Levi-Civita symbol: 3D matrix












13















During the current review of the tensors I have arrived at a page of Wikipedia where you can see the symbol of Levi-Civita in a beautiful three-dimensional matrix.



enter image description here



I hope that nobody will be angry with me if I do not produce any MWE but for me it would be nice to see the construction of a matrix so made and can be made available to other users.










share|improve this question


















  • 2





    Nobody will be angry, don't worry. If I hadn't reached my 40-vote limit, you would have got my +1. Your question is very interesting (and hard).

    – JouleV
    10 hours ago













  • @JouleV LOL LOL when I thought about what to write, I sincerely thought about you :-). Isn't it that you write to me that I'm 10k and I don't produce even a minimum MWE?

    – Sebastiano
    10 hours ago






  • 1





    Well, I was thinking about how to solve this and I read that word ;-) lol I knew I had to write something :D

    – JouleV
    10 hours ago
















13















During the current review of the tensors I have arrived at a page of Wikipedia where you can see the symbol of Levi-Civita in a beautiful three-dimensional matrix.



enter image description here



I hope that nobody will be angry with me if I do not produce any MWE but for me it would be nice to see the construction of a matrix so made and can be made available to other users.










share|improve this question


















  • 2





    Nobody will be angry, don't worry. If I hadn't reached my 40-vote limit, you would have got my +1. Your question is very interesting (and hard).

    – JouleV
    10 hours ago













  • @JouleV LOL LOL when I thought about what to write, I sincerely thought about you :-). Isn't it that you write to me that I'm 10k and I don't produce even a minimum MWE?

    – Sebastiano
    10 hours ago






  • 1





    Well, I was thinking about how to solve this and I read that word ;-) lol I knew I had to write something :D

    – JouleV
    10 hours ago














13












13








13


2






During the current review of the tensors I have arrived at a page of Wikipedia where you can see the symbol of Levi-Civita in a beautiful three-dimensional matrix.



enter image description here



I hope that nobody will be angry with me if I do not produce any MWE but for me it would be nice to see the construction of a matrix so made and can be made available to other users.










share|improve this question














During the current review of the tensors I have arrived at a page of Wikipedia where you can see the symbol of Levi-Civita in a beautiful three-dimensional matrix.



enter image description here



I hope that nobody will be angry with me if I do not produce any MWE but for me it would be nice to see the construction of a matrix so made and can be made available to other users.







matrices 3d tikz-matrix






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked 10 hours ago









SebastianoSebastiano

10.5k42061




10.5k42061








  • 2





    Nobody will be angry, don't worry. If I hadn't reached my 40-vote limit, you would have got my +1. Your question is very interesting (and hard).

    – JouleV
    10 hours ago













  • @JouleV LOL LOL when I thought about what to write, I sincerely thought about you :-). Isn't it that you write to me that I'm 10k and I don't produce even a minimum MWE?

    – Sebastiano
    10 hours ago






  • 1





    Well, I was thinking about how to solve this and I read that word ;-) lol I knew I had to write something :D

    – JouleV
    10 hours ago














  • 2





    Nobody will be angry, don't worry. If I hadn't reached my 40-vote limit, you would have got my +1. Your question is very interesting (and hard).

    – JouleV
    10 hours ago













  • @JouleV LOL LOL when I thought about what to write, I sincerely thought about you :-). Isn't it that you write to me that I'm 10k and I don't produce even a minimum MWE?

    – Sebastiano
    10 hours ago






  • 1





    Well, I was thinking about how to solve this and I read that word ;-) lol I knew I had to write something :D

    – JouleV
    10 hours ago








2




2





Nobody will be angry, don't worry. If I hadn't reached my 40-vote limit, you would have got my +1. Your question is very interesting (and hard).

– JouleV
10 hours ago







Nobody will be angry, don't worry. If I hadn't reached my 40-vote limit, you would have got my +1. Your question is very interesting (and hard).

– JouleV
10 hours ago















@JouleV LOL LOL when I thought about what to write, I sincerely thought about you :-). Isn't it that you write to me that I'm 10k and I don't produce even a minimum MWE?

– Sebastiano
10 hours ago





@JouleV LOL LOL when I thought about what to write, I sincerely thought about you :-). Isn't it that you write to me that I'm 10k and I don't produce even a minimum MWE?

