How do I create a UDP packet?











up vote
14
down vote

favorite
4












When I perform the following Netcat command and view the packets with Wireshark, it says the UDP packet is malformed.



$ echo "this is a test" | nc -u 127.0.0.1 53


Similarly, using commands like $ echo "this is a test" > /dev/udp/127.0.0.1/53 produce "malformed packet" errors in Wireshark.



Enter image description here



The echo command gets sent/delivered to the Netcat server without errors. But this got me wondering: is it possible to manually construct a proper UDP packet with echo or some other native Unix tool(s)?



I'm using Debian and macOS.










share|improve this question




















  • 10




    According to your screenshot it's not the udp-packet itself which is malformed but its content, as port 53 is used for DNS and your packet doesn't contain a valid DNS request.
    – tkausl
    Nov 23 at 18:17










  • @tkausl you're absolutely right. There are no "malformed" errors when using ports other than 53. Thank you for pointing that out.
    – user322500
    Nov 23 at 18:22






  • 1




    If you aren't using standard protocols you are supposed to use ports in the range 49152 to 65535. Since Linux by default uses the range 32768 to 60999 as ephemeral ports I recommend not choosing those either for non-standard protocols. However 61000 to 65535 are fair game for non-standard protocols. I usually use echo $[61002+RANDOM%4532] to pick a random port number in that range.
    – kasperd
    Nov 23 at 21:21






  • 1




    Don't be logged in as root. You should do most of your activity as a non-root user. If you do stuff as root, you will be back on here asking how to fix your machine, and we won't be able to help (except to recommend a re-install).
    – ctrl-alt-delor
    Nov 24 at 0:18






  • 1




    @tkausl Look what have you lost for not posting your comment as answer....
    – George Vasiliou
    Nov 25 at 20:23















up vote
14
down vote

favorite
4












When I perform the following Netcat command and view the packets with Wireshark, it says the UDP packet is malformed.



$ echo "this is a test" | nc -u 127.0.0.1 53


Similarly, using commands like $ echo "this is a test" > /dev/udp/127.0.0.1/53 produce "malformed packet" errors in Wireshark.



Enter image description here



The echo command gets sent/delivered to the Netcat server without errors. But this got me wondering: is it possible to manually construct a proper UDP packet with echo or some other native Unix tool(s)?



I'm using Debian and macOS.










share|improve this question




















  • 10




    According to your screenshot it's not the udp-packet itself which is malformed but its content, as port 53 is used for DNS and your packet doesn't contain a valid DNS request.
    – tkausl
    Nov 23 at 18:17










  • @tkausl you're absolutely right. There are no "malformed" errors when using ports other than 53. Thank you for pointing that out.
    – user322500
    Nov 23 at 18:22






  • 1




    If you aren't using standard protocols you are supposed to use ports in the range 49152 to 65535. Since Linux by default uses the range 32768 to 60999 as ephemeral ports I recommend not choosing those either for non-standard protocols. However 61000 to 65535 are fair game for non-standard protocols. I usually use echo $[61002+RANDOM%4532] to pick a random port number in that range.
    – kasperd
    Nov 23 at 21:21






  • 1




    Don't be logged in as root. You should do most of your activity as a non-root user. If you do stuff as root, you will be back on here asking how to fix your machine, and we won't be able to help (except to recommend a re-install).
    – ctrl-alt-delor
    Nov 24 at 0:18






  • 1




    @tkausl Look what have you lost for not posting your comment as answer....
    – George Vasiliou
    Nov 25 at 20:23













up vote
14
down vote

favorite
4









up vote
14
down vote

favorite
4






4





When I perform the following Netcat command and view the packets with Wireshark, it says the UDP packet is malformed.



$ echo "this is a test" | nc -u 127.0.0.1 53


Similarly, using commands like $ echo "this is a test" > /dev/udp/127.0.0.1/53 produce "malformed packet" errors in Wireshark.



Enter image description here



The echo command gets sent/delivered to the Netcat server without errors. But this got me wondering: is it possible to manually construct a proper UDP packet with echo or some other native Unix tool(s)?



I'm using Debian and macOS.










share|improve this question















When I perform the following Netcat command and view the packets with Wireshark, it says the UDP packet is malformed.



$ echo "this is a test" | nc -u 127.0.0.1 53


Similarly, using commands like $ echo "this is a test" > /dev/udp/127.0.0.1/53 produce "malformed packet" errors in Wireshark.



Enter image description here



The echo command gets sent/delivered to the Netcat server without errors. But this got me wondering: is it possible to manually construct a proper UDP packet with echo or some other native Unix tool(s)?



