Python reduce sum tuple
2
I have an input that will vary in size.
data = [(("101","A"),5), (("105","C"),12), (("101", "B"),4)]
Looking for an output that groups by key[0], keeps all items of key[1]. And, sums up the values.
output = [(("101", "A", "B"),9), (("105", "C"),12)]
I've tried.
my_dict = dict(data)
final_values = {}
for k,v in my_dict.items():
key1 = k[0]
key2 = k[1]
if key1 not in final_values:
final_values[key1] =
final_values[key1].append(key2)
final_values[key1].append(v)
Which returns.
{'101': ['A', 5, 'B', 4], '105': ['C', 12]}
I'd like to get the sum of the numbers in the list.
python
asked Nov 20 at 5:05
mushg
1814
add a comment |
2
I have an input that will vary in size.
data = [(("101","A"),5), (("105","C"),12), (("101", "B"),4)]
Looking for an output that groups by key[0], keeps all items of key[1]. And, sums up the values.
output = [(("101", "A", "B"),9), (("105", "C"),12)]
I've tried.
my_dict = dict(data)
final_values = {}
for k,v in my_dict.items():
key1 = k[0]
key2 = k[1]
if key1 not in final_values:
final_values[key1] =
final_values[key1].append(key2)
final_values[key1].append(v)
Which returns.
{'101': ['A', 5, 'B', 4], '105': ['C', 12]}
I'd like to get the sum of the numbers in the list.
python
asked Nov 20 at 5:05
mushg
1814
add a comment |
2
2
2
1
I have an input that will vary in size.
data = [(("101","A"),5), (("105","C"),12), (("101", "B"),4)]
Looking for an output that groups by key[0], keeps all items of key[1]. And, sums up the values.
output = [(("101", "A", "B"),9), (("105", "C"),12)]
I've tried.
my_dict = dict(data)
final_values = {}
for k,v in my_dict.items():
key1 = k[0]
key2 = k[1]
if key1 not in final_values:
final_values[key1] =
final_values[key1].append(key2)
final_values[key1].append(v)
Which returns.
{'101': ['A', 5, 'B', 4], '105': ['C', 12]}
I'd like to get the sum of the numbers in the list.
python
asked Nov 20 at 5:05
mushg
1814
I have an input that will vary in size.
data = [(("101","A"),5), (("105","C"),12), (("101", "B"),4)]
Looking for an output that groups by key[0], keeps all items of key[1]. And, sums up the values.
output = [(("101", "A", "B"),9), (("105", "C"),12)]
I've tried.
my_dict = dict(data)
final_values = {}
for k,v in my_dict.items():
key1 = k[0]
key2 = k[1]
if key1 not in final_values:
final_values[key1] =
final_values[key1].append(key2)
final_values[key1].append(v)
Which returns.
{'101': ['A', 5, 'B', 4], '105': ['C', 12]}
I'd like to get the sum of the numbers in the list.
python
python
asked Nov 20 at 5:05
mushg
1814
asked Nov 20 at 5:05
mushg
1814
asked Nov 20 at 5:05
mushg
1814
asked Nov 20 at 5:05
mushg
1814
asked Nov 20 at 5:05
mushg
1814
1814
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
0
You can try using a collections.defaultdict() to group the items, then flattening the results at the end:
from collections import defaultdict
from operator import itemgetter
data = [(("101","A"),5), (("105","C"),12), (("101", "B"),4)]
d = defaultdict(list)
for (x, y), z in data:
d[x].append((y, z))
result = [
((k, *tuple(map(itemgetter(0), v))), sum(map(itemgetter(1), v)))
for k, v in d.items()
]
print(result)
# [(('101', 'A', 'B'), 9), (('105', 'C'), 12)]
answered Nov 20 at 5:12
RoadRunner
10.2k31340
add a comment |
3
for k in final_values:
print '%s: sum is %d' % (k, sum([x for x in final_values[k] if type(x) is int]))
answered Nov 20 at 5:10
John Gordon
9,48051728
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
You can try using a collections.defaultdict() to group the items, then flattening the results at the end:
from collections import defaultdict
from operator import itemgetter
data = [(("101","A"),5), (("105","C"),12), (("101", "B"),4)]
d = defaultdict(list)
for (x, y), z in data:
d[x].append((y, z))
result = [
((k, *tuple(map(itemgetter(0), v))), sum(map(itemgetter(1), v)))
for k, v in d.items()
]
print(result)
# [(('101', 'A', 'B'), 9), (('105', 'C'), 12)]
answered Nov 20 at 5:12
RoadRunner
10.2k31340
add a comment |
0
You can try using a collections.defaultdict() to group the items, then flattening the results at the end:
from collections import defaultdict
from operator import itemgetter
data = [(("101","A"),5), (("105","C"),12), (("101", "B"),4)]
d = defaultdict(list)
for (x, y), z in data:
d[x].append((y, z))
result = [
((k, *tuple(map(itemgetter(0), v))), sum(map(itemgetter(1), v)))
for k, v in d.items()
]
print(result)
# [(('101', 'A', 'B'), 9), (('105', 'C'), 12)]
answered Nov 20 at 5:12
RoadRunner
10.2k31340
add a comment |
0
0
0
You can try using a collections.defaultdict() to group the items, then flattening the results at the end:
from collections import defaultdict
from operator import itemgetter
data = [(("101","A"),5), (("105","C"),12), (("101", "B"),4)]
d = defaultdict(list)
for (x, y), z in data:
d[x].append((y, z))
result = [
((k, *tuple(map(itemgetter(0), v))), sum(map(itemgetter(1), v)))
for k, v in d.items()
]
print(result)
# [(('101', 'A', 'B'), 9), (('105', 'C'), 12)]
answered Nov 20 at 5:12
RoadRunner
10.2k31340
You can try using a collections.defaultdict() to group the items, then flattening the results at the end:
from collections import defaultdict
from operator import itemgetter
data = [(("101","A"),5), (("105","C"),12), (("101", "B"),4)]
d = defaultdict(list)
for (x, y), z in data:
d[x].append((y, z))
result = [
((k, *tuple(map(itemgetter(0), v))), sum(map(itemgetter(1), v)))
for k, v in d.items()
]
print(result)
# [(('101', 'A', 'B'), 9), (('105', 'C'), 12)]
answered Nov 20 at 5:12
RoadRunner
10.2k31340
edited Nov 20 at 5:53
answered Nov 20 at 5:12
RoadRunner
10.2k31340
answered Nov 20 at 5:12
RoadRunner
10.2k31340
answered Nov 20 at 5:12
RoadRunner
10.2k31340
10.2k31340
add a comment |
add a comment |
3
for k in final_values:
print '%s: sum is %d' % (k, sum([x for x in final_values[k] if type(x) is int]))
answered Nov 20 at 5:10
John Gordon
9,48051728
add a comment |
3
for k in final_values:
print '%s: sum is %d' % (k, sum([x for x in final_values[k] if type(x) is int]))
answered Nov 20 at 5:10
John Gordon
9,48051728
add a comment |
3
3
3
for k in final_values:
print '%s: sum is %d' % (k, sum([x for x in final_values[k] if type(x) is int]))
answered Nov 20 at 5:10
John Gordon
9,48051728
for k in final_values:
print '%s: sum is %d' % (k, sum([x for x in final_values[k] if type(x) is int]))
answered Nov 20 at 5:10
John Gordon
9,48051728
answered Nov 20 at 5:10
John Gordon
9,48051728
answered Nov 20 at 5:10
John Gordon
9,48051728
answered Nov 20 at 5:10
John Gordon
9,48051728
9,48051728
add a comment |
add a comment |
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