– Sebastiano
10 hours ago




1




1





Well, I was thinking about how to solve this and I read that word ;-) lol I knew I had to write something :D

– JouleV
10 hours ago





Well, I was thinking about how to solve this and I read that word ;-) lol I knew I had to write something :D

– JouleV
10 hours ago










2 Answers
2






active

oldest

votes


















13














More or less:



documentclass[tikz,border=2mm]{standalone} 
usetikzlibrary{positioning, matrix}
usepackage{amsmath}

newcommand{arrayfilling}[2]{
fill[#2!30, opacity=.5] ([shift={(1mm,1mm)}]#1.north west) coordinate(#1auxnw)--([shift={(1mm,1mm)}]#1.north east)coordinate(#1auxne) to[out=-75, in=75] ([shift={(1mm,-1mm)}]#1.south east)coordinate(#1auxse)--([shift={(1mm,-1mm)}]#1.south west)coordinate(#1auxsw) to[out=105, in=-105] cycle;
fill[#2!80!black, opacity=1] (#1auxne) to[out=-75, in=75] (#1auxse) to[out=78, in=-78] cycle;
fill[#2!80!black, opacity=1] (#1auxnw) to[out=-105, in=105] (#1auxsw) to[out=102, in=-102] cycle;
}


begin{document}
begin{tikzpicture}[font=ttfamily,
mymatrix/.style={
matrix of math nodes, inner sep=0pt, color=#1,
column sep=-pgflinewidth, row sep=-pgflinewidth, anchor=south west,
nodes={anchor=center, minimum width=5mm,
minimum height=3mm, outer sep=0pt, inner sep=0pt,
text width=5mm, align=right,
draw=none, font=small},
}
]

matrix (C) [mymatrix=green] at (6mm,5mm)
{0 & 1 & 0 \ -1 & 0 & 0\ 0 & 0 & 0\};
arrayfilling{C}{green}

matrix (B) [mymatrix=red] at (3mm,2.5mm)
{0 & 0 & -1 \ 0 & 0 & 0\ 1 & 0 & 0\};
arrayfilling{B}{red}

matrix (A) [mymatrix=blue] at (0,0)
{0 & 0 & 0 \ 0 & 0 & 1\ 0 & -1 & 0\};
arrayfilling{A}{blue}

foreach i in {auxnw, auxne, auxse, auxsw}
draw[brown, ultra thin] (Ai)--(Ci);

node[below left=-1mm and 5mm of B.west] {$epsilon_{ijk} =$};
end{tikzpicture}
end{document}


enter image description here






share|improve this answer


























  • Please see point (1) in my comment to the answer by @marmot.

    – barbara beeton
    9 hours ago











  • @barbarabeeton Is it better now?

    – Ignasi
    9 hours ago











  • Yes, better. one might quibble that there is more space than necessary, compared with the space at the right. I think it's best to pay attention to what is actually present in each column, but that does require more attention.

    – barbara beeton
    8 hours ago



















12














Something like that?



documentclass[tikz,border=3.14mm]{standalone}
usepackage{mathtools}
usetikzlibrary{matrix,backgrounds,3d}
usepackage{tikz-3dplot}
%definecolor{mygreen}{RGB}{12,252,12}
begin{document}
tdplotsetmaincoords{75}{20}
begin{tikzpicture}[tdplot_main_coords]
begin{scope}[canvas is xz plane at y=1,transform shape]
node[inner sep=0pt,text=green!70!black,opacity=0.8] (mat1)
{$displaystylebegin{pmatrix*}[r]
0 & 1 & 0 \
-1 & 0 & 0 \
0 & 0 & 0 \
end{pmatrix*}$};
begin{scope}[on background layer]
fill[green!70!black,opacity=0.2] ([xshift=8.5pt]mat1.south west)
coordinate (blb) to[out=140,in=-140,looseness=0.7]
([xshift=8.5pt]mat1.north west) coordinate (tlb) --
([xshift=-8.5pt]mat1.north east) coordinate (trb)
to[out=-40,in=40,looseness=0.7] ([xshift=-8.5pt]mat1.south east)
coordinate (brb)
-- cycle;
end{scope}
end{scope}
%
begin{scope}[canvas is xz plane at y=0,transform shape]
node[inner sep=0pt,text=red,opacity=0.8] (mat2) {$displaystyle
begin{pmatrix*}[r]
0 & 0 & -1 \
0 & 0 & 0 \
1 & 0 & 0 \
end{pmatrix*}$};
begin{scope}[on background layer]
fill[red,opacity=0.2] ([xshift=8.5pt]mat2.south west) to[out=140,in=-140,looseness=0.7]
([xshift=8.5pt]mat2.north west) -- ([xshift=-8.5pt]mat2.north east)
to[out=-40,in=40,looseness=0.7] ([xshift=-8.5pt]mat2.south east) -- cycle;
end{scope}
end{scope}
%
begin{scope}[canvas is xz plane at y=-1,transform shape]
node[inner sep=0pt,text=blue,opacity=0.8] (mat3) {$displaystyle
begin{pmatrix*}[r]
0 & 0 & 0 \
0 & 0 & 1 \
0 & -1 & 0 \
end{pmatrix*}$};
begin{scope}[on background layer]
fill[blue,opacity=0.2]
([xshift=8.5pt]mat3.south west) coordinate (blf)
to[out=140,in=-140,looseness=0.7]
([xshift=8.5pt]mat3.north west) coordinate (tlf)
-- ([xshift=-8.5pt]mat3.north east) coordinate (trf)
to[out=-40,in=40,looseness=0.7] ([xshift=-8.5pt]mat3.south east)
coordinate (brf) -- cycle;
end{scope}
end{scope}
foreach X in {tl,tr,br}
{draw[thin,orange] (X f) -- (X b);}
begin{scope}[on background layer]
draw[thin,orange] (blf) -- (blb);
end{scope}
node[left] at (mat3.west) {$varepsilon_{ijk}=$};
end{tikzpicture}
end{document}