I'm using Debian and macOS.







linux debian osx netcat udp






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 24 at 9:36









Peter Mortensen

85758




85758










asked Nov 23 at 16:01









user322500

714




714








  • 10




    According to your screenshot it's not the udp-packet itself which is malformed but its content, as port 53 is used for DNS and your packet doesn't contain a valid DNS request.
    – tkausl
    Nov 23 at 18:17










  • @tkausl you're absolutely right. There are no "malformed" errors when using ports other than 53. Thank you for pointing that out.
    – user322500
    Nov 23 at 18:22






  • 1




    If you aren't using standard protocols you are supposed to use ports in the range 49152 to 65535. Since Linux by default uses the range 32768 to 60999 as ephemeral ports I recommend not choosing those either for non-standard protocols. However 61000 to 65535 are fair game for non-standard protocols. I usually use echo $[61002+RANDOM%4532] to pick a random port number in that range.
    – kasperd
    Nov 23 at 21:21






  • 1




    Don't be logged in as root. You should do most of your activity as a non-root user. If you do stuff as root, you will be back on here asking how to fix your machine, and we won't be able to help (except to recommend a re-install).
    – ctrl-alt-delor
    Nov 24 at 0:18






  • 1




    @tkausl Look what have you lost for not posting your comment as answer....
    – George Vasiliou
    Nov 25 at 20:23














  • 10




    According to your screenshot it's not the udp-packet itself which is malformed but its content, as port 53 is used for DNS and your packet doesn't contain a valid DNS request.
    – tkausl
    Nov 23 at 18:17










  • @tkausl you're absolutely right. There are no "malformed" errors when using ports other than 53. Thank you for pointing that out.
    – user322500
    Nov 23 at 18:22






  • 1




    If you aren't using standard protocols you are supposed to use ports in the range 49152 to 65535. Since Linux by default uses the range 32768 to 60999 as ephemeral ports I recommend not choosing those either for non-standard protocols. However 61000 to 65535 are fair game for non-standard protocols. I usually use echo $[61002+RANDOM%4532] to pick a random port number in that range.
    – kasperd
    Nov 23 at 21:21






  • 1




    Don't be logged in as root. You should do most of your activity as a non-root user. If you do stuff as root, you will be back on here asking how to fix your machine, and we won't be able to help (except to recommend a re-install).
    – ctrl-alt-delor
    Nov 24 at 0:18






  • 1




    @tkausl Look what have you lost for not posting your comment as answer....
    – George Vasiliou
    Nov 25 at 20:23








10




10




According to your screenshot it's not the udp-packet itself which is malformed but its content, as port 53 is used for DNS and your packet doesn't contain a valid DNS request.
– tkausl
Nov 23 at 18:17




According to your screenshot it's not the udp-packet itself which is malformed but its content, as port 53 is used for DNS and your packet doesn't contain a valid DNS request.
– tkausl
Nov 23 at 18:17












@tkausl you're absolutely right. There are no "malformed" errors when using ports other than 53. Thank you for pointing that out.
– user322500
Nov 23 at 18:22




@tkausl you're absolutely right. There are no "malformed" errors when using ports other than 53. Thank you for pointing that out.
– user322500
Nov 23 at 18:22




1




1




If you aren't using standard protocols you are supposed to use ports in the range 49152 to 65535. Since Linux by default uses the range 32768 to 60999 as ephemeral ports I recommend not choosing those either for non-standard protocols. However 61000 to 65535 are fair game for non-standard protocols. I usually use echo $[61002+RANDOM%4532] to pick a random port number in that range.
– kasperd
Nov 23 at 21:21




If you aren't using standard protocols you are supposed to use ports in the range 49152 to 65535. Since Linux by default uses the range 32768 to 60999 as ephemeral ports I recommend not choosing those either for non-standard protocols. However 61000 to 65535 are fair game for non-standard protocols. I usually use echo $[61002+RANDOM%4532] to pick a random port number in that range.
– kasperd
Nov 23 at 21:21




1




1




Don't be logged in as root. You should do most of your activity as a non-root user. If you do stuff as root, you will be back on here asking how to fix your machine, and we won't be able to help (except to recommend a re-install).
– ctrl-alt-delor
Nov 24 at 0:18




Don't be logged in as root. You should do most of your activity as a non-root user. If you do stuff as root, you will be back on here asking how to fix your machine, and we won't be able to help (except to recommend a re-install).
– ctrl-alt-delor
Nov 24 at 0:18




1




1




@tkausl Look what have you lost for not posting your comment as answer....
– George Vasiliou
Nov 25 at 20:23




@tkausl Look what have you lost for not posting your comment as answer....
– George Vasiliou
Nov 25 at 20:23










3 Answers
3






active

oldest

votes

















up vote
40
down vote













Your packet is completely valid, from the viewpoint of IP and UDP. If you expand the protocol details for Ethernet/IP/UDP in the lower pane of Wireshark, you will see that the packet is successfully parsed.



