How to remove the white space in a string or make a regular expression that would accept all type of valid...
I have a string which is separated by a "," like string:= "abc@bk.com, cde@bk.com" I want to make a regular expression which will cover all the whitespace after and before the emails or is there another function strings.Replace to replace the whitespace? They both do the same work but I don't know which is better. If the regular expression is better then an you give a example and if strings.Replace function is better then provide an example of that. I have tried a small code on it:-
package main
import (
"fmt"
"regexp"
"strings"
)
type User struct {
Name CustomerDetails `json:"name" bson:"name"`
}
type CustomerDetails struct {
Value string `json:"value" bson:"value"`
Note string `json:"note" bson:"note"`
SendNotifications bool `json:"send_notifications" bson:"send_notifications"`
}
func main() {
var emailRegexp = regexp.MustCompile("^[a-zA-Z0-9.!#$%&'*+/=?^_`{|}~-]+@[a-zA-Z0-9](?:[a-zA-Z0-9-]{0,61}[a-zA-Z0-9])?(?:\.[a-zA-Z0-9](?:[a-zA-Z0-9-]{0,61}[a-zA-Z0-9])?)*$")
var custName User
emails := "abc@bk.com, cde@bk.com"
splitEmails := strings.Split(emails, ",")
fmt.Println(splitEmails)
for _, email := range splitEmails {
email = strings.Replace(email, " ", "", -1)
if emailRegexp.MatchString(email) {
custName.Name = append(custName.Name, CustomerDetails{
Value: email,
})
}
}
fmt.Println(custName)
}
This example is based on the function strings.Replace. Can anybody help me to solve this?
Thanks for your precious time.
regex string go whitespace
edited Nov 22 '18 at 7:29
Nick
31.6k121942
asked Nov 22 '18 at 7:12
user10665991user10665991
64
add a comment |
I have a string which is separated by a "," like string:= "abc@bk.com, cde@bk.com" I want to make a regular expression which will cover all the whitespace after and before the emails or is there another function strings.Replace to replace the whitespace? They both do the same work but I don't know which is better. If the regular expression is better then an you give a example and if strings.Replace function is better then provide an example of that. I have tried a small code on it:-
package main
import (
"fmt"
"regexp"
"strings"
)
type User struct {
Name CustomerDetails `json:"name" bson:"name"`
}
type CustomerDetails struct {
Value string `json:"value" bson:"value"`
Note string `json:"note" bson:"note"`
SendNotifications bool `json:"send_notifications" bson:"send_notifications"`
}
func main() {
var emailRegexp = regexp.MustCompile("^[a-zA-Z0-9.!#$%&'*+/=?^_`{|}~-]+@[a-zA-Z0-9](?:[a-zA-Z0-9-]{0,61}[a-zA-Z0-9])?(?:\.[a-zA-Z0-9](?:[a-zA-Z0-9-]{0,61}[a-zA-Z0-9])?)*$")
var custName User
emails := "abc@bk.com, cde@bk.com"
splitEmails := strings.Split(emails, ",")
fmt.Println(splitEmails)
for _, email := range splitEmails {
email = strings.Replace(email, " ", "", -1)
if emailRegexp.MatchString(email) {
custName.Name = append(custName.Name, CustomerDetails{
Value: email,
})
}
}
fmt.Println(custName)
}
This example is based on the function strings.Replace. Can anybody help me to solve this?
Thanks for your precious time.
regex string go whitespace
edited Nov 22 '18 at 7:29
Nick
31.6k121942
asked Nov 22 '18 at 7:12
user10665991user10665991
64
1
You cannot and you must not try this: This will fail. Email addresses are far to complex to parse with a regexp. Do what Flimzy suggests.
