What is the difference between a zero operator, zero function, zero scalar, and zero vector?












2












$begingroup$


I'm pretty sure that a zero vector is just a vector of length zero with direction, zero scalar is just the number zero, and that a zero function is any function that maps to zero. Not entirely sure what exactly a zero operator is however.










share|cite|improve this question









New contributor




Arlene is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$

















    2












    $begingroup$


    I'm pretty sure that a zero vector is just a vector of length zero with direction, zero scalar is just the number zero, and that a zero function is any function that maps to zero. Not entirely sure what exactly a zero operator is however.










    share|cite|improve this question









    New contributor




    Arlene is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.







    $endgroup$















      2












      2








      2


      1



      $begingroup$


      I'm pretty sure that a zero vector is just a vector of length zero with direction, zero scalar is just the number zero, and that a zero function is any function that maps to zero. Not entirely sure what exactly a zero operator is however.










      share|cite|improve this question









      New contributor




      Arlene is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.







      $endgroup$




      I'm pretty sure that a zero vector is just a vector of length zero with direction, zero scalar is just the number zero, and that a zero function is any function that maps to zero. Not entirely sure what exactly a zero operator is however.







      linear-algebra soft-question terminology






      share|cite|improve this question









      New contributor




      Arlene is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|cite|improve this question









      New contributor




      Arlene is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      share|cite|improve this question




      share|cite|improve this question








      edited 4 hours ago









      J. W. Tanner

      2,0791117




      2,0791117






      New contributor




      Arlene is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      asked 5 hours ago









      ArleneArlene

      133




      133




      New contributor




      Arlene is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.





      New contributor





      Arlene is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      Arlene is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






















          2 Answers
          2






          active

          oldest

          votes


















          4












          $begingroup$

          The zero vector is a vector, i.e. a member of whatever vector space is under consideration. It has the property that adding it to any vector $bf v$ in the vector space leaves $bf v$ unchanged.



          The zero scalar is a scalar, i.e. a member of the field that is part of the definition of the vector space (usually the real or complex numbers in an elementary linear algebra course). It has the property that multiplying
          any vector $bf v$ by it gives the zero vector of the second vector space.



          The zero operator is a linear operator, i.e. a linear map from a vector space to a vector space (possibly the same one). It has the property that it maps any member of the first vector space to the zero vector in the second vector space.



          The zero functional is a linear functional, i.e. a linear map from a vector space to the scalars. It has the property that it maps any member of the vector space to the zero scalar.






          share|cite|improve this answer











          $endgroup$





















            2












            $begingroup$

            In an algebraic context where there is a notion of addition, $0$ is the element such that
            $$
            x + 0 = x
            $$

            for every $x$.



            If the context is the real numbers, then $0$ is just a number. If the context is the Euclidean coordinate plane, $0$ is the vector $(0,0)$. If the context is the set of real valued functions on the unit interval then $0$ is the function whose value at every point is $0$. If the context is the set of linear operators from one vector space to another then $0$ is the operator whose value at every point of the domain is the $0$ vector in the codomain.



            So the meaning of the symbol "$0$" changes depending on the context. That's potentially confusing (which is why you are asking the question.) The advantage in using the same symbol in these different contexts is that it's easy to associate that symbol with its behavior: it's the additive identity.






            share|cite|improve this answer









            $endgroup$













              Your Answer





              StackExchange.ifUsing("editor", function () {
              return StackExchange.using("mathjaxEditing", function () {
              StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
              StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
              });
              });
              }, "mathjax-editing");

              StackExchange.ready(function() {
              var channelOptions = {
              tags: "".split(" "),
              id: "69"
              };
              initTagRenderer("".split(" "), "".split(" "), channelOptions);

              StackExchange.using("externalEditor", function() {
              // Have to fire editor after snippets, if snippets enabled
              if (StackExchange.settings.snippets.snippetsEnabled) {
              StackExchange.using("snippets", function() {
              createEditor();
              });
              }
              else {
              createEditor();
              }
              });

              function createEditor() {
              StackExchange.prepareEditor({
              heartbeatType: 'answer',
              autoActivateHeartbeat: false,
              convertImagesToLinks: true,
              noModals: true,
              showLowRepImageUploadWarning: true,
              reputationToPostImages: 10,
              bindNavPrevention: true,
              postfix: "",
              imageUploader: {
              brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
              contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
              allowUrls: true
              },
              noCode: true, onDemand: true,
              discardSelector: ".discard-answer"
              ,immediatelyShowMarkdownHelp:true
              });


