How to convert data into JSON dictionary?

So I get a response and print it. The result is bytes:

payload = request.body

print (payload)

b'a=123&b=345&c=678&d=910'

I decode it, and the result is:

dataform = payload.decode('utf-8').replace("'", '"')

print(dataform, 'dataform')

a=123&b=345&c=678&d=910

I dumps it, and the result is:

result = json.dumps(dataform, indent=4, sort_keys=True)

print(result, 'result')

"a=123&b=345&c=678&d=910"

I loads it, and the result is:

jason = json.loads(result)

print(jason, 'jason')

a=123&b=345&c=678&d=910

I just want a normal json dictionary that I can refer to like data['string']. What am I doing wrong or not doing?

edited Nov 23 '18 at 9:10

asked Nov 23 '18 at 9:03

Whodini

611117

1

The string doesn't contain any single quotes, so replacing them is superfluous (and if it wasn't, it'd be wrong). Other than that, are you looking for d = dict(x.split('=', 1) for x in payload.decode('utf-8').split('&')) perhaps?

– tripleee
Nov 23 '18 at 9:18

add a comment |

So I get a response and print it. The result is bytes:

payload = request.body

print (payload)

b'a=123&b=345&c=678&d=910'

I decode it, and the result is:

dataform = payload.decode('utf-8').replace("'", '"')

print(dataform, 'dataform')

a=123&b=345&c=678&d=910

I dumps it, and the result is:

result = json.dumps(dataform, indent=4, sort_keys=True)

print(result, 'result')

"a=123&b=345&c=678&d=910"

I loads it, and the result is:

jason = json.loads(result)

print(jason, 'jason')

a=123&b=345&c=678&d=910

I just want a normal json dictionary that I can refer to like data['string']. What am I doing wrong or not doing?

edited Nov 23 '18 at 9:10

asked Nov 23 '18 at 9:03

Whodini

611117

1

The string doesn't contain any single quotes, so replacing them is superfluous (and if it wasn't, it'd be wrong). Other than that, are you looking for d = dict(x.split('=', 1) for x in payload.decode('utf-8').split('&')) perhaps?

– tripleee
Nov 23 '18 at 9:18

add a comment |

So I get a response and print it. The result is bytes:

payload = request.body

print (payload)

b'a=123&b=345&c=678&d=910'

I decode it, and the result is:

dataform = payload.decode('utf-8').replace("'", '"')

print(dataform, 'dataform')

a=123&b=345&c=678&d=910

I dumps it, and the result is:

result = json.dumps(dataform, indent=4, sort_keys=True)

print(result, 'result')

"a=123&b=345&c=678&d=910"

I loads it, and the result is:

jason = json.loads(result)

print(jason, 'jason')

a=123&b=345&c=678&d=910

I just want a normal json dictionary that I can refer to like data['string']. What am I doing wrong or not doing?

edited Nov 23 '18 at 9:10

asked Nov 23 '18 at 9:03

Whodini

611117

So I get a response and print it. The result is bytes:

payload = request.body

print (payload)

b'a=123&b=345&c=678&d=910'

I decode it, and the result is:

dataform = payload.decode('utf-8').replace("'", '"')

print(dataform, 'dataform')

a=123&b=345&c=678&d=910

I dumps it, and the result is:

result = json.dumps(dataform, indent=4, sort_keys=True)

print(result, 'result')

"a=123&b=345&c=678&d=910"

I loads it, and the result is:

jason = json.loads(result)

print(jason, 'jason')

a=123&b=345&c=678&d=910

I just want a normal json dictionary that I can refer to like data['string']. What am I doing wrong or not doing?

python json

edited Nov 23 '18 at 9:10

asked Nov 23 '18 at 9:03

Whodini

611117

edited Nov 23 '18 at 9:10

asked Nov 23 '18 at 9:03

Whodini

611117

edited Nov 23 '18 at 9:10

asked Nov 23 '18 at 9:03

Whodini

611117

asked Nov 23 '18 at 9:03

Whodini

611117

asked Nov 23 '18 at 9:03

Whodini

611117

1

The string doesn't contain any single quotes, so replacing them is superfluous (and if it wasn't, it'd be wrong). Other than that, are you looking for d = dict(x.split('=', 1) for x in payload.decode('utf-8').split('&')) perhaps?

– tripleee
Nov 23 '18 at 9:18

add a comment |

1

The string doesn't contain any single quotes, so replacing them is superfluous (and if it wasn't, it'd be wrong). Other than that, are you looking for d = dict(x.split('=', 1) for x in payload.decode('utf-8').split('&')) perhaps?

