Can't show equation tag properly
2
begin{align*}
sum_{j=1}^{m_0-1},(-1)^{j-1}hspace{-3ex}
sum_{substack{ k_{m_0 +1} leq k_{m_0} leq cdots leq k_{j+2} leq k_1 leq boldsymbol{ell} \ k_2 < cdots < k_j < k_{j+1} leq k_1 }}
= sum_{ k_{m_0 +1} leq k_{m_0} leq cdots leq k_2 leq k_1 leq
boldsymbol{ell}, } tag(3) label{eq:3}
end{align*}
which is very close to our goal, equation eqref{eq:2}.
Comparing equation eqref{eq:3} with equation eqref{eq:2}, we discover that both have the identical 1ts{st} through $(m_0 -2)$ts{th} terms ($1 leq j leq m_0-2$).
The only difference of the two is that the $(m_0 -1)$ts{th} term in equation eqref{eq:3} is ...
end{document}
I try to put a tag next to the equation, but the result comes out as:
The tag is not displayed correctly. Also, the eqref{eq:3} are displayed in the same, wrong way. (I omit the code having eq:2 and eq:1.)
tags
edited 2 days ago
Werner
437k649591650
asked Dec 30 '18 at 2:52
HankY
111
New contributor
HankY is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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add a comment |
2
begin{align*}
sum_{j=1}^{m_0-1},(-1)^{j-1}hspace{-3ex}
sum_{substack{ k_{m_0 +1} leq k_{m_0} leq cdots leq k_{j+2} leq k_1 leq boldsymbol{ell} \ k_2 < cdots < k_j < k_{j+1} leq k_1 }}
= sum_{ k_{m_0 +1} leq k_{m_0} leq cdots leq k_2 leq k_1 leq
boldsymbol{ell}, } tag(3) label{eq:3}
end{align*}
which is very close to our goal, equation eqref{eq:2}.
Comparing equation eqref{eq:3} with equation eqref{eq:2}, we discover that both have the identical 1ts{st} through $(m_0 -2)$ts{th} terms ($1 leq j leq m_0-2$).
The only difference of the two is that the $(m_0 -1)$ts{th} term in equation eqref{eq:3} is ...
end{document}
I try to put a tag next to the equation, but the result comes out as:
The tag is not displayed correctly. Also, the eqref{eq:3} are displayed in the same, wrong way. (I omit the code having eq:2 and eq:1.)
tags
edited 2 days ago
Werner
437k649591650
asked Dec 30 '18 at 2:52
HankY
111
New contributor
HankY is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
1
Welcome to TeX.SE! Replacetag(3)bytag{3}(curly brackets around3). Otherwise LaTeX thinks you meantag{(}.
– marmot
Dec 30 '18 at 2:57
It worked, thank you!
– HankY
Dec 30 '18 at 3:08
You're welcome! BTW, I'd recommend to move the comma afterboldsymbol{ell}out of the subscript, and not to abbreviatetextsuperscriptbytsif you ever plan to share your documents with others.
– marmot
Dec 30 '18 at 3:11
add a comment |
2
2
2
begin{align*}
sum_{j=1}^{m_0-1},(-1)^{j-1}hspace{-3ex}
sum_{substack{ k_{m_0 +1} leq k_{m_0} leq cdots leq k_{j+2} leq k_1 leq boldsymbol{ell} \ k_2 < cdots < k_j < k_{j+1} leq k_1 }}
= sum_{ k_{m_0 +1} leq k_{m_0} leq cdots leq k_2 leq k_1 leq
boldsymbol{ell}, } tag(3) label{eq:3}
end{align*}
which is very close to our goal, equation eqref{eq:2}.
Comparing equation eqref{eq:3} with equation eqref{eq:2}, we discover that both have the identical 1ts{st} through $(m_0 -2)$ts{th} terms ($1 leq j leq m_0-2$).