enter image description here



EDIT: Aligned the entries right, big thanks to Barbara Beeton. (I just wonder why no one complained that the Levi-Civita tensor is not a tensor, but a tensor density. ;-)






share|improve this answer


























  • Two main differences with the image in the question: (1) in the negative entries, the digits are not aligned (and the spacing between columns adjusted to make them visually uniform), and (2) the tops and bottoms of the parentheses are not connected. of these, (1) detracts more from the appearance, although the meaning isn't affected; I happen to velue graceful appearance.

    – barbara beeton
    9 hours ago











  • @barbarabeeton Thanks! (1) can be addressed in a very simple way: loading mathtools and using begin{pmatrix*}[r]. (2) I do not understand. In Sebastiano's screen shot there are these four lines. Of course, if you'd ask me what they are good for, I'd admit that this is a very good question. ;-) Will revise my answer to address (1), thanks again!

    – marmot
    9 hours ago











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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









13














More or less:



documentclass[tikz,border=2mm]{standalone} 
usetikzlibrary{positioning, matrix}
usepackage{amsmath}

newcommand{arrayfilling}[2]{
fill[#2!30, opacity=.5] ([shift={(1mm,1mm)}]#1.north west) coordinate(#1auxnw)--([shift={(1mm,1mm)}]#1.north east)coordinate(#1auxne) to[out=-75, in=75] ([shift={(1mm,-1mm)}]#1.south east)coordinate(#1auxse)--([shift={(1mm,-1mm)}]#1.south west)coordinate(#1auxsw) to[out=105, in=-105] cycle;
fill[#2!80!black, opacity=1] (#1auxne) to[out=-75, in=75] (#1auxse) to[out=78, in=-78] cycle;
fill[#2!80!black, opacity=1] (#1auxnw) to[out=-105, in=105] (#1auxsw) to[out=102, in=-102] cycle;
}


begin{document}
begin{tikzpicture}[font=ttfamily,
mymatrix/.style={
matrix of math nodes, inner sep=0pt, color=#1,
column sep=-pgflinewidth, row sep=-pgflinewidth, anchor=south west,
nodes={anchor=center, minimum width=5mm,
minimum height=3mm, outer sep=0pt, inner sep=0pt,
text width=5mm, align=right,
draw=none, font=small},
}
]

matrix (C) [mymatrix=green] at (6mm,5mm)
{0 & 1 & 0 \ -1 & 0 & 0\ 0 & 0 & 0\};
arrayfilling{C}{green}

matrix (B) [mymatrix=red] at (3mm,2.5mm)
{0 & 0 & -1 \ 0 & 0 & 0\ 1 & 0 & 0\};
arrayfilling{B}{red}

matrix (A) [mymatrix=blue] at (0,0)
{0 & 0 & 0 \ 0 & 0 & 1\ 0 & -1 & 0\};
arrayfilling{A}{blue}

foreach i in {auxnw, auxne, auxse, auxsw}
draw[brown, ultra thin] (Ai)--(Ci);

node[below left=-1mm and 5mm of B.west] {$epsilon_{ijk} =$};
end{tikzpicture}
end{document}


enter image description here






share|improve this answer


























  • Please see point (1) in my comment to the answer by @marmot.

    – barbara beeton
    9 hours ago











  • @barbarabeeton Is it better now?

    – Ignasi
    9 hours ago











  • Yes, better. one might quibble that there is more space than necessary, compared with the space at the right. I think it's best to pay attention to what is actually present in each column, but that does require more attention.

    – barbara beeton
    8 hours ago
















13














More or less:



documentclass[tikz,border=2mm]{standalone} 
usetikzlibrary{positioning, matrix}
usepackage{amsmath}

newcommand{arrayfilling}[2]{
fill[#2!30, opacity=.5] ([shift={(1mm,1mm)}]#1.north west) coordinate(#1auxnw)--([shift={(1mm,1mm)}]#1.north east)coordinate(#1auxne) to[out=-75, in=75] ([shift={(1mm,-1mm)}]#1.south east)coordinate(#1auxse)--([shift={(1mm,-1mm)}]#1.south west)coordinate(#1auxsw) to[out=105, in=-105] cycle;
fill[#2!80!black, opacity=1] (#1auxne) to[out=-75, in=75] (#1auxse) to[out=78, in=-78] cycle;
fill[#2!80!black, opacity=1] (#1auxnw) to[out=-105, in=105] (#1auxsw) to[out=102, in=-102] cycle;
}


begin{document}
begin{tikzpicture}[font=ttfamily,
mymatrix/.style={
matrix of math nodes, inner sep=0pt, color=#1,
column sep=-pgflinewidth, row sep=-pgflinewidth, anchor=south west,
nodes={anchor=center, minimum width=5mm,
minimum height=3mm, outer sep=0pt, inner sep=0pt,
text width=5mm, align=right,
draw=none, font=small},
}
]