– tripleee
Nov 23 '18 at 9:18

The string doesn't contain any single quotes, so replacing them is superfluous (and if it wasn't, it'd be wrong). Other than that, are you looking for d = dict(x.split('=', 1) for x in payload.decode('utf-8').split('&')) perhaps?

– tripleee
Nov 23 '18 at 9:18

add a comment |

3 Answers
3

active

oldest

votes

There's a few errors here.

First off, dumping to JSON and then loading it again does absolutely nothing (it does have a few side-effects, but that's not important here).

Secondly, and mainly, your input data isn't JSON - it's either a query string or, more likely, form-data.

You can try to parse it using the standard parse_qs in urllib.parse, but if that fails you'll have to look around for a library that can handle proper form data.

In [1]: from urllib.parse import parse_qs



In [2]: payload = b'a=123&b=345&c=678&d=910'



In [3]: dataform = payload.decode('utf-8').replace("'", '"')



In [4]: result = parse_qs(dataform)



In [5]: print(result)

{'a': ['123'], 'b': ['345'], 'c': ['678'], 'd': ['910']}

answered Nov 23 '18 at 9:19

Raniz

8,52112356

1

The .replace() part is superfluous. Also in python2, you should do from urlparse import parse_qs.

– SMir
Nov 23 '18 at 9:23

the parse_qs is what I needed. Thanks. I did not know of that.

– Whodini
Nov 23 '18 at 9:32

add a comment |

At first, you need to convert the string (here, as the example, to the array, but you can use that you want)

data = [x.split('=') for x in data.split('&')]

>>> data

[['a', '123'], ['b', '345'], ['c', '678'], ['d', '910']]

And after this, you can easily create the dictionary.

dict = {key: value for (key,value) in data}

>>> dict

{'a': '123', 'c': '678', 'b': '345', 'd': '910'}

Or if you want to store numbers as int:

dict = {key: int(value) for (key,value) in data}

>>> dict

{'a': 123, 'c': 678, 'b': 345, 'd': 910}

edited Nov 23 '18 at 9:19

tripleee

95.5k13133189

answered Nov 23 '18 at 9:18

Ihor Voronin

1857

add a comment |

import json

from urllib.parse import parse_qs



payload = request.body

# b'a=123&b=345&c=678&d=910'



qs = parse_qs(payload.decode())

# {'a': ['123'], 'b': ['345'], 'c': ['678'], 'd': ['910']}

Convert list values and convert data into JSON

json.dumps({k: v[0] for k, v in qs.items()})

# '{"a": "123", "b": "345", "c": "678", "d": "910"}'

edited Nov 23 '18 at 10:42

answered Nov 23 '18 at 9:13

vczm

555

2

An explanation, what the posted code does and how this addresses the problem in the question, rarely fails to improve an answer.

– blue-phoenox
Nov 23 '18 at 9:35

add a comment |

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3 Answers
3

active

oldest

votes

3 Answers
3

active

oldest

votes

There's a few errors here.

First off, dumping to JSON and then loading it again does absolutely nothing (it does have a few side-effects, but that's not important here).

Secondly, and mainly, your input data isn't JSON - it's either a query string or, more likely, form-data.

You can try to parse it using the standard parse_qs in urllib.parse, but if that fails you'll have to look around for a library that can handle proper form data.

In [1]: from urllib.parse import parse_qs



In [2]: payload = b'a=123&b=345&c=678&d=910'



In [3]: dataform = payload.decode('utf-8').replace("'", '"')



In [4]: result = parse_qs(dataform)



In [5]: print(result)

{'a': ['123'], 'b': ['345'], 'c': ['678'], 'd': ['910']}

answered Nov 23 '18 at 9:19

Raniz

8,52112356

1

The .replace() part is superfluous. Also in python2, you should do from urlparse import parse_qs.

– SMir
Nov 23 '18 at 9:23

the parse_qs is what I needed. Thanks. I did not know of that.

– Whodini
Nov 23 '18 at 9:32

add a comment |

There's a few errors here.

First off, dumping to JSON and then loading it again does absolutely nothing (it does have a few side-effects, but that's not important here).

Secondly, and mainly, your input data isn't JSON - it's either a query string or, more likely, form-data.

You can try to parse it using the standard parse_qs in urllib.parse, but if that fails you'll have to look around for a library that can handle proper form data.

In [1]: from urllib.parse import parse_qs



In [2]: payload = b'a=123&b=345&c=678&d=910'



In [3]: dataform = payload.decode('utf-8').replace("'", '"')



In [4]: result = parse_qs(dataform)



In [5]: print(result)

{'a': ['123'], 'b': ['345'], 'c': ['678'], 'd': ['910']}

answered Nov 23 '18 at 9:19

Raniz

8,52112356

1

The .replace() part is superfluous. Also in python2, you should do from urlparse import parse_qs.

