Busybox filter string list

Consider I have a list like this:

list='item1.service item2.service item3.target item4.service'

I need to filter this list to get something as:

item1 item2 item4

So, there are two things to notice:

I need keep only the .service items.

I need only the "base" names, without the .service suffix.

And one more important information: I am running on busybox, where tools are often crippled (e.g.: my grep has no support for Perl regexes).

I have been struggling against combinations of sed and grep and the best I could get is:

$ echo $list | grep -io '[a-z0-9-_@]*.service' | sed 's/.service//'

item1

item2

item4

but it needs to perform essentially the same match twice for each input, what doesn't look very efficient.
Could anyone suggest any better solution, please?

Thanks in advance.

asked Dec 11 at 16:06

j4x

1054

What does this have to do with Busybox?
– JakeGould
Dec 11 at 16:38

sed does all the job echo "$list"|sed -r 's/[a-z0-9@_-]+.target//;s/ +/ /g;s/ /n/g'. This works in BusyBox 1.2.1, very old.
– Paulo
Dec 11 at 23:27

Thanks @Paulo for your response. Unfortunatelly, sed doesn't remove the suffix and the generate output is item1.service instead of simply item1 as I need.
– j4x
Dec 12 at 8:03

1

@j4x The sed you posted has the command to cut the suffix, just append it to sed script sed -r 's/[a-z0-9@_-]+.target//;s/.service//g;s/ +/ /g;s/ /n/g'. g flag is needed to replace all matches, without it sed will replace only the first match.
– Paulo
Dec 12 at 11:52

Good. IT is devilish to understand but works! @Paulo, please post an answer so I can mark it. Thanks!
– j4x
Dec 12 at 12:13

add a comment |

Consider I have a list like this:

list='item1.service item2.service item3.target item4.service'

I need to filter this list to get something as:

item1 item2 item4

So, there are two things to notice:

I need keep only the .service items.

I need only the "base" names, without the .service suffix.

And one more important information: I am running on busybox, where tools are often crippled (e.g.: my grep has no support for Perl regexes).

I have been struggling against combinations of sed and grep and the best I could get is:

$ echo $list | grep -io '[a-z0-9-_@]*.service' | sed 's/.service//'

item1

item2

item4

but it needs to perform essentially the same match twice for each input, what doesn't look very efficient.
Could anyone suggest any better solution, please?

Thanks in advance.

asked Dec 11 at 16:06

j4x

1054

What does this have to do with Busybox?
– JakeGould
Dec 11 at 16:38

sed does all the job echo "$list"|sed -r 's/[a-z0-9@_-]+.target//;s/ +/ /g;s/ /n/g'. This works in BusyBox 1.2.1, very old.
– Paulo
Dec 11 at 23:27

Thanks @Paulo for your response. Unfortunatelly, sed doesn't remove the suffix and the generate output is item1.service instead of simply item1 as I need.
– j4x
Dec 12 at 8:03

1

@j4x The sed you posted has the command to cut the suffix, just append it to sed script sed -r 's/[a-z0-9@_-]+.target//;s/.service//g;s/ +/ /g;s/ /n/g'. g flag is needed to replace all matches, without it sed will replace only the first match.
– Paulo
Dec 12 at 11:52

Good. IT is devilish to understand but works! @Paulo, please post an answer so I can mark it. Thanks!
– j4x
Dec 12 at 12:13

add a comment |

Consider I have a list like this:

list='item1.service item2.service item3.target item4.service'

I need to filter this list to get something as:

item1 item2 item4

So, there are two things to notice:

I need keep only the .service items.

I need only the "base" names, without the .service suffix.

And one more important information: I am running on busybox, where tools are often crippled (e.g.: my grep has no support for Perl regexes).

I have been struggling against combinations of sed and grep and the best I could get is:

$ echo $list | grep -io '[a-z0-9-_@]*.service' | sed 's/.service//'

item1

item2

item4

but it needs to perform essentially the same match twice for each input, what doesn't look very efficient.
Could anyone suggest any better solution, please?

