Why are we able to see air bubbles under water?












17














Title is self explanatory.



I'm assuming both water and air are transparent. (Are these premisses false?)



So, if they are true, how can I clearly distinguish an air bubble under water?



enter image description here



Ps: I don't have a strong scientific background (high school level only), sorry if it's a silly question.










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  • 4




    I would use the term transparent instead of invisible in the question
    – user1936752
    Dec 23 at 20:22








  • 1




    Ironically we can see the water in your picture. Perhaps it has to do with light.
    – KingDuken
    2 days ago






  • 3




    Note that it is the same reason as why we can see water drops in air.
    – Jan Hudec
    2 days ago










  • @user1936752 You're right, thanks
    – ihavenoidea
    yesterday
















17














Title is self explanatory.



I'm assuming both water and air are transparent. (Are these premisses false?)



So, if they are true, how can I clearly distinguish an air bubble under water?



enter image description here



Ps: I don't have a strong scientific background (high school level only), sorry if it's a silly question.










share|cite|improve this question









New contributor




ihavenoidea is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
















  • 4




    I would use the term transparent instead of invisible in the question
    – user1936752
    Dec 23 at 20:22








  • 1




    Ironically we can see the water in your picture. Perhaps it has to do with light.
    – KingDuken
    2 days ago






  • 3




    Note that it is the same reason as why we can see water drops in air.
    – Jan Hudec
    2 days ago










  • @user1936752 You're right, thanks
    – ihavenoidea
    yesterday














17












17








17


2





Title is self explanatory.



I'm assuming both water and air are transparent. (Are these premisses false?)



So, if they are true, how can I clearly distinguish an air bubble under water?



enter image description here



Ps: I don't have a strong scientific background (high school level only), sorry if it's a silly question.










share|cite|improve this question









New contributor




ihavenoidea is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











Title is self explanatory.



I'm assuming both water and air are transparent. (Are these premisses false?)



So, if they are true, how can I clearly distinguish an air bubble under water?



enter image description here



Ps: I don't have a strong scientific background (high school level only), sorry if it's a silly question.







optics water air bubble






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share|cite|improve this question








edited yesterday





















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asked Dec 23 at 19:49









ihavenoidea

916




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  • 4




    I would use the term transparent instead of invisible in the question
    – user1936752
    Dec 23 at 20:22








  • 1




    Ironically we can see the water in your picture. Perhaps it has to do with light.
    – KingDuken
    2 days ago






  • 3




    Note that it is the same reason as why we can see water drops in air.
    – Jan Hudec
    2 days ago










  • @user1936752 You're right, thanks
    – ihavenoidea
    yesterday














  • 4




    I would use the term transparent instead of invisible in the question
    – user1936752
    Dec 23 at 20:22








  • 1




    Ironically we can see the water in your picture. Perhaps it has to do with light.
    – KingDuken
    2 days ago






  • 3




    Note that it is the same reason as why we can see water drops in air.
    – Jan Hudec
    2 days ago










  • @user1936752 You're right, thanks
    – ihavenoidea
    yesterday








4




4




I would use the term transparent instead of invisible in the question
– user1936752
Dec 23 at 20:22






I would use the term transparent instead of invisible in the question
– user1936752
Dec 23 at 20:22






1




1




Ironically we can see the water in your picture. Perhaps it has to do with light.
– KingDuken
2 days ago




Ironically we can see the water in your picture. Perhaps it has to do with light.
– KingDuken
2 days ago




3




3




Note that it is the same reason as why we can see water drops in air.
– Jan Hudec
2 days ago




Note that it is the same reason as why we can see water drops in air.
– Jan Hudec
2 days ago












@user1936752 You're right, thanks
– ihavenoidea
yesterday




@user1936752 You're right, thanks
– ihavenoidea
yesterday










4 Answers
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active

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30














Air and water are both transparent to a good enough approximation. However, light travels more slowly in water: the speed of light in air is about 33% faster than in water. As a result, when light passes from one medium to the other, it is partly reflected and partly refracted (bent). For the refracted part, the general rule for determining the bending angle is called Snell's law, which can be expressed like this:
$$
frac{sintheta_text{w}}{sintheta_text{a}}=frac{v_text{w}}{v_text{a}}
approx frac{1}{1.33}
tag{1}
$$

where $v_text{w}$ and $v_text{a}$ are the speed of light in water and air, respectively, and where $theta_text{w}$ and $theta_text{a}$ are the angles of the light ray relative to a line perpendicular to the surface, on the water side and on the air side, respectively.



