Remove columns from a CSV using CMD/Batch
0
I currently have a CSV I download from a vendor which has data in it I do not require before importing it into our system.
I need to removed some columns from the CSV using a batch file as we are on citrix we have not got powershell as an option.
There are no column headers and below is what the CSV looks like:
"9826XXXXXXXXXX217","60007834 "," 10.00","D","22/11/2018"
"9826XXXXXXXXXX324","60008504 "," 12.00","D","22/11/2018"
"9826XXXXXXXXXX414","60010605 "," 12.00","D","22/11/2018"
"9826XXXXXXXXXX013","60011385 "," 12.00","D","22/11/2018"
I need the output to be 2nd, 3rd, 5th column.
"60007834 "," 10.00","22/11/2018"
"60008504 "," 12.00","22/11/2018"
"60010605 "," 12.00","22/11/2018"
"60011385 "," 12.00","22/11/2018"
csv batch-file cmd
asked Nov 23 '18 at 9:37
ryall579ryall579
246
add a comment |
0
I currently have a CSV I download from a vendor which has data in it I do not require before importing it into our system.
I need to removed some columns from the CSV using a batch file as we are on citrix we have not got powershell as an option.
There are no column headers and below is what the CSV looks like:
"9826XXXXXXXXXX217","60007834 "," 10.00","D","22/11/2018"
"9826XXXXXXXXXX324","60008504 "," 12.00","D","22/11/2018"
"9826XXXXXXXXXX414","60010605 "," 12.00","D","22/11/2018"
"9826XXXXXXXXXX013","60011385 "," 12.00","D","22/11/2018"
I need the output to be 2nd, 3rd, 5th column.
"60007834 "," 10.00","22/11/2018"
"60008504 "," 12.00","22/11/2018"
"60010605 "," 12.00","22/11/2018"
"60011385 "," 12.00","22/11/2018"
csv batch-file cmd
asked Nov 23 '18 at 9:37
ryall579ryall579
246
1
for more complex csv manipulation with batch files you can take a look at this
– npocmaka
Nov 23 '18 at 9:52
What have you tried, where are you stuck? Please share your efforts!
– aschipfl
Nov 23 '18 at 10:15
@Echo off For %%F in (.txt) do ( (for /f "delims=" %%A in (%%F) do Call :Split %%A ) > "C:Run Folder%%~nF_New.txt" ) goto :Eof :Split if "%~2"=="" goto :eof Echo(%2,%3,%5 move ".txt" "C:Archive" >nul The above is what I ended with which takes columns 2,3,5 and pushes it to an output file which mirrors the old file name with "_New" and it removes the blank line at the end of the file.
– ryall579
Nov 28 '18 at 14:40
add a comment |
0
0
0
I currently have a CSV I download from a vendor which has data in it I do not require before importing it into our system.
I need to removed some columns from the CSV using a batch file as we are on citrix we have not got powershell as an option.
There are no column headers and below is what the CSV looks like:
"9826XXXXXXXXXX217","60007834 "," 10.00","D","22/11/2018"
"9826XXXXXXXXXX324","60008504 "," 12.00","D","22/11/2018"
"9826XXXXXXXXXX414","60010605 "," 12.00","D","22/11/2018"
"9826XXXXXXXXXX013","60011385 "," 12.00","D","22/11/2018"
I need the output to be 2nd, 3rd, 5th column.
"60007834 "," 10.00","22/11/2018"
"60008504 "," 12.00","22/11/2018"
"60010605 "," 12.00","22/11/2018"
"60011385 "," 12.00","22/11/2018"
csv batch-file cmd
asked Nov 23 '18 at 9:37
ryall579ryall579
246
I currently have a CSV I download from a vendor which has data in it I do not require before importing it into our system.
I need to removed some columns from the CSV using a batch file as we are on citrix we have not got powershell as an option.
There are no column headers and below is what the CSV looks like:
"9826XXXXXXXXXX217","60007834 "," 10.00","D","22/11/2018"
"9826XXXXXXXXXX324","60008504 "," 12.00","D","22/11/2018"
"9826XXXXXXXXXX414","60010605 "," 12.00","D","22/11/2018"
"9826XXXXXXXXXX013","60011385 "," 12.00","D","22/11/2018"
I need the output to be 2nd, 3rd, 5th column.