The only difference of the two is that the $(m_0 -1)$ts{th} term in equation eqref{eq:3} is ...
end{document}
I try to put a tag next to the equation, but the result comes out as:
The tag is not displayed correctly. Also, the eqref{eq:3} are displayed in the same, wrong way. (I omit the code having eq:2 and eq:1.)
tags
edited 2 days ago
Werner
437k649591650
asked Dec 30 '18 at 2:52
HankY
111
New contributor
HankY is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
begin{align*}
sum_{j=1}^{m_0-1},(-1)^{j-1}hspace{-3ex}
sum_{substack{ k_{m_0 +1} leq k_{m_0} leq cdots leq k_{j+2} leq k_1 leq boldsymbol{ell} \ k_2 < cdots < k_j < k_{j+1} leq k_1 }}
= sum_{ k_{m_0 +1} leq k_{m_0} leq cdots leq k_2 leq k_1 leq
boldsymbol{ell}, } tag(3) label{eq:3}
end{align*}
which is very close to our goal, equation eqref{eq:2}.
Comparing equation eqref{eq:3} with equation eqref{eq:2}, we discover that both have the identical 1ts{st} through $(m_0 -2)$ts{th} terms ($1 leq j leq m_0-2$).
The only difference of the two is that the $(m_0 -1)$ts{th} term in equation eqref{eq:3} is ...
end{document}
I try to put a tag next to the equation, but the result comes out as:
The tag is not displayed correctly. Also, the eqref{eq:3} are displayed in the same, wrong way. (I omit the code having eq:2 and eq:1.)
tags
tags
edited 2 days ago
Werner
437k649591650
asked Dec 30 '18 at 2:52
HankY
111
New contributor
HankY is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 2 days ago
Werner
437k649591650
asked Dec 30 '18 at 2:52
HankY
111
New contributor
HankY is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 2 days ago
Werner
437k649591650
edited 2 days ago
Werner
437k649591650
edited 2 days ago
Werner
437k649591650
437k649591650
asked Dec 30 '18 at 2:52
HankY
111
New contributor
HankY is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Dec 30 '18 at 2:52
HankY
111
asked Dec 30 '18 at 2:52
HankY
111
111
New contributor
HankY is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
HankY is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
HankY is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
1
Welcome to TeX.SE! Replacetag(3)bytag{3}(curly brackets around3). Otherwise LaTeX thinks you meantag{(}.
– marmot
Dec 30 '18 at 2:57
It worked, thank you!
– HankY
Dec 30 '18 at 3:08
You're welcome! BTW, I'd recommend to move the comma afterboldsymbol{ell}out of the subscript, and not to abbreviatetextsuperscriptbytsif you ever plan to share your documents with others.
– marmot
Dec 30 '18 at 3:11
add a comment |
1
Welcome to TeX.SE! Replacetag(3)bytag{3}(curly brackets around3). Otherwise LaTeX thinks you meantag{(}.
– marmot
Dec 30 '18 at 2:57
It worked, thank you!
– HankY
Dec 30 '18 at 3:08
You're welcome! BTW, I'd recommend to move the comma afterboldsymbol{ell}out of the subscript, and not to abbreviatetextsuperscriptbytsif you ever plan to share your documents with others.
– marmot
Dec 30 '18 at 3:11
1
1
Welcome to TeX.SE! Replace
tag(3) by tag{3} (curly brackets around 3). Otherwise LaTeX thinks you mean tag{(}.– marmot
Dec 30 '18 at 2:57
Welcome to TeX.SE! Replace
tag(3) by tag{3} (curly brackets around 3). Otherwise LaTeX thinks you mean tag{(}.– marmot
Dec 30 '18 at 2:57
It worked, thank you!
– HankY
Dec 30 '18 at 3:08
It worked, thank you!