Thanks in advance.

asked Dec 11 at 16:06

j4x

1054

Consider I have a list like this:

list='item1.service item2.service item3.target item4.service'

I need to filter this list to get something as:

item1 item2 item4

So, there are two things to notice:

I need keep only the .service items.

I need only the "base" names, without the .service suffix.

And one more important information: I am running on busybox, where tools are often crippled (e.g.: my grep has no support for Perl regexes).

I have been struggling against combinations of sed and grep and the best I could get is:

$ echo $list | grep -io '[a-z0-9-_@]*.service' | sed 's/.service//'

item1

item2

item4

but it needs to perform essentially the same match twice for each input, what doesn't look very efficient.
Could anyone suggest any better solution, please?

Thanks in advance.

regex string-manipulation busybox

asked Dec 11 at 16:06

j4x

1054

asked Dec 11 at 16:06

j4x

1054

asked Dec 11 at 16:06

j4x

1054

asked Dec 11 at 16:06

j4x

1054

asked Dec 11 at 16:06

j4x

1054

What does this have to do with Busybox?
– JakeGould
Dec 11 at 16:38

sed does all the job echo "$list"|sed -r 's/[a-z0-9@_-]+.target//;s/ +/ /g;s/ /n/g'. This works in BusyBox 1.2.1, very old.
– Paulo
Dec 11 at 23:27

Thanks @Paulo for your response. Unfortunatelly, sed doesn't remove the suffix and the generate output is item1.service instead of simply item1 as I need.
– j4x
Dec 12 at 8:03

1

@j4x The sed you posted has the command to cut the suffix, just append it to sed script sed -r 's/[a-z0-9@_-]+.target//;s/.service//g;s/ +/ /g;s/ /n/g'. g flag is needed to replace all matches, without it sed will replace only the first match.
– Paulo
Dec 12 at 11:52

Good. IT is devilish to understand but works! @Paulo, please post an answer so I can mark it. Thanks!
– j4x
Dec 12 at 12:13

add a comment |

What does this have to do with Busybox?
– JakeGould
Dec 11 at 16:38

sed does all the job echo "$list"|sed -r 's/[a-z0-9@_-]+.target//;s/ +/ /g;s/ /n/g'. This works in BusyBox 1.2.1, very old.
– Paulo
Dec 11 at 23:27

Thanks @Paulo for your response. Unfortunatelly, sed doesn't remove the suffix and the generate output is item1.service instead of simply item1 as I need.
– j4x
Dec 12 at 8:03

1

@j4x The sed you posted has the command to cut the suffix, just append it to sed script sed -r 's/[a-z0-9@_-]+.target//;s/.service//g;s/ +/ /g;s/ /n/g'. g flag is needed to replace all matches, without it sed will replace only the first match.
– Paulo
Dec 12 at 11:52

Good. IT is devilish to understand but works! @Paulo, please post an answer so I can mark it. Thanks!
– j4x
Dec 12 at 12:13

What does this have to do with Busybox?
– JakeGould
Dec 11 at 16:38

sed does all the job echo "$list"|sed -r 's/[a-z0-9@_-]+.target//;s/ +/ /g;s/ /n/g'. This works in BusyBox 1.2.1, very old.
– Paulo
Dec 11 at 23:27

Thanks @Paulo for your response. Unfortunatelly, sed doesn't remove the suffix and the generate output is item1.service instead of simply item1 as I need.
– j4x
Dec 12 at 8:03

@j4x The sed you posted has the command to cut the suffix, just append it to sed script sed -r 's/[a-z0-9@_-]+.target//;s/.service//g;s/ +/ /g;s/ /n/g'. g flag is needed to replace all matches, without it sed will replace only the first match.
– Paulo
Dec 12 at 11:52

