Angular Routes: Problem defining a NotFoundComponent with multiple routings files
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
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I am creating a NotFoundComponent so that every non-existing url, a friendly page will apear to the user.
My Angular 6 project has 5 features(CRUDL):
CompanyComponent,
EmployeeComponent,
BranchComponent,
BenefitsComponent,
MainComponent
Each component have it own .module and .routing, for example the company.routing.ts defines the route like this:
export const routes: Routes = [
{
path: "branch",
component: EmptyComponent,
}
...
@NgModule({
imports: [
RouterModule.forChild(routes),
...
it also defines its childrens, like path: "branch/:id".
So, i have no problem with the way i built the routing.
The problem I am facing now is the way I can define a path to the NotFoundComponent.
Because I don't have a single file where I define my routes, if I put the definition of the /404 page on the on the bottom of routers definition in the main.routing.ts, every other route defined on the features(like the company.routing.ts) will be redirected to the /404, since angular uses the first match strategy.
Things i tried so far:
on the main.routing.ts:
export const routes: Routes = [
{
path: "main",
component: MainComponent,
},
{
path: "404",
resolve: {
routeTitle: TitleResolver,
},
component: NotFoundComponent,
},
{
path: "",
pathMatch: "full",
redirectTo: "/main",
},
{
path: "**",
redirectTo: "/404",
}
if I put this way, when I try accessing the route /company (defined in the company.routing.ts) it will be redirected to the /404.
I also tried defining it on any a routing of one of my features, like on the company.routing.ts
{
path: "**",
redirectTo: "/404",
}
Than, a funny thing happened, if I define this piece of code on the benefits.routing.ts, i can access /benefits but /branch, /employee and the rest of the routes will be redirected to /404.
if I define it on branch, I can access /benefits, /branch but /employee and the rest of the routes will be redirected to /404.
I could just place this code on the last feature loaded and it would work but I would like to know if I can solve this with another approach, can't I define a route that I want to be the last one loaded?
thanks in advance.
javascript
angular typescript angular6 asked Nov 23 '18 at 17:45
GustavoGustavo
689
add a comment |
I am creating a NotFoundComponent so that every non-existing url, a friendly page will apear to the user.
My Angular 6 project has 5 features(CRUDL):
CompanyComponent,
EmployeeComponent,
BranchComponent,
BenefitsComponent,
MainComponent
Each component have it own .module and .routing, for example the company.routing.ts defines the route like this:
export const routes: Routes = [
{
path: "branch",
component: EmptyComponent,
}
...
@NgModule({
imports: [
RouterModule.forChild(routes),
...
it also defines its childrens, like path: "branch/:id".
So, i have no problem with the way i built the routing.
The problem I am facing now is the way I can define a path to the NotFoundComponent.
Because I don't have a single file where I define my routes, if I put the definition of the /404 page on the on the bottom of routers definition in the main.routing.ts, every other route defined on the features(like the company.routing.ts) will be redirected to the /404, since angular uses the first match strategy.
Things i tried so far:
on the main.routing.ts:
export const routes: Routes = [
{
path: "main",
component: MainComponent,
},
{
path: "404",
resolve: {
routeTitle: TitleResolver,
},
component: NotFoundComponent,
},
{
path: "",
pathMatch: "full",
redirectTo: "/main",
},
{
path: "**",
redirectTo: "/404",
}
if I put this way, when I try accessing the route /company (defined in the company.routing.ts) it will be redirected to the /404.
I also tried defining it on any a routing of one of my features, like on the company.routing.ts
{
path: "**",
redirectTo: "/404",
}
Than, a funny thing happened, if I define this piece of code on the benefits.routing.ts, i can access /benefits but /branch, /employee and the rest of the routes will be redirected to /404.
if I define it on branch, I can access /benefits, /branch but /employee and the rest of the routes will be redirected to /404.