matrix (C) [mymatrix=green] at (6mm,5mm)
{0 & 1 & 0 \ -1 & 0 & 0\ 0 & 0 & 0\};
arrayfilling{C}{green}

matrix (B) [mymatrix=red] at (3mm,2.5mm)
{0 & 0 & -1 \ 0 & 0 & 0\ 1 & 0 & 0\};
arrayfilling{B}{red}

matrix (A) [mymatrix=blue] at (0,0)
{0 & 0 & 0 \ 0 & 0 & 1\ 0 & -1 & 0\};
arrayfilling{A}{blue}

foreach i in {auxnw, auxne, auxse, auxsw}
draw[brown, ultra thin] (Ai)--(Ci);

node[below left=-1mm and 5mm of B.west] {$epsilon_{ijk} =$};
end{tikzpicture}
end{document}


enter image description here






share|improve this answer


























  • Please see point (1) in my comment to the answer by @marmot.

    – barbara beeton
    9 hours ago











  • @barbarabeeton Is it better now?

    – Ignasi
    9 hours ago











  • Yes, better. one might quibble that there is more space than necessary, compared with the space at the right. I think it's best to pay attention to what is actually present in each column, but that does require more attention.

    – barbara beeton
    8 hours ago














13












13








13







More or less:



documentclass[tikz,border=2mm]{standalone} 
usetikzlibrary{positioning, matrix}
usepackage{amsmath}

newcommand{arrayfilling}[2]{
fill[#2!30, opacity=.5] ([shift={(1mm,1mm)}]#1.north west) coordinate(#1auxnw)--([shift={(1mm,1mm)}]#1.north east)coordinate(#1auxne) to[out=-75, in=75] ([shift={(1mm,-1mm)}]#1.south east)coordinate(#1auxse)--([shift={(1mm,-1mm)}]#1.south west)coordinate(#1auxsw) to[out=105, in=-105] cycle;
fill[#2!80!black, opacity=1] (#1auxne) to[out=-75, in=75] (#1auxse) to[out=78, in=-78] cycle;
fill[#2!80!black, opacity=1] (#1auxnw) to[out=-105, in=105] (#1auxsw) to[out=102, in=-102] cycle;
}


begin{document}
begin{tikzpicture}[font=ttfamily,
mymatrix/.style={
matrix of math nodes, inner sep=0pt, color=#1,
column sep=-pgflinewidth, row sep=-pgflinewidth, anchor=south west,
nodes={anchor=center, minimum width=5mm,
minimum height=3mm, outer sep=0pt, inner sep=0pt,
text width=5mm, align=right,
draw=none, font=small},
}
]

matrix (C) [mymatrix=green] at (6mm,5mm)
{0 & 1 & 0 \ -1 & 0 & 0\ 0 & 0 & 0\};
arrayfilling{C}{green}

matrix (B) [mymatrix=red] at (3mm,2.5mm)
{0 & 0 & -1 \ 0 & 0 & 0\ 1 & 0 & 0\};
arrayfilling{B}{red}

matrix (A) [mymatrix=blue] at (0,0)
{0 & 0 & 0 \ 0 & 0 & 1\ 0 & -1 & 0\};
arrayfilling{A}{blue}

foreach i in {auxnw, auxne, auxse, auxsw}
draw[brown, ultra thin] (Ai)--(Ci);

node[below left=-1mm and 5mm of B.west] {$epsilon_{ijk} =$};
end{tikzpicture}
end{document}


enter image description here






share|improve this answer















More or less:



documentclass[tikz,border=2mm]{standalone} 
usetikzlibrary{positioning, matrix}
usepackage{amsmath}

newcommand{arrayfilling}[2]{
fill[#2!30, opacity=.5] ([shift={(1mm,1mm)}]#1.north west) coordinate(#1auxnw)--([shift={(1mm,1mm)}]#1.north east)coordinate(#1auxne) to[out=-75, in=75] ([shift={(1mm,-1mm)}]#1.south east)coordinate(#1auxse)--([shift={(1mm,-1mm)}]#1.south west)coordinate(#1auxsw) to[out=105, in=-105] cycle;
fill[#2!80!black, opacity=1] (#1auxne) to[out=-75, in=75] (#1auxse) to[out=78, in=-78] cycle;
fill[#2!80!black, opacity=1] (#1auxnw) to[out=-105, in=105] (#1auxsw) to[out=102, in=-102] cycle;
}


begin{document}
begin{tikzpicture}[font=ttfamily,
mymatrix/.style={
matrix of math nodes, inner sep=0pt, color=#1,
column sep=-pgflinewidth, row sep=-pgflinewidth, anchor=south west,
nodes={anchor=center, minimum width=5mm,
minimum height=3mm, outer sep=0pt, inner sep=0pt,
text width=5mm, align=right,
draw=none, font=small},
}
]