Good. IT is devilish to understand but works! @Paulo, please post an answer so I can mark it. Thanks!
– j4x
Dec 12 at 12:13

add a comment |

1 Answer
1

active

oldest

votes

list='item1.service item2.service item3.target item4.service'

echo "$list" | sed -r '



# Since the input is only one line, all commands will scan all the pattern space,

# so the commands order matters.



# replace for nothing unwanted text

s/[a-z0-9@_-]+.target//



# replace for nothing unwanted suffix

# (with 'g' flag the command will replace all occurrences)

s/.service//g



# squeeze double spaces

s/ +/ /g



# replace space for new line character

s/ /n/g'

I think this will work in all versions of BusyBox's sed (could be awk too if you have it in your BusyBox).

I just downloaded the latest BusyBox version and ran make menuconfig but couldn't
find any reference to Perl regex.

answered Dec 12 at 14:09

Paulo

52928

add a comment |

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list='item1.service item2.service item3.target item4.service'

echo "$list" | sed -r '



# Since the input is only one line, all commands will scan all the pattern space,

# so the commands order matters.



# replace for nothing unwanted text

s/[a-z0-9@_-]+.target//



# replace for nothing unwanted suffix

# (with 'g' flag the command will replace all occurrences)

s/.service//g



# squeeze double spaces

s/ +/ /g



# replace space for new line character

s/ /n/g'

I think this will work in all versions of BusyBox's sed (could be awk too if you have it in your BusyBox).

I just downloaded the latest BusyBox version and ran make menuconfig but couldn't
find any reference to Perl regex.

answered Dec 12 at 14:09

Paulo

52928

add a comment |

list='item1.service item2.service item3.target item4.service'

echo "$list" | sed -r '



# Since the input is only one line, all commands will scan all the pattern space,

# so the commands order matters.



# replace for nothing unwanted text

s/[a-z0-9@_-]+.target//



# replace for nothing unwanted suffix

# (with 'g' flag the command will replace all occurrences)

s/.service//g



# squeeze double spaces

s/ +/ /g



# replace space for new line character

s/ /n/g'

I think this will work in all versions of BusyBox's sed (could be awk too if you have it in your BusyBox).

I just downloaded the latest BusyBox version and ran make menuconfig but couldn't
find any reference to Perl regex.

answered Dec 12 at 14:09

Paulo

52928

add a comment |

list='item1.service item2.service item3.target item4.service'

echo "$list" | sed -r '



# Since the input is only one line, all commands will scan all the pattern space,

# so the commands order matters.



# replace for nothing unwanted text

s/[a-z0-9@_-]+.target//



# replace for nothing unwanted suffix

# (with 'g' flag the command will replace all occurrences)

s/.service//g



# squeeze double spaces

s/ +/ /g



# replace space for new line character

s/ /n/g'

I think this will work in all versions of BusyBox's sed (could be awk too if you have it in your BusyBox).

I just downloaded the latest BusyBox version and ran make menuconfig but couldn't
find any reference to Perl regex.

answered Dec 12 at 14:09

Paulo

52928

list='item1.service item2.service item3.target item4.service'

echo "$list" | sed -r '



# Since the input is only one line, all commands will scan all the pattern space,

# so the commands order matters.



# replace for nothing unwanted text

s/[a-z0-9@_-]+.target//



# replace for nothing unwanted suffix

# (with 'g' flag the command will replace all occurrences)

s/.service//g



# squeeze double spaces

s/ +/ /g



# replace space for new line character

s/ /n/g'

I think this will work in all versions of BusyBox's sed (could be awk too if you have it in your BusyBox).

I just downloaded the latest BusyBox version and ran make menuconfig but couldn't
find any reference to Perl regex.

answered Dec 12 at 14:09

Paulo

52928

answered Dec 12 at 14:09

Paulo

52928

answered Dec 12 at 14:09

Paulo

52928

answered Dec 12 at 14:09

Paulo

52928

add a comment |

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