– HankY
Dec 30 '18 at 3:08
You're welcome! BTW, I'd recommend to move the comma after
boldsymbol{ell} out of the subscript, and not to abbreviate textsuperscript by ts if you ever plan to share your documents with others.– marmot
Dec 30 '18 at 3:11
You're welcome! BTW, I'd recommend to move the comma after
boldsymbol{ell} out of the subscript, and not to abbreviate textsuperscript by ts if you ever plan to share your documents with others.– marmot
Dec 30 '18 at 3:11
add a comment |
1 Answer
1
active
oldest
votes
3
tag{<tag>} takes a mandatory argument. If you don't supply the surrounding braces, then it takes the next token as the argument.
In your case, tag(3) doesn't use the suggested format tag{<tag>}, so it turns into tag{(}3), numbering the equation with ( and leaving 3) in the input stream. You're looking for tag{3}:
documentclass{article}
usepackage{amsmath,amssymb}
begin{document}
begin{align*}
sum_{j = 1}^{m_0 - 1},(-1)^{j - 1}hspace{-3ex}
sum_{
substack
{ k_{m_0 + 1} leq k_{m_0} leq cdots leq k_{j + 2} leq k_1 leq boldsymbol{ell} \
k_2 < cdots < k_j < k_{j+1} leq k_1
}
}
= sum_{ k_{m_0 + 1} leq k_{m_0} leq cdots leq k_2 leq k_1 leq boldsymbol{ell} }, tag{3} label{eq:3}
end{align*}
which is very close to our goal, equation~(2). Comparing equation~eqref{eq:3} with equation~(2), we discover that both have the identical
1textsuperscript{st} through $(m_0 - 2)$textsuperscript{th} terms ($1 leq j leq m_0 - 2$). The only difference of the two is that the
$(m_0 - 1)$textsuperscript{th} term in equation eqref{eq:3} is ldots
end{document}
answered 2 days ago
Werner
437k649591650
add a comment |
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3
tag{<tag>} takes a mandatory argument. If you don't supply the surrounding braces, then it takes the next token as the argument.
In your case, tag(3) doesn't use the suggested format tag{<tag>}, so it turns into tag{(}3), numbering the equation with ( and leaving 3) in the input stream. You're looking for tag{3}:
documentclass{article}
usepackage{amsmath,amssymb}
begin{document}
begin{align*}
sum_{j = 1}^{m_0 - 1},(-1)^{j - 1}hspace{-3ex}
sum_{
substack
{ k_{m_0 + 1} leq k_{m_0} leq cdots leq k_{j + 2} leq k_1 leq boldsymbol{ell} \
k_2 < cdots < k_j < k_{j+1} leq k_1
}
}
= sum_{ k_{m_0 + 1} leq k_{m_0} leq cdots leq k_2 leq k_1 leq boldsymbol{ell} }, tag{3} label{eq:3}
end{align*}
which is very close to our goal, equation~(2). Comparing equation~eqref{eq:3} with equation~(2), we discover that both have the identical
1textsuperscript{st} through $(m_0 - 2)$textsuperscript{th} terms ($1 leq j leq m_0 - 2$). The only difference of the two is that the
$(m_0 - 1)$textsuperscript{th} term in equation eqref{eq:3} is ldots
end{document}
answered 2 days ago
Werner
437k649591650
add a comment |
3
tag{<tag>} takes a mandatory argument. If you don't supply the surrounding braces, then it takes the next token as the argument.
In your case, tag(3) doesn't use the suggested format tag{<tag>}, so it turns into tag{(}3), numbering the equation with ( and leaving 3) in the input stream. You're looking for tag{3}:
documentclass{article}
usepackage{amsmath,amssymb}
begin{document}
begin{align*}
sum_{j = 1}^{m_0 - 1},(-1)^{j - 1}hspace{-3ex}
sum_{
substack
{ k_{m_0 + 1} leq k_{m_0} leq cdots leq k_{j + 2} leq k_1 leq boldsymbol{ell} \
k_2 < cdots < k_j < k_{j+1} leq k_1
}
}
= sum_{ k_{m_0 + 1} leq k_{m_0} leq cdots leq k_2 leq k_1 leq boldsymbol{ell} }, tag{3} label{eq:3}
end{align*}
which is very close to our goal, equation~(2). Comparing equation~eqref{eq:3} with equation~(2), we discover that both have the identical
1textsuperscript{st} through $(m_0 - 2)$textsuperscript{th} terms ($1 leq j leq m_0 - 2$). The only difference of the two is that the
$(m_0 - 1)$textsuperscript{th} term in equation eqref{eq:3} is ldots
end{document}
answered 2 days ago
Werner
437k649591650
add a comment |
3
3
3
tag{<tag>} takes a mandatory argument. If you don't supply the surrounding braces, then it takes the next token as the argument.