"60007834 "," 10.00","22/11/2018"
"60008504 "," 12.00","22/11/2018"
"60010605 "," 12.00","22/11/2018"
"60011385 "," 12.00","22/11/2018"
csv batch-file cmd
csv batch-file cmd
asked Nov 23 '18 at 9:37
ryall579ryall579
246
asked Nov 23 '18 at 9:37
ryall579ryall579
246
asked Nov 23 '18 at 9:37
ryall579ryall579
246
asked Nov 23 '18 at 9:37
ryall579ryall579
246
asked Nov 23 '18 at 9:37
ryall579ryall579
246
246
1
for more complex csv manipulation with batch files you can take a look at this
– npocmaka
Nov 23 '18 at 9:52
What have you tried, where are you stuck? Please share your efforts!
– aschipfl
Nov 23 '18 at 10:15
@Echo off For %%F in (.txt) do ( (for /f "delims=" %%A in (%%F) do Call :Split %%A ) > "C:Run Folder%%~nF_New.txt" ) goto :Eof :Split if "%~2"=="" goto :eof Echo(%2,%3,%5 move ".txt" "C:Archive" >nul The above is what I ended with which takes columns 2,3,5 and pushes it to an output file which mirrors the old file name with "_New" and it removes the blank line at the end of the file.
– ryall579
Nov 28 '18 at 14:40
add a comment |
1
for more complex csv manipulation with batch files you can take a look at this
– npocmaka
Nov 23 '18 at 9:52
What have you tried, where are you stuck? Please share your efforts!
– aschipfl
Nov 23 '18 at 10:15
@Echo off For %%F in (.txt) do ( (for /f "delims=" %%A in (%%F) do Call :Split %%A ) > "C:Run Folder%%~nF_New.txt" ) goto :Eof :Split if "%~2"=="" goto :eof Echo(%2,%3,%5 move ".txt" "C:Archive" >nul The above is what I ended with which takes columns 2,3,5 and pushes it to an output file which mirrors the old file name with "_New" and it removes the blank line at the end of the file.
– ryall579
Nov 28 '18 at 14:40
1
1
for more complex csv manipulation with batch files you can take a look at this
– npocmaka
Nov 23 '18 at 9:52
for more complex csv manipulation with batch files you can take a look at this
– npocmaka
Nov 23 '18 at 9:52
What have you tried, where are you stuck? Please share your efforts!
– aschipfl
Nov 23 '18 at 10:15
What have you tried, where are you stuck? Please share your efforts!
– aschipfl
Nov 23 '18 at 10:15
@Echo off For %%F in (.txt) do ( (for /f "delims=" %%A in (%%F) do Call :Split %%A ) > "C:Run Folder%%~nF_New.txt" ) goto :Eof :Split if "%~2"=="" goto :eof Echo(%2,%3,%5 move ".txt" "C:Archive" >nul The above is what I ended with which takes columns 2,3,5 and pushes it to an output file which mirrors the old file name with "_New" and it removes the blank line at the end of the file.
– ryall579
Nov 28 '18 at 14:40
@Echo off For %%F in (.txt) do ( (for /f "delims=" %%A in (%%F) do Call :Split %%A ) > "C:Run Folder%%~nF_New.txt" ) goto :Eof :Split if "%~2"=="" goto :eof Echo(%2,%3,%5 move ".txt" "C:Archive" >nul The above is what I ended with which takes columns 2,3,5 and pushes it to an output file which mirrors the old file name with "_New" and it removes the blank line at the end of the file.