– SMir
Nov 23 '18 at 9:23

the parse_qs is what I needed. Thanks. I did not know of that.

– Whodini
Nov 23 '18 at 9:32

add a comment |

There's a few errors here.

First off, dumping to JSON and then loading it again does absolutely nothing (it does have a few side-effects, but that's not important here).

Secondly, and mainly, your input data isn't JSON - it's either a query string or, more likely, form-data.

You can try to parse it using the standard parse_qs in urllib.parse, but if that fails you'll have to look around for a library that can handle proper form data.

In [1]: from urllib.parse import parse_qs



In [2]: payload = b'a=123&b=345&c=678&d=910'



In [3]: dataform = payload.decode('utf-8').replace("'", '"')



In [4]: result = parse_qs(dataform)



In [5]: print(result)

{'a': ['123'], 'b': ['345'], 'c': ['678'], 'd': ['910']}

answered Nov 23 '18 at 9:19

Raniz

8,52112356

There's a few errors here.

First off, dumping to JSON and then loading it again does absolutely nothing (it does have a few side-effects, but that's not important here).

Secondly, and mainly, your input data isn't JSON - it's either a query string or, more likely, form-data.

You can try to parse it using the standard parse_qs in urllib.parse, but if that fails you'll have to look around for a library that can handle proper form data.

In [1]: from urllib.parse import parse_qs



In [2]: payload = b'a=123&b=345&c=678&d=910'



In [3]: dataform = payload.decode('utf-8').replace("'", '"')



In [4]: result = parse_qs(dataform)



In [5]: print(result)

{'a': ['123'], 'b': ['345'], 'c': ['678'], 'd': ['910']}

answered Nov 23 '18 at 9:19

Raniz

8,52112356

answered Nov 23 '18 at 9:19

Raniz

8,52112356

answered Nov 23 '18 at 9:19

Raniz

8,52112356

answered Nov 23 '18 at 9:19

Raniz

8,52112356

1

The .replace() part is superfluous. Also in python2, you should do from urlparse import parse_qs.

– SMir
Nov 23 '18 at 9:23

the parse_qs is what I needed. Thanks. I did not know of that.

– Whodini
Nov 23 '18 at 9:32

add a comment |

1

The .replace() part is superfluous. Also in python2, you should do from urlparse import parse_qs.

– SMir
Nov 23 '18 at 9:23

the parse_qs is what I needed. Thanks. I did not know of that.

– Whodini
Nov 23 '18 at 9:32

The .replace() part is superfluous. Also in python2, you should do from urlparse import parse_qs.

– SMir
Nov 23 '18 at 9:23

the parse_qs is what I needed. Thanks. I did not know of that.

– Whodini
Nov 23 '18 at 9:32

add a comment |

At first, you need to convert the string (here, as the example, to the array, but you can use that you want)

data = [x.split('=') for x in data.split('&')]

>>> data

[['a', '123'], ['b', '345'], ['c', '678'], ['d', '910']]

And after this, you can easily create the dictionary.

dict = {key: value for (key,value) in data}

>>> dict

{'a': '123', 'c': '678', 'b': '345', 'd': '910'}

Or if you want to store numbers as int:

dict = {key: int(value) for (key,value) in data}

>>> dict

{'a': 123, 'c': 678, 'b': 345, 'd': 910}

edited Nov 23 '18 at 9:19

tripleee

95.5k13133189

answered Nov 23 '18 at 9:18

Ihor Voronin

1857

add a comment |

At first, you need to convert the string (here, as the example, to the array, but you can use that you want)

data = [x.split('=') for x in data.split('&')]

>>> data

[['a', '123'], ['b', '345'], ['c', '678'], ['d', '910']]

And after this, you can easily create the dictionary.

dict = {key: value for (key,value) in data}

>>> dict

{'a': '123', 'c': '678', 'b': '345', 'd': '910'}

Or if you want to store numbers as int:

dict = {key: int(value) for (key,value) in data}

>>> dict

{'a': 123, 'c': 678, 'b': 345, 'd': 910}

edited Nov 23 '18 at 9:19

tripleee

95.5k13133189

answered Nov 23 '18 at 9:18

Ihor Voronin

1857

add a comment |

At first, you need to convert the string (here, as the example, to the array, but you can use that you want)

data = [x.split('=') for x in data.split('&')]

>>> data

[['a', '123'], ['b', '345'], ['c', '678'], ['d', '910']]

And after this, you can easily create the dictionary.

