WorksheetFunction.Match as array with variable range





.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}







1















I am trying to implement a .Match function as array with a variable range in VBA, to find the first non-zero cell in a specific range.



However, currently I only receive a runtime error 1004.



Any help is much appreciated! Thanks



Set myRange = Worksheets("Portf_Mod").Range("AB368:CY368") 
With Application.WorksheetFunction
Date_col = .Match(True, [myRange <> 0], 0)
End With









share|improve this question

























  • Take a look here, you could probably adjust this answer to fit your needs

    – Jchang43
    Nov 23 '18 at 16:52











  • I think the problem came from your =MATCH utilisation. You use it on multiple column. If you try the same on a formula you will have a "#NA" error.

    – BenderIO
    Nov 23 '18 at 16:54


















1















I am trying to implement a .Match function as array with a variable range in VBA, to find the first non-zero cell in a specific range.



However, currently I only receive a runtime error 1004.



Any help is much appreciated! Thanks



Set myRange = Worksheets("Portf_Mod").Range("AB368:CY368") 
With Application.WorksheetFunction
Date_col = .Match(True, [myRange <> 0], 0)
End With









share|improve this question

























  • Take a look here, you could probably adjust this answer to fit your needs

    – Jchang43
    Nov 23 '18 at 16:52











  • I think the problem came from your =MATCH utilisation. You use it on multiple column. If you try the same on a formula you will have a "#NA" error.

    – BenderIO
    Nov 23 '18 at 16:54














1












1








1








I am trying to implement a .Match function as array with a variable range in VBA, to find the first non-zero cell in a specific range.



However, currently I only receive a runtime error 1004.



Any help is much appreciated! Thanks



Set myRange = Worksheets("Portf_Mod").Range("AB368:CY368") 
With Application.WorksheetFunction
Date_col = .Match(True, [myRange <> 0], 0)
End With









share|improve this question
















I am trying to implement a .Match function as array with a variable range in VBA, to find the first non-zero cell in a specific range.



However, currently I only receive a runtime error 1004.



Any help is much appreciated! Thanks



Set myRange = Worksheets("Portf_Mod").Range("AB368:CY368") 
With Application.WorksheetFunction
Date_col = .Match(True, [myRange <> 0], 0)
End With






excel vba excel-vba worksheet-function






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 26 '18 at 7:28









Pᴇʜ

25.3k63052




25.3k63052










asked Nov 23 '18 at 16:38









Tobi1990Tobi1990

405




405













  • Take a look here, you could probably adjust this answer to fit your needs

    – Jchang43
    Nov 23 '18 at 16:52











  • I think the problem came from your =MATCH utilisation. You use it on multiple column. If you try the same on a formula you will have a "#NA" error.

    – BenderIO
    Nov 23 '18 at 16:54



















  • Take a look here, you could probably adjust this answer to fit your needs

    – Jchang43
    Nov 23 '18 at 16:52











  • I think the problem came from your =MATCH utilisation. You use it on multiple column. If you try the same on a formula you will have a "#NA" error.

    – BenderIO
    Nov 23 '18 at 16:54

















Take a look here, you could probably adjust this answer to fit your needs

– Jchang43
Nov 23 '18 at 16:52





Take a look here, you could probably adjust this answer to fit your needs

– Jchang43
Nov 23 '18 at 16:52













I think the problem came from your =MATCH utilisation. You use it on multiple column. If you try the same on a formula you will have a "#NA" error.

– BenderIO
Nov 23 '18 at 16:54





I think the problem came from your =MATCH utilisation. You use it on multiple column. If you try the same on a formula you will have a "#NA" error.

– BenderIO
Nov 23 '18 at 16:54












4 Answers
4






active

oldest

votes


















2














As you are using VBA, instead of using Match you could use the API to make for a more explicit and maintainable code:



Function FirstNonZeroCell(rng As Range) As Range
Dim cell As Range
For Each cell In rng.Cells
If cell.Value <> 0 Then
Set FirstNonZeroCell = cell
Exit Function
End If
Next
End Function


Or if you want a more compact version (but less readable in my opinion):



Function FirstNonZeroCell(rng As Range) As Range
For Each FirstNonZeroCell In rng.Cells
If FirstNonZeroCell.Value <> 0 Then Exit Function
Next
Set FirstNonZeroCell = Nothing
End Function


Here is a sample of use:



Sub test()
Dim res As Range
Set res = FirstNonZeroCell(Range("A1:Z100"))
If Not res Is Nothing Then
MsgBox "Found value " & res.Value & " in cell " & res.Address & "."
Else
MsgBox "No match has been found!"
End If
End Sub





share|improve this answer































    1














    Think the array element is throwing out your approach so here is an alternative.