– ryall579
Nov 28 '18 at 14:40
add a comment |
2 Answers
2
active
oldest
votes
1
In case there are possibly commas inside the fields,
use a call to a sub passing the quoted arguments:
:: Q:Test20181123SO_53444017.cmd
@Echo off
(for /f "delims=" %%A in (test.csv) do Call :Split %%A
) > test_New.csv
goto :Eof
:Split
Echo(%2,%3,%5
> type test_New.csv
"60007834 "," 10.00","22/11/2018"
"60008504 "," 12.00","22/11/2018"
"60010605 "," 12.00","22/11/2018"
"60011385 "," 12.00","22/11/2018"
Edit: Variant processing all *.csv files (appending _New to the name)
:: Q:Test20181123SO_53444017.cmd
@Echo off
For %%F in (*.csv) do (
(for /f "delims=" %%A in (%%F) do Call :Split %%A
) > "X:Path%%~nF_New.csv"
)
goto :Eof
:Split
Echo(%2,%3,%5
answered Nov 23 '18 at 10:40
LotPingsLotPings
20.1k61633
Thanks, this works a treat, anyway I could have the file name as a wild character like: (*.csv), when I try do that it returns a blank file
– ryall579
Nov 23 '18 at 10:54
You'll need an outer for loop to enumerate the files. See edit to the answer.
– LotPings
Nov 23 '18 at 11:00
1
just following the label:splitinsert anif "%~2"=="" goto :eofor a similar check on other columns
– LotPings
Nov 28 '18 at 11:58
1
There is only one redirection to change to directly save in the folder you'd like so) > "%~dpnF_New.csv"-->) > "X:Yourpath%~nF_New.csv"But this should be a new question and my answer here deserves an upvote ;-)
– LotPings
Nov 28 '18 at 12:29
1
Sorry missed one % sign, see changed answer. How to vote up
– LotPings
Nov 28 '18 at 12:55
|
show 4 more comments
0
Not too difficult really.
from batch file, assuming file name is test.csv
(for /f "tokens=2,3,5 delims=," %%i in (test.csv) do echo %%i,%%j,%%k) > newcsv.csv
This will simply write values 2,3,5 to the new csv file..
To run it from cmdline instead, simply remove one of each %
(for /f "tokens=2,3,5 delims=," %i in (test.csv) do echo %i,%j,%k) > newcsv.csv
Please note, this assumes the data within your values do not contain , if they do, we need to make some changes.
answered Nov 23 '18 at 9:48
Gerhard BarnardGerhard Barnard
9,24731233
1
much faster:(for ... ...,%%k)>newcsv.csv(very noticeable with larger files)
– Stephan
Nov 23 '18 at 11:21
Thanks @Stephan , updated.
– Gerhard Barnard
Nov 23 '18 at 11:27
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
In case there are possibly commas inside the fields,
use a call to a sub passing the quoted arguments:
:: Q:Test20181123SO_53444017.cmd
@Echo off
(for /f "delims=" %%A in (test.csv) do Call :Split %%A
) > test_New.csv
goto :Eof
:Split
Echo(%2,%3,%5
> type test_New.csv
"60007834 "," 10.00","22/11/2018"
"60008504 "," 12.00","22/11/2018"
"60010605 "," 12.00","22/11/2018"
"60011385 "," 12.00","22/11/2018"
Edit: Variant processing all *.csv files (appending _New to the name)
:: Q:Test20181123SO_53444017.cmd
@Echo off
For %%F in (*.csv) do (
(for /f "delims=" %%A in (%%F) do Call :Split %%A
) > "X:Path%%~nF_New.csv"
)
goto :Eof
:Split
Echo(%2,%3,%5
answered Nov 23 '18 at 10:40
LotPingsLotPings
20.1k61633
Thanks, this works a treat, anyway I could have the file name as a wild character like: (*.csv), when I try do that it returns a blank file
– ryall579
Nov 23 '18 at 10:54
You'll need an outer for loop to enumerate the files. See edit to the answer.
