Why does int('.0') give ValueError?

I pass float number as string format in int('.0')

0.0 is valid floating point number, so why it is giving error?

edited Nov 20 at 2:15

smci

14.6k672104

asked Nov 20 at 1:53

Nishant Kadivar

3

Because integers are not floating-point.
– SLaks
Nov 20 at 1:55

Thanks for answering. int(2.1) gives 2 in return. so int convert it into int.
– Nishant Kadivar
Nov 20 at 1:58

3

int('2.1') returns a value error too. Similarly int(0.1) returns 0.
– Loocid
Nov 20 at 2:01

add a comment |

I pass float number as string format in int('.0')

0.0 is valid floating point number, so why it is giving error?

edited Nov 20 at 2:15

smci

14.6k672104

asked Nov 20 at 1:53

Nishant Kadivar

3

Because integers are not floating-point.
– SLaks
Nov 20 at 1:55

Thanks for answering. int(2.1) gives 2 in return. so int convert it into int.
– Nishant Kadivar
Nov 20 at 1:58

3

int('2.1') returns a value error too. Similarly int(0.1) returns 0.
– Loocid
Nov 20 at 2:01

add a comment |

I pass float number as string format in int('.0')

0.0 is valid floating point number, so why it is giving error?

edited Nov 20 at 2:15

smci

14.6k672104

asked Nov 20 at 1:53

Nishant Kadivar

I pass float number as string format in int('.0')

0.0 is valid floating point number, so why it is giving error?

python floating-point type-conversion int valueerror

edited Nov 20 at 2:15

smci

14.6k672104

asked Nov 20 at 1:53

Nishant Kadivar

edited Nov 20 at 2:15

smci

14.6k672104

asked Nov 20 at 1:53

Nishant Kadivar

edited Nov 20 at 2:15

smci

14.6k672104

edited Nov 20 at 2:15

smci

14.6k672104

edited Nov 20 at 2:15

smci

14.6k672104

asked Nov 20 at 1:53

Nishant Kadivar

asked Nov 20 at 1:53

Nishant Kadivar

asked Nov 20 at 1:53

Nishant Kadivar

3

Because integers are not floating-point.
– SLaks
Nov 20 at 1:55

Thanks for answering. int(2.1) gives 2 in return. so int convert it into int.
– Nishant Kadivar
Nov 20 at 1:58

3

int('2.1') returns a value error too. Similarly int(0.1) returns 0.
– Loocid
Nov 20 at 2:01

add a comment |

3

Because integers are not floating-point.
– SLaks
Nov 20 at 1:55

Thanks for answering. int(2.1) gives 2 in return. so int convert it into int.
– Nishant Kadivar
Nov 20 at 1:58

3

int('2.1') returns a value error too. Similarly int(0.1) returns 0.
– Loocid
Nov 20 at 2:01

Because integers are not floating-point.
– SLaks
Nov 20 at 1:55

Thanks for answering. int(2.1) gives 2 in return. so int convert it into int.
– Nishant Kadivar
Nov 20 at 1:58

int('2.1') returns a value error too. Similarly int(0.1) returns 0.
– Loocid
Nov 20 at 2:01

add a comment |

3 Answers
3

active

oldest

votes

From the documentation of int:

If x is not a number or if base is given, then x must be a string,
bytes, or bytearray instance representing an integer literal in radix
base. Optionally, the literal can be preceded by + or - (with no space
in between) and surrounded by whitespace.

So it gives you ValueError because the string '.0' does not represent an integer literal.

answered Nov 20 at 2:13

Daniel Mesejo

12.1k1924

@Nishant: Notice how it doesn't say "the literal can be preceded by a .".
– martineau
Nov 20 at 2:23

add a comment |

Because you can type cast one step at a time. For example you can convert float to int or string to int. Not a floating point string which here is 2steps.

answered Nov 20 at 2:00

Kireeti K

240211

add a comment |

You can do it if you remove the quotes and make it a float like:

int(.1)

But strings don't work if inside the string is a float, because they will think it's a number and will break saying '.' is not a numeric value, also the reason the above works is because:

>>> .1

0.1

>>>

And:

float(0.1)

Works.

Note that even a real float in a string can't be converted into an integer:

>>> int('3.1')

Traceback (most recent call last):

  File "<pyshell#1>", line 1, in <module>

    int('3.1')

ValueError: invalid literal for int() with base 10: '3.1'

edited Nov 20 at 7:10

Rudy Velthuis

24k43474

answered Nov 20 at 2:41

U9-Forward

12.1k21136

add a comment |

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3 Answers
3

active

oldest

votes

3 Answers
3

active

oldest

votes

From the documentation of int:

If x is not a number or if base is given, then x must be a string,
bytes, or bytearray instance representing an integer literal in radix
base. Optionally, the literal can be preceded by + or - (with no space
in between) and surrounded by whitespace.

So it gives you ValueError because the string '.0' does not represent an integer literal.

answered Nov 20 at 2:13

Daniel Mesejo

12.1k1924

@Nishant: Notice how it doesn't say "the literal can be preceded by a .".
– martineau
Nov 20 at 2:23

add a comment |

From the documentation of int:

If x is not a number or if base is given, then x must be a string,
bytes, or bytearray instance representing an integer literal in radix
base. Optionally, the literal can be preceded by + or - (with no space
in between) and surrounded by whitespace.

