How do I slice a string by characters in Python? [duplicate]
9
This question already has an answer here:
Python - Find sequence of same characters
3 answers
Splitting a string with repeated characters into a list using regex
3 answers
There is a string with one or more characters. I want to slice the list so that the adjoining same characters are in the same element. For example:
'a' -> ['a']
'abbbcc' -> ['a', 'bbb', 'cc']
'abcabc' -> ['a', 'b', 'c', 'a', 'b', 'c']
How do I make this in Python?
python
edited yesterday
Peter Mortensen
13.8k1987113
asked yesterday
Hank ChowHank Chow
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marked as duplicate by Kasrâmvd python
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yesterday
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
add a comment |
9
This question already has an answer here:
Python - Find sequence of same characters
3 answers
Splitting a string with repeated characters into a list using regex
3 answers
There is a string with one or more characters. I want to slice the list so that the adjoining same characters are in the same element. For example:
'a' -> ['a']
'abbbcc' -> ['a', 'bbb', 'cc']
'abcabc' -> ['a', 'b', 'c', 'a', 'b', 'c']
How do I make this in Python?
python
edited yesterday
Peter Mortensen
13.8k1987113
asked yesterday
Hank ChowHank Chow
571
marked as duplicate by Kasrâmvd python
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yesterday
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
1
FYI, if you google "python group identical elements" or something similar you'll find plenty of recipes that would help you get started.
– Aran-Fey
yesterday
add a comment |
9
9
9
3
This question already has an answer here:
Python - Find sequence of same characters
3 answers
Splitting a string with repeated characters into a list using regex
3 answers
There is a string with one or more characters. I want to slice the list so that the adjoining same characters are in the same element. For example:
'a' -> ['a']
'abbbcc' -> ['a', 'bbb', 'cc']
'abcabc' -> ['a', 'b', 'c', 'a', 'b', 'c']
How do I make this in Python?
python
edited yesterday
Peter Mortensen
13.8k1987113
asked yesterday
Hank ChowHank Chow
571
This question already has an answer here:
Python - Find sequence of same characters
3 answers
Splitting a string with repeated characters into a list using regex
3 answers
There is a string with one or more characters. I want to slice the list so that the adjoining same characters are in the same element. For example:
'a' -> ['a']
'abbbcc' -> ['a', 'bbb', 'cc']
'abcabc' -> ['a', 'b', 'c', 'a', 'b', 'c']
How do I make this in Python?
This question already has an answer here:
Python - Find sequence of same characters
3 answers
Splitting a string with repeated characters into a list using regex
3 answers
python
python
edited yesterday
Peter Mortensen
13.8k1987113
asked yesterday
Hank ChowHank Chow
571
edited yesterday
Peter Mortensen
13.8k1987113
asked yesterday
Hank ChowHank Chow
571
edited yesterday
Peter Mortensen
13.8k1987113
edited yesterday
Peter Mortensen
13.8k1987113
edited yesterday
Peter Mortensen
13.8k1987113
13.8k1987113
asked yesterday
Hank ChowHank Chow
571
asked yesterday
Hank ChowHank Chow
571
asked yesterday
Hank ChowHank Chow
571
571
marked as duplicate by Kasrâmvd python
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yesterday
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
1
FYI, if you google "python group identical elements" or something similar you'll find plenty of recipes that would help you get started.
– Aran-Fey
yesterday
add a comment |
1
FYI, if you google "python group identical elements" or something similar you'll find plenty of recipes that would help you get started.
– Aran-Fey
yesterday
1
1
FYI, if you google "python group identical elements" or something similar you'll find plenty of recipes that would help you get started.
– Aran-Fey
yesterday
FYI, if you google "python group identical elements" or something similar you'll find plenty of recipes that would help you get started.
– Aran-Fey
yesterday
add a comment |
5 Answers
5
active
oldest
votes
15
Use itertools.groupby:
from itertools import groupby
s = 'abccbba'
print([''.join(v) for _, v in groupby(s)])
# ['a', 'b', 'cc', 'bb', 'a']
edited yesterday
Aran-Fey
20.1k53671
answered yesterday
AustinAustin
12.3k3930
add a comment |
4
Can be achieved with re.finditer()
import re
s='aabccdd'
print([m.group(0) for m in re.finditer(r"(w)1*", s)])
#['aa', 'b', 'cc', 'dd']
answered yesterday
denis_lordenis_lor
1,45611130
add a comment |
2
Without any modules and using for loop also it can be done in interesting way:
l=
str="aabccc"
s=str[0]
for c in str[1:]:
if(c!=s[-1]):
l.append(s)
s=c
else:
s=s+c
l.append(s)
print(l)
answered yesterday
TojrahTojrah
461
New contributor
Tojrah is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
2
Just one more alternative solution. You need no import for it in python2. In python3 you need import from functools.
from functools import reduce # in python3
s='aaabccdddddaa'
reduce(lambda x,y:x[:-1]+[x[-1]+y] if len(x)>0 and x[-1][-1]==y else x+[y], s, )
answered yesterday
quantummindquantummind
1,3541817
5
Wow...this is as unreadable as it could get...