– Volker
Nov 22 '18 at 8:18
add a comment |
I have a string which is separated by a "," like string:= "abc@bk.com, cde@bk.com" I want to make a regular expression which will cover all the whitespace after and before the emails or is there another function strings.Replace to replace the whitespace? They both do the same work but I don't know which is better. If the regular expression is better then an you give a example and if strings.Replace function is better then provide an example of that. I have tried a small code on it:-
package main
import (
"fmt"
"regexp"
"strings"
)
type User struct {
Name CustomerDetails `json:"name" bson:"name"`
}
type CustomerDetails struct {
Value string `json:"value" bson:"value"`
Note string `json:"note" bson:"note"`
SendNotifications bool `json:"send_notifications" bson:"send_notifications"`
}
func main() {
var emailRegexp = regexp.MustCompile("^[a-zA-Z0-9.!#$%&'*+/=?^_`{|}~-]+@[a-zA-Z0-9](?:[a-zA-Z0-9-]{0,61}[a-zA-Z0-9])?(?:\.[a-zA-Z0-9](?:[a-zA-Z0-9-]{0,61}[a-zA-Z0-9])?)*$")
var custName User
emails := "abc@bk.com, cde@bk.com"
splitEmails := strings.Split(emails, ",")
fmt.Println(splitEmails)
for _, email := range splitEmails {
email = strings.Replace(email, " ", "", -1)
if emailRegexp.MatchString(email) {
custName.Name = append(custName.Name, CustomerDetails{
Value: email,
})
}
}
fmt.Println(custName)
}
This example is based on the function strings.Replace. Can anybody help me to solve this?
Thanks for your precious time.
regex string go whitespace
edited Nov 22 '18 at 7:29
Nick
31.6k121942
asked Nov 22 '18 at 7:12
user10665991user10665991
64
I have a string which is separated by a "," like string:= "abc@bk.com, cde@bk.com" I want to make a regular expression which will cover all the whitespace after and before the emails or is there another function strings.Replace to replace the whitespace? They both do the same work but I don't know which is better. If the regular expression is better then an you give a example and if strings.Replace function is better then provide an example of that. I have tried a small code on it:-
package main
import (
"fmt"
"regexp"
"strings"
)
type User struct {
Name CustomerDetails `json:"name" bson:"name"`
}
type CustomerDetails struct {
Value string `json:"value" bson:"value"`
Note string `json:"note" bson:"note"`
SendNotifications bool `json:"send_notifications" bson:"send_notifications"`
}
func main() {
var emailRegexp = regexp.MustCompile("^[a-zA-Z0-9.!#$%&'*+/=?^_`{|}~-]+@[a-zA-Z0-9](?:[a-zA-Z0-9-]{0,61}[a-zA-Z0-9])?(?:\.[a-zA-Z0-9](?:[a-zA-Z0-9-]{0,61}[a-zA-Z0-9])?)*$")
var custName User
emails := "abc@bk.com, cde@bk.com"
splitEmails := strings.Split(emails, ",")
fmt.Println(splitEmails)
for _, email := range splitEmails {
email = strings.Replace(email, " ", "", -1)
if emailRegexp.MatchString(email) {
custName.Name = append(custName.Name, CustomerDetails{
Value: email,
})
}
}
fmt.Println(custName)
}
This example is based on the function strings.Replace. Can anybody help me to solve this?
Thanks for your precious time.
regex string go whitespace
regex string go whitespace
edited Nov 22 '18 at 7:29
Nick
31.6k121942
asked Nov 22 '18 at 7:12
user10665991user10665991
64
edited Nov 22 '18 at 7:29
Nick
31.6k121942
asked Nov 22 '18 at 7:12
user10665991user10665991
64
edited Nov 22 '18 at 7:29
Nick
31.6k121942
edited Nov 22 '18 at 7:29
Nick
31.6k121942
edited Nov 22 '18 at 7:29
Nick
31.6k121942
31.6k121942
asked Nov 22 '18 at 7:12
user10665991user10665991
64
asked Nov 22 '18 at 7:12
user10665991user10665991
64
asked Nov 22 '18 at 7:12
user10665991user10665991
64
64
1
You cannot and you must not try this: This will fail. Email addresses are far to complex to parse with a regexp. Do what Flimzy suggests.
– Volker
Nov 22 '18 at 8:18
add a comment |
1
You cannot and you must not try this: This will fail. Email addresses are far to complex to parse with a regexp. Do what Flimzy suggests.
– Volker
Nov 22 '18 at 8:18
1
1
You cannot and you must not try this: This will fail. Email addresses are far to complex to parse with a regexp. Do what Flimzy suggests.
– Volker
Nov 22 '18 at 8:18
You cannot and you must not try this: This will fail. Email addresses are far to complex to parse with a regexp. Do what Flimzy suggests.