So it gives you ValueError because the string '.0' does not represent an integer literal.

answered Nov 20 at 2:13

Daniel Mesejo

12.1k1924

@Nishant: Notice how it doesn't say "the literal can be preceded by a .".
– martineau
Nov 20 at 2:23

add a comment |

From the documentation of int:

If x is not a number or if base is given, then x must be a string,
bytes, or bytearray instance representing an integer literal in radix
base. Optionally, the literal can be preceded by + or - (with no space
in between) and surrounded by whitespace.

So it gives you ValueError because the string '.0' does not represent an integer literal.

answered Nov 20 at 2:13

Daniel Mesejo

12.1k1924

From the documentation of int:

If x is not a number or if base is given, then x must be a string,
bytes, or bytearray instance representing an integer literal in radix
base. Optionally, the literal can be preceded by + or - (with no space
in between) and surrounded by whitespace.

So it gives you ValueError because the string '.0' does not represent an integer literal.

answered Nov 20 at 2:13

Daniel Mesejo

12.1k1924

answered Nov 20 at 2:13

Daniel Mesejo

12.1k1924

answered Nov 20 at 2:13

Daniel Mesejo

12.1k1924

answered Nov 20 at 2:13

Daniel Mesejo

12.1k1924

@Nishant: Notice how it doesn't say "the literal can be preceded by a .".
– martineau
Nov 20 at 2:23

add a comment |

@Nishant: Notice how it doesn't say "the literal can be preceded by a .".
– martineau
Nov 20 at 2:23

@Nishant: Notice how it doesn't say "the literal can be preceded by a .".
– martineau
Nov 20 at 2:23

add a comment |

Because you can type cast one step at a time. For example you can convert float to int or string to int. Not a floating point string which here is 2steps.

answered Nov 20 at 2:00

Kireeti K

240211

add a comment |

Because you can type cast one step at a time. For example you can convert float to int or string to int. Not a floating point string which here is 2steps.

answered Nov 20 at 2:00

Kireeti K

240211

add a comment |

Because you can type cast one step at a time. For example you can convert float to int or string to int. Not a floating point string which here is 2steps.

answered Nov 20 at 2:00

Kireeti K

240211

Because you can type cast one step at a time. For example you can convert float to int or string to int. Not a floating point string which here is 2steps.

answered Nov 20 at 2:00

Kireeti K

240211

answered Nov 20 at 2:00

Kireeti K

240211

answered Nov 20 at 2:00

Kireeti K

240211

answered Nov 20 at 2:00

Kireeti K

240211

add a comment |

You can do it if you remove the quotes and make it a float like:

int(.1)

But strings don't work if inside the string is a float, because they will think it's a number and will break saying '.' is not a numeric value, also the reason the above works is because:

>>> .1

0.1

>>>

And:

float(0.1)

Works.

Note that even a real float in a string can't be converted into an integer:

>>> int('3.1')

Traceback (most recent call last):

  File "<pyshell#1>", line 1, in <module>

    int('3.1')

ValueError: invalid literal for int() with base 10: '3.1'

edited Nov 20 at 7:10

Rudy Velthuis

24k43474

answered Nov 20 at 2:41

U9-Forward

12.1k21136

add a comment |

You can do it if you remove the quotes and make it a float like:

int(.1)

But strings don't work if inside the string is a float, because they will think it's a number and will break saying '.' is not a numeric value, also the reason the above works is because:

>>> .1

0.1

>>>

And:

float(0.1)

Works.

Note that even a real float in a string can't be converted into an integer:

>>> int('3.1')

Traceback (most recent call last):

  File "<pyshell#1>", line 1, in <module>

    int('3.1')

ValueError: invalid literal for int() with base 10: '3.1'

edited Nov 20 at 7:10

Rudy Velthuis

24k43474

answered Nov 20 at 2:41

U9-Forward

12.1k21136

add a comment |

You can do it if you remove the quotes and make it a float like:

int(.1)

But strings don't work if inside the string is a float, because they will think it's a number and will break saying '.' is not a numeric value, also the reason the above works is because:

>>> .1

0.1

>>>

And:

float(0.1)

Works.

Note that even a real float in a string can't be converted into an integer:

>>> int('3.1')

Traceback (most recent call last):

  File "<pyshell#1>", line 1, in <module>

    int('3.1')

ValueError: invalid literal for int() with base 10: '3.1'

edited Nov 20 at 7:10

Rudy Velthuis

24k43474

answered Nov 20 at 2:41

U9-Forward

12.1k21136

You can do it if you remove the quotes and make it a float like:

int(.1)

But strings don't work if inside the string is a float, because they will think it's a number and will break saying '.' is not a numeric value, also the reason the above works is because:

>>> .1

0.1

>>>

And:

float(0.1)

Works.

Note that even a real float in a string can't be converted into an integer:

>>> int('3.1')

Traceback (most recent call last):

  File "<pyshell#1>", line 1, in <module>

    int('3.1')

ValueError: invalid literal for int() with base 10: '3.1'

edited Nov 20 at 7:10

Rudy Velthuis

24k43474

answered Nov 20 at 2:41

U9-Forward

12.1k21136

edited Nov 20 at 7:10

Rudy Velthuis

24k43474

edited Nov 20 at 7:10

Rudy Velthuis

24k43474

edited Nov 20 at 7:10

Rudy Velthuis

24k43474

answered Nov 20 at 2:41

U9-Forward

12.1k21136

answered Nov 20 at 2:41

U9-Forward

12.1k21136

answered Nov 20 at 2:41

U9-Forward

12.1k21136

add a comment |

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