    It's not clear if you want the first non-zero value or its position so this covers both.



    Date_col = Evaluate("MATCH(TRUE," & myRange.Address & "<>0,0)") 'returns position
    Date_col = Evaluate("INDEX(" & myRange.Address & ",MATCH(TRUE," & myRange.Address & "<>0,0))") 'returns value





    share|improve this answer


























    • This works perfectly! Thanks

      – Tobi1990
      Nov 23 '18 at 17:25



















    0














    It's the first time I came across an "array formula" in VBA. This is not wrong, but not very evident to understand/troubleshoot. On my machine [where the range had all empty cells, it gives an error [myRange <> 0] = Error 2092, then within the Match function, then gets another error...



    The array formulas are great in a formula worksheet only, but I feel you should avoid them in VBA. You have the ability to use loops in VBA, so, don't hesitate to use them! Having your train of though as explicit as possible is key when writing software (so you will understand it later!).



    My suggestion would be this :



    Option Explicit

    Function FindDateColumnInRange(ByVal RangeToLookIn As Range) As Long

    If RangeToLookIn.Rows.Count <> 1 Then
    'The range you're looking in has more than one row
    'what should you do in this case? Look only in the first row?

    Else

    Dim i As Long
    'The range has only one row
    For i = 0 To RangeToLookIn.Columns.Count - 1
    If RangeToLookIn.Item(1, i).Value <> 0 Then
    'should you verifiy that the value is a date value?
    FindDateColumnInRange = RangeToLookIn.Item(1, i).Column
    Exit Function
    End If
    Next
    End If

    'the range didn't have a value different from 0
    FindDateColumnInRange = 0

    End Function


    In action, you would get :



    Sub Test()

    Dim MyRange As Range
    Set MyRange = Worksheets("Portf_Mod").Range("AB368:CY368")
    Dim date_col As Integer

    date_col = FindDateColumnInRange(MyRange)

    If date_col = 0 Then
    'There was no date in your range
    End If

    End Sub


    Yeah, it's a lot more long than SJR suggestions, but, it covers every exceptions and you can control how to look if you were to pass a multidimensionnal array (iterate through rows first then columns, or the other way around).






    share|improve this answer































      0














      I wouldn't use the Match function for this...



      Set myRange = Worksheets("Portf_Mod").Range("AB368:CY368") 
      On Error Resume Next
      Date_col = myRange.Find("*", LookIn:=xlValues, SearchOrder:=xlByColumns).Column
      On Error GoTo 0





      share|improve this answer


























        Your Answer






        StackExchange.ifUsing("editor", function () {
        StackExchange.using("externalEditor", function () {
        StackExchange.using("snippets", function () {
        StackExchange.snippets.init();
        });
        });
        }, "code-snippets");

        StackExchange.ready(function() {
        var channelOptions = {
        tags: "".split(" "),
        id: "1"
        };
        initTagRenderer("".split(" "), "".split(" "), channelOptions);

        StackExchange.using("externalEditor", function() {
        // Have to fire editor after snippets, if snippets enabled
        if (StackExchange.settings.snippets.snippetsEnabled) {
        StackExchange.using("snippets", function() {
        createEditor();
        });
        }
        else {
        createEditor();
        }
        });

        function createEditor() {
        StackExchange.prepareEditor({
        heartbeatType: 'answer',
        autoActivateHeartbeat: false,
        convertImagesToLinks: true,
        noModals: true,
        showLowRepImageUploadWarning: true,
        reputationToPostImages: 10,
        bindNavPrevention: true,
        postfix: "",
        imageUploader: {
        brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
        contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
        allowUrls: true
        },
        onDemand: true,
        discardSelector: ".discard-answer"
        ,immediatelyShowMarkdownHelp:true
        });


