C# Reflection Expression Linq












3















I'm having some problems with C# dynamic generated lambda expressions.



Considering the following scenario:



public class Person {
public long Id { get; set; }
public string Name { get; set; }
}

List<Person> persons = new List<Person> () {
new Person { Id = 1, Name = "Foo" },
new Person { Id = 2, Name = "Bar" },
new Person { Id = 3, Name = "Baz" },
new Person { Id = 4, Name = null },
};


Now, doing the follow code



ParameterExpression param = Expression.Parameter(typeof(Person), "arg");
Expression prop = Expression.Property(param, "Name");
Expression value = Expression.Constant("bar");
Type type = prop.Type;

MethodInfo toLower = typeof(String).GetMethod("ToLower", Type.EmptyTypes);
Expression expLower = Expression.Call(prop, toLower);

Expression clausule = Expression.Call(expLower, type.GetMethod("Contains", new { type }), value);
Expression notNull = Expression.NotEqual(prop, Expression.Constant(null));

clausule = Expression.And(notNull, clausule);

var exp = Expression.Lambda<Func<T, bool>>(clausule, param);


The above code generate the following exp.



//arg => ((arg.Name != null) And (arg.Name.ToLower().Contains("bar")))


Now, trying to apply that to my list.



The filter below works



var filteredListThatWorks = persons.Where(arg => arg.Name != null && arg.Name.ToLower().Contains("bar")).ToList();


The one below throws exception of Null object ( because of Id 4 name)



var filteredListThatGivesExp = persons.Where(exp.Compile()).ToList();


The same expression, when generated by lambda, throws exp, when manually inputed, works.
Anyone knows a way to solve that ?



Br,










share|improve this question


















  • 1





    also keep in mind - when you use var filteredListThatGivesExp = persons.Where(exp.Compile()).ToList();, that is being compiled to a delegate, not an expression tree; if you want truly equivalent code, you should perhaps use persons.AsQueryable().Where(...), which forces it to use the expression-tree API

    – Marc Gravell
    Nov 23 '18 at 10:49
















3















I'm having some problems with C# dynamic generated lambda expressions.



Considering the following scenario:



public class Person {
public long Id { get; set; }
public string Name { get; set; }
}

List<Person> persons = new List<Person> () {
new Person { Id = 1, Name = "Foo" },
new Person { Id = 2, Name = "Bar" },
new Person { Id = 3, Name = "Baz" },
new Person { Id = 4, Name = null },
};


Now, doing the follow code



ParameterExpression param = Expression.Parameter(typeof(Person), "arg");
Expression prop = Expression.Property(param, "Name");
Expression value = Expression.Constant("bar");
Type type = prop.Type;

MethodInfo toLower = typeof(String).GetMethod("ToLower", Type.EmptyTypes);
Expression expLower = Expression.Call(prop, toLower);

Expression clausule = Expression.Call(expLower, type.GetMethod("Contains", new { type }), value);
Expression notNull = Expression.NotEqual(prop, Expression.Constant(null));

clausule = Expression.And(notNull, clausule);

var exp = Expression.Lambda<Func<T, bool>>(clausule, param);


The above code generate the following exp.



//arg => ((arg.Name != null) And (arg.Name.ToLower().Contains("bar")))


Now, trying to apply that to my list.



The filter below works



var filteredListThatWorks = persons.Where(arg => arg.Name != null && arg.Name.ToLower().Contains("bar")).ToList();


The one below throws exception of Null object ( because of Id 4 name)



var filteredListThatGivesExp = persons.Where(exp.Compile()).ToList();


The same expression, when generated by lambda, throws exp, when manually inputed, works.
Anyone knows a way to solve that ?



Br,










share|improve this question


















  • 1





    also keep in mind - when you use var filteredListThatGivesExp = persons.Where(exp.Compile()).ToList();, that is being compiled to a delegate, not an expression tree; if you want truly equivalent code, you should perhaps use persons.AsQueryable().Where(...), which forces it to use the expression-tree API

    – Marc Gravell
    Nov 23 '18 at 10:49














3












3








3








I'm having some problems with C# dynamic generated lambda expressions.