– LotPings
Nov 23 '18 at 11:00
1
just following the label:splitinsert anif "%~2"=="" goto :eofor a similar check on other columns
– LotPings
Nov 28 '18 at 11:58
1
There is only one redirection to change to directly save in the folder you'd like so) > "%~dpnF_New.csv"-->) > "X:Yourpath%~nF_New.csv"But this should be a new question and my answer here deserves an upvote ;-)
– LotPings
Nov 28 '18 at 12:29
1
Sorry missed one % sign, see changed answer. How to vote up
– LotPings
Nov 28 '18 at 12:55
|
show 4 more comments
1
In case there are possibly commas inside the fields,
use a call to a sub passing the quoted arguments:
:: Q:Test20181123SO_53444017.cmd
@Echo off
(for /f "delims=" %%A in (test.csv) do Call :Split %%A
) > test_New.csv
goto :Eof
:Split
Echo(%2,%3,%5
> type test_New.csv
"60007834 "," 10.00","22/11/2018"
"60008504 "," 12.00","22/11/2018"
"60010605 "," 12.00","22/11/2018"
"60011385 "," 12.00","22/11/2018"
Edit: Variant processing all *.csv files (appending _New to the name)
:: Q:Test20181123SO_53444017.cmd
@Echo off
For %%F in (*.csv) do (
(for /f "delims=" %%A in (%%F) do Call :Split %%A
) > "X:Path%%~nF_New.csv"
)
goto :Eof
:Split
Echo(%2,%3,%5
answered Nov 23 '18 at 10:40
LotPingsLotPings
20.1k61633
Thanks, this works a treat, anyway I could have the file name as a wild character like: (*.csv), when I try do that it returns a blank file
– ryall579
Nov 23 '18 at 10:54
You'll need an outer for loop to enumerate the files. See edit to the answer.
– LotPings
Nov 23 '18 at 11:00
1
just following the label:splitinsert anif "%~2"=="" goto :eofor a similar check on other columns
– LotPings
Nov 28 '18 at 11:58
1
There is only one redirection to change to directly save in the folder you'd like so) > "%~dpnF_New.csv"-->) > "X:Yourpath%~nF_New.csv"But this should be a new question and my answer here deserves an upvote ;-)
– LotPings
Nov 28 '18 at 12:29
1
Sorry missed one % sign, see changed answer. How to vote up
– LotPings
Nov 28 '18 at 12:55
|
show 4 more comments
1
1
1
In case there are possibly commas inside the fields,
use a call to a sub passing the quoted arguments:
:: Q:Test20181123SO_53444017.cmd
@Echo off
(for /f "delims=" %%A in (test.csv) do Call :Split %%A
) > test_New.csv
goto :Eof
:Split
Echo(%2,%3,%5
> type test_New.csv
"60007834 "," 10.00","22/11/2018"
"60008504 "," 12.00","22/11/2018"
"60010605 "," 12.00","22/11/2018"
"60011385 "," 12.00","22/11/2018"
Edit: Variant processing all *.csv files (appending _New to the name)
:: Q:Test20181123SO_53444017.cmd
@Echo off
For %%F in (*.csv) do (
(for /f "delims=" %%A in (%%F) do Call :Split %%A
) > "X:Path%%~nF_New.csv"
)
goto :Eof
:Split
Echo(%2,%3,%5
answered Nov 23 '18 at 10:40
LotPingsLotPings
20.1k61633
In case there are possibly commas inside the fields,
use a call to a sub passing the quoted arguments:
:: Q:Test20181123SO_53444017.cmd
@Echo off
(for /f "delims=" %%A in (test.csv) do Call :Split %%A
) > test_New.csv
goto :Eof
:Split
Echo(%2,%3,%5
> type test_New.csv
"60007834 "," 10.00","22/11/2018"
"60008504 "," 12.00","22/11/2018"
"60010605 "," 12.00","22/11/2018"
"60011385 "," 12.00","22/11/2018"
Edit: Variant processing all *.csv files (appending _New to the name)
:: Q:Test20181123SO_53444017.cmd
@Echo off
For %%F in (*.csv) do (
(for /f "delims=" %%A in (%%F) do Call :Split %%A
) > "X:Path%%~nF_New.csv"
)
goto :Eof
:Split
Echo(%2,%3,%5
answered Nov 23 '18 at 10:40
LotPingsLotPings
20.1k61633
edited Nov 28 '18 at 12:53
answered Nov 23 '18 at 10:40
LotPingsLotPings
20.1k61633
answered Nov 23 '18 at 10:40
LotPingsLotPings
20.1k61633
answered Nov 23 '18 at 10:40
LotPingsLotPings
20.1k61633
20.1k61633
Thanks, this works a treat, anyway I could have the file name as a wild character like: (*.csv), when I try do that it returns a blank file
– ryall579
Nov 23 '18 at 10:54
You'll need an outer for loop to enumerate the files. See edit to the answer.