              }
              });






              Arlene is a new contributor. Be nice, and check out our Code of Conduct.










              draft saved

              draft discarded


















              StackExchange.ready(
              function () {
              StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3117052%2fwhat-is-the-difference-between-a-zero-operator-zero-function-zero-scalar-and%23new-answer', 'question_page');
              }
              );

              Post as a guest















              Required, but never shown

























              2 Answers
              2






              active

              oldest

              votes








              2 Answers
              2






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes









              4












              $begingroup$

              The zero vector is a vector, i.e. a member of whatever vector space is under consideration. It has the property that adding it to any vector $bf v$ in the vector space leaves $bf v$ unchanged.



              The zero scalar is a scalar, i.e. a member of the field that is part of the definition of the vector space (usually the real or complex numbers in an elementary linear algebra course). It has the property that multiplying
              any vector $bf v$ by it gives the zero vector of the second vector space.



              The zero operator is a linear operator, i.e. a linear map from a vector space to a vector space (possibly the same one). It has the property that it maps any member of the first vector space to the zero vector in the second vector space.



              The zero functional is a linear functional, i.e. a linear map from a vector space to the scalars. It has the property that it maps any member of the vector space to the zero scalar.






              share|cite|improve this answer











              $endgroup$


















                4












                $begingroup$

                The zero vector is a vector, i.e. a member of whatever vector space is under consideration. It has the property that adding it to any vector $bf v$ in the vector space leaves $bf v$ unchanged.



                The zero scalar is a scalar, i.e. a member of the field that is part of the definition of the vector space (usually the real or complex numbers in an elementary linear algebra course). It has the property that multiplying
                any vector $bf v$ by it gives the zero vector of the second vector space.



                The zero operator is a linear operator, i.e. a linear map from a vector space to a vector space (possibly the same one). It has the property that it maps any member of the first vector space to the zero vector in the second vector space.



                The zero functional is a linear functional, i.e. a linear map from a vector space to the scalars. It has the property that it maps any member of the vector space to the zero scalar.






                share|cite|improve this answer











                $endgroup$
















                  4












                  4








                  4





                  $begingroup$

                  The zero vector is a vector, i.e. a member of whatever vector space is under consideration. It has the property that adding it to any vector $bf v$ in the vector space leaves $bf v$ unchanged.



                  The zero scalar is a scalar, i.e. a member of the field that is part of the definition of the vector space (usually the real or complex numbers in an elementary linear algebra course). It has the property that multiplying
                  any vector $bf v$ by it gives the zero vector of the second vector space.



                  The zero operator is a linear operator, i.e. a linear map from a vector space to a vector space (possibly the same one). It has the property that it maps any member of the first vector space to the zero vector in the second vector space.



                  The zero functional is a linear functional, i.e. a linear map from a vector space to the scalars. It has the property that it maps any member of the vector space to the zero scalar.






                  share|cite|improve this answer











                  $endgroup$



                  The zero vector is a vector, i.e. a member of whatever vector space is under consideration. It has the property that adding it to any vector $bf v$ in the vector space leaves $bf v$ unchanged.



                  The zero scalar is a scalar, i.e. a member of the field that is part of the definition of the vector space (usually the real or complex numbers in an elementary linear algebra course). It has the property that multiplying
                  any vector $bf v$ by it gives the zero vector of the second vector space.



                  The zero operator is a linear operator, i.e. a linear map from a vector space to a vector space (possibly the same one). It has the property that it maps any member of the first vector space to the zero vector in the second vector space.



                  The zero functional is a linear functional, i.e. a linear map from a vector space to the scalars. It has the property that it maps any member of the vector space to the zero scalar.







                  share|cite|improve this answer














                  share|cite|improve this answer



                  share|cite|improve this answer








                  edited 4 hours ago

























                  answered 4 hours ago









                  Robert IsraelRobert Israel

                  324k23213467




                  324k23213467























                      2












                      $begingroup$

                      In an algebraic context where there is a notion of addition, $0$ is the element such that
                      $$
                      x + 0 = x
                      $$

                      for every $x$.



                      If the context is the real numbers, then $0$ is just a number. If the context is the Euclidean coordinate plane, $0$ is the vector $(0,0)$. If the context is the set of real valued functions on the unit interval then $0$ is the function whose value at every point is $0$. If the context is the set of linear operators from one vector space to another then $0$ is the operator whose value at every point of the domain is the $0$ vector in the codomain.