Considering the following scenario:



public class Person {
public long Id { get; set; }
public string Name { get; set; }
}

List<Person> persons = new List<Person> () {
new Person { Id = 1, Name = "Foo" },
new Person { Id = 2, Name = "Bar" },
new Person { Id = 3, Name = "Baz" },
new Person { Id = 4, Name = null },
};


Now, doing the follow code



ParameterExpression param = Expression.Parameter(typeof(Person), "arg");
Expression prop = Expression.Property(param, "Name");
Expression value = Expression.Constant("bar");
Type type = prop.Type;

MethodInfo toLower = typeof(String).GetMethod("ToLower", Type.EmptyTypes);
Expression expLower = Expression.Call(prop, toLower);

Expression clausule = Expression.Call(expLower, type.GetMethod("Contains", new { type }), value);
Expression notNull = Expression.NotEqual(prop, Expression.Constant(null));

clausule = Expression.And(notNull, clausule);

var exp = Expression.Lambda<Func<T, bool>>(clausule, param);


The above code generate the following exp.



//arg => ((arg.Name != null) And (arg.Name.ToLower().Contains("bar")))


Now, trying to apply that to my list.



The filter below works



var filteredListThatWorks = persons.Where(arg => arg.Name != null && arg.Name.ToLower().Contains("bar")).ToList();


The one below throws exception of Null object ( because of Id 4 name)



var filteredListThatGivesExp = persons.Where(exp.Compile()).ToList();


The same expression, when generated by lambda, throws exp, when manually inputed, works.
Anyone knows a way to solve that ?



Br,










share|improve this question














I'm having some problems with C# dynamic generated lambda expressions.



Considering the following scenario:



public class Person {
public long Id { get; set; }
public string Name { get; set; }
}

List<Person> persons = new List<Person> () {
new Person { Id = 1, Name = "Foo" },
new Person { Id = 2, Name = "Bar" },
new Person { Id = 3, Name = "Baz" },
new Person { Id = 4, Name = null },
};


Now, doing the follow code



ParameterExpression param = Expression.Parameter(typeof(Person), "arg");
Expression prop = Expression.Property(param, "Name");
Expression value = Expression.Constant("bar");
Type type = prop.Type;

MethodInfo toLower = typeof(String).GetMethod("ToLower", Type.EmptyTypes);
Expression expLower = Expression.Call(prop, toLower);

Expression clausule = Expression.Call(expLower, type.GetMethod("Contains", new { type }), value);
Expression notNull = Expression.NotEqual(prop, Expression.Constant(null));

clausule = Expression.And(notNull, clausule);

var exp = Expression.Lambda<Func<T, bool>>(clausule, param);


The above code generate the following exp.



//arg => ((arg.Name != null) And (arg.Name.ToLower().Contains("bar")))


Now, trying to apply that to my list.



The filter below works



var filteredListThatWorks = persons.Where(arg => arg.Name != null && arg.Name.ToLower().Contains("bar")).ToList();


The one below throws exception of Null object ( because of Id 4 name)



var filteredListThatGivesExp = persons.Where(exp.Compile()).ToList();


The same expression, when generated by lambda, throws exp, when manually inputed, works.
Anyone knows a way to solve that ?



Br,







c# lambda reflection






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 23 '18 at 10:38









Lucas FreitasLucas Freitas

4502928




4502928








  • 1





    also keep in mind - when you use var filteredListThatGivesExp = persons.Where(exp.Compile()).ToList();, that is being compiled to a delegate, not an expression tree; if you want truly equivalent code, you should perhaps use persons.AsQueryable().Where(...), which forces it to use the expression-tree API

    – Marc Gravell
    Nov 23 '18 at 10:49














  • 1





    also keep in mind - when you use var filteredListThatGivesExp = persons.Where(exp.Compile()).ToList();, that is being compiled to a delegate, not an expression tree; if you want truly equivalent code, you should perhaps use persons.AsQueryable().Where(...), which forces it to use the expression-tree API

    – Marc Gravell
    Nov 23 '18 at 10:49








1




1





also keep in mind - when you use var filteredListThatGivesExp = persons.Where(exp.Compile()).ToList();, that is being compiled to a delegate, not an expression tree; if you want truly equivalent code, you should perhaps use persons.AsQueryable().Where(...), which forces it to use the expression-tree API

– Marc Gravell
Nov 23 '18 at 10:49





also keep in mind - when you use var filteredListThatGivesExp = persons.Where(exp.Compile()).ToList();, that is being compiled to a delegate, not an expression tree; if you want truly equivalent code, you should perhaps use persons.AsQueryable().Where(...), which forces it to use the expression-tree API