If the angle on the water side is $theta_text{w} gtrsim 49^circ$, then equation (1) does not have any solution: there is no air-side angle $theta_text{a}$ that satisfies the equation. In this case, as niels nielsen indicated, light propagating inside the water will be completely reflected at the water-air interface. So the rim of the bubble acts like a mirror: if you do a reverse ray-trace from your eye back to near the rim of an air bubble in the water, the angle between the ray and the line perpendicular to the surface of the bubble will be greater than $49^circ$ (this defines what "near the rim" means), so that part of the bubble acts like a mirror for light coming from those angles, as illustrated here:
enter image description here






share|cite|improve this answer































    12














    You can see light reflected off of the surface of a submerged bubble because the index of refraction of the air inside the bubble is different from that of the water that surrounds the bubble.



    That difference, if great enough, will turn a bubble surface into a mirror for light rays that approach it from certain directions, thereby making it easy to see.



    This condition is easily met for the combination of air and water.



    A google search on "refraction" and "total internal reflection" will furnish more examples of this, and explain the math behind it.






    share|cite|improve this answer

















    • 1




      You said - "...light propagating inside the water will be completely reflected at the water-air interface" Does this mean that it is completely dark inside an air bubble underwater?
      – MarkTO
      2 days ago










    • No, it means that the bubble will behave like a bent mirror- which is exactly what the bubbles in the picture above look like.
      – niels nielsen
      2 days ago



















    1














    The inside of the bubble is not dark because only the light making a more glancing intersection than 49 degrees is completely reflected. Light that hits near the center of the bubble with respect to the direction it is traveling will be mostly transmitted into the bubble, illuminating the interior.






    share|cite|improve this answer










    New contributor




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      0














      For the exact same reason why you can see rain. Light waves hit it and the direction of propagation(travel) of the wave changes because it goes from one medium to another. Its movement causes the refraction to happen differently making it different from it's surroundings and visible to you.






      share|cite|improve this answer








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        4 Answers
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        active

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        4 Answers
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        30














        Air and water are both transparent to a good enough approximation. However, light travels more slowly in water: the speed of light in air is about 33% faster than in water. As a result, when light passes from one medium to the other, it is partly reflected and partly refracted (bent). For the refracted part, the general rule for determining the bending angle is called Snell's law, which can be expressed like this:
        $$
        frac{sintheta_text{w}}{sintheta_text{a}}=frac{v_text{w}}{v_text{a}}
        approx frac{1}{1.33}
        tag{1}
        $$

        where $v_text{w}$ and $v_text{a}$ are the speed of light in water and air, respectively, and where $theta_text{w}$ and $theta_text{a}$ are the angles of the light ray relative to a line perpendicular to the surface, on the water side and on the air side, respectively.



        If the angle on the water side is $theta_text{w} gtrsim 49^circ$, then equation (1) does not have any solution: there is no air-side angle $theta_text{a}$ that satisfies the equation. In this case, as niels nielsen indicated, light propagating inside the water will be completely reflected at the water-air interface. So the rim of the bubble acts like a mirror: if you do a reverse ray-trace from your eye back to near the rim of an air bubble in the water, the angle between the ray and the line perpendicular to the surface of the bubble will be greater than $49^circ$ (this defines what "near the rim" means), so that part of the bubble acts like a mirror for light coming from those angles, as illustrated here:
        enter image description here






        share|cite|improve this answer




























          30














          Air and water are both transparent to a good enough approximation. However, light travels more slowly in water: the speed of light in air is about 33% faster than in water. As a result, when light passes from one medium to the other, it is partly reflected and partly refracted (bent). For the refracted part, the general rule for determining the bending angle is called Snell's law, which can be expressed like this:
          $$
          frac{sintheta_text{w}}{sintheta_text{a}}=frac{v_text{w}}{v_text{a}}
          approx frac{1}{1.33}
          tag{1}
          $$

          where $v_text{w}$ and $v_text{a}$ are the speed of light in water and air, respectively, and where $theta_text{w}$ and $theta_text{a}$ are the angles of the light ray relative to a line perpendicular to the surface, on the water side and on the air side, respectively.