I could just place this code on the last feature loaded and it would work but I would like to know if I can solve this with another approach, can't I define a route that I want to be the last one loaded?
thanks in advance.
javascript
angular typescript angular6 asked Nov 23 '18 at 17:45
GustavoGustavo
689
Need to see how you load your other modules using route - stackblitz will do great - please add
– Rahul
Nov 23 '18 at 19:12
@Gustavo. The link below may solve your issues:stackoverflow.com/questions/49621578/…. It explains lazy loading and children routes. Each module has its own <router-outlet>. You can have lots of modules and you should import them like a tree structure.
– harold_mean2
Nov 23 '18 at 20:02
my problem is because I lazy load modules, but I can't change the way I import stuffs because otherwise it will be a performance loss, can't find any work around yet, I probably would need to define my routes elsewhere and import them.
– Gustavo
Nov 26 '18 at 19:19
add a comment |
I am creating a NotFoundComponent so that every non-existing url, a friendly page will apear to the user.
My Angular 6 project has 5 features(CRUDL):
CompanyComponent,
EmployeeComponent,
BranchComponent,
BenefitsComponent,
MainComponent
Each component have it own .module and .routing, for example the company.routing.ts defines the route like this:
export const routes: Routes = [
{
path: "branch",
component: EmptyComponent,
}
...
@NgModule({
imports: [
RouterModule.forChild(routes),
...
it also defines its childrens, like path: "branch/:id".
So, i have no problem with the way i built the routing.
The problem I am facing now is the way I can define a path to the NotFoundComponent.
Because I don't have a single file where I define my routes, if I put the definition of the /404 page on the on the bottom of routers definition in the main.routing.ts, every other route defined on the features(like the company.routing.ts) will be redirected to the /404, since angular uses the first match strategy.
Things i tried so far:
on the main.routing.ts:
export const routes: Routes = [
{
path: "main",
component: MainComponent,
},
{
path: "404",
resolve: {
routeTitle: TitleResolver,
},
component: NotFoundComponent,
},
{
path: "",
pathMatch: "full",
redirectTo: "/main",
},
{
path: "**",
redirectTo: "/404",
}
if I put this way, when I try accessing the route /company (defined in the company.routing.ts) it will be redirected to the /404.
I also tried defining it on any a routing of one of my features, like on the company.routing.ts
{
path: "**",
redirectTo: "/404",
}
Than, a funny thing happened, if I define this piece of code on the benefits.routing.ts, i can access /benefits but /branch, /employee and the rest of the routes will be redirected to /404.
if I define it on branch, I can access /benefits, /branch but /employee and the rest of the routes will be redirected to /404.
I could just place this code on the last feature loaded and it would work but I would like to know if I can solve this with another approach, can't I define a route that I want to be the last one loaded?
thanks in advance.
javascript
angular typescript angular6 asked Nov 23 '18 at 17:45
GustavoGustavo
689
I am creating a NotFoundComponent so that every non-existing url, a friendly page will apear to the user.
My Angular 6 project has 5 features(CRUDL):
CompanyComponent,
EmployeeComponent,
BranchComponent,
BenefitsComponent,
MainComponent
Each component have it own .module and .routing, for example the company.routing.ts defines the route like this:
export const routes: Routes = [
{
path: "branch",
component: EmptyComponent,
}
...
@NgModule({
imports: [
RouterModule.forChild(routes),
...
it also defines its childrens, like path: "branch/:id".
So, i have no problem with the way i built the routing.
The problem I am facing now is the way I can define a path to the NotFoundComponent.
Because I don't have a single file where I define my routes, if I put the definition of the /404 page on the on the bottom of routers definition in the main.routing.ts, every other route defined on the features(like the company.routing.ts) will be redirected to the /404, since angular uses the first match strategy.
Things i tried so far:
on the main.routing.ts:
export const routes: Routes = [
{
path: "main",
component: MainComponent,
},
{
path: "404",
resolve: {
routeTitle: TitleResolver,
},
component: NotFoundComponent,
},
{
path: "",
pathMatch: "full",
redirectTo: "/main",
},
{
path: "**",
redirectTo: "/404",
}
if I put this way, when I try accessing the route /company (defined in the company.routing.ts) it will be redirected to the /404.