        }
        });














        draft saved

        draft discarded


















        StackExchange.ready(
        function () {
        StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53450262%2fworksheetfunction-match-as-array-with-variable-range%23new-answer', 'question_page');
        }
        );

        Post as a guest















        Required, but never shown

























        4 Answers
        4






        active

        oldest

        votes








        4 Answers
        4






        active

        oldest

        votes









        active

        oldest

        votes






        active

        oldest

        votes









        2














        As you are using VBA, instead of using Match you could use the API to make for a more explicit and maintainable code:



        Function FirstNonZeroCell(rng As Range) As Range
        Dim cell As Range
        For Each cell In rng.Cells
        If cell.Value <> 0 Then
        Set FirstNonZeroCell = cell
        Exit Function
        End If
        Next
        End Function


        Or if you want a more compact version (but less readable in my opinion):



        Function FirstNonZeroCell(rng As Range) As Range
        For Each FirstNonZeroCell In rng.Cells
        If FirstNonZeroCell.Value <> 0 Then Exit Function
        Next
        Set FirstNonZeroCell = Nothing
        End Function


        Here is a sample of use:



        Sub test()
        Dim res As Range
        Set res = FirstNonZeroCell(Range("A1:Z100"))
        If Not res Is Nothing Then
        MsgBox "Found value " & res.Value & " in cell " & res.Address & "."
        Else
        MsgBox "No match has been found!"
        End If
        End Sub





        share|improve this answer




























          2














          As you are using VBA, instead of using Match you could use the API to make for a more explicit and maintainable code:



          Function FirstNonZeroCell(rng As Range) As Range
          Dim cell As Range
          For Each cell In rng.Cells
          If cell.Value <> 0 Then
          Set FirstNonZeroCell = cell
          Exit Function
          End If
          Next
          End Function


          Or if you want a more compact version (but less readable in my opinion):



          Function FirstNonZeroCell(rng As Range) As Range
          For Each FirstNonZeroCell In rng.Cells
          If FirstNonZeroCell.Value <> 0 Then Exit Function
          Next
          Set FirstNonZeroCell = Nothing
          End Function


          Here is a sample of use:



          Sub test()
          Dim res As Range
          Set res = FirstNonZeroCell(Range("A1:Z100"))
          If Not res Is Nothing Then
          MsgBox "Found value " & res.Value & " in cell " & res.Address & "."
          Else
          MsgBox "No match has been found!"
          End If
          End Sub





          share|improve this answer


























            2












            2








            2







            As you are using VBA, instead of using Match you could use the API to make for a more explicit and maintainable code:



            Function FirstNonZeroCell(rng As Range) As Range
            Dim cell As Range
            For Each cell In rng.Cells
            If cell.Value <> 0 Then
            Set FirstNonZeroCell = cell
            Exit Function
            End If
            Next
            End Function


            Or if you want a more compact version (but less readable in my opinion):



            Function FirstNonZeroCell(rng As Range) As Range
            For Each FirstNonZeroCell In rng.Cells
            If FirstNonZeroCell.Value <> 0 Then Exit Function
            Next
            Set FirstNonZeroCell = Nothing
            End Function


            Here is a sample of use:



            Sub test()
            Dim res As Range
            Set res = FirstNonZeroCell(Range("A1:Z100"))
            If Not res Is Nothing Then
            MsgBox "Found value " & res.Value & " in cell " & res.Address & "."
            Else
            MsgBox "No match has been found!"
            End If
            End Sub





            share|improve this answer













            As you are using VBA, instead of using Match you could use the API to make for a more explicit and maintainable code:



            Function FirstNonZeroCell(rng As Range) As Range
            Dim cell As Range
            For Each cell In rng.Cells
            If cell.Value <> 0 Then
            Set FirstNonZeroCell = cell
            Exit Function
            End If
            Next
            End Function


            Or if you want a more compact version (but less readable in my opinion):



            Function FirstNonZeroCell(rng As Range) As Range
            For Each FirstNonZeroCell In rng.Cells
            If FirstNonZeroCell.Value <> 0 Then Exit Function
            Next
            Set FirstNonZeroCell = Nothing
            End Function


            Here is a sample of use:



            Sub test()
            Dim res As Range
            Set res = FirstNonZeroCell(Range("A1:Z100"))
            If Not res Is Nothing Then
            MsgBox "Found value " & res.Value & " in cell " & res.Address & "."
            Else
            MsgBox "No match has been found!"
            End If
            End Sub






            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Nov 23 '18 at 17:18









            PragmateekPragmateek

            9,39695591




            9,39695591

























                1














                Think the array element is throwing out your approach so here is an alternative.