          If the angle on the water side is $theta_text{w} gtrsim 49^circ$, then equation (1) does not have any solution: there is no air-side angle $theta_text{a}$ that satisfies the equation. In this case, as niels nielsen indicated, light propagating inside the water will be completely reflected at the water-air interface. So the rim of the bubble acts like a mirror: if you do a reverse ray-trace from your eye back to near the rim of an air bubble in the water, the angle between the ray and the line perpendicular to the surface of the bubble will be greater than $49^circ$ (this defines what "near the rim" means), so that part of the bubble acts like a mirror for light coming from those angles, as illustrated here:
          enter image description here






          share|cite|improve this answer


























            30












            30








            30






            Air and water are both transparent to a good enough approximation. However, light travels more slowly in water: the speed of light in air is about 33% faster than in water. As a result, when light passes from one medium to the other, it is partly reflected and partly refracted (bent). For the refracted part, the general rule for determining the bending angle is called Snell's law, which can be expressed like this:
            $$
            frac{sintheta_text{w}}{sintheta_text{a}}=frac{v_text{w}}{v_text{a}}
            approx frac{1}{1.33}
            tag{1}
            $$

            where $v_text{w}$ and $v_text{a}$ are the speed of light in water and air, respectively, and where $theta_text{w}$ and $theta_text{a}$ are the angles of the light ray relative to a line perpendicular to the surface, on the water side and on the air side, respectively.



            If the angle on the water side is $theta_text{w} gtrsim 49^circ$, then equation (1) does not have any solution: there is no air-side angle $theta_text{a}$ that satisfies the equation. In this case, as niels nielsen indicated, light propagating inside the water will be completely reflected at the water-air interface. So the rim of the bubble acts like a mirror: if you do a reverse ray-trace from your eye back to near the rim of an air bubble in the water, the angle between the ray and the line perpendicular to the surface of the bubble will be greater than $49^circ$ (this defines what "near the rim" means), so that part of the bubble acts like a mirror for light coming from those angles, as illustrated here:
            enter image description here






            share|cite|improve this answer














            Air and water are both transparent to a good enough approximation. However, light travels more slowly in water: the speed of light in air is about 33% faster than in water. As a result, when light passes from one medium to the other, it is partly reflected and partly refracted (bent). For the refracted part, the general rule for determining the bending angle is called Snell's law, which can be expressed like this:
            $$
            frac{sintheta_text{w}}{sintheta_text{a}}=frac{v_text{w}}{v_text{a}}
            approx frac{1}{1.33}
            tag{1}
            $$

            where $v_text{w}$ and $v_text{a}$ are the speed of light in water and air, respectively, and where $theta_text{w}$ and $theta_text{a}$ are the angles of the light ray relative to a line perpendicular to the surface, on the water side and on the air side, respectively.



            If the angle on the water side is $theta_text{w} gtrsim 49^circ$, then equation (1) does not have any solution: there is no air-side angle $theta_text{a}$ that satisfies the equation. In this case, as niels nielsen indicated, light propagating inside the water will be completely reflected at the water-air interface. So the rim of the bubble acts like a mirror: if you do a reverse ray-trace from your eye back to near the rim of an air bubble in the water, the angle between the ray and the line perpendicular to the surface of the bubble will be greater than $49^circ$ (this defines what "near the rim" means), so that part of the bubble acts like a mirror for light coming from those angles, as illustrated here:
            enter image description here







            share|cite|improve this answer














            share|cite|improve this answer



            share|cite|improve this answer








            edited Dec 23 at 22:34

























            answered Dec 23 at 21:50









            Dan Yand

            6,4391730




            6,4391730























                12














                You can see light reflected off of the surface of a submerged bubble because the index of refraction of the air inside the bubble is different from that of the water that surrounds the bubble.



                That difference, if great enough, will turn a bubble surface into a mirror for light rays that approach it from certain directions, thereby making it easy to see.



                This condition is easily met for the combination of air and water.



                A google search on "refraction" and "total internal reflection" will furnish more examples of this, and explain the math behind it.






                share|cite|improve this answer

















                • 1




                  You said - "...light propagating inside the water will be completely reflected at the water-air interface" Does this mean that it is completely dark inside an air bubble underwater?
                  – MarkTO
                  2 days ago










                • No, it means that the bubble will behave like a bent mirror- which is exactly what the bubbles in the picture above look like.
                  – niels nielsen
                  2 days ago
















                12














                You can see light reflected off of the surface of a submerged bubble because the index of refraction of the air inside the bubble is different from that of the water that surrounds the bubble.



                That difference, if great enough, will turn a bubble surface into a mirror for light rays that approach it from certain directions, thereby making it easy to see.



                This condition is easily met for the combination of air and water.



                A google search on "refraction" and "total internal reflection" will furnish more examples of this, and explain the math behind it.






                share|cite|improve this answer

















                • 1




                  You said - "...light propagating inside the water will be completely reflected at the water-air interface" Does this mean that it is completely dark inside an air bubble underwater?
                  – MarkTO
                  2 days ago










                • No, it means that the bubble will behave like a bent mirror- which is exactly what the bubbles in the picture above look like.
                  – niels nielsen
                  2 days ago














                12












                12








                12






                You can see light reflected off of the surface of a submerged bubble because the index of refraction of the air inside the bubble is different from that of the water that surrounds the bubble.