– heemayl
yesterday
add a comment |
1
t=input()
c=[t[0]]
for i in range(1,len(t)):
if t[i]==c[-1][0]:
c[-1]=c[-1]+t[i]
else:
c.append(t[i])
print(c)
answered yesterday
Mr.AMr.A
112
New contributor
Mr.A is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Please add some text to make the answer more descriptive.
– v.coder
yesterday
add a comment |
5 Answers
5
active
oldest
votes
5 Answers
5
active
oldest
votes
active
oldest
votes
active
oldest
votes
15
Use itertools.groupby:
from itertools import groupby
s = 'abccbba'
print([''.join(v) for _, v in groupby(s)])
# ['a', 'b', 'cc', 'bb', 'a']
edited yesterday
Aran-Fey
20.1k53671
answered yesterday
AustinAustin
12.3k3930
add a comment |
15
Use itertools.groupby:
from itertools import groupby
s = 'abccbba'
print([''.join(v) for _, v in groupby(s)])
# ['a', 'b', 'cc', 'bb', 'a']
edited yesterday
Aran-Fey
20.1k53671
answered yesterday
AustinAustin
12.3k3930
add a comment |
15
15
15
Use itertools.groupby:
from itertools import groupby
s = 'abccbba'
print([''.join(v) for _, v in groupby(s)])
# ['a', 'b', 'cc', 'bb', 'a']
edited yesterday
Aran-Fey
20.1k53671
answered yesterday
AustinAustin
12.3k3930
Use itertools.groupby:
from itertools import groupby
s = 'abccbba'
print([''.join(v) for _, v in groupby(s)])
# ['a', 'b', 'cc', 'bb', 'a']
edited yesterday
Aran-Fey
20.1k53671
answered yesterday
AustinAustin
12.3k3930
edited yesterday
Aran-Fey
20.1k53671
edited yesterday
Aran-Fey
20.1k53671
edited yesterday
Aran-Fey
20.1k53671
20.1k53671
answered yesterday
AustinAustin
12.3k3930
answered yesterday
AustinAustin
12.3k3930
answered yesterday
AustinAustin
12.3k3930
12.3k3930
add a comment |
add a comment |
4
Can be achieved with re.finditer()
import re
s='aabccdd'
print([m.group(0) for m in re.finditer(r"(w)1*", s)])
#['aa', 'b', 'cc', 'dd']
answered yesterday
denis_lordenis_lor
1,45611130
add a comment |
4
Can be achieved with re.finditer()
import re
s='aabccdd'
print([m.group(0) for m in re.finditer(r"(w)1*", s)])
#['aa', 'b', 'cc', 'dd']
answered yesterday
denis_lordenis_lor
1,45611130
add a comment |
4
4
4
Can be achieved with re.finditer()
import re
s='aabccdd'
print([m.group(0) for m in re.finditer(r"(w)1*", s)])
#['aa', 'b', 'cc', 'dd']
answered yesterday
denis_lordenis_lor
1,45611130
Can be achieved with re.finditer()
import re
s='aabccdd'
print([m.group(0) for m in re.finditer(r"(w)1*", s)])
#['aa', 'b', 'cc', 'dd']
answered yesterday
denis_lordenis_lor
1,45611130
answered yesterday
denis_lordenis_lor
1,45611130
answered yesterday
denis_lordenis_lor
1,45611130
answered yesterday
denis_lordenis_lor
1,45611130
1,45611130
add a comment |
add a comment |
2
Without any modules and using for loop also it can be done in interesting way:
l=
str="aabccc"
s=str[0]
for c in str[1:]:
if(c!=s[-1]):
l.append(s)
s=c
else:
s=s+c
l.append(s)
print(l)
answered yesterday
TojrahTojrah
461
New contributor
Tojrah is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
2
Without any modules and using for loop also it can be done in interesting way:
l=
str="aabccc"
s=str[0]
for c in str[1:]:
if(c!=s[-1]):
l.append(s)
s=c
else:
s=s+c
l.append(s)
print(l)
answered yesterday
TojrahTojrah
461
New contributor
Tojrah is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
2
2
2
Without any modules and using for loop also it can be done in interesting way:
l=
str="aabccc"
s=str[0]
for c in str[1:]:
if(c!=s[-1]):
l.append(s)
s=c
else:
s=s+c
l.append(s)
print(l)
answered yesterday
TojrahTojrah
461
New contributor
Tojrah is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Without any modules and using for loop also it can be done in interesting way:
l=
str="aabccc"
s=str[0]
for c in str[1:]:
if(c!=s[-1]):
l.append(s)
s=c
else:
s=s+c
l.append(s)
print(l)
answered yesterday
TojrahTojrah
461
New contributor
Tojrah is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered yesterday
TojrahTojrah
461
New contributor
Tojrah is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered yesterday
TojrahTojrah
461
answered yesterday
TojrahTojrah
461
461
New contributor
Tojrah is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Tojrah is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Tojrah is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
2
Just one more alternative solution. You need no import for it in python2. In python3 you need import from functools.