                It's not clear if you want the first non-zero value or its position so this covers both.



                Date_col = Evaluate("MATCH(TRUE," & myRange.Address & "<>0,0)") 'returns position
                Date_col = Evaluate("INDEX(" & myRange.Address & ",MATCH(TRUE," & myRange.Address & "<>0,0))") 'returns value





                share|improve this answer


























                • This works perfectly! Thanks

                  – Tobi1990
                  Nov 23 '18 at 17:25
















                1














                Think the array element is throwing out your approach so here is an alternative.



                It's not clear if you want the first non-zero value or its position so this covers both.



                Date_col = Evaluate("MATCH(TRUE," & myRange.Address & "<>0,0)") 'returns position
                Date_col = Evaluate("INDEX(" & myRange.Address & ",MATCH(TRUE," & myRange.Address & "<>0,0))") 'returns value





                share|improve this answer


























                • This works perfectly! Thanks

                  – Tobi1990
                  Nov 23 '18 at 17:25














                1












                1








                1







                Think the array element is throwing out your approach so here is an alternative.



                It's not clear if you want the first non-zero value or its position so this covers both.



                Date_col = Evaluate("MATCH(TRUE," & myRange.Address & "<>0,0)") 'returns position
                Date_col = Evaluate("INDEX(" & myRange.Address & ",MATCH(TRUE," & myRange.Address & "<>0,0))") 'returns value





                share|improve this answer















                Think the array element is throwing out your approach so here is an alternative.



                It's not clear if you want the first non-zero value or its position so this covers both.



                Date_col = Evaluate("MATCH(TRUE," & myRange.Address & "<>0,0)") 'returns position
                Date_col = Evaluate("INDEX(" & myRange.Address & ",MATCH(TRUE," & myRange.Address & "<>0,0))") 'returns value






                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited Nov 23 '18 at 17:07

























                answered Nov 23 '18 at 17:02









                SJRSJR

                13.8k31219




                13.8k31219













                • This works perfectly! Thanks

                  – Tobi1990
                  Nov 23 '18 at 17:25



















                • This works perfectly! Thanks

                  – Tobi1990
                  Nov 23 '18 at 17:25

















                This works perfectly! Thanks

                – Tobi1990
                Nov 23 '18 at 17:25





                This works perfectly! Thanks

                – Tobi1990
                Nov 23 '18 at 17:25











                0














                It's the first time I came across an "array formula" in VBA. This is not wrong, but not very evident to understand/troubleshoot. On my machine [where the range had all empty cells, it gives an error [myRange <> 0] = Error 2092, then within the Match function, then gets another error...



                The array formulas are great in a formula worksheet only, but I feel you should avoid them in VBA. You have the ability to use loops in VBA, so, don't hesitate to use them! Having your train of though as explicit as possible is key when writing software (so you will understand it later!).



                My suggestion would be this :



                Option Explicit

                Function FindDateColumnInRange(ByVal RangeToLookIn As Range) As Long

                If RangeToLookIn.Rows.Count <> 1 Then
                'The range you're looking in has more than one row
                'what should you do in this case? Look only in the first row?

                Else

                Dim i As Long
                'The range has only one row
                For i = 0 To RangeToLookIn.Columns.Count - 1
                If RangeToLookIn.Item(1, i).Value <> 0 Then
                'should you verifiy that the value is a date value?
                FindDateColumnInRange = RangeToLookIn.Item(1, i).Column
                Exit Function
                End If
                Next
                End If

                'the range didn't have a value different from 0
                FindDateColumnInRange = 0

                End Function


                In action, you would get :



                Sub Test()

                Dim MyRange As Range
                Set MyRange = Worksheets("Portf_Mod").Range("AB368:CY368")
                Dim date_col As Integer

                date_col = FindDateColumnInRange(MyRange)

                If date_col = 0 Then
                'There was no date in your range
                End If

                End Sub


                Yeah, it's a lot more long than SJR suggestions, but, it covers every exceptions and you can control how to look if you were to pass a multidimensionnal array (iterate through rows first then columns, or the other way around).






                share|improve this answer




























                  0














                  It's the first time I came across an "array formula" in VBA. This is not wrong, but not very evident to understand/troubleshoot. On my machine [where the range had all empty cells, it gives an error [myRange <> 0] = Error 2092, then within the Match function, then gets another error...