matrix (C) [mymatrix=green] at (6mm,5mm)
{0 & 1 & 0 \ -1 & 0 & 0\ 0 & 0 & 0\};
arrayfilling{C}{green}

matrix (B) [mymatrix=red] at (3mm,2.5mm)
{0 & 0 & -1 \ 0 & 0 & 0\ 1 & 0 & 0\};
arrayfilling{B}{red}

matrix (A) [mymatrix=blue] at (0,0)
{0 & 0 & 0 \ 0 & 0 & 1\ 0 & -1 & 0\};
arrayfilling{A}{blue}

foreach i in {auxnw, auxne, auxse, auxsw}
draw[brown, ultra thin] (Ai)--(Ci);

node[below left=-1mm and 5mm of B.west] {$epsilon_{ijk} =$};
end{tikzpicture}
end{document}


enter image description here







share|improve this answer














share|improve this answer



share|improve this answer








edited 7 hours ago

























answered 9 hours ago









IgnasiIgnasi

94.1k4170313




94.1k4170313













  • Please see point (1) in my comment to the answer by @marmot.

    – barbara beeton
    9 hours ago











  • @barbarabeeton Is it better now?

    – Ignasi
    9 hours ago











  • Yes, better. one might quibble that there is more space than necessary, compared with the space at the right. I think it's best to pay attention to what is actually present in each column, but that does require more attention.

    – barbara beeton
    8 hours ago



















  • Please see point (1) in my comment to the answer by @marmot.

    – barbara beeton
    9 hours ago











  • @barbarabeeton Is it better now?

    – Ignasi
    9 hours ago











  • Yes, better. one might quibble that there is more space than necessary, compared with the space at the right. I think it's best to pay attention to what is actually present in each column, but that does require more attention.

    – barbara beeton
    8 hours ago

















Please see point (1) in my comment to the answer by @marmot.

– barbara beeton
9 hours ago





Please see point (1) in my comment to the answer by @marmot.

– barbara beeton
9 hours ago













@barbarabeeton Is it better now?

– Ignasi
9 hours ago





@barbarabeeton Is it better now?

– Ignasi
9 hours ago













Yes, better. one might quibble that there is more space than necessary, compared with the space at the right. I think it's best to pay attention to what is actually present in each column, but that does require more attention.

– barbara beeton
8 hours ago





Yes, better. one might quibble that there is more space than necessary, compared with the space at the right. I think it's best to pay attention to what is actually present in each column, but that does require more attention.

– barbara beeton
8 hours ago











12














Something like that?



documentclass[tikz,border=3.14mm]{standalone}
usepackage{mathtools}
usetikzlibrary{matrix,backgrounds,3d}
usepackage{tikz-3dplot}
%definecolor{mygreen}{RGB}{12,252,12}
begin{document}
tdplotsetmaincoords{75}{20}
begin{tikzpicture}[tdplot_main_coords]
begin{scope}[canvas is xz plane at y=1,transform shape]
node[inner sep=0pt,text=green!70!black,opacity=0.8] (mat1)
{$displaystylebegin{pmatrix*}[r]
0 & 1 & 0 \
-1 & 0 & 0 \
0 & 0 & 0 \
end{pmatrix*}$};
begin{scope}[on background layer]
fill[green!70!black,opacity=0.2] ([xshift=8.5pt]mat1.south west)
coordinate (blb) to[out=140,in=-140,looseness=0.7]
([xshift=8.5pt]mat1.north west) coordinate (tlb) --
([xshift=-8.5pt]mat1.north east) coordinate (trb)
to[out=-40,in=40,looseness=0.7] ([xshift=-8.5pt]mat1.south east)
coordinate (brb)
-- cycle;
end{scope}
end{scope}
%
begin{scope}[canvas is xz plane at y=0,transform shape]
node[inner sep=0pt,text=red,opacity=0.8] (mat2) {$displaystyle
begin{pmatrix*}[r]
0 & 0 & -1 \
0 & 0 & 0 \
1 & 0 & 0 \
end{pmatrix*}$};
begin{scope}[on background layer]
fill[red,opacity=0.2] ([xshift=8.5pt]mat2.south west) to[out=140,in=-140,looseness=0.7]
([xshift=8.5pt]mat2.north west) -- ([xshift=-8.5pt]mat2.north east)
to[out=-40,in=40,looseness=0.7] ([xshift=-8.5pt]mat2.south east) -- cycle;
end{scope}
end{scope}
%
begin{scope}[canvas is xz plane at y=-1,transform shape]
node[inner sep=0pt,text=blue,opacity=0.8] (mat3) {$displaystyle
begin{pmatrix*}[r]
0 & 0 & 0 \
0 & 0 & 1 \
0 & -1 & 0 \
end{pmatrix*}$};
begin{scope}[on background layer]
fill[blue,opacity=0.2]
([xshift=8.5pt]mat3.south west) coordinate (blf)
to[out=140,in=-140,looseness=0.7]
([xshift=8.5pt]mat3.north west) coordinate (tlf)
-- ([xshift=-8.5pt]mat3.north east) coordinate (trf)
to[out=-40,in=40,looseness=0.7] ([xshift=-8.5pt]mat3.south east)
coordinate (brf) -- cycle;
end{scope}
end{scope}
foreach X in {tl,tr,br}
{draw[thin,orange] (X f) -- (X b);}
begin{scope}[on background layer]
draw[thin,orange] (blf) -- (blb);
end{scope}
node[left] at (mat3.west) {$varepsilon_{ijk}=$};
end{tikzpicture}
end{document}