– Volker
Nov 22 '18 at 8:18
add a comment |
2 Answers
2
active
oldest
votes
Do not use regular expressions for this. Your current approach, of splitting on white space, will break with valid email addresses that contain whitespace. While it is possible to parse many email addresses with a regular expression, the necessary regular expression is very, very ugly, and even that doesn't handle all corner cases.
Instead, to parse a list of email addresses, you should use the standard library's mail.ParseAddressList function.
answered Nov 22 '18 at 7:46
FlimzyFlimzy
38.8k106597
The expression in the linked answer is often quoted, however "the regular expression does not cope with comments in email addresses. The RFC allows comments to be arbitrarily nested. A single regular expression cannot cope with this." ex-parrot.com/~pdw/Mail-RFC822-Address.html. There is also the matter that this is Perl syntax and does not work unmodified in RE2. So yeah, definitely use the parsing functions in the mail package.
– Peter
Nov 22 '18 at 9:10
@Peter: Thanks, I've added a comment to the effect that the mentioned RE isn't complete.
– Flimzy
Nov 22 '18 at 11:14
add a comment |
You may use .strip() to clear whitespace on both sides.
Or re.split() to split with pattern /,s*/.
answered Nov 22 '18 at 7:51
TechnobulkaTechnobulka
14
This question is about Go.
– Flimzy
Nov 22 '18 at 11:15
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Do not use regular expressions for this. Your current approach, of splitting on white space, will break with valid email addresses that contain whitespace. While it is possible to parse many email addresses with a regular expression, the necessary regular expression is very, very ugly, and even that doesn't handle all corner cases.
Instead, to parse a list of email addresses, you should use the standard library's mail.ParseAddressList function.
answered Nov 22 '18 at 7:46
FlimzyFlimzy
38.8k106597
The expression in the linked answer is often quoted, however "the regular expression does not cope with comments in email addresses. The RFC allows comments to be arbitrarily nested. A single regular expression cannot cope with this." ex-parrot.com/~pdw/Mail-RFC822-Address.html. There is also the matter that this is Perl syntax and does not work unmodified in RE2. So yeah, definitely use the parsing functions in the mail package.
– Peter
Nov 22 '18 at 9:10
@Peter: Thanks, I've added a comment to the effect that the mentioned RE isn't complete.
– Flimzy
Nov 22 '18 at 11:14
add a comment |
Do not use regular expressions for this. Your current approach, of splitting on white space, will break with valid email addresses that contain whitespace. While it is possible to parse many email addresses with a regular expression, the necessary regular expression is very, very ugly, and even that doesn't handle all corner cases.
Instead, to parse a list of email addresses, you should use the standard library's mail.ParseAddressList function.
answered Nov 22 '18 at 7:46
FlimzyFlimzy
38.8k106597
The expression in the linked answer is often quoted, however "the regular expression does not cope with comments in email addresses. The RFC allows comments to be arbitrarily nested. A single regular expression cannot cope with this." ex-parrot.com/~pdw/Mail-RFC822-Address.html. There is also the matter that this is Perl syntax and does not work unmodified in RE2. So yeah, definitely use the parsing functions in the mail package.
– Peter
Nov 22 '18 at 9:10
@Peter: Thanks, I've added a comment to the effect that the mentioned RE isn't complete.
– Flimzy
Nov 22 '18 at 11:14
add a comment |
Do not use regular expressions for this. Your current approach, of splitting on white space, will break with valid email addresses that contain whitespace. While it is possible to parse many email addresses with a regular expression, the necessary regular expression is very, very ugly, and even that doesn't handle all corner cases.
Instead, to parse a list of email addresses, you should use the standard library's mail.ParseAddressList function.
answered Nov 22 '18 at 7:46
FlimzyFlimzy
38.8k106597
Do not use regular expressions for this. Your current approach, of splitting on white space, will break with valid email addresses that contain whitespace. While it is possible to parse many email addresses with a regular expression, the necessary regular expression is very, very ugly, and even that doesn't handle all corner cases.
