Why does int('.0') give ValueError?
I pass float number as string format in int('.0')
0.0 is valid floating point number, so why it is giving error?
python floating-point type-conversion int valueerror
edited Nov 20 at 2:15
smci
14.6k672104
asked Nov 20 at 1:53
Nishant Kadivar
32
add a comment |
I pass float number as string format in int('.0')
0.0 is valid floating point number, so why it is giving error?
python floating-point type-conversion int valueerror
edited Nov 20 at 2:15
smci
14.6k672104
asked Nov 20 at 1:53
Nishant Kadivar
32
3
Because integers are not floating-point.
– SLaks
Nov 20 at 1:55
Thanks for answering. int(2.1) gives 2 in return. so int convert it into int.
– Nishant Kadivar
Nov 20 at 1:58
3
int('2.1')returns a value error too. Similarlyint(0.1)returns 0.
– Loocid
Nov 20 at 2:01
add a comment |
I pass float number as string format in int('.0')
0.0 is valid floating point number, so why it is giving error?
python floating-point type-conversion int valueerror
edited Nov 20 at 2:15
smci
14.6k672104
asked Nov 20 at 1:53
Nishant Kadivar
32
I pass float number as string format in int('.0')
0.0 is valid floating point number, so why it is giving error?
python floating-point type-conversion int valueerror
python floating-point type-conversion int valueerror
edited Nov 20 at 2:15
smci
14.6k672104
asked Nov 20 at 1:53
Nishant Kadivar
32
edited Nov 20 at 2:15
smci
14.6k672104
asked Nov 20 at 1:53
Nishant Kadivar
32
edited Nov 20 at 2:15
smci
14.6k672104
edited Nov 20 at 2:15
smci
14.6k672104
edited Nov 20 at 2:15
smci
14.6k672104
14.6k672104
asked Nov 20 at 1:53
Nishant Kadivar
32
asked Nov 20 at 1:53
Nishant Kadivar
32
asked Nov 20 at 1:53
Nishant Kadivar
32
32
3
Because integers are not floating-point.
– SLaks
Nov 20 at 1:55
Thanks for answering. int(2.1) gives 2 in return. so int convert it into int.
– Nishant Kadivar
Nov 20 at 1:58
3
int('2.1')returns a value error too. Similarlyint(0.1)returns 0.
– Loocid
Nov 20 at 2:01
add a comment |
3
Because integers are not floating-point.
– SLaks
Nov 20 at 1:55
Thanks for answering. int(2.1) gives 2 in return. so int convert it into int.
– Nishant Kadivar
Nov 20 at 1:58
3
int('2.1')returns a value error too. Similarlyint(0.1)returns 0.
– Loocid
Nov 20 at 2:01
3
3
Because integers are not floating-point.
– SLaks
Nov 20 at 1:55
Because integers are not floating-point.
– SLaks
Nov 20 at 1:55
Thanks for answering. int(2.1) gives 2 in return. so int convert it into int.
– Nishant Kadivar
Nov 20 at 1:58
Thanks for answering. int(2.1) gives 2 in return. so int convert it into int.
– Nishant Kadivar
Nov 20 at 1:58
3
3
int('2.1') returns a value error too. Similarly int(0.1) returns 0.– Loocid
Nov 20 at 2:01
int('2.1') returns a value error too. Similarly int(0.1) returns 0.– Loocid
Nov 20 at 2:01
add a comment |
3 Answers
3
active
oldest
votes
From the documentation of int:
If x is not a number or if base is given, then x must be a string,
bytes, or bytearray instance representing an integer literal in radix
base. Optionally, the literal can be preceded by + or - (with no space
in between) and surrounded by whitespace.
So it gives you ValueError because the string '.0' does not represent an integer literal.
answered Nov 20 at 2:13
Daniel Mesejo
12.1k1924
@Nishant: Notice how it doesn't say "the literal can be preceded by a.".
