Python: Updating Exported Data to Excel (OpenPyXl)












0














Nested_Array = [['GOOGL', 9822.6], ['FB', 98.25], ['SPY', 1291]]

now = datetime.datetime.now()
Current_Date = (now.strftime('%Y-%m-%d'))

row_start = 1
col_start = 1

ws4.cell(row=row_start, column=col_start + 1).value = Current_Date

for ticker, profit in (Nested_Array):
ws4.cell(row=row_start + 1, column=col_start).value = ticker
ws4.cell(row=row_start + 1, column=col_start + 1).value = profit
row_start += 1


The screenshot below shows what it exports. However, when I run the program, I'd like it to save the previous days data and then move to a different column for the next day.



If that's possible, I'd like the program to see if it's still the same day when I run it, if it is, it should just update the cells of the days column it's in rather than moving to a new column. Although, if it's not the same day, I'd like it to move to the next day.



Any feedback helps!



This is what it exports currently:



enter image description here



This is what I'd like it to do if it's a new day:



enter image description here










share|improve this question





























    0














    Nested_Array = [['GOOGL', 9822.6], ['FB', 98.25], ['SPY', 1291]]

    now = datetime.datetime.now()
    Current_Date = (now.strftime('%Y-%m-%d'))

    row_start = 1
    col_start = 1

    ws4.cell(row=row_start, column=col_start + 1).value = Current_Date

    for ticker, profit in (Nested_Array):
    ws4.cell(row=row_start + 1, column=col_start).value = ticker
    ws4.cell(row=row_start + 1, column=col_start + 1).value = profit
    row_start += 1


    The screenshot below shows what it exports. However, when I run the program, I'd like it to save the previous days data and then move to a different column for the next day.



    If that's possible, I'd like the program to see if it's still the same day when I run it, if it is, it should just update the cells of the days column it's in rather than moving to a new column. Although, if it's not the same day, I'd like it to move to the next day.



    Any feedback helps!



    This is what it exports currently:



    enter image description here



    This is what I'd like it to do if it's a new day:



    enter image description here










    share|improve this question



























      0












      0








      0







      Nested_Array = [['GOOGL', 9822.6], ['FB', 98.25], ['SPY', 1291]]

      now = datetime.datetime.now()
      Current_Date = (now.strftime('%Y-%m-%d'))

      row_start = 1
      col_start = 1

      ws4.cell(row=row_start, column=col_start + 1).value = Current_Date

      for ticker, profit in (Nested_Array):
      ws4.cell(row=row_start + 1, column=col_start).value = ticker
      ws4.cell(row=row_start + 1, column=col_start + 1).value = profit
      row_start += 1


      The screenshot below shows what it exports. However, when I run the program, I'd like it to save the previous days data and then move to a different column for the next day.



      If that's possible, I'd like the program to see if it's still the same day when I run it, if it is, it should just update the cells of the days column it's in rather than moving to a new column. Although, if it's not the same day, I'd like it to move to the next day.



      Any feedback helps!



      This is what it exports currently:



      enter image description here



      This is what I'd like it to do if it's a new day:



      enter image description here










      share|improve this question















      Nested_Array = [['GOOGL', 9822.6], ['FB', 98.25], ['SPY', 1291]]

      now = datetime.datetime.now()
      Current_Date = (now.strftime('%Y-%m-%d'))

      row_start = 1
      col_start = 1

      ws4.cell(row=row_start, column=col_start + 1).value = Current_Date

      for ticker, profit in (Nested_Array):
      ws4.cell(row=row_start + 1, column=col_start).value = ticker
      ws4.cell(row=row_start + 1, column=col_start + 1).value = profit
      row_start += 1


      The screenshot below shows what it exports. However, when I run the program, I'd like it to save the previous days data and then move to a different column for the next day.



      If that's possible, I'd like the program to see if it's still the same day when I run it, if it is, it should just update the cells of the days column it's in rather than moving to a new column. Although, if it's not the same day, I'd like it to move to the next day.



      Any feedback helps!



      This is what it exports currently:



      enter image description here



      This is what I'd like it to do if it's a new day:



      enter image description here







      python excel python-3.x for-loop openpyxl






      share|improve this question















      share|improve this question













      share|improve this question




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      edited Nov 19 at 22:13









      grrigore

      704820




      704820










      asked Nov 19 at 21:31







      user10676065































          1 Answer
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          0














          In openpyxl you should generally avoid creating your own counters because it provides useful methods that get this right.



          You can probably do something like this:



          col_idx = ws.max_col + 1
          ws.cell(1, col_idx) = CurrentDate

          for stock, row in zip(NestedArray, ws.iter_cols(min_col=col_idx, max_col=col_idx, min_row=2):
          row[0].value = stock[1]





          share|improve this answer





















          • I tried that out and it threw up a bunch of errors.
            – user10676065
            Nov 20 at 17:01











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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          0














          In openpyxl you should generally avoid creating your own counters because it provides useful methods that get this right.



          You can probably do something like this:



          col_idx = ws.max_col + 1
          ws.cell(1, col_idx) = CurrentDate

          for stock, row in zip(NestedArray, ws.iter_cols(min_col=col_idx, max_col=col_idx, min_row=2):
          row[0].value = stock[1]





          share|improve this answer





















          • I tried that out and it threw up a bunch of errors.
            – user10676065
            Nov 20 at 17:01
















          0














          In openpyxl you should generally avoid creating your own counters because it provides useful methods that get this right.



          You can probably do something like this:



          col_idx = ws.max_col + 1
          ws.cell(1, col_idx) = CurrentDate

          for stock, row in zip(NestedArray, ws.iter_cols(min_col=col_idx, max_col=col_idx, min_row=2):
          row[0].value = stock[1]





          share|improve this answer





















          • I tried that out and it threw up a bunch of errors.
            – user10676065
            Nov 20 at 17:01














          0












          0








          0






          In openpyxl you should generally avoid creating your own counters because it provides useful methods that get this right.



          You can probably do something like this:



          col_idx = ws.max_col + 1
          ws.cell(1, col_idx) = CurrentDate

          for stock, row in zip(NestedArray, ws.iter_cols(min_col=col_idx, max_col=col_idx, min_row=2):
          row[0].value = stock[1]





          share|improve this answer












          In openpyxl you should generally avoid creating your own counters because it provides useful methods that get this right.



          You can probably do something like this:



          col_idx = ws.max_col + 1
          ws.cell(1, col_idx) = CurrentDate

          for stock, row in zip(NestedArray, ws.iter_cols(min_col=col_idx, max_col=col_idx, min_row=2):
          row[0].value = stock[1]






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 20 at 9:20









          Charlie Clark

          9,64622233




          9,64622233












          • I tried that out and it threw up a bunch of errors.
            – user10676065
            Nov 20 at 17:01


















          • I tried that out and it threw up a bunch of errors.
            – user10676065
            Nov 20 at 17:01
















          I tried that out and it threw up a bunch of errors.
          – user10676065
          Nov 20 at 17:01




          I tried that out and it threw up a bunch of errors.
          – user10676065
          Nov 20 at 17:01


















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