How to divide the information of an array and send it to another array? [duplicate]
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This question already has an answer here:
Group by element in array by keyword
3 answers
I have this array in Javascript:
cars = [
{color: red, type: sedan, name: ferrari},
{color: blue, type: sedan, name: ferrari},
{color: yellow, type: sedan, name: ferrari},
{color: red, type: coupe, name: toyota},
{color: red, type: sedan, name: toyota}
]
What I am trying to do is create a multidimensional array where I have the information of the first array but it looks like this:
I want to separate ferraris cars from Toyota
carsseparated[0] = [
{color: red, type: sedan, name: ferrari},
{color: blue, type: sedan, name: ferrari},
{color: yellow, type: sedan, name: ferrari}
]
carsseparated[1] = [
{color: red, type: coupe, name: toyota},
{color: red, type: sedan, name: toyota}
]
this is what I have been coding
$scope.carsseparated= ;
var cont = 0;
$.each($scope.cars, function (index,value) {
$scope.carsseparated[cont] = [value.color, value.type, value.name]
cont = cont+1;
}
javascript jquery arrays angularjs
edited Nov 23 '18 at 17:41
georgeawg
34.7k115470
asked Nov 23 '18 at 15:21
TalkedTalked
205
marked as duplicate by Ori Drori arrays
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Nov 23 '18 at 15:24
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
add a comment |
0
This question already has an answer here:
Group by element in array by keyword
3 answers
I have this array in Javascript:
cars = [
{color: red, type: sedan, name: ferrari},
{color: blue, type: sedan, name: ferrari},
{color: yellow, type: sedan, name: ferrari},
{color: red, type: coupe, name: toyota},
{color: red, type: sedan, name: toyota}
]
What I am trying to do is create a multidimensional array where I have the information of the first array but it looks like this:
I want to separate ferraris cars from Toyota
carsseparated[0] = [
{color: red, type: sedan, name: ferrari},
{color: blue, type: sedan, name: ferrari},
{color: yellow, type: sedan, name: ferrari}
]
carsseparated[1] = [
{color: red, type: coupe, name: toyota},
{color: red, type: sedan, name: toyota}
]
this is what I have been coding
$scope.carsseparated= ;
var cont = 0;
$.each($scope.cars, function (index,value) {
$scope.carsseparated[cont] = [value.color, value.type, value.name]
cont = cont+1;
}
javascript jquery arrays angularjs
edited Nov 23 '18 at 17:41
georgeawg
34.7k115470
asked Nov 23 '18 at 15:21
TalkedTalked
205
marked as duplicate by Ori Drori arrays
Users with the arrays badge can single-handedly close arrays questions as duplicates and reopen them as needed.
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Nov 23 '18 at 15:24
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
add a comment |
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0
This question already has an answer here:
Group by element in array by keyword
3 answers
I have this array in Javascript:
cars = [
{color: red, type: sedan, name: ferrari},
{color: blue, type: sedan, name: ferrari},
{color: yellow, type: sedan, name: ferrari},
{color: red, type: coupe, name: toyota},
{color: red, type: sedan, name: toyota}
]
What I am trying to do is create a multidimensional array where I have the information of the first array but it looks like this:
I want to separate ferraris cars from Toyota
carsseparated[0] = [
{color: red, type: sedan, name: ferrari},
{color: blue, type: sedan, name: ferrari},
{color: yellow, type: sedan, name: ferrari}
]
carsseparated[1] = [
{color: red, type: coupe, name: toyota},
{color: red, type: sedan, name: toyota}
]
this is what I have been coding
$scope.carsseparated= ;
var cont = 0;
$.each($scope.cars, function (index,value) {
$scope.carsseparated[cont] = [value.color, value.type, value.name]
cont = cont+1;
}
javascript jquery arrays angularjs
edited Nov 23 '18 at 17:41
georgeawg
34.7k115470
asked Nov 23 '18 at 15:21
TalkedTalked
205
This question already has an answer here:
Group by element in array by keyword
3 answers
I have this array in Javascript:
cars = [
{color: red, type: sedan, name: ferrari},
{color: blue, type: sedan, name: ferrari},
{color: yellow, type: sedan, name: ferrari},
{color: red, type: coupe, name: toyota},
{color: red, type: sedan, name: toyota}
]
What I am trying to do is create a multidimensional array where I have the information of the first array but it looks like this:
I want to separate ferraris cars from Toyota
carsseparated[0] = [
{color: red, type: sedan, name: ferrari},
{color: blue, type: sedan, name: ferrari},
{color: yellow, type: sedan, name: ferrari}
]
carsseparated[1] = [
{color: red, type: coupe, name: toyota},
{color: red, type: sedan, name: toyota}
]
this is what I have been coding
$scope.carsseparated= ;
var cont = 0;
$.each($scope.cars, function (index,value) {
$scope.carsseparated[cont] = [value.color, value.type, value.name]
cont = cont+1;
}
This question already has an answer here:
Group by element in array by keyword
3 answers
javascript jquery arrays angularjs
javascript jquery arrays angularjs
edited Nov 23 '18 at 17:41
georgeawg
34.7k115470
asked Nov 23 '18 at 15:21
TalkedTalked
205
edited Nov 23 '18 at 17:41
georgeawg
34.7k115470
asked Nov 23 '18 at 15:21
TalkedTalked
205
edited Nov 23 '18 at 17:41
georgeawg
34.7k115470
edited Nov 23 '18 at 17:41
georgeawg
34.7k115470
edited Nov 23 '18 at 17:41
georgeawg
34.7k115470
34.7k115470
asked Nov 23 '18 at 15:21
TalkedTalked
205
asked Nov 23 '18 at 15:21
TalkedTalked
205
asked Nov 23 '18 at 15:21
TalkedTalked
205
205
marked as duplicate by Ori Drori arrays
Users with the arrays badge can single-handedly close arrays questions as duplicates and reopen them as needed.