enter image description here



EDIT: Aligned the entries right, big thanks to Barbara Beeton. (I just wonder why no one complained that the Levi-Civita tensor is not a tensor, but a tensor density. ;-)






share|improve this answer


























  • Two main differences with the image in the question: (1) in the negative entries, the digits are not aligned (and the spacing between columns adjusted to make them visually uniform), and (2) the tops and bottoms of the parentheses are not connected. of these, (1) detracts more from the appearance, although the meaning isn't affected; I happen to velue graceful appearance.

    – barbara beeton
    9 hours ago











  • @barbarabeeton Thanks! (1) can be addressed in a very simple way: loading mathtools and using begin{pmatrix*}[r]. (2) I do not understand. In Sebastiano's screen shot there are these four lines. Of course, if you'd ask me what they are good for, I'd admit that this is a very good question. ;-) Will revise my answer to address (1), thanks again!

    – marmot
    9 hours ago
















12














Something like that?



documentclass[tikz,border=3.14mm]{standalone}
usepackage{mathtools}
usetikzlibrary{matrix,backgrounds,3d}
usepackage{tikz-3dplot}
%definecolor{mygreen}{RGB}{12,252,12}
begin{document}
tdplotsetmaincoords{75}{20}
begin{tikzpicture}[tdplot_main_coords]
begin{scope}[canvas is xz plane at y=1,transform shape]
node[inner sep=0pt,text=green!70!black,opacity=0.8] (mat1)
{$displaystylebegin{pmatrix*}[r]
0 & 1 & 0 \
-1 & 0 & 0 \
0 & 0 & 0 \
end{pmatrix*}$};
begin{scope}[on background layer]
fill[green!70!black,opacity=0.2] ([xshift=8.5pt]mat1.south west)
coordinate (blb) to[out=140,in=-140,looseness=0.7]
([xshift=8.5pt]mat1.north west) coordinate (tlb) --
([xshift=-8.5pt]mat1.north east) coordinate (trb)
to[out=-40,in=40,looseness=0.7] ([xshift=-8.5pt]mat1.south east)
coordinate (brb)
-- cycle;
end{scope}
end{scope}
%
begin{scope}[canvas is xz plane at y=0,transform shape]
node[inner sep=0pt,text=red,opacity=0.8] (mat2) {$displaystyle
begin{pmatrix*}[r]
0 & 0 & -1 \
0 & 0 & 0 \
1 & 0 & 0 \
end{pmatrix*}$};
begin{scope}[on background layer]
fill[red,opacity=0.2] ([xshift=8.5pt]mat2.south west) to[out=140,in=-140,looseness=0.7]
([xshift=8.5pt]mat2.north west) -- ([xshift=-8.5pt]mat2.north east)
to[out=-40,in=40,looseness=0.7] ([xshift=-8.5pt]mat2.south east) -- cycle;
end{scope}
end{scope}
%
begin{scope}[canvas is xz plane at y=-1,transform shape]
node[inner sep=0pt,text=blue,opacity=0.8] (mat3) {$displaystyle
begin{pmatrix*}[r]
0 & 0 & 0 \
0 & 0 & 1 \
0 & -1 & 0 \
end{pmatrix*}$};
begin{scope}[on background layer]
fill[blue,opacity=0.2]
([xshift=8.5pt]mat3.south west) coordinate (blf)
to[out=140,in=-140,looseness=0.7]
([xshift=8.5pt]mat3.north west) coordinate (tlf)
-- ([xshift=-8.5pt]mat3.north east) coordinate (trf)
to[out=-40,in=40,looseness=0.7] ([xshift=-8.5pt]mat3.south east)
coordinate (brf) -- cycle;
end{scope}
end{scope}
foreach X in {tl,tr,br}
{draw[thin,orange] (X f) -- (X b);}
begin{scope}[on background layer]
draw[thin,orange] (blf) -- (blb);
end{scope}
node[left] at (mat3.west) {$varepsilon_{ijk}=$};
end{tikzpicture}
end{document}


enter image description here



EDIT: Aligned the entries right, big thanks to Barbara Beeton. (I just wonder why no one complained that the Levi-Civita tensor is not a tensor, but a tensor density. ;-)






share|improve this answer


























  • Two main differences with the image in the question: (1) in the negative entries, the digits are not aligned (and the spacing between columns adjusted to make them visually uniform), and (2) the tops and bottoms of the parentheses are not connected. of these, (1) detracts more from the appearance, although the meaning isn't affected; I happen to velue graceful appearance.

