Use the Output as the New Input into Matlab Function block in Simulink
I have three inputs into a Matlab Function block in my Simulink Model. The inputs consist of a 1D array thetaArray and two variables currentIndex and trackingError. The Matlab Function block will output two variables called newIndex and theta.
What would be an ideal way to use the newIndex variable as my new input into the Matlab Function block?
Here is the image of my Simulink Model
And here is the code for the Matlab Function Block in the model:
function [newIndex,theta] = arraySelector(thetaArray,currentIndex,trackingError)
if currentIndex < length(thetaArray) && trackingError <= 0.00002
newIndex = currentIndex + 1;
else
newIndex = currentIndex;
end
theta = thetaArray(newIndex);
end
Thank you in advance.
matlab simulink
asked Nov 20 at 7:35
dekaranger00
61
add a comment |
I have three inputs into a Matlab Function block in my Simulink Model. The inputs consist of a 1D array thetaArray and two variables currentIndex and trackingError. The Matlab Function block will output two variables called newIndex and theta.
What would be an ideal way to use the newIndex variable as my new input into the Matlab Function block?
Here is the image of my Simulink Model
And here is the code for the Matlab Function Block in the model:
function [newIndex,theta] = arraySelector(thetaArray,currentIndex,trackingError)
if currentIndex < length(thetaArray) && trackingError <= 0.00002
newIndex = currentIndex + 1;
else
newIndex = currentIndex;
end
theta = thetaArray(newIndex);
end
Thank you in advance.
matlab simulink
asked Nov 20 at 7:35
dekaranger00
61
3
Send it back through a unit delay block.
– Navan
Nov 20 at 13:15
add a comment |
I have three inputs into a Matlab Function block in my Simulink Model. The inputs consist of a 1D array thetaArray and two variables currentIndex and trackingError. The Matlab Function block will output two variables called newIndex and theta.
What would be an ideal way to use the newIndex variable as my new input into the Matlab Function block?
Here is the image of my Simulink Model
And here is the code for the Matlab Function Block in the model:
function [newIndex,theta] = arraySelector(thetaArray,currentIndex,trackingError)
if currentIndex < length(thetaArray) && trackingError <= 0.00002
newIndex = currentIndex + 1;
else
newIndex = currentIndex;
end
theta = thetaArray(newIndex);
end
Thank you in advance.
matlab simulink
asked Nov 20 at 7:35
dekaranger00
61
I have three inputs into a Matlab Function block in my Simulink Model. The inputs consist of a 1D array thetaArray and two variables currentIndex and trackingError. The Matlab Function block will output two variables called newIndex and theta.
What would be an ideal way to use the newIndex variable as my new input into the Matlab Function block?
Here is the image of my Simulink Model
And here is the code for the Matlab Function Block in the model:
function [newIndex,theta] = arraySelector(thetaArray,currentIndex,trackingError)
if currentIndex < length(thetaArray) && trackingError <= 0.00002
newIndex = currentIndex + 1;
else
newIndex = currentIndex;
end
theta = thetaArray(newIndex);
end
Thank you in advance.
matlab simulink
matlab simulink
asked Nov 20 at 7:35
dekaranger00
61
asked Nov 20 at 7:35
dekaranger00
61
asked Nov 20 at 7:35
dekaranger00
61
asked Nov 20 at 7:35
dekaranger00
61
asked Nov 20 at 7:35
dekaranger00
61
61
3
Send it back through a unit delay block.
– Navan
Nov 20 at 13:15
add a comment |
3
Send it back through a unit delay block.
– Navan
Nov 20 at 13:15
3
3
Send it back through a unit delay block.
– Navan
Nov 20 at 13:15
Send it back through a unit delay block.
– Navan
Nov 20 at 13:15
add a comment |
1 Answer
1
active
oldest
votes
If theta will be the output and the input of the model you will have a model which contains an
algebraic loop.
It is unclear from your question if you
- need to solve the algebraic loop within a single time step OR
- you want your model advance in time with each iteration of the loop.
For 2nd case:
This is the easier case. (more likely when studying your model). Here you will break the loop e.g. by introducing a delay block. The initial condition of the delay block will be what you have now defined in the example (block theta_1).