                  The array formulas are great in a formula worksheet only, but I feel you should avoid them in VBA. You have the ability to use loops in VBA, so, don't hesitate to use them! Having your train of though as explicit as possible is key when writing software (so you will understand it later!).



                  My suggestion would be this :



                  Option Explicit

                  Function FindDateColumnInRange(ByVal RangeToLookIn As Range) As Long

                  If RangeToLookIn.Rows.Count <> 1 Then
                  'The range you're looking in has more than one row
                  'what should you do in this case? Look only in the first row?

                  Else

                  Dim i As Long
                  'The range has only one row
                  For i = 0 To RangeToLookIn.Columns.Count - 1
                  If RangeToLookIn.Item(1, i).Value <> 0 Then
                  'should you verifiy that the value is a date value?
                  FindDateColumnInRange = RangeToLookIn.Item(1, i).Column
                  Exit Function
                  End If
                  Next
                  End If

                  'the range didn't have a value different from 0
                  FindDateColumnInRange = 0

                  End Function


                  In action, you would get :



                  Sub Test()

                  Dim MyRange As Range
                  Set MyRange = Worksheets("Portf_Mod").Range("AB368:CY368")
                  Dim date_col As Integer

                  date_col = FindDateColumnInRange(MyRange)

                  If date_col = 0 Then
                  'There was no date in your range
                  End If

                  End Sub


                  Yeah, it's a lot more long than SJR suggestions, but, it covers every exceptions and you can control how to look if you were to pass a multidimensionnal array (iterate through rows first then columns, or the other way around).






                  share|improve this answer


























                    0












                    0








                    0







                    It's the first time I came across an "array formula" in VBA. This is not wrong, but not very evident to understand/troubleshoot. On my machine [where the range had all empty cells, it gives an error [myRange <> 0] = Error 2092, then within the Match function, then gets another error...



                    The array formulas are great in a formula worksheet only, but I feel you should avoid them in VBA. You have the ability to use loops in VBA, so, don't hesitate to use them! Having your train of though as explicit as possible is key when writing software (so you will understand it later!).



                    My suggestion would be this :



                    Option Explicit

                    Function FindDateColumnInRange(ByVal RangeToLookIn As Range) As Long

                    If RangeToLookIn.Rows.Count <> 1 Then
                    'The range you're looking in has more than one row
                    'what should you do in this case? Look only in the first row?

                    Else

                    Dim i As Long
                    'The range has only one row
                    For i = 0 To RangeToLookIn.Columns.Count - 1
                    If RangeToLookIn.Item(1, i).Value <> 0 Then
                    'should you verifiy that the value is a date value?
                    FindDateColumnInRange = RangeToLookIn.Item(1, i).Column
                    Exit Function
                    End If
                    Next
                    End If

                    'the range didn't have a value different from 0
                    FindDateColumnInRange = 0

                    End Function


                    In action, you would get :



                    Sub Test()

                    Dim MyRange As Range
                    Set MyRange = Worksheets("Portf_Mod").Range("AB368:CY368")
                    Dim date_col As Integer

                    date_col = FindDateColumnInRange(MyRange)

                    If date_col = 0 Then
                    'There was no date in your range
                    End If

                    End Sub


                    Yeah, it's a lot more long than SJR suggestions, but, it covers every exceptions and you can control how to look if you were to pass a multidimensionnal array (iterate through rows first then columns, or the other way around).






                    share|improve this answer













                    It's the first time I came across an "array formula" in VBA. This is not wrong, but not very evident to understand/troubleshoot. On my machine [where the range had all empty cells, it gives an error [myRange <> 0] = Error 2092, then within the Match function, then gets another error...