Instead, to parse a list of email addresses, you should use the standard library's mail.ParseAddressList function.
answered Nov 22 '18 at 7:46
FlimzyFlimzy
38.8k106597
edited Nov 22 '18 at 11:22
answered Nov 22 '18 at 7:46
FlimzyFlimzy
38.8k106597
answered Nov 22 '18 at 7:46
FlimzyFlimzy
38.8k106597
answered Nov 22 '18 at 7:46
FlimzyFlimzy
38.8k106597
38.8k106597
The expression in the linked answer is often quoted, however "the regular expression does not cope with comments in email addresses. The RFC allows comments to be arbitrarily nested. A single regular expression cannot cope with this." ex-parrot.com/~pdw/Mail-RFC822-Address.html. There is also the matter that this is Perl syntax and does not work unmodified in RE2. So yeah, definitely use the parsing functions in the mail package.
– Peter
Nov 22 '18 at 9:10
@Peter: Thanks, I've added a comment to the effect that the mentioned RE isn't complete.
– Flimzy
Nov 22 '18 at 11:14
add a comment |
The expression in the linked answer is often quoted, however "the regular expression does not cope with comments in email addresses. The RFC allows comments to be arbitrarily nested. A single regular expression cannot cope with this." ex-parrot.com/~pdw/Mail-RFC822-Address.html. There is also the matter that this is Perl syntax and does not work unmodified in RE2. So yeah, definitely use the parsing functions in the mail package.
– Peter
Nov 22 '18 at 9:10
@Peter: Thanks, I've added a comment to the effect that the mentioned RE isn't complete.
– Flimzy
Nov 22 '18 at 11:14
The expression in the linked answer is often quoted, however "the regular expression does not cope with comments in email addresses. The RFC allows comments to be arbitrarily nested. A single regular expression cannot cope with this." ex-parrot.com/~pdw/Mail-RFC822-Address.html. There is also the matter that this is Perl syntax and does not work unmodified in RE2. So yeah, definitely use the parsing functions in the mail package.
– Peter
Nov 22 '18 at 9:10
The expression in the linked answer is often quoted, however "the regular expression does not cope with comments in email addresses. The RFC allows comments to be arbitrarily nested. A single regular expression cannot cope with this." ex-parrot.com/~pdw/Mail-RFC822-Address.html. There is also the matter that this is Perl syntax and does not work unmodified in RE2. So yeah, definitely use the parsing functions in the mail package.
– Peter
Nov 22 '18 at 9:10
@Peter: Thanks, I've added a comment to the effect that the mentioned RE isn't complete.
– Flimzy
Nov 22 '18 at 11:14
@Peter: Thanks, I've added a comment to the effect that the mentioned RE isn't complete.
– Flimzy
Nov 22 '18 at 11:14
add a comment |
You may use .strip() to clear whitespace on both sides.
Or re.split() to split with pattern /,s*/.
answered Nov 22 '18 at 7:51
TechnobulkaTechnobulka
14
This question is about Go.
– Flimzy
Nov 22 '18 at 11:15
add a comment |
You may use .strip() to clear whitespace on both sides.
Or re.split() to split with pattern /,s*/.
answered Nov 22 '18 at 7:51
TechnobulkaTechnobulka
14
This question is about Go.
– Flimzy
Nov 22 '18 at 11:15
add a comment |
You may use .strip() to clear whitespace on both sides.
Or re.split() to split with pattern /,s*/.
answered Nov 22 '18 at 7:51
TechnobulkaTechnobulka
14
You may use .strip() to clear whitespace on both sides.
Or re.split() to split with pattern /,s*/.
answered Nov 22 '18 at 7:51
TechnobulkaTechnobulka
14
answered Nov 22 '18 at 7:51
TechnobulkaTechnobulka
14
answered Nov 22 '18 at 7:51
TechnobulkaTechnobulka
14
answered Nov 22 '18 at 7:51
TechnobulkaTechnobulka
14
14
This question is about Go.
– Flimzy
Nov 22 '18 at 11:15
add a comment |
This question is about Go.
– Flimzy
Nov 22 '18 at 11:15
This question is about Go.
– Flimzy
Nov 22 '18 at 11:15
This question is about Go.
– Flimzy
Nov 22 '18 at 11:15
add a comment |
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1
You cannot and you must not try this: This will fail. Email addresses are far to complex to parse with a regexp. Do what Flimzy suggests.
– Volker
Nov 22 '18 at 8:18