                      So the meaning of the symbol "$0$" changes depending on the context. That's potentially confusing (which is why you are asking the question.) The advantage in using the same symbol in these different contexts is that it's easy to associate that symbol with its behavior: it's the additive identity.






                      share|cite|improve this answer









                      $endgroup$


















                        2












                        $begingroup$

                        In an algebraic context where there is a notion of addition, $0$ is the element such that
                        $$
                        x + 0 = x
                        $$

                        for every $x$.



                        If the context is the real numbers, then $0$ is just a number. If the context is the Euclidean coordinate plane, $0$ is the vector $(0,0)$. If the context is the set of real valued functions on the unit interval then $0$ is the function whose value at every point is $0$. If the context is the set of linear operators from one vector space to another then $0$ is the operator whose value at every point of the domain is the $0$ vector in the codomain.



                        So the meaning of the symbol "$0$" changes depending on the context. That's potentially confusing (which is why you are asking the question.) The advantage in using the same symbol in these different contexts is that it's easy to associate that symbol with its behavior: it's the additive identity.






                        share|cite|improve this answer









                        $endgroup$
















                          2












                          2








                          2





                          $begingroup$

                          In an algebraic context where there is a notion of addition, $0$ is the element such that
                          $$
                          x + 0 = x
                          $$

                          for every $x$.



                          If the context is the real numbers, then $0$ is just a number. If the context is the Euclidean coordinate plane, $0$ is the vector $(0,0)$. If the context is the set of real valued functions on the unit interval then $0$ is the function whose value at every point is $0$. If the context is the set of linear operators from one vector space to another then $0$ is the operator whose value at every point of the domain is the $0$ vector in the codomain.



                          So the meaning of the symbol "$0$" changes depending on the context. That's potentially confusing (which is why you are asking the question.) The advantage in using the same symbol in these different contexts is that it's easy to associate that symbol with its behavior: it's the additive identity.






                          share|cite|improve this answer









                          $endgroup$



                          In an algebraic context where there is a notion of addition, $0$ is the element such that
                          $$
                          x + 0 = x
                          $$

                          for every $x$.



                          If the context is the real numbers, then $0$ is just a number. If the context is the Euclidean coordinate plane, $0$ is the vector $(0,0)$. If the context is the set of real valued functions on the unit interval then $0$ is the function whose value at every point is $0$. If the context is the set of linear operators from one vector space to another then $0$ is the operator whose value at every point of the domain is the $0$ vector in the codomain.



                          So the meaning of the symbol "$0$" changes depending on the context. That's potentially confusing (which is why you are asking the question.) The advantage in using the same symbol in these different contexts is that it's easy to associate that symbol with its behavior: it's the additive identity.







                          share|cite|improve this answer












                          share|cite|improve this answer



                          share|cite|improve this answer










                          answered 4 hours ago









                          Ethan BolkerEthan Bolker

                          43.4k551116




                          43.4k551116






















                              Arlene is a new contributor. Be nice, and check out our Code of Conduct.










                              draft saved

                              draft discarded


















                              Arlene is a new contributor. Be nice, and check out our Code of Conduct.













                              Arlene is a new contributor. Be nice, and check out our Code of Conduct.












                              Arlene is a new contributor. Be nice, and check out our Code of Conduct.
















                              Thanks for contributing an answer to Mathematics Stack Exchange!


                              • Please be sure to answer the question. Provide details and share your research!

                              But avoid



                              • Asking for help, clarification, or responding to other answers.

                              • Making statements based on opinion; back them up with references or personal experience.


                              Use MathJax to format equations. MathJax reference.


                              To learn more, see our tips on writing great answers.




                              draft saved


                              draft discarded














                              StackExchange.ready(
                              function () {
                              StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3117052%2fwhat-is-the-difference-between-a-zero-operator-zero-function-zero-scalar-and%23new-answer', 'question_page');
                              }
                              );

                              Post as a guest















                              Required, but never shown





















































                              Required, but never shown














                              Required, but never shown












                              Required, but never shown







                              Required, but never shown

































                              Required, but never shown














                              Required, but never shown












                              Required, but never shown







                              Required, but never shown







                              Popular posts from this blog

                              If I really need a card on my start hand, how many mulligans make sense? [duplicate]

                              Alcedinidae

                              Can an atomic nucleus contain both particles and antiparticles? [duplicate]