                    The array formulas are great in a formula worksheet only, but I feel you should avoid them in VBA. You have the ability to use loops in VBA, so, don't hesitate to use them! Having your train of though as explicit as possible is key when writing software (so you will understand it later!).



                    My suggestion would be this :



                    Option Explicit

                    Function FindDateColumnInRange(ByVal RangeToLookIn As Range) As Long

                    If RangeToLookIn.Rows.Count <> 1 Then
                    'The range you're looking in has more than one row
                    'what should you do in this case? Look only in the first row?

                    Else

                    Dim i As Long
                    'The range has only one row
                    For i = 0 To RangeToLookIn.Columns.Count - 1
                    If RangeToLookIn.Item(1, i).Value <> 0 Then
                    'should you verifiy that the value is a date value?
                    FindDateColumnInRange = RangeToLookIn.Item(1, i).Column
                    Exit Function
                    End If
                    Next
                    End If

                    'the range didn't have a value different from 0
                    FindDateColumnInRange = 0

                    End Function


                    In action, you would get :



                    Sub Test()

                    Dim MyRange As Range
                    Set MyRange = Worksheets("Portf_Mod").Range("AB368:CY368")
                    Dim date_col As Integer

                    date_col = FindDateColumnInRange(MyRange)

                    If date_col = 0 Then
                    'There was no date in your range
                    End If

                    End Sub


                    Yeah, it's a lot more long than SJR suggestions, but, it covers every exceptions and you can control how to look if you were to pass a multidimensionnal array (iterate through rows first then columns, or the other way around).







                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered Nov 23 '18 at 17:46









                    CharlesPLCharlesPL

                    1969




                    1969























                        0














                        I wouldn't use the Match function for this...



                        Set myRange = Worksheets("Portf_Mod").Range("AB368:CY368") 
                        On Error Resume Next
                        Date_col = myRange.Find("*", LookIn:=xlValues, SearchOrder:=xlByColumns).Column
                        On Error GoTo 0





                        share|improve this answer






























                          0














                          I wouldn't use the Match function for this...



                          Set myRange = Worksheets("Portf_Mod").Range("AB368:CY368") 
                          On Error Resume Next
                          Date_col = myRange.Find("*", LookIn:=xlValues, SearchOrder:=xlByColumns).Column
                          On Error GoTo 0





                          share|improve this answer




























                            0












                            0








                            0







                            I wouldn't use the Match function for this...



                            Set myRange = Worksheets("Portf_Mod").Range("AB368:CY368") 
                            On Error Resume Next
                            Date_col = myRange.Find("*", LookIn:=xlValues, SearchOrder:=xlByColumns).Column
                            On Error GoTo 0





                            share|improve this answer















                            I wouldn't use the Match function for this...



                            Set myRange = Worksheets("Portf_Mod").Range("AB368:CY368") 
                            On Error Resume Next
                            Date_col = myRange.Find("*", LookIn:=xlValues, SearchOrder:=xlByColumns).Column
                            On Error GoTo 0






                            share|improve this answer














                            share|improve this answer



                            share|improve this answer








                            edited Nov 25 '18 at 1:44

























                            answered Nov 23 '18 at 17:37









                            TragamorTragamor

                            1,76931024




                            1,76931024






























                                draft saved

                                draft discarded




















































                                Thanks for contributing an answer to Stack Overflow!


                                • Please be sure to answer the question. Provide details and share your research!

                                But avoid



                                • Asking for help, clarification, or responding to other answers.

                                • Making statements based on opinion; back them up with references or personal experience.


                                To learn more, see our tips on writing great answers.




                                draft saved


                                draft discarded














                                StackExchange.ready(
                                function () {
                                StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53450262%2fworksheetfunction-match-as-array-with-variable-range%23new-answer', 'question_page');
                                }
                                );

                                Post as a guest















                                Required, but never shown





















































                                Required, but never shown














                                Required, but never shown












                                Required, but never shown







                                Required, but never shown

































                                Required, but never shown














                                Required, but never shown












                                Required, but never shown







                                Required, but never shown







                                Popular posts from this blog

                                "Incorrect syntax near the keyword 'ON'. (on update cascade, on delete cascade,)

                                Alcedinidae

                                RAC Tourist Trophy