Argthtjtr

Here is a cropped example (about 11x9 pixels) of the kind of images (which ultimately are actually all of size 28x28, but stored in memory flattened as a 784-components array) I will be trying to apply the algorithm on:

Basically, I want to be able to recognize when this shape appears (red lines are used to put emphasis on the separation of the pixels, while the surrounding black border is used to better outline the image against the white background of StackOverflow):

The orientation of it doesn't matter: it must be detected in any of its possible representations (rotations and symmetries) along the horizontal and vertical axis (so, for example, a 45° rotation shouldn't be considered, nor a diagonal symmetry: only consider 90°, 180°, and 270° rotations, for example).

There are two solutions to be found on that image that I first presented, though only one needs to be found (ignore the gray blurr surrounding the white region):

Take this other sample (which also demonstrates that the white figures inside the images aren't always fully surrounded by black pixels):

The function should return True because the shape is present:

Now, there is obviously a simple solution to this:

Use a variable such as pattern = [[1,0,0,0],[1,1,1,1]], produce its variations, and then slide all of the variations along the image until an exact match is found at which point the whole thing just stops and returns True.

This would, however, in the worst case scenario, take up to 8*(28-2)*(28-4)*(2*4) which is approximately 40000 operations for a single image, which seem a bit overkill (if I did my quick calculations right).

I'm guessing one way of making this naive approach better would be to first of all scan the image until I find the very first white pixel, and then start looking for the pattern 4 rows and 4 columns earlier than that point, but even that doesn't seem good enough.

Any ideas? Maybe this kind of function has already been implemented in some library? I'm looking for an implementation or an algorithm that beats my naive approach.

As a side note, while kind of a hack, I'm guessing this is the kind of problem that can be offloaded to the GPU but I do not have much experience with that. While it wouldn't be what I'm looking for primarily, if you provide an answer, feel free to add a GPU-related note.

If you have too many operations, think how to do less of them.

For this problem I'd use image integrals.

If you convolve a summing kernel over the image (this is a very fast operation in fft domain with just conv2,imfilter), you know that only locations where the integral is equal to 5 (in your case) are possible pattern matching places. Checking those (even for your 4 rotations) should be computationally very fast. There can not be more than 50 locations in your example image that fit this pattern.

My python is not too fluent, but this is the proof of concept for your first image in MATLAB, I am sure that translating this code should not be a problem.

% get the same image you have (imgur upscaled it and made it RGB)

I=rgb2gray(imread('https://i.stack.imgur.com/l3u4A.png'));

I=imresize(I,[9 11]);

I=double(I>50);



% Integral filter definition (with your desired size)

h=ones(3,4);



% horizontal and vertical filter (because your filter is  not square)

Ifiltv=imfilter(I,h);

Ifilth=imfilter(I,h');

% find the locations where integral is exactly the value you want

[xh,yh]=find(Ifilth==5);

[xv,yv]=find(Ifiltv==5);



% this is just plotting, for completeness

figure()

imshow(I,);

hold on

plot(yh,xh,'r.');

plot(yv,xv,'r.');

This results in 14 locations to check. My standard computer takes 230ns on average on computing both image integrals, which I would call fast.

Also GPU computing is not a hack :D. Its the way to go with a big bunch of problems because of the enormous computing power they have. E.g. convolutions in GPUs are incredibly fast.

The operation you are implementing is an operator in Mathematical Morphology called hit and miss.

It can be implemented very efficiently as a composition of two erosions. If the shape you’re detecting can be decomposed into a few simple geometrical shapes (especially rectangles are quick to compute) then the operator can be even more efficient.

You’ll find very efficient erosions in most image processing libraries, for example try OpenCV. OpenCV also has a hit and miss operator, here is a tutorial for how to use it.

As an example for what output to expect, I generated a simple test image (left), applied a hit and miss operator with a template that matches at exactly one place in the image (middle), and again with a template that does not match anywhere (right):

I did this in MATLAB, not Python, because I have it open and it's easiest for me to use. This is the code:

se = [1,1,1,1      % Defines the template

      0,0,0,1];

img = [0,0,0,0,0,0 % Defines the test image

       0,1,1,1,1,0

       0,0,0,0,1,0

       0,0,0,0,0,0

       0,0,0,0,0,0

       0,0,0,0,0,0];

img = dip_image(img,'bin');



res1 = hitmiss(img,se);

res2 = hitmiss(img,rot90(se,2));



% Quick-and-dirty display

h = dipshow([img,res1,res2]);

diptruesize(h,'tight',3000)

hold on

plot([5.5,5.5],[-0.5,5.5],'r-')

plot([11.5,11.5],[-0.5,5.5],'r-')

The code above uses the hit and miss operator as I implemented in DIPimage. This same implementation is available in Python in PyDIP as HitAndMiss (there is not yet a binary release of PyDIP, you need to compile it yourself):

import PyDIP as dip

# ...

res = dip.HitAndMiss(img, se)