– Marc Gravell
Nov 23 '18 at 10:49












1 Answer
1






active

oldest

votes


















6














And is &; you want to use AndAlso (&&):



clausule = Expression.AndAlso(notNull, clausule);


When in doubt, sharplab.io is an excellent tool here; if I use:



Expression<Func<Person, bool>> filter
= arg => arg.Name != null && arg.Name.ToLower().Contains("bar");


it tells me that it compiles to be equivalent to:



// ...
BinaryExpression body = Expression.AndAlso(left, Expression.Call(instance, method, obj));
// ...


(note that it has to lie about some of the instructions though, as it compiles to things that can't actually be expressed in raw C#)



see it in action






share|improve this answer
























  • You deserve a cookie Sir! 4 more mins to mark as Correct. Thank you very much

    – Lucas Freitas
    Nov 23 '18 at 10:49












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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









6














And is &; you want to use AndAlso (&&):



clausule = Expression.AndAlso(notNull, clausule);


When in doubt, sharplab.io is an excellent tool here; if I use:



Expression<Func<Person, bool>> filter
= arg => arg.Name != null && arg.Name.ToLower().Contains("bar");


it tells me that it compiles to be equivalent to:



// ...
BinaryExpression body = Expression.AndAlso(left, Expression.Call(instance, method, obj));
// ...


(note that it has to lie about some of the instructions though, as it compiles to things that can't actually be expressed in raw C#)



see it in action






share|improve this answer
























  • You deserve a cookie Sir! 4 more mins to mark as Correct. Thank you very much

    – Lucas Freitas
    Nov 23 '18 at 10:49
















6














And is &; you want to use AndAlso (&&):



clausule = Expression.AndAlso(notNull, clausule);


When in doubt, sharplab.io is an excellent tool here; if I use:



Expression<Func<Person, bool>> filter
= arg => arg.Name != null && arg.Name.ToLower().Contains("bar");


it tells me that it compiles to be equivalent to:



// ...
BinaryExpression body = Expression.AndAlso(left, Expression.Call(instance, method, obj));
// ...


(note that it has to lie about some of the instructions though, as it compiles to things that can't actually be expressed in raw C#)



see it in action






share|improve this answer
























  • You deserve a cookie Sir! 4 more mins to mark as Correct. Thank you very much

    – Lucas Freitas
    Nov 23 '18 at 10:49














6












6








6







And is &; you want to use AndAlso (&&):



clausule = Expression.AndAlso(notNull, clausule);


When in doubt, sharplab.io is an excellent tool here; if I use:



Expression<Func<Person, bool>> filter
= arg => arg.Name != null && arg.Name.ToLower().Contains("bar");


it tells me that it compiles to be equivalent to:



// ...
BinaryExpression body = Expression.AndAlso(left, Expression.Call(instance, method, obj));
// ...


(note that it has to lie about some of the instructions though, as it compiles to things that can't actually be expressed in raw C#)



see it in action






share|improve this answer













And is &; you want to use AndAlso (&&):



clausule = Expression.AndAlso(notNull, clausule);


When in doubt, sharplab.io is an excellent tool here; if I use:



Expression<Func<Person, bool>> filter
= arg => arg.Name != null && arg.Name.ToLower().Contains("bar");


it tells me that it compiles to be equivalent to:



// ...
BinaryExpression body = Expression.AndAlso(left, Expression.Call(instance, method, obj));
// ...


(note that it has to lie about some of the instructions though, as it compiles to things that can't actually be expressed in raw C#)



see it in action







share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 23 '18 at 10:43









Marc GravellMarc Gravell

793k19821612565




793k19821612565













  • You deserve a cookie Sir! 4 more mins to mark as Correct. Thank you very much

    – Lucas Freitas
    Nov 23 '18 at 10:49



















  • You deserve a cookie Sir! 4 more mins to mark as Correct. Thank you very much

    – Lucas Freitas
    Nov 23 '18 at 10:49

















You deserve a cookie Sir! 4 more mins to mark as Correct. Thank you very much

– Lucas Freitas
Nov 23 '18 at 10:49





You deserve a cookie Sir! 4 more mins to mark as Correct. Thank you very much

– Lucas Freitas
Nov 23 '18 at 10:49




















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