change the length of the mesh to 10. Is there a way to keep this constant? Similarly, I wish to keep the length of the mesh in the other direction constant (now it is 15), regardless of the number of divisions. Let's say that I wish the mesh to be of length 10 in both directions. Hopefully this is more clear.
            – marko
            2 days ago




            Sorry for the unclear comment. As it stands now, the number of subdivisions (set to 5) defined in Subdivide[g1, g2, 5] defines also the length of the mesh in this direction (the direction I called "Y"). Setting the number of divisions to 10, will change the length of the mesh to 10. Is there a way to keep this constant? Similarly, I wish to keep the length of the mesh in the other direction constant (now it is 15), regardless of the number of divisions. Let's say that I wish the mesh to be of length 10 in both directions. Hopefully this is more clear.
            – marko
            2 days ago












            @marko You can scale the mesh by inserting the required scaling factor in front of the first or second element of {First[#2], #1, 0} in MapIndexed. A bit inconvenient, as you'd need to sync the factor with the value in Range and Subdivide, but it will work :-)
            – Szabolcs
            2 days ago






            @marko You can scale the mesh by inserting the required scaling factor in front of the first or second element of {First[#2], #1, 0} in MapIndexed. A bit inconvenient, as you'd need to sync the factor with the value in Range and Subdivide, but it will work :-)
            – Szabolcs
            2 days ago














            Thank you. I managed to get it working, using the code bellow, where I define number of elements in both directions and the length (for a hyperbolic paraboloid) NumElements1 = 16; NumElements2 = 10; len = 2; g1 = Prepend[Accumulate@Range[NumElements2], 0]; g2 = Prepend[Accumulate@Reverse@Range[NumElements2], 0]; Flatten[MapIndexed[{len/ Last[g1]*#1, (len/(NumElements1 + 1))*(First[#2] - 1), (len/Last[g1]*#1 - len/2)^2 - ((len/(NumElements1 + 1))*(First[#2] - 1) - len/2)^2} &, Subdivide[g1, g2, NumElements1], {2}], 1] // ListPointPlot3D
            – marko
            2 days ago






            Thank you. I managed to get it working, using the code bellow, where I define number of elements in both directions and the length (for a hyperbolic paraboloid) NumElements1 = 16; NumElements2 = 10; len = 2; g1 = Prepend[Accumulate@Range[NumElements2], 0]; g2 = Prepend[Accumulate@Reverse@Range[NumElements2], 0]; Flatten[MapIndexed[{len/ Last[g1]*#1, (len/(NumElements1 + 1))*(First[#2] - 1), (len/Last[g1]*#1 - len/2)^2 - ((len/(NumElements1 + 1))*(First[#2] - 1) - len/2)^2} &, Subdivide[g1, g2, NumElements1], {2}], 1] // ListPointPlot3D
            – marko
            2 days ago












            up vote
            2
            down vote













            MasterMesh =
            Flatten[Table[{1.7^x, 1.7^y, 0},
            {x, 1, 2, .1},
            {y, 1, 2, .1}], 1];
            ListPointPlot3D[MasterMesh]





            share|improve this answer





















            • Your code indeed produces something similar to what I would need, but the step length is not increasing in a way that I wish. For the set of data that you provided, it goes: L1=0.19, L2=0.21, L3=0.24. Also the max distance in X or Y direction, location of the first point and the step change seem to be all dependable on each other.
              – marko
              2 days ago















            up vote
            2
            down vote













            MasterMesh =
            Flatten[Table[{1.7^x, 1.7^y, 0},
            {x, 1, 2, .1},
            {y, 1, 2, .1}], 1];
            ListPointPlot3D[MasterMesh]





            share|improve this answer





















            • Your code indeed produces something similar to what I would need, but the step length is not increasing in a way that I wish. For the set of data that you provided, it goes: L1=0.19, L2=0.21, L3=0.24. Also the max distance in X or Y direction, location of the first point and the step change seem to be all dependable on each other.
              – marko
              2 days ago













            up vote
            2
            down vote










            up vote
            2
            down vote









            MasterMesh =
            Flatten[Table[{1.7^x, 1.7^y, 0},
            {x, 1, 2, .1},
            {y, 1, 2, .1}], 1];
            ListPointPlot3D[MasterMesh]





            share|improve this answer












            MasterMesh =
            Flatten[Table[{1.7^x, 1.7^y, 0},
            {x, 1, 2, .1},
            {y, 1, 2, .1}], 1];
            ListPointPlot3D[MasterMesh]