– LotPings
Nov 23 '18 at 11:00
1
just following the label:splitinsert anif "%~2"=="" goto :eofor a similar check on other columns
– LotPings
Nov 28 '18 at 11:58
1
There is only one redirection to change to directly save in the folder you'd like so) > "%~dpnF_New.csv"-->) > "X:Yourpath%~nF_New.csv"But this should be a new question and my answer here deserves an upvote ;-)
– LotPings
Nov 28 '18 at 12:29
1
Sorry missed one % sign, see changed answer. How to vote up
– LotPings
Nov 28 '18 at 12:55
|
show 4 more comments
Thanks, this works a treat, anyway I could have the file name as a wild character like: (*.csv), when I try do that it returns a blank file
– ryall579
Nov 23 '18 at 10:54
You'll need an outer for loop to enumerate the files. See edit to the answer.
– LotPings
Nov 23 '18 at 11:00
1
just following the label:splitinsert anif "%~2"=="" goto :eofor a similar check on other columns
– LotPings
Nov 28 '18 at 11:58
1
There is only one redirection to change to directly save in the folder you'd like so) > "%~dpnF_New.csv"-->) > "X:Yourpath%~nF_New.csv"But this should be a new question and my answer here deserves an upvote ;-)
– LotPings
Nov 28 '18 at 12:29
1
Sorry missed one % sign, see changed answer. How to vote up
– LotPings
Nov 28 '18 at 12:55
Thanks, this works a treat, anyway I could have the file name as a wild character like: (*.csv), when I try do that it returns a blank file
– ryall579
Nov 23 '18 at 10:54
Thanks, this works a treat, anyway I could have the file name as a wild character like: (*.csv), when I try do that it returns a blank file
– ryall579
Nov 23 '18 at 10:54
You'll need an outer for loop to enumerate the files. See edit to the answer.
– LotPings
Nov 23 '18 at 11:00
You'll need an outer for loop to enumerate the files. See edit to the answer.
– LotPings
Nov 23 '18 at 11:00
1
1
just following the label
:split insert an if "%~2"=="" goto :eof or a similar check on other columns– LotPings
Nov 28 '18 at 11:58
just following the label
:split insert an if "%~2"=="" goto :eof or a similar check on other columns– LotPings
Nov 28 '18 at 11:58
1
1
There is only one redirection to change to directly save in the folder you'd like so
) > "%~dpnF_New.csv" --> ) > "X:Yourpath%~nF_New.csv" But this should be a new question and my answer here deserves an upvote ;-)– LotPings
Nov 28 '18 at 12:29
There is only one redirection to change to directly save in the folder you'd like so
) > "%~dpnF_New.csv" --> ) > "X:Yourpath%~nF_New.csv" But this should be a new question and my answer here deserves an upvote ;-)– LotPings
Nov 28 '18 at 12:29
1
1
Sorry missed one % sign, see changed answer. How to vote up
– LotPings
Nov 28 '18 at 12:55
Sorry missed one % sign, see changed answer. How to vote up
– LotPings
Nov 28 '18 at 12:55
|
show 4 more comments
0
Not too difficult really.
from batch file, assuming file name is test.csv
(for /f "tokens=2,3,5 delims=," %%i in (test.csv) do echo %%i,%%j,%%k) > newcsv.csv
This will simply write values 2,3,5 to the new csv file..
To run it from cmdline instead, simply remove one of each %
(for /f "tokens=2,3,5 delims=," %i in (test.csv) do echo %i,%j,%k) > newcsv.csv
Please note, this assumes the data within your values do not contain , if they do, we need to make some changes.
answered Nov 23 '18 at 9:48
Gerhard BarnardGerhard Barnard
9,24731233
1
much faster:(for ... ...,%%k)>newcsv.csv(very noticeable with larger files)
– Stephan
Nov 23 '18 at 11:21
Thanks @Stephan , updated.