– martineau
Nov 20 at 2:23
add a comment |
Because you can type cast one step at a time. For example you can convert float to int or string to int. Not a floating point string which here is 2steps.
answered Nov 20 at 2:00
Kireeti K
240211
add a comment |
You can do it if you remove the quotes and make it a float like:
int(.1)
But strings don't work if inside the string is a float, because they will think it's a number and will break saying '.' is not a numeric value, also the reason the above works is because:
>>> .1
0.1
>>>
And:
float(0.1)
Works.
Note that even a real float in a string can't be converted into an integer:
>>> int('3.1')
Traceback (most recent call last):
File "<pyshell#1>", line 1, in <module>
int('3.1')
ValueError: invalid literal for int() with base 10: '3.1'
edited Nov 20 at 7:10
Rudy Velthuis
24k43474
answered Nov 20 at 2:41
U9-Forward
12.1k21136
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
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active
oldest
votes
From the documentation of int:
If x is not a number or if base is given, then x must be a string,
bytes, or bytearray instance representing an integer literal in radix
base. Optionally, the literal can be preceded by + or - (with no space
in between) and surrounded by whitespace.
So it gives you ValueError because the string '.0' does not represent an integer literal.
answered Nov 20 at 2:13
Daniel Mesejo
12.1k1924
@Nishant: Notice how it doesn't say "the literal can be preceded by a.".
– martineau
Nov 20 at 2:23
add a comment |
From the documentation of int:
If x is not a number or if base is given, then x must be a string,
bytes, or bytearray instance representing an integer literal in radix
base. Optionally, the literal can be preceded by + or - (with no space
in between) and surrounded by whitespace.
So it gives you ValueError because the string '.0' does not represent an integer literal.
answered Nov 20 at 2:13
Daniel Mesejo
12.1k1924
@Nishant: Notice how it doesn't say "the literal can be preceded by a.".
– martineau
Nov 20 at 2:23
add a comment |
From the documentation of int:
If x is not a number or if base is given, then x must be a string,
bytes, or bytearray instance representing an integer literal in radix
base. Optionally, the literal can be preceded by + or - (with no space
in between) and surrounded by whitespace.
So it gives you ValueError because the string '.0' does not represent an integer literal.
answered Nov 20 at 2:13
Daniel Mesejo
12.1k1924
From the documentation of int:
If x is not a number or if base is given, then x must be a string,
bytes, or bytearray instance representing an integer literal in radix
base. Optionally, the literal can be preceded by + or - (with no space
in between) and surrounded by whitespace.
So it gives you ValueError because the string '.0' does not represent an integer literal.
answered Nov 20 at 2:13
Daniel Mesejo
12.1k1924
answered Nov 20 at 2:13
Daniel Mesejo
12.1k1924
answered Nov 20 at 2:13
Daniel Mesejo
12.1k1924
answered Nov 20 at 2:13
Daniel Mesejo
12.1k1924
12.1k1924
@Nishant: Notice how it doesn't say "the literal can be preceded by a.".
– martineau
Nov 20 at 2:23
add a comment |
@Nishant: Notice how it doesn't say "the literal can be preceded by a.".
– martineau
Nov 20 at 2:23
@Nishant: Notice how it doesn't say "the literal can be preceded by a
.".– martineau
Nov 20 at 2:23
@Nishant: Notice how it doesn't say "the literal can be preceded by a
.".– martineau
Nov 20 at 2:23
add a comment |
Because you can type cast one step at a time. For example you can convert float to int or string to int. Not a floating point string which here is 2steps.
answered Nov 20 at 2:00
Kireeti K
240211
add a comment |
Because you can type cast one step at a time. For example you can convert float to int or string to int. Not a floating point string which here is 2steps.
answered Nov 20 at 2:00
Kireeti K
240211
add a comment |
Because you can type cast one step at a time. For example you can convert float to int or string to int. Not a floating point string which here is 2steps.