In your case, tag(3) doesn't use the suggested format tag{<tag>}, so it turns into tag{(}3), numbering the equation with ( and leaving 3) in the input stream. You're looking for tag{3}:
documentclass{article}
usepackage{amsmath,amssymb}
begin{document}
begin{align*}
sum_{j = 1}^{m_0 - 1},(-1)^{j - 1}hspace{-3ex}
sum_{
substack
{ k_{m_0 + 1} leq k_{m_0} leq cdots leq k_{j + 2} leq k_1 leq boldsymbol{ell} \
k_2 < cdots < k_j < k_{j+1} leq k_1
}
}
= sum_{ k_{m_0 + 1} leq k_{m_0} leq cdots leq k_2 leq k_1 leq boldsymbol{ell} }, tag{3} label{eq:3}
end{align*}
which is very close to our goal, equation~(2). Comparing equation~eqref{eq:3} with equation~(2), we discover that both have the identical
1textsuperscript{st} through $(m_0 - 2)$textsuperscript{th} terms ($1 leq j leq m_0 - 2$). The only difference of the two is that the
$(m_0 - 1)$textsuperscript{th} term in equation eqref{eq:3} is ldots
end{document}
answered 2 days ago
Werner
437k649591650
tag{<tag>} takes a mandatory argument. If you don't supply the surrounding braces, then it takes the next token as the argument.
In your case, tag(3) doesn't use the suggested format tag{<tag>}, so it turns into tag{(}3), numbering the equation with ( and leaving 3) in the input stream. You're looking for tag{3}:
documentclass{article}
usepackage{amsmath,amssymb}
begin{document}
begin{align*}
sum_{j = 1}^{m_0 - 1},(-1)^{j - 1}hspace{-3ex}
sum_{
substack
{ k_{m_0 + 1} leq k_{m_0} leq cdots leq k_{j + 2} leq k_1 leq boldsymbol{ell} \
k_2 < cdots < k_j < k_{j+1} leq k_1
}
}
= sum_{ k_{m_0 + 1} leq k_{m_0} leq cdots leq k_2 leq k_1 leq boldsymbol{ell} }, tag{3} label{eq:3}
end{align*}
which is very close to our goal, equation~(2). Comparing equation~eqref{eq:3} with equation~(2), we discover that both have the identical
1textsuperscript{st} through $(m_0 - 2)$textsuperscript{th} terms ($1 leq j leq m_0 - 2$). The only difference of the two is that the
$(m_0 - 1)$textsuperscript{th} term in equation eqref{eq:3} is ldots
end{document}
answered 2 days ago
Werner
437k649591650
answered 2 days ago
Werner
437k649591650
answered 2 days ago
Werner
437k649591650
answered 2 days ago
Werner
437k649591650
437k649591650
add a comment |
add a comment |
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1
Welcome to TeX.SE! Replace
tag(3)bytag{3}(curly brackets around3). Otherwise LaTeX thinks you meantag{(}.– marmot
Dec 30 '18 at 2:57
It worked, thank you!
– HankY
Dec 30 '18 at 3:08
You're welcome! BTW, I'd recommend to move the comma after
boldsymbol{ell}out of the subscript, and not to abbreviatetextsuperscriptbytsif you ever plan to share your documents with others.– marmot
Dec 30 '18 at 3:11