from functools import reduce # in python3
s='aaabccdddddaa'
reduce(lambda x,y:x[:-1]+[x[-1]+y] if len(x)>0 and x[-1][-1]==y else x+[y], s, )
answered yesterday
quantummindquantummind
1,3541817
5
Wow...this is as unreadable as it could get...
– heemayl
yesterday
add a comment |
2
Just one more alternative solution. You need no import for it in python2. In python3 you need import from functools.
from functools import reduce # in python3
s='aaabccdddddaa'
reduce(lambda x,y:x[:-1]+[x[-1]+y] if len(x)>0 and x[-1][-1]==y else x+[y], s, )
answered yesterday
quantummindquantummind
1,3541817
5
Wow...this is as unreadable as it could get...
– heemayl
yesterday
add a comment |
2
2
2
Just one more alternative solution. You need no import for it in python2. In python3 you need import from functools.
from functools import reduce # in python3
s='aaabccdddddaa'
reduce(lambda x,y:x[:-1]+[x[-1]+y] if len(x)>0 and x[-1][-1]==y else x+[y], s, )
answered yesterday
quantummindquantummind
1,3541817
Just one more alternative solution. You need no import for it in python2. In python3 you need import from functools.
from functools import reduce # in python3
s='aaabccdddddaa'
reduce(lambda x,y:x[:-1]+[x[-1]+y] if len(x)>0 and x[-1][-1]==y else x+[y], s, )
answered yesterday
quantummindquantummind
1,3541817
answered yesterday
quantummindquantummind
1,3541817
answered yesterday
quantummindquantummind
1,3541817
answered yesterday
quantummindquantummind
1,3541817
1,3541817
5
Wow...this is as unreadable as it could get...
– heemayl
yesterday
add a comment |
5
Wow...this is as unreadable as it could get...
– heemayl
yesterday
5
5
Wow...this is as unreadable as it could get...
– heemayl
yesterday
Wow...this is as unreadable as it could get...
– heemayl
yesterday
add a comment |
1
t=input()
c=[t[0]]
for i in range(1,len(t)):
if t[i]==c[-1][0]:
c[-1]=c[-1]+t[i]
else:
c.append(t[i])
print(c)
answered yesterday
Mr.AMr.A
112
New contributor
Mr.A is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Please add some text to make the answer more descriptive.
– v.coder
yesterday
add a comment |
1
t=input()
c=[t[0]]
for i in range(1,len(t)):
if t[i]==c[-1][0]:
c[-1]=c[-1]+t[i]
else:
c.append(t[i])
print(c)
answered yesterday
Mr.AMr.A
112
New contributor
Mr.A is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Please add some text to make the answer more descriptive.
– v.coder
yesterday
add a comment |
1
1
1
t=input()
c=[t[0]]
for i in range(1,len(t)):
if t[i]==c[-1][0]:
c[-1]=c[-1]+t[i]
else:
c.append(t[i])
print(c)
answered yesterday
Mr.AMr.A
112
New contributor
Mr.A is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
t=input()
c=[t[0]]
for i in range(1,len(t)):
if t[i]==c[-1][0]:
c[-1]=c[-1]+t[i]
else:
c.append(t[i])
print(c)
answered yesterday
Mr.AMr.A
112
New contributor
Mr.A is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered yesterday
Mr.AMr.A
112
New contributor
Mr.A is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered yesterday
Mr.AMr.A
112
answered yesterday
Mr.AMr.A
112
112
New contributor
Mr.A is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Mr.A is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Mr.A is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Please add some text to make the answer more descriptive.
– v.coder
yesterday
add a comment |
Please add some text to make the answer more descriptive.
– v.coder
yesterday
Please add some text to make the answer more descriptive.
– v.coder
yesterday
Please add some text to make the answer more descriptive.
– v.coder
yesterday
add a comment |
1
FYI, if you google "python group identical elements" or something similar you'll find plenty of recipes that would help you get started.
– Aran-Fey
yesterday