How can I perform flatMap using multiple threads in Reactor?
1
I have tried running a flatMap on a Flux range followed by subscribeOn and it seems all operations run on the same thread. Is this normal?
Flux.range(0, 1000000).log().flatMap{ it + 1 }.subscribeOn(Schedulers.parallel()).subscribe()
multithreading kotlin project-reactor
edited Nov 21 '18 at 10:25
honk
4,837114349
asked Nov 21 '18 at 10:04
AndrewAndrew
4871919
add a comment |
1
I have tried running a flatMap on a Flux range followed by subscribeOn and it seems all operations run on the same thread. Is this normal?
Flux.range(0, 1000000).log().flatMap{ it + 1 }.subscribeOn(Schedulers.parallel()).subscribe()
multithreading kotlin project-reactor
edited Nov 21 '18 at 10:25
honk
4,837114349
asked Nov 21 '18 at 10:04
AndrewAndrew
4871919
add a comment |
1
1
1
I have tried running a flatMap on a Flux range followed by subscribeOn and it seems all operations run on the same thread. Is this normal?
Flux.range(0, 1000000).log().flatMap{ it + 1 }.subscribeOn(Schedulers.parallel()).subscribe()
multithreading kotlin project-reactor
edited Nov 21 '18 at 10:25
honk
4,837114349
asked Nov 21 '18 at 10:04
AndrewAndrew
4871919
I have tried running a flatMap on a Flux range followed by subscribeOn and it seems all operations run on the same thread. Is this normal?
Flux.range(0, 1000000).log().flatMap{ it + 1 }.subscribeOn(Schedulers.parallel()).subscribe()
multithreading kotlin project-reactor
multithreading kotlin project-reactor
edited Nov 21 '18 at 10:25
honk
4,837114349
asked Nov 21 '18 at 10:04
AndrewAndrew
4871919
edited Nov 21 '18 at 10:25
honk
4,837114349
asked Nov 21 '18 at 10:04
AndrewAndrew
4871919
edited Nov 21 '18 at 10:25
honk
4,837114349
edited Nov 21 '18 at 10:25
honk
4,837114349
edited Nov 21 '18 at 10:25
honk
4,837114349
4,837114349
asked Nov 21 '18 at 10:04
AndrewAndrew
4871919
asked Nov 21 '18 at 10:04
AndrewAndrew
4871919
asked Nov 21 '18 at 10:04
AndrewAndrew
4871919
4871919
add a comment |
add a comment |
1 Answer
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3
You can create a ParallelFlux as follows:
Flux.range(0, 100000).parallel(2).runOn(Schedulers.parallel()).log().map{ it + 1 }.subscribe()
^^^^^^^^^^^ ^^^^^^use runOn ^^^^^^^^^^^
answered Nov 21 '18 at 13:13
ReneRene
1,77126
So flatMap doesn't break your streams into sub-streams that are processed in parallel? This is how the method was documented and thought only subscribeOn is necessary.
– Andrew
Nov 21 '18 at 14:21
flatmapwill only parallelize if you create a new Observable(Flux, Mono) inside the block. In your example withit +1the operatorflatMapwill not compile and you should usemap. I just updated my answer. See stackoverflow.com/questions/43269275/…
– Rene
Nov 22 '18 at 10:39
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
3
You can create a ParallelFlux as follows:
Flux.range(0, 100000).parallel(2).runOn(Schedulers.parallel()).log().map{ it + 1 }.subscribe()
^^^^^^^^^^^ ^^^^^^use runOn ^^^^^^^^^^^
answered Nov 21 '18 at 13:13
ReneRene
1,77126
So flatMap doesn't break your streams into sub-streams that are processed in parallel? This is how the method was documented and thought only subscribeOn is necessary.
– Andrew
Nov 21 '18 at 14:21
flatmapwill only parallelize if you create a new Observable(Flux, Mono) inside the block. In your example withit +1the operatorflatMapwill not compile and you should usemap. I just updated my answer. See stackoverflow.com/questions/43269275/…
– Rene
Nov 22 '18 at 10:39
add a comment |
3
You can create a ParallelFlux as follows:
Flux.range(0, 100000).parallel(2).runOn(Schedulers.parallel()).log().map{ it + 1 }.subscribe()
^^^^^^^^^^^ ^^^^^^use runOn ^^^^^^^^^^^
answered Nov 21 '18 at 13:13
ReneRene
1,77126
So flatMap doesn't break your streams into sub-streams that are processed in parallel? This is how the method was documented and thought only subscribeOn is necessary.
– Andrew
Nov 21 '18 at 14:21
flatmapwill only parallelize if you create a new Observable(Flux, Mono) inside the block. In your example withit +1the operatorflatMapwill not compile and you should usemap. I just updated my answer. See stackoverflow.com/questions/43269275/…
– Rene
Nov 22 '18 at 10:39
add a comment |
3
3
3
You can create a ParallelFlux as follows:
Flux.range(0, 100000).parallel(2).runOn(Schedulers.parallel()).log().map{ it + 1 }.subscribe()
^^^^^^^^^^^ ^^^^^^use runOn ^^^^^^^^^^^
answered Nov 21 '18 at 13:13
ReneRene
1,77126
You can create a ParallelFlux as follows:
Flux.range(0, 100000).parallel(2).runOn(Schedulers.parallel()).log().map{ it + 1 }.subscribe()
^^^^^^^^^^^ ^^^^^^use runOn ^^^^^^^^^^^
answered Nov 21 '18 at 13:13
ReneRene
1,77126
edited Nov 22 '18 at 10:36
answered Nov 21 '18 at 13:13
ReneRene
1,77126
answered Nov 21 '18 at 13:13
ReneRene
1,77126
answered Nov 21 '18 at 13:13
ReneRene
1,77126
1,77126
So flatMap doesn't break your streams into sub-streams that are processed in parallel? This is how the method was documented and thought only subscribeOn is necessary.
– Andrew
Nov 21 '18 at 14:21
flatmapwill only parallelize if you create a new Observable(Flux, Mono) inside the block. In your example withit +1the operatorflatMapwill not compile and you should usemap. I just updated my answer. See stackoverflow.com/questions/43269275/…
– Rene
Nov 22 '18 at 10:39
add a comment |
So flatMap doesn't break your streams into sub-streams that are processed in parallel? This is how the method was documented and thought only subscribeOn is necessary.
– Andrew
Nov 21 '18 at 14:21
flatmapwill only parallelize if you create a new Observable(Flux, Mono) inside the block. In your example withit +1the operatorflatMapwill not compile and you should usemap. I just updated my answer. See stackoverflow.com/questions/43269275/…
– Rene
Nov 22 '18 at 10:39
So flatMap doesn't break your streams into sub-streams that are processed in parallel? This is how the method was documented and thought only subscribeOn is necessary.
– Andrew
Nov 21 '18 at 14:21
So flatMap doesn't break your streams into sub-streams that are processed in parallel? This is how the method was documented and thought only subscribeOn is necessary.
– Andrew
Nov 21 '18 at 14:21
flatmap will only parallelize if you create a new Observable(Flux, Mono) inside the block. In your example with it +1 the operator flatMap will not compile and you should use map. I just updated my answer. See stackoverflow.com/questions/43269275/…– Rene
Nov 22 '18 at 10:39
flatmap will only parallelize if you create a new Observable(Flux, Mono) inside the block. In your example with it +1 the operator flatMap will not compile and you should use map. I just updated my answer. See stackoverflow.com/questions/43269275/…– Rene
Nov 22 '18 at 10:39
add a comment |
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