However, as it is destined for port 53, Wireshark attempts to parse it as a DNS packet, which it cannot do (since the string "this is a test" is not a valid DNS request per the RFC 1035 spec).



If you follow the specification at that link, you will be able to construct a packet that is valid when parsed as a DNS request. If you send the packet to another port, you'll notice that Wireshark will no longer parse it as a DNS request and will hence not show that warning.






share|improve this answer




























    up vote
    14
    down vote













    You can send them to Bash special aliases with redirection.



    From Bash manpages:




    /dev/tcp/host/port
    If host is a valid hostname or Internet address, and port is an integer port number or service name, bash attempts to open the
    corresponding TCP socket.



    /dev/udp/host/port
    If host is a valid hostname or Internet address, and port is an integer port number or service name, bash attempts to open the
    corresponding UDP socket.




    This will send a UDP packet to 192.168.2.11 to port 8080:



    echo "This is a test" > /dev/udp/192.168.2.11/8080





    share|improve this answer























    • Thanks for this answer. I've updated my question. Using your method also produces a "malformed packet" error message, unfortunately.
      – user322500
      Nov 23 at 16:42


















    up vote
    -1
    down vote













    There are multiple questions here; the claim of a "malformed packet" may be due to checksum offloading and if so is a false error as it reflects the packet capture not having a complete view--some of the work was instead done on the network hardware. WireShark should have documentation on this.



    Otherwise, various tools (such as socat, nc or netcat, or via extremely similar features in shells such as ksh93 or bash) can take bytes from standard input and dump them into what becomes a UDP packet. Whether this is "proper" depends on the protocol; one could in theory construct and send a DNS or DHCP packet this way, though more often folks use a library or dedicated software that (hopefully) correctly implements the protocol in question, as there is usually a lot more involved than setting a few bits in the body of a packet and sending that out over the wire, notably handling responses, retrying after timeout or error, packet header fields, etc. The protocols are usually very well documented in RFC, or see the "TCP/IP Illustrated" book series by Stevens for even more documentation.



    Specific tools such as nmap do very custom things with packet construction. Otherwise for manual packet construction a programming language is typically used, though again most software will use existing libraries or system services to send out DNS or DHCP or other UDP packets, as those are far less work and far less error prone than manually crafting a raw packet from scratch.






    share|improve this answer























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      3 Answers
      3






      active

      oldest

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      3 Answers
      3






      active

      oldest

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      active

      oldest

      votes






      active

      oldest

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      up vote
      40
      down vote













      Your packet is completely valid, from the viewpoint of IP and UDP. If you expand the protocol details for Ethernet/IP/UDP in the lower pane of Wireshark, you will see that the packet is successfully parsed.



      However, as it is destined for port 53, Wireshark attempts to parse it as a DNS packet, which it cannot do (since the string "this is a test" is not a valid DNS request per the RFC 1035 spec).



      If you follow the specification at that link, you will be able to construct a packet that is valid when parsed as a DNS request. If you send the packet to another port, you'll notice that Wireshark will no longer parse it as a DNS request and will hence not show that warning.






      share|improve this answer

























        up vote
        40
        down vote













        Your packet is completely valid, from the viewpoint of IP and UDP. If you expand the protocol details for Ethernet/IP/UDP in the lower pane of Wireshark, you will see that the packet is successfully parsed.



        However, as it is destined for port 53, Wireshark attempts to parse it as a DNS packet, which it cannot do (since the string "this is a test" is not a valid DNS request per the RFC 1035 spec).



        If you follow the specification at that link, you will be able to construct a packet that is valid when parsed as a DNS request. If you send the packet to another port, you'll notice that Wireshark will no longer parse it as a DNS request and will hence not show that warning.






        share|improve this answer























          up vote
          40
          down vote










          up vote
          40
          down vote









          Your packet is completely valid, from the viewpoint of IP and UDP. If you expand the protocol details for Ethernet/IP/UDP in the lower pane of Wireshark, you will see that the packet is successfully parsed.



          However, as it is destined for port 53, Wireshark attempts to parse it as a DNS packet, which it cannot do (since the string "this is a test" is not a valid DNS request per the RFC 1035 spec).