            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered 2 days ago









            David G. Stork

            22.3k21848




            22.3k21848












            • Your code indeed produces something similar to what I would need, but the step length is not increasing in a way that I wish. For the set of data that you provided, it goes: L1=0.19, L2=0.21, L3=0.24. Also the max distance in X or Y direction, location of the first point and the step change seem to be all dependable on each other.
              – marko
              2 days ago


















            • Your code indeed produces something similar to what I would need, but the step length is not increasing in a way that I wish. For the set of data that you provided, it goes: L1=0.19, L2=0.21, L3=0.24. Also the max distance in X or Y direction, location of the first point and the step change seem to be all dependable on each other.
              – marko
              2 days ago
















            Your code indeed produces something similar to what I would need, but the step length is not increasing in a way that I wish. For the set of data that you provided, it goes: L1=0.19, L2=0.21, L3=0.24. Also the max distance in X or Y direction, location of the first point and the step change seem to be all dependable on each other.
            – marko
            2 days ago




            Your code indeed produces something similar to what I would need, but the step length is not increasing in a way that I wish. For the set of data that you provided, it goes: L1=0.19, L2=0.21, L3=0.24. Also the max distance in X or Y direction, location of the first point and the step change seem to be all dependable on each other.
            – marko
            2 days ago










            up vote
            2
            down vote













            You can change n and range



            n = 5
            range = .5
            d = 2 range/n
            x = FoldList[# + 1/(n*(n + 1)/2)*#2*2 range &, -range, Range@n];
            h = Table[{x[[i]], j, 0}, {i, n + 1}, {j, -range, range, d}];
            g = Table[Diagonal@Table[{i, k, 0}, {i, x[[j]], -x[[-j]],
            Abs[x[[j]] + x[[-j]]]/(n + 1)}, {k, -range, range, d}], {j, 2, n}];
            ListPointPlot3D[Join[{h[[1]]}, g, {h[[n + 1]]}],PlotStyle -> PointSize[Large]]


            enter image description here



            n=12 and range=2     


            enter image description here






            share|improve this answer



























              up vote
              2
              down vote













              You can change n and range



              n = 5
              range = .5
              d = 2 range/n
              x = FoldList[# + 1/(n*(n + 1)/2)*#2*2 range &, -range, Range@n];
              h = Table[{x[[i]], j, 0}, {i, n + 1}, {j, -range, range, d}];
              g = Table[Diagonal@Table[{i, k, 0}, {i, x[[j]], -x[[-j]],
              Abs[x[[j]] + x[[-j]]]/(n + 1)}, {k, -range, range, d}], {j, 2, n}];
              ListPointPlot3D[Join[{h[[1]]}, g, {h[[n + 1]]}],PlotStyle -> PointSize[Large]]


              enter image description here



              n=12 and range=2     


              enter image description here






              share|improve this answer

























                up vote
                2
                down vote










                up vote
                2
                down vote









                You can change n and range



                n = 5
                range = .5
                d = 2 range/n
                x = FoldList[# + 1/(n*(n + 1)/2)*#2*2 range &, -range, Range@n];
                h = Table[{x[[i]], j, 0}, {i, n + 1}, {j, -range, range, d}];
                g = Table[Diagonal@Table[{i, k, 0}, {i, x[[j]], -x[[-j]],
                Abs[x[[j]] + x[[-j]]]/(n + 1)}, {k, -range, range, d}], {j, 2, n}];
                ListPointPlot3D[Join[{h[[1]]}, g, {h[[n + 1]]}],PlotStyle -> PointSize[Large]]


                enter image description here



                n=12 and range=2     


                enter image description here






                share|improve this answer














                You can change n and range



                n = 5
                range = .5
                d = 2 range/n
                x = FoldList[# + 1/(n*(n + 1)/2)*#2*2 range &, -range, Range@n];
                h = Table[{x[[i]], j, 0}, {i, n + 1}, {j, -range, range, d}];
                g = Table[Diagonal@Table[{i, k, 0}, {i, x[[j]], -x[[-j]],
                Abs[x[[j]] + x[[-j]]]/(n + 1)}, {k, -range, range, d}], {j, 2, n}];
                ListPointPlot3D[Join[{h[[1]]}, g, {h[[n + 1]]}],PlotStyle -> PointSize[Large]]


                enter image description here



                n=12 and range=2     


                enter image description here







                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited 2 days ago

























                answered 2 days ago









                J42161217

                3,077219




                3,077219






























                     

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