    – barbara beeton
    9 hours ago











  • @barbarabeeton Thanks! (1) can be addressed in a very simple way: loading mathtools and using begin{pmatrix*}[r]. (2) I do not understand. In Sebastiano's screen shot there are these four lines. Of course, if you'd ask me what they are good for, I'd admit that this is a very good question. ;-) Will revise my answer to address (1), thanks again!

    – marmot
    9 hours ago














12












12








12







Something like that?



documentclass[tikz,border=3.14mm]{standalone}
usepackage{mathtools}
usetikzlibrary{matrix,backgrounds,3d}
usepackage{tikz-3dplot}
%definecolor{mygreen}{RGB}{12,252,12}
begin{document}
tdplotsetmaincoords{75}{20}
begin{tikzpicture}[tdplot_main_coords]
begin{scope}[canvas is xz plane at y=1,transform shape]
node[inner sep=0pt,text=green!70!black,opacity=0.8] (mat1)
{$displaystylebegin{pmatrix*}[r]
0 & 1 & 0 \
-1 & 0 & 0 \
0 & 0 & 0 \
end{pmatrix*}$};
begin{scope}[on background layer]
fill[green!70!black,opacity=0.2] ([xshift=8.5pt]mat1.south west)
coordinate (blb) to[out=140,in=-140,looseness=0.7]
([xshift=8.5pt]mat1.north west) coordinate (tlb) --
([xshift=-8.5pt]mat1.north east) coordinate (trb)
to[out=-40,in=40,looseness=0.7] ([xshift=-8.5pt]mat1.south east)
coordinate (brb)
-- cycle;
end{scope}
end{scope}
%
begin{scope}[canvas is xz plane at y=0,transform shape]
node[inner sep=0pt,text=red,opacity=0.8] (mat2) {$displaystyle
begin{pmatrix*}[r]
0 & 0 & -1 \
0 & 0 & 0 \
1 & 0 & 0 \
end{pmatrix*}$};
begin{scope}[on background layer]
fill[red,opacity=0.2] ([xshift=8.5pt]mat2.south west) to[out=140,in=-140,looseness=0.7]
([xshift=8.5pt]mat2.north west) -- ([xshift=-8.5pt]mat2.north east)
to[out=-40,in=40,looseness=0.7] ([xshift=-8.5pt]mat2.south east) -- cycle;
end{scope}
end{scope}
%
begin{scope}[canvas is xz plane at y=-1,transform shape]
node[inner sep=0pt,text=blue,opacity=0.8] (mat3) {$displaystyle
begin{pmatrix*}[r]
0 & 0 & 0 \
0 & 0 & 1 \
0 & -1 & 0 \
end{pmatrix*}$};
begin{scope}[on background layer]
fill[blue,opacity=0.2]
([xshift=8.5pt]mat3.south west) coordinate (blf)
to[out=140,in=-140,looseness=0.7]
([xshift=8.5pt]mat3.north west) coordinate (tlf)
-- ([xshift=-8.5pt]mat3.north east) coordinate (trf)
to[out=-40,in=40,looseness=0.7] ([xshift=-8.5pt]mat3.south east)
coordinate (brf) -- cycle;
end{scope}
end{scope}
foreach X in {tl,tr,br}
{draw[thin,orange] (X f) -- (X b);}
begin{scope}[on background layer]
draw[thin,orange] (blf) -- (blb);
end{scope}
node[left] at (mat3.west) {$varepsilon_{ijk}=$};
end{tikzpicture}
end{document}


enter image description here



EDIT: Aligned the entries right, big thanks to Barbara Beeton. (I just wonder why no one complained that the Levi-Civita tensor is not a tensor, but a tensor density. ;-)






share|improve this answer















Something like that?