– Gerhard Barnard
Nov 23 '18 at 11:27
add a comment |
0
Not too difficult really.
from batch file, assuming file name is test.csv
(for /f "tokens=2,3,5 delims=," %%i in (test.csv) do echo %%i,%%j,%%k) > newcsv.csv
This will simply write values 2,3,5 to the new csv file..
To run it from cmdline instead, simply remove one of each %
(for /f "tokens=2,3,5 delims=," %i in (test.csv) do echo %i,%j,%k) > newcsv.csv
Please note, this assumes the data within your values do not contain , if they do, we need to make some changes.
answered Nov 23 '18 at 9:48
Gerhard BarnardGerhard Barnard
9,24731233
1
much faster:(for ... ...,%%k)>newcsv.csv(very noticeable with larger files)
– Stephan
Nov 23 '18 at 11:21
Thanks @Stephan , updated.
– Gerhard Barnard
Nov 23 '18 at 11:27
add a comment |
0
0
0
Not too difficult really.
from batch file, assuming file name is test.csv
(for /f "tokens=2,3,5 delims=," %%i in (test.csv) do echo %%i,%%j,%%k) > newcsv.csv
This will simply write values 2,3,5 to the new csv file..
To run it from cmdline instead, simply remove one of each %
(for /f "tokens=2,3,5 delims=," %i in (test.csv) do echo %i,%j,%k) > newcsv.csv
Please note, this assumes the data within your values do not contain , if they do, we need to make some changes.
answered Nov 23 '18 at 9:48
Gerhard BarnardGerhard Barnard
9,24731233
Not too difficult really.
from batch file, assuming file name is test.csv
(for /f "tokens=2,3,5 delims=," %%i in (test.csv) do echo %%i,%%j,%%k) > newcsv.csv
This will simply write values 2,3,5 to the new csv file..
To run it from cmdline instead, simply remove one of each %
(for /f "tokens=2,3,5 delims=," %i in (test.csv) do echo %i,%j,%k) > newcsv.csv
Please note, this assumes the data within your values do not contain , if they do, we need to make some changes.
answered Nov 23 '18 at 9:48
Gerhard BarnardGerhard Barnard
9,24731233
edited Nov 23 '18 at 11:27
answered Nov 23 '18 at 9:48
Gerhard BarnardGerhard Barnard
9,24731233
answered Nov 23 '18 at 9:48
Gerhard BarnardGerhard Barnard
9,24731233
answered Nov 23 '18 at 9:48
Gerhard BarnardGerhard Barnard
9,24731233
9,24731233
1
much faster:(for ... ...,%%k)>newcsv.csv(very noticeable with larger files)
– Stephan
Nov 23 '18 at 11:21
Thanks @Stephan , updated.
– Gerhard Barnard
Nov 23 '18 at 11:27
add a comment |
1
much faster:(for ... ...,%%k)>newcsv.csv(very noticeable with larger files)
– Stephan
Nov 23 '18 at 11:21
Thanks @Stephan , updated.
– Gerhard Barnard
Nov 23 '18 at 11:27
1
1
much faster:
(for ... ...,%%k)>newcsv.csv (very noticeable with larger files)– Stephan
Nov 23 '18 at 11:21
much faster:
(for ... ...,%%k)>newcsv.csv (very noticeable with larger files)– Stephan
Nov 23 '18 at 11:21
Thanks @Stephan , updated.
– Gerhard Barnard
Nov 23 '18 at 11:27
Thanks @Stephan , updated.
– Gerhard Barnard
Nov 23 '18 at 11:27
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for more complex csv manipulation with batch files you can take a look at this
– npocmaka
Nov 23 '18 at 9:52
What have you tried, where are you stuck? Please share your efforts!
– aschipfl
Nov 23 '18 at 10:15
@Echo off For %%F in (.txt) do ( (for /f "delims=" %%A in (%%F) do Call :Split %%A ) > "C:Run Folder%%~nF_New.txt" ) goto :Eof :Split if "%~2"=="" goto :eof Echo(%2,%3,%5 move ".txt" "C:Archive" >nul The above is what I ended with which takes columns 2,3,5 and pushes it to an output file which mirrors the old file name with "_New" and it removes the blank line at the end of the file.
– ryall579
Nov 28 '18 at 14:40