          If you follow the specification at that link, you will be able to construct a packet that is valid when parsed as a DNS request. If you send the packet to another port, you'll notice that Wireshark will no longer parse it as a DNS request and will hence not show that warning.






          share|improve this answer












          Your packet is completely valid, from the viewpoint of IP and UDP. If you expand the protocol details for Ethernet/IP/UDP in the lower pane of Wireshark, you will see that the packet is successfully parsed.



          However, as it is destined for port 53, Wireshark attempts to parse it as a DNS packet, which it cannot do (since the string "this is a test" is not a valid DNS request per the RFC 1035 spec).



          If you follow the specification at that link, you will be able to construct a packet that is valid when parsed as a DNS request. If you send the packet to another port, you'll notice that Wireshark will no longer parse it as a DNS request and will hence not show that warning.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 23 at 19:29









          hexafraction

          540518




          540518
























              up vote
              14
              down vote













              You can send them to Bash special aliases with redirection.



              From Bash manpages:




              /dev/tcp/host/port
              If host is a valid hostname or Internet address, and port is an integer port number or service name, bash attempts to open the
              corresponding TCP socket.



              /dev/udp/host/port
              If host is a valid hostname or Internet address, and port is an integer port number or service name, bash attempts to open the
              corresponding UDP socket.




              This will send a UDP packet to 192.168.2.11 to port 8080:



              echo "This is a test" > /dev/udp/192.168.2.11/8080





              share|improve this answer























              • Thanks for this answer. I've updated my question. Using your method also produces a "malformed packet" error message, unfortunately.
                – user322500
                Nov 23 at 16:42















              up vote
              14
              down vote













              You can send them to Bash special aliases with redirection.



              From Bash manpages:




              /dev/tcp/host/port
              If host is a valid hostname or Internet address, and port is an integer port number or service name, bash attempts to open the
              corresponding TCP socket.



              /dev/udp/host/port
              If host is a valid hostname or Internet address, and port is an integer port number or service name, bash attempts to open the
              corresponding UDP socket.




              This will send a UDP packet to 192.168.2.11 to port 8080:



              echo "This is a test" > /dev/udp/192.168.2.11/8080





              share|improve this answer























              • Thanks for this answer. I've updated my question. Using your method also produces a "malformed packet" error message, unfortunately.
                – user322500
                Nov 23 at 16:42













              up vote
              14
              down vote










              up vote
              14
              down vote









              You can send them to Bash special aliases with redirection.



              From Bash manpages:




              /dev/tcp/host/port
              If host is a valid hostname or Internet address, and port is an integer port number or service name, bash attempts to open the
              corresponding TCP socket.



              /dev/udp/host/port
              If host is a valid hostname or Internet address, and port is an integer port number or service name, bash attempts to open the
              corresponding UDP socket.




              This will send a UDP packet to 192.168.2.11 to port 8080:



              echo "This is a test" > /dev/udp/192.168.2.11/8080





              share|improve this answer














              You can send them to Bash special aliases with redirection.



              From Bash manpages:




              /dev/tcp/host/port
              If host is a valid hostname or Internet address, and port is an integer port number or service name, bash attempts to open the
              corresponding TCP socket.



              /dev/udp/host/port
              If host is a valid hostname or Internet address, and port is an integer port number or service name, bash attempts to open the
              corresponding UDP socket.




              This will send a UDP packet to 192.168.2.11 to port 8080:



              echo "This is a test" > /dev/udp/192.168.2.11/8080






              share|improve this answer














              share|improve this answer



              share|improve this answer








              edited Nov 23 at 20:05









              Peter Mortensen

              85758




              85758










              answered Nov 23 at 16:13









              rAlen

              675410




              675410












              • Thanks for this answer. I've updated my question. Using your method also produces a "malformed packet" error message, unfortunately.
                – user322500
                Nov 23 at 16:42


















              • Thanks for this answer. I've updated my question. Using your method also produces a "malformed packet" error message, unfortunately.
                – user322500
                Nov 23 at 16:42
















              Thanks for this answer. I've updated my question. Using your method also produces a "malformed packet" error message, unfortunately.
              – user322500
              Nov 23 at 16:42




              Thanks for this answer. I've updated my question. Using your method also produces a "malformed packet" error message, unfortunately.
              – user322500
              Nov 23 at 16:42










              up vote
              -1
              down vote













              There are multiple questions here; the claim of a "malformed packet" may be due to checksum offloading and if so is a false error as it reflects the packet capture not having a complete view--some of the work was instead done on the network hardware. WireShark should have documentation on this.