I also tried defining it on any a routing of one of my features, like on the company.routing.ts
{
path: "**",
redirectTo: "/404",
}
Than, a funny thing happened, if I define this piece of code on the benefits.routing.ts, i can access /benefits but /branch, /employee and the rest of the routes will be redirected to /404.
if I define it on branch, I can access /benefits, /branch but /employee and the rest of the routes will be redirected to /404.
I could just place this code on the last feature loaded and it would work but I would like to know if I can solve this with another approach, can't I define a route that I want to be the last one loaded?
thanks in advance.
javascript
angular typescript angular6 javascript
angular typescript angular6 asked Nov 23 '18 at 17:45
GustavoGustavo
689
asked Nov 23 '18 at 17:45
GustavoGustavo
689
asked Nov 23 '18 at 17:45
GustavoGustavo
689
asked Nov 23 '18 at 17:45
GustavoGustavo
689
asked Nov 23 '18 at 17:45
GustavoGustavo
689
689
Need to see how you load your other modules using route - stackblitz will do great - please add
– Rahul
Nov 23 '18 at 19:12
@Gustavo. The link below may solve your issues:stackoverflow.com/questions/49621578/…. It explains lazy loading and children routes. Each module has its own <router-outlet>. You can have lots of modules and you should import them like a tree structure.
– harold_mean2
Nov 23 '18 at 20:02
my problem is because I lazy load modules, but I can't change the way I import stuffs because otherwise it will be a performance loss, can't find any work around yet, I probably would need to define my routes elsewhere and import them.
– Gustavo
Nov 26 '18 at 19:19
add a comment |
Need to see how you load your other modules using route - stackblitz will do great - please add
– Rahul
Nov 23 '18 at 19:12
@Gustavo. The link below may solve your issues:stackoverflow.com/questions/49621578/…. It explains lazy loading and children routes. Each module has its own <router-outlet>. You can have lots of modules and you should import them like a tree structure.
– harold_mean2
Nov 23 '18 at 20:02
my problem is because I lazy load modules, but I can't change the way I import stuffs because otherwise it will be a performance loss, can't find any work around yet, I probably would need to define my routes elsewhere and import them.
– Gustavo
Nov 26 '18 at 19:19
Need to see how you load your other modules using route - stackblitz will do great - please add
– Rahul
Nov 23 '18 at 19:12
Need to see how you load your other modules using route - stackblitz will do great - please add
– Rahul
Nov 23 '18 at 19:12
@Gustavo. The link below may solve your issues:stackoverflow.com/questions/49621578/…. It explains lazy loading and children routes. Each module has its own <router-outlet>. You can have lots of modules and you should import them like a tree structure.
– harold_mean2
Nov 23 '18 at 20:02
@Gustavo. The link below may solve your issues:stackoverflow.com/questions/49621578/…. It explains lazy loading and children routes. Each module has its own <router-outlet>. You can have lots of modules and you should import them like a tree structure.
– harold_mean2
Nov 23 '18 at 20:02
my problem is because I lazy load modules, but I can't change the way I import stuffs because otherwise it will be a performance loss, can't find any work around yet, I probably would need to define my routes elsewhere and import them.
– Gustavo
Nov 26 '18 at 19:19
my problem is because I lazy load modules, but I can't change the way I import stuffs because otherwise it will be a performance loss, can't find any work around yet, I probably would need to define my routes elsewhere and import them.
– Gustavo
Nov 26 '18 at 19:19
add a comment |
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Need to see how you load your other modules using route - stackblitz will do great - please add
– Rahul
Nov 23 '18 at 19:12
@Gustavo. The link below may solve your issues:stackoverflow.com/questions/49621578/…. It explains lazy loading and children routes. Each module has its own <router-outlet>. You can have lots of modules and you should import them like a tree structure.
– harold_mean2
Nov 23 '18 at 20:02
my problem is because I lazy load modules, but I can't change the way I import stuffs because otherwise it will be a performance loss, can't find any work around yet, I probably would need to define my routes elsewhere and import them.
– Gustavo
Nov 26 '18 at 19:19