For 1st case:
Follow the description in How to Handle Algebraic Loops in a Model. I would recommend that you first study with an example where you use a scalar instead of an array. You need to define the initial condition for the index, e.g. by introducing an IC-Block (like you did for the trackingerror) into the loop. If simulink is still unable to solve the algebraic loop consider an alternative implementation inside your Matlab Function Block which changes the status of your input .
from direct feedthrough to non-direct feedthrough
answered Nov 21 at 14:12
ToBe
4041418
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
If theta will be the output and the input of the model you will have a model which contains an
algebraic loop.
It is unclear from your question if you
- need to solve the algebraic loop within a single time step OR
- you want your model advance in time with each iteration of the loop.
For 2nd case:
This is the easier case. (more likely when studying your model). Here you will break the loop e.g. by introducing a delay block. The initial condition of the delay block will be what you have now defined in the example (block theta_1).
For 1st case:
Follow the description in How to Handle Algebraic Loops in a Model. I would recommend that you first study with an example where you use a scalar instead of an array. You need to define the initial condition for the index, e.g. by introducing an IC-Block (like you did for the trackingerror) into the loop. If simulink is still unable to solve the algebraic loop consider an alternative implementation inside your Matlab Function Block which changes the status of your input .
from direct feedthrough to non-direct feedthrough
answered Nov 21 at 14:12
ToBe
4041418
add a comment |
If theta will be the output and the input of the model you will have a model which contains an
algebraic loop.
It is unclear from your question if you
- need to solve the algebraic loop within a single time step OR
- you want your model advance in time with each iteration of the loop.
For 2nd case:
This is the easier case. (more likely when studying your model). Here you will break the loop e.g. by introducing a delay block. The initial condition of the delay block will be what you have now defined in the example (block theta_1).
For 1st case:
Follow the description in How to Handle Algebraic Loops in a Model. I would recommend that you first study with an example where you use a scalar instead of an array. You need to define the initial condition for the index, e.g. by introducing an IC-Block (like you did for the trackingerror) into the loop. If simulink is still unable to solve the algebraic loop consider an alternative implementation inside your Matlab Function Block which changes the status of your input .
from direct feedthrough to non-direct feedthrough
answered Nov 21 at 14:12
ToBe
4041418
add a comment |
If theta will be the output and the input of the model you will have a model which contains an
algebraic loop.
It is unclear from your question if you
- need to solve the algebraic loop within a single time step OR
- you want your model advance in time with each iteration of the loop.
For 2nd case:
This is the easier case. (more likely when studying your model). Here you will break the loop e.g. by introducing a delay block. The initial condition of the delay block will be what you have now defined in the example (block theta_1).
For 1st case:
Follow the description in How to Handle Algebraic Loops in a Model. I would recommend that you first study with an example where you use a scalar instead of an array. You need to define the initial condition for the index, e.g. by introducing an IC-Block (like you did for the trackingerror) into the loop. If simulink is still unable to solve the algebraic loop consider an alternative implementation inside your Matlab Function Block which changes the status of your input .
from direct feedthrough to non-direct feedthrough
answered Nov 21 at 14:12
ToBe
4041418
If theta will be the output and the input of the model you will have a model which contains an
algebraic loop.
It is unclear from your question if you
- need to solve the algebraic loop within a single time step OR
- you want your model advance in time with each iteration of the loop.
For 2nd case:
This is the easier case. (more likely when studying your model). Here you will break the loop e.g. by introducing a delay block. The initial condition of the delay block will be what you have now defined in the example (block theta_1).
For 1st case:
Follow the description in How to Handle Algebraic Loops in a Model. I would recommend that you first study with an example where you use a scalar instead of an array. You need to define the initial condition for the index, e.g. by introducing an IC-Block (like you did for the trackingerror) into the loop. If simulink is still unable to solve the algebraic loop consider an alternative implementation inside your Matlab Function Block which changes the status of your input .
from direct feedthrough to non-direct feedthrough
answered Nov 21 at 14:12
ToBe
4041418
answered Nov 21 at 14:12
ToBe
4041418
answered Nov 21 at 14:12
ToBe
4041418
answered Nov 21 at 14:12
ToBe
4041418
4041418
add a comment |
add a comment |
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3
Send it back through a unit delay block.
– Navan
Nov 20 at 13:15