              Otherwise, various tools (such as socat, nc or netcat, or via extremely similar features in shells such as ksh93 or bash) can take bytes from standard input and dump them into what becomes a UDP packet. Whether this is "proper" depends on the protocol; one could in theory construct and send a DNS or DHCP packet this way, though more often folks use a library or dedicated software that (hopefully) correctly implements the protocol in question, as there is usually a lot more involved than setting a few bits in the body of a packet and sending that out over the wire, notably handling responses, retrying after timeout or error, packet header fields, etc. The protocols are usually very well documented in RFC, or see the "TCP/IP Illustrated" book series by Stevens for even more documentation.



              Specific tools such as nmap do very custom things with packet construction. Otherwise for manual packet construction a programming language is typically used, though again most software will use existing libraries or system services to send out DNS or DHCP or other UDP packets, as those are far less work and far less error prone than manually crafting a raw packet from scratch.






              share|improve this answer



























                up vote
                -1
                down vote













                There are multiple questions here; the claim of a "malformed packet" may be due to checksum offloading and if so is a false error as it reflects the packet capture not having a complete view--some of the work was instead done on the network hardware. WireShark should have documentation on this.



                Otherwise, various tools (such as socat, nc or netcat, or via extremely similar features in shells such as ksh93 or bash) can take bytes from standard input and dump them into what becomes a UDP packet. Whether this is "proper" depends on the protocol; one could in theory construct and send a DNS or DHCP packet this way, though more often folks use a library or dedicated software that (hopefully) correctly implements the protocol in question, as there is usually a lot more involved than setting a few bits in the body of a packet and sending that out over the wire, notably handling responses, retrying after timeout or error, packet header fields, etc. The protocols are usually very well documented in RFC, or see the "TCP/IP Illustrated" book series by Stevens for even more documentation.



                Specific tools such as nmap do very custom things with packet construction. Otherwise for manual packet construction a programming language is typically used, though again most software will use existing libraries or system services to send out DNS or DHCP or other UDP packets, as those are far less work and far less error prone than manually crafting a raw packet from scratch.






                share|improve this answer

























                  up vote
                  -1
                  down vote










                  up vote
                  -1
                  down vote









                  There are multiple questions here; the claim of a "malformed packet" may be due to checksum offloading and if so is a false error as it reflects the packet capture not having a complete view--some of the work was instead done on the network hardware. WireShark should have documentation on this.



                  Otherwise, various tools (such as socat, nc or netcat, or via extremely similar features in shells such as ksh93 or bash) can take bytes from standard input and dump them into what becomes a UDP packet. Whether this is "proper" depends on the protocol; one could in theory construct and send a DNS or DHCP packet this way, though more often folks use a library or dedicated software that (hopefully) correctly implements the protocol in question, as there is usually a lot more involved than setting a few bits in the body of a packet and sending that out over the wire, notably handling responses, retrying after timeout or error, packet header fields, etc. The protocols are usually very well documented in RFC, or see the "TCP/IP Illustrated" book series by Stevens for even more documentation.



                  Specific tools such as nmap do very custom things with packet construction. Otherwise for manual packet construction a programming language is typically used, though again most software will use existing libraries or system services to send out DNS or DHCP or other UDP packets, as those are far less work and far less error prone than manually crafting a raw packet from scratch.






                  share|improve this answer














                  There are multiple questions here; the claim of a "malformed packet" may be due to checksum offloading and if so is a false error as it reflects the packet capture not having a complete view--some of the work was instead done on the network hardware. WireShark should have documentation on this.



                  Otherwise, various tools (such as socat, nc or netcat, or via extremely similar features in shells such as ksh93 or bash) can take bytes from standard input and dump them into what becomes a UDP packet. Whether this is "proper" depends on the protocol; one could in theory construct and send a DNS or DHCP packet this way, though more often folks use a library or dedicated software that (hopefully) correctly implements the protocol in question, as there is usually a lot more involved than setting a few bits in the body of a packet and sending that out over the wire, notably handling responses, retrying after timeout or error, packet header fields, etc. The protocols are usually very well documented in RFC, or see the "TCP/IP Illustrated" book series by Stevens for even more documentation.



                  Specific tools such as nmap do very custom things with packet construction. Otherwise for manual packet construction a programming language is typically used, though again most software will use existing libraries or system services to send out DNS or DHCP or other UDP packets, as those are far less work and far less error prone than manually crafting a raw packet from scratch.







                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited Nov 24 at 9:12









                  Stéphane Chazelas

                  295k54559902




                  295k54559902










                  answered Nov 23 at 17:47









                  thrig

                  23.8k12955




                  23.8k12955






























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