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Nov 23 '18 at 15:24
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
marked as duplicate by Ori Drori arrays
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Nov 23 '18 at 15:24
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
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1 Answer
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let cars = [{color: "red", type: "sedan", name: "ferrari"}, {color: "blue", type: "sedan", name: "ferrari"}, {color: "yellow", type: "sedan", name: "ferrari"}, {color: "red", type: "coupe", name: "toyota"},
{color: "red", type: "sedan", name: "toyota"}];
let car1 = cars.filter(val => val.name === 'ferrari');
let car2 = cars.filter(val => val.name === 'toyota');
console.log(car1)answered Nov 23 '18 at 15:28
raviravi
25828
yes, I guess that may work, but I'm trying to make it dynamic, what I want to say is that, I do not want to do this: val.name === 'ferrari' thanks for answering.
– Talked
Nov 23 '18 at 15:42
add a comment |
1 Answer
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1 Answer
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1
let cars = [{color: "red", type: "sedan", name: "ferrari"}, {color: "blue", type: "sedan", name: "ferrari"}, {color: "yellow", type: "sedan", name: "ferrari"}, {color: "red", type: "coupe", name: "toyota"},
{color: "red", type: "sedan", name: "toyota"}];
let car1 = cars.filter(val => val.name === 'ferrari');
let car2 = cars.filter(val => val.name === 'toyota');
console.log(car1)answered Nov 23 '18 at 15:28
raviravi
25828
yes, I guess that may work, but I'm trying to make it dynamic, what I want to say is that, I do not want to do this: val.name === 'ferrari' thanks for answering.
– Talked
Nov 23 '18 at 15:42
add a comment |
1
let cars = [{color: "red", type: "sedan", name: "ferrari"}, {color: "blue", type: "sedan", name: "ferrari"}, {color: "yellow", type: "sedan", name: "ferrari"}, {color: "red", type: "coupe", name: "toyota"},
{color: "red", type: "sedan", name: "toyota"}];
let car1 = cars.filter(val => val.name === 'ferrari');
let car2 = cars.filter(val => val.name === 'toyota');
console.log(car1)answered Nov 23 '18 at 15:28
raviravi
25828
yes, I guess that may work, but I'm trying to make it dynamic, what I want to say is that, I do not want to do this: val.name === 'ferrari' thanks for answering.
– Talked
Nov 23 '18 at 15:42
add a comment |
1
1
1
let cars = [{color: "red", type: "sedan", name: "ferrari"}, {color: "blue", type: "sedan", name: "ferrari"}, {color: "yellow", type: "sedan", name: "ferrari"}, {color: "red", type: "coupe", name: "toyota"},
{color: "red", type: "sedan", name: "toyota"}];
let car1 = cars.filter(val => val.name === 'ferrari');
let car2 = cars.filter(val => val.name === 'toyota');
console.log(car1)answered Nov 23 '18 at 15:28
raviravi
25828
let cars = [{color: "red", type: "sedan", name: "ferrari"}, {color: "blue", type: "sedan", name: "ferrari"}, {color: "yellow", type: "sedan", name: "ferrari"}, {color: "red", type: "coupe", name: "toyota"},
{color: "red", type: "sedan", name: "toyota"}];
let car1 = cars.filter(val => val.name === 'ferrari');
let car2 = cars.filter(val => val.name === 'toyota');
console.log(car1)let cars = [{color: "red", type: "sedan", name: "ferrari"}, {color: "blue", type: "sedan", name: "ferrari"}, {color: "yellow", type: "sedan", name: "ferrari"}, {color: "red", type: "coupe", name: "toyota"},
{color: "red", type: "sedan", name: "toyota"}];
let car1 = cars.filter(val => val.name === 'ferrari');
let car2 = cars.filter(val => val.name === 'toyota');
console.log(car1)let cars = [{color: "red", type: "sedan", name: "ferrari"}, {color: "blue", type: "sedan", name: "ferrari"}, {color: "yellow", type: "sedan", name: "ferrari"}, {color: "red", type: "coupe", name: "toyota"},
{color: "red", type: "sedan", name: "toyota"}];
let car1 = cars.filter(val => val.name === 'ferrari');
let car2 = cars.filter(val => val.name === 'toyota');
console.log(car1)answered Nov 23 '18 at 15:28
raviravi
25828
answered Nov 23 '18 at 15:28
raviravi
25828
answered Nov 23 '18 at 15:28
raviravi
25828
answered Nov 23 '18 at 15:28
raviravi
25828
25828
yes, I guess that may work, but I'm trying to make it dynamic, what I want to say is that, I do not want to do this: val.name === 'ferrari' thanks for answering.
– Talked
Nov 23 '18 at 15:42
add a comment |
yes, I guess that may work, but I'm trying to make it dynamic, what I want to say is that, I do not want to do this: val.name === 'ferrari' thanks for answering.
– Talked
Nov 23 '18 at 15:42
yes, I guess that may work, but I'm trying to make it dynamic, what I want to say is that, I do not want to do this: val.name === 'ferrari' thanks for answering.
– Talked
Nov 23 '18 at 15:42
yes, I guess that may work, but I'm trying to make it dynamic, what I want to say is that, I do not want to do this: val.name === 'ferrari' thanks for answering.
– Talked
Nov 23 '18 at 15:42
add a comment |