dict = {key: value for (key,value) in data}

>>> dict

{'a': '123', 'c': '678', 'b': '345', 'd': '910'}

Or if you want to store numbers as int:

dict = {key: int(value) for (key,value) in data}

>>> dict

{'a': 123, 'c': 678, 'b': 345, 'd': 910}

edited Nov 23 '18 at 9:19

tripleee

95.5k13133189

answered Nov 23 '18 at 9:18

Ihor Voronin

1857

At first, you need to convert the string (here, as the example, to the array, but you can use that you want)

data = [x.split('=') for x in data.split('&')]

>>> data

[['a', '123'], ['b', '345'], ['c', '678'], ['d', '910']]

And after this, you can easily create the dictionary.

dict = {key: value for (key,value) in data}

>>> dict

{'a': '123', 'c': '678', 'b': '345', 'd': '910'}

Or if you want to store numbers as int:

dict = {key: int(value) for (key,value) in data}

>>> dict

{'a': 123, 'c': 678, 'b': 345, 'd': 910}

edited Nov 23 '18 at 9:19

tripleee

95.5k13133189

answered Nov 23 '18 at 9:18

Ihor Voronin

1857

edited Nov 23 '18 at 9:19

tripleee

95.5k13133189

edited Nov 23 '18 at 9:19

tripleee

95.5k13133189

edited Nov 23 '18 at 9:19

tripleee

95.5k13133189

answered Nov 23 '18 at 9:18

Ihor Voronin

1857

answered Nov 23 '18 at 9:18

Ihor Voronin

1857

answered Nov 23 '18 at 9:18

Ihor Voronin

1857

add a comment |

import json

from urllib.parse import parse_qs



payload = request.body

# b'a=123&b=345&c=678&d=910'



qs = parse_qs(payload.decode())

# {'a': ['123'], 'b': ['345'], 'c': ['678'], 'd': ['910']}

Convert list values and convert data into JSON

json.dumps({k: v[0] for k, v in qs.items()})

# '{"a": "123", "b": "345", "c": "678", "d": "910"}'

edited Nov 23 '18 at 10:42

answered Nov 23 '18 at 9:13

vczm

555

2

An explanation, what the posted code does and how this addresses the problem in the question, rarely fails to improve an answer.

– blue-phoenox
Nov 23 '18 at 9:35

add a comment |

import json

from urllib.parse import parse_qs



payload = request.body

# b'a=123&b=345&c=678&d=910'



qs = parse_qs(payload.decode())

# {'a': ['123'], 'b': ['345'], 'c': ['678'], 'd': ['910']}

Convert list values and convert data into JSON

json.dumps({k: v[0] for k, v in qs.items()})

# '{"a": "123", "b": "345", "c": "678", "d": "910"}'

edited Nov 23 '18 at 10:42

answered Nov 23 '18 at 9:13

vczm

555

2

An explanation, what the posted code does and how this addresses the problem in the question, rarely fails to improve an answer.

– blue-phoenox
Nov 23 '18 at 9:35

add a comment |

import json

from urllib.parse import parse_qs



payload = request.body

# b'a=123&b=345&c=678&d=910'



qs = parse_qs(payload.decode())

# {'a': ['123'], 'b': ['345'], 'c': ['678'], 'd': ['910']}

Convert list values and convert data into JSON

json.dumps({k: v[0] for k, v in qs.items()})

# '{"a": "123", "b": "345", "c": "678", "d": "910"}'

edited Nov 23 '18 at 10:42

answered Nov 23 '18 at 9:13

vczm

555

import json

from urllib.parse import parse_qs



payload = request.body

# b'a=123&b=345&c=678&d=910'



qs = parse_qs(payload.decode())

# {'a': ['123'], 'b': ['345'], 'c': ['678'], 'd': ['910']}

Convert list values and convert data into JSON

json.dumps({k: v[0] for k, v in qs.items()})

# '{"a": "123", "b": "345", "c": "678", "d": "910"}'

edited Nov 23 '18 at 10:42

answered Nov 23 '18 at 9:13

vczm

555

edited Nov 23 '18 at 10:42

answered Nov 23 '18 at 9:13

vczm

555

answered Nov 23 '18 at 9:13

vczm

555

answered Nov 23 '18 at 9:13

vczm

555

2

An explanation, what the posted code does and how this addresses the problem in the question, rarely fails to improve an answer.

– blue-phoenox
Nov 23 '18 at 9:35

add a comment |

2

An explanation, what the posted code does and how this addresses the problem in the question, rarely fails to improve an answer.

– blue-phoenox
Nov 23 '18 at 9:35

An explanation, what the posted code does and how this addresses the problem in the question, rarely fails to improve an answer.

– blue-phoenox
Nov 23 '18 at 9:35

add a comment |

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