                That difference, if great enough, will turn a bubble surface into a mirror for light rays that approach it from certain directions, thereby making it easy to see.



                This condition is easily met for the combination of air and water.



                A google search on "refraction" and "total internal reflection" will furnish more examples of this, and explain the math behind it.






                share|cite|improve this answer












                You can see light reflected off of the surface of a submerged bubble because the index of refraction of the air inside the bubble is different from that of the water that surrounds the bubble.



                That difference, if great enough, will turn a bubble surface into a mirror for light rays that approach it from certain directions, thereby making it easy to see.



                This condition is easily met for the combination of air and water.



                A google search on "refraction" and "total internal reflection" will furnish more examples of this, and explain the math behind it.







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered Dec 23 at 20:21









                niels nielsen

                15.8k42651




                15.8k42651








                • 1




                  You said - "...light propagating inside the water will be completely reflected at the water-air interface" Does this mean that it is completely dark inside an air bubble underwater?
                  – MarkTO
                  2 days ago










                • No, it means that the bubble will behave like a bent mirror- which is exactly what the bubbles in the picture above look like.
                  – niels nielsen
                  2 days ago














                • 1




                  You said - "...light propagating inside the water will be completely reflected at the water-air interface" Does this mean that it is completely dark inside an air bubble underwater?
                  – MarkTO
                  2 days ago










                • No, it means that the bubble will behave like a bent mirror- which is exactly what the bubbles in the picture above look like.
                  – niels nielsen
                  2 days ago








                1




                1




                You said - "...light propagating inside the water will be completely reflected at the water-air interface" Does this mean that it is completely dark inside an air bubble underwater?
                – MarkTO
                2 days ago




                You said - "...light propagating inside the water will be completely reflected at the water-air interface" Does this mean that it is completely dark inside an air bubble underwater?
                – MarkTO
                2 days ago












                No, it means that the bubble will behave like a bent mirror- which is exactly what the bubbles in the picture above look like.
                – niels nielsen
                2 days ago




                No, it means that the bubble will behave like a bent mirror- which is exactly what the bubbles in the picture above look like.
                – niels nielsen
                2 days ago











                1














                The inside of the bubble is not dark because only the light making a more glancing intersection than 49 degrees is completely reflected. Light that hits near the center of the bubble with respect to the direction it is traveling will be mostly transmitted into the bubble, illuminating the interior.






                share|cite|improve this answer










                New contributor




                Gus Michel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.























                  1














                  The inside of the bubble is not dark because only the light making a more glancing intersection than 49 degrees is completely reflected. Light that hits near the center of the bubble with respect to the direction it is traveling will be mostly transmitted into the bubble, illuminating the interior.






                  share|cite|improve this answer










                  New contributor




                  Gus Michel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.





















                    1












                    1








                    1






                    The inside of the bubble is not dark because only the light making a more glancing intersection than 49 degrees is completely reflected. Light that hits near the center of the bubble with respect to the direction it is traveling will be mostly transmitted into the bubble, illuminating the interior.






                    share|cite|improve this answer










                    New contributor




                    Gus Michel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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                    The inside of the bubble is not dark because only the light making a more glancing intersection than 49 degrees is completely reflected. Light that hits near the center of the bubble with respect to the direction it is traveling will be mostly transmitted into the bubble, illuminating the interior.







                    share|cite|improve this answer










                    New contributor




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                    share|cite|improve this answer



                    share|cite|improve this answer








                    edited yesterday





















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                    answered 2 days ago









                    Gus Michel

                    563




                    563




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                        0














                        For the exact same reason why you can see rain. Light waves hit it and the direction of propagation(travel) of the wave changes because it goes from one medium to another. Its movement causes the refraction to happen differently making it different from it's surroundings and visible to you.






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                          0














                          For the exact same reason why you can see rain. Light waves hit it and the direction of propagation(travel) of the wave changes because it goes from one medium to another. Its movement causes the refraction to happen differently making it different from it's surroundings and visible to you.






                          share|cite|improve this answer








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                            0












                            0








                            0






                            For the exact same reason why you can see rain. Light waves hit it and the direction of propagation(travel) of the wave changes because it goes from one medium to another. Its movement causes the refraction to happen differently making it different from it's surroundings and visible to you.






                            share|cite|improve this answer








                            New contributor




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                            For the exact same reason why you can see rain. Light waves hit it and the direction of propagation(travel) of the wave changes because it goes from one medium to another. Its movement causes the refraction to happen differently making it different from it's surroundings and visible to you.







                            share|cite|improve this answer








                            New contributor




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                            share|cite|improve this answer






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                            answered yesterday









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