documentclass[tikz,border=3.14mm]{standalone}
usepackage{mathtools}
usetikzlibrary{matrix,backgrounds,3d}
usepackage{tikz-3dplot}
%definecolor{mygreen}{RGB}{12,252,12}
begin{document}
tdplotsetmaincoords{75}{20}
begin{tikzpicture}[tdplot_main_coords]
begin{scope}[canvas is xz plane at y=1,transform shape]
node[inner sep=0pt,text=green!70!black,opacity=0.8] (mat1)
{$displaystylebegin{pmatrix*}[r]
0 & 1 & 0 \
-1 & 0 & 0 \
0 & 0 & 0 \
end{pmatrix*}$};
begin{scope}[on background layer]
fill[green!70!black,opacity=0.2] ([xshift=8.5pt]mat1.south west)
coordinate (blb) to[out=140,in=-140,looseness=0.7]
([xshift=8.5pt]mat1.north west) coordinate (tlb) --
([xshift=-8.5pt]mat1.north east) coordinate (trb)
to[out=-40,in=40,looseness=0.7] ([xshift=-8.5pt]mat1.south east)
coordinate (brb)
-- cycle;
end{scope}
end{scope}
%
begin{scope}[canvas is xz plane at y=0,transform shape]
node[inner sep=0pt,text=red,opacity=0.8] (mat2) {$displaystyle
begin{pmatrix*}[r]
0 & 0 & -1 \
0 & 0 & 0 \
1 & 0 & 0 \
end{pmatrix*}$};
begin{scope}[on background layer]
fill[red,opacity=0.2] ([xshift=8.5pt]mat2.south west) to[out=140,in=-140,looseness=0.7]
([xshift=8.5pt]mat2.north west) -- ([xshift=-8.5pt]mat2.north east)
to[out=-40,in=40,looseness=0.7] ([xshift=-8.5pt]mat2.south east) -- cycle;
end{scope}
end{scope}
%
begin{scope}[canvas is xz plane at y=-1,transform shape]
node[inner sep=0pt,text=blue,opacity=0.8] (mat3) {$displaystyle
begin{pmatrix*}[r]
0 & 0 & 0 \
0 & 0 & 1 \
0 & -1 & 0 \
end{pmatrix*}$};
begin{scope}[on background layer]
fill[blue,opacity=0.2]
([xshift=8.5pt]mat3.south west) coordinate (blf)
to[out=140,in=-140,looseness=0.7]
([xshift=8.5pt]mat3.north west) coordinate (tlf)
-- ([xshift=-8.5pt]mat3.north east) coordinate (trf)
to[out=-40,in=40,looseness=0.7] ([xshift=-8.5pt]mat3.south east)
coordinate (brf) -- cycle;
end{scope}
end{scope}
foreach X in {tl,tr,br}
{draw[thin,orange] (X f) -- (X b);}
begin{scope}[on background layer]
draw[thin,orange] (blf) -- (blb);
end{scope}
node[left] at (mat3.west) {$varepsilon_{ijk}=$};
end{tikzpicture}
end{document}


enter image description here



EDIT: Aligned the entries right, big thanks to Barbara Beeton. (I just wonder why no one complained that the Levi-Civita tensor is not a tensor, but a tensor density. ;-)







share|improve this answer














share|improve this answer



share|improve this answer








edited 9 hours ago

























answered 9 hours ago









marmotmarmot

106k4127242




106k4127242













  • Two main differences with the image in the question: (1) in the negative entries, the digits are not aligned (and the spacing between columns adjusted to make them visually uniform), and (2) the tops and bottoms of the parentheses are not connected. of these, (1) detracts more from the appearance, although the meaning isn't affected; I happen to velue graceful appearance.

    – barbara beeton
    9 hours ago











  • @barbarabeeton Thanks! (1) can be addressed in a very simple way: loading mathtools and using begin{pmatrix*}[r]. (2) I do not understand. In Sebastiano's screen shot there are these four lines. Of course, if you'd ask me what they are good for, I'd admit that this is a very good question. ;-) Will revise my answer to address (1), thanks again!

    – marmot
    9 hours ago



















  • Two main differences with the image in the question: (1) in the negative entries, the digits are not aligned (and the spacing between columns adjusted to make them visually uniform), and (2) the tops and bottoms of the parentheses are not connected. of these, (1) detracts more from the appearance, although the meaning isn't affected; I happen to velue graceful appearance.

    – barbara beeton
    9 hours ago











  • @barbarabeeton Thanks! (1) can be addressed in a very simple way: loading mathtools and using begin{pmatrix*}[r]. (2) I do not understand. In Sebastiano's screen shot there are these four lines. Of course, if you'd ask me what they are good for, I'd admit that this is a very good question. ;-) Will revise my answer to address (1), thanks again!

    – marmot
    9 hours ago

















Two main differences with the image in the question: (1) in the negative entries, the digits are not aligned (and the spacing between columns adjusted to make them visually uniform), and (2) the tops and bottoms of the parentheses are not connected. of these, (1) detracts more from the appearance, although the meaning isn't affected; I happen to velue graceful appearance.

– barbara beeton
9 hours ago





Two main differences with the image in the question: (1) in the negative entries, the digits are not aligned (and the spacing between columns adjusted to make them visually uniform), and (2) the tops and bottoms of the parentheses are not connected. of these, (1) detracts more from the appearance, although the meaning isn't affected; I happen to velue graceful appearance.

– barbara beeton
9 hours ago













@barbarabeeton Thanks! (1) can be addressed in a very simple way: loading mathtools and using begin{pmatrix*}[r]. (2) I do not understand. In Sebastiano's screen shot there are these four lines. Of course, if you'd ask me what they are good for, I'd admit that this is a very good question. ;-) Will revise my answer to address (1), thanks again!

– marmot
9 hours ago





@barbarabeeton Thanks! (1) can be addressed in a very simple way: loading mathtools and using begin{pmatrix*}[r]. (2) I do not understand. In Sebastiano's screen shot there are these four lines. Of course, if you'd ask me what they are good for, I'd admit that this is a very good question. ;-) Will revise my answer to address (1), thanks again!

– marmot
9 hours ago


















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