Argthtjtr

I am new to python and I've tried to search but can seem to find a sample of what I am trying to accomplish. Any ideas are much appreciated. I am working with a nested dictionary with lots of key and values but I only want to print specific ones using a filtered list variable.

my_nested_dict = {"global": {"peers": {"15.1.1.1": {"remote_id": "15.1.1.1", "address_family": {"ipv4": {"sent_prefixes": 1, "received_prefixes": 4, "accepted_prefixes": 4}}, "remote_as": 65002, "uptime": 13002, "is_enabled": true, "is_up": true, "description": "== R3 BGP Neighbor ==", "local_as": 65002}}, "router_id": "15.1.1.2"}}

I would like to a filter through it and choose which keys and values to print out

filtered_list = ['peers', 'remote_id', 'remote_as', 'uptime']

and achieve a out out of

peers: 15.1.1.1

remote_id: 15.1.1.1

remote_as: 65002

uptime: 13002

Use recursion and isinstance:

my_nested_dict = {"global": {"peers": {"15.1.1.1": {"remote_id": "15.1.1.1", "address_family": {"ipv4": {"sent_prefixes": 1, "received_prefixes": 4, "accepted_prefixes": 4}}, "remote_as": 65002, "uptime": 13002, "is_enabled": True, "is_up": True, "description": "== R3 BGP Neighbor ==", "local_as": 65002}}, "router_id": "15.1.1.2"}}



filtered_list = ['peers', 'remote_id', 'remote_as', 'uptime']



def seek_keys(d, key_list):

    for k, v in d.items():

        if k in key_list:

            if isinstance(v, dict):

                print(k + ": " + list(v.keys())[0])

            else:

                print(k + ": " + str(v))

        if isinstance(v, dict):

            seek_keys(v, key_list)



seek_keys(my_nested_dict, filtered_list)

Note: There is a built in assumption here that if you ever want the "value" from a key whose value is another dictionary, you get the first key.

On top of @JacobIRR;s answer, I would say you can try caching the recursed data in a flat dict. That way, it will be much faster than recurse every time. You need not worry about memory since the values in the flat dict will simply refer to the original objects in the deep dictionary. I will leave the modification of JacobIRR's code to you :).

@JacobIRR has posted a great answer, but since you are attempting to join the matching keys with the its corresponding value, a much shorter solution arises:

my_nested_dict = {"global": {"peers": {"15.1.1.1": {"remote_id": "15.1.1.1", "address_family": {"ipv4": {"sent_prefixes": 1, "received_prefixes": 4, "accepted_prefixes": 4}}, "remote_as": 65002, "uptime": 13002, "is_enabled": True, "is_up": True, "description": "== R3 BGP Neighbor ==", "local_as": 65002}}, "router_id": "15.1.1.2"}}

_list = ['peers', 'remote_id', 'remote_as', 'uptime']



def _join(a, b):

  return '{}:{}n'.format(a, _keys(b, True) if isinstance(b, dict) else b)



def _keys(_d, flag = False):

  return ''.join(_join(a, b) if a in _list else (a+'n' if flag else '')+_keys(b) 

          for a, b in _d.items())



print(get_keys(my_nested_dict))

Output:

peers:15.1.1.1

remote_id:15.1.1.1

remote_as:65002

uptime:13002