answered Nov 20 at 2:00
Kireeti K
240211
Because you can type cast one step at a time. For example you can convert float to int or string to int. Not a floating point string which here is 2steps.
answered Nov 20 at 2:00
Kireeti K
240211
answered Nov 20 at 2:00
Kireeti K
240211
answered Nov 20 at 2:00
Kireeti K
240211
answered Nov 20 at 2:00
Kireeti K
240211
240211
add a comment |
add a comment |
You can do it if you remove the quotes and make it a float like:
int(.1)
But strings don't work if inside the string is a float, because they will think it's a number and will break saying '.' is not a numeric value, also the reason the above works is because:
>>> .1
0.1
>>>
And:
float(0.1)
Works.
Note that even a real float in a string can't be converted into an integer:
>>> int('3.1')
Traceback (most recent call last):
File "<pyshell#1>", line 1, in <module>
int('3.1')
ValueError: invalid literal for int() with base 10: '3.1'
edited Nov 20 at 7:10
Rudy Velthuis
24k43474
answered Nov 20 at 2:41
U9-Forward
12.1k21136
add a comment |
You can do it if you remove the quotes and make it a float like:
int(.1)
But strings don't work if inside the string is a float, because they will think it's a number and will break saying '.' is not a numeric value, also the reason the above works is because:
>>> .1
0.1
>>>
And:
float(0.1)
Works.
Note that even a real float in a string can't be converted into an integer:
>>> int('3.1')
Traceback (most recent call last):
File "<pyshell#1>", line 1, in <module>
int('3.1')
ValueError: invalid literal for int() with base 10: '3.1'
edited Nov 20 at 7:10
Rudy Velthuis
24k43474
answered Nov 20 at 2:41
U9-Forward
12.1k21136
add a comment |
You can do it if you remove the quotes and make it a float like:
int(.1)
But strings don't work if inside the string is a float, because they will think it's a number and will break saying '.' is not a numeric value, also the reason the above works is because:
>>> .1
0.1
>>>
And:
float(0.1)
Works.
Note that even a real float in a string can't be converted into an integer:
>>> int('3.1')
Traceback (most recent call last):
File "<pyshell#1>", line 1, in <module>
int('3.1')
ValueError: invalid literal for int() with base 10: '3.1'
edited Nov 20 at 7:10
Rudy Velthuis
24k43474
answered Nov 20 at 2:41
U9-Forward
12.1k21136
You can do it if you remove the quotes and make it a float like:
int(.1)
But strings don't work if inside the string is a float, because they will think it's a number and will break saying '.' is not a numeric value, also the reason the above works is because:
>>> .1
0.1
>>>
And:
float(0.1)
Works.
Note that even a real float in a string can't be converted into an integer:
>>> int('3.1')
Traceback (most recent call last):
File "<pyshell#1>", line 1, in <module>
int('3.1')
ValueError: invalid literal for int() with base 10: '3.1'
edited Nov 20 at 7:10
Rudy Velthuis
24k43474
answered Nov 20 at 2:41
U9-Forward
12.1k21136
edited Nov 20 at 7:10
Rudy Velthuis
24k43474
edited Nov 20 at 7:10
Rudy Velthuis
24k43474
edited Nov 20 at 7:10
Rudy Velthuis
24k43474
24k43474
answered Nov 20 at 2:41
U9-Forward
12.1k21136
answered Nov 20 at 2:41
U9-Forward
12.1k21136
answered Nov 20 at 2:41
U9-Forward
12.1k21136
12.1k21136
add a comment |
add a comment |
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3
Because integers are not floating-point.
– SLaks
Nov 20 at 1:55
Thanks for answering. int(2.1) gives 2 in return. so int convert it into int.
– Nishant Kadivar
Nov 20 at 1:58
3
int('2.1')returns a value error too. Similarlyint(0.1)returns 0.– Loocid
Nov 20 at 2:01