Alternatives of lists vs Alternatives of strings

up vote
4
down vote

favorite

Obviously I am missing something obvious.

I have:

lis = {"a"}|{"b"}|{"c"}

but I want:

lis2 = "a"|"b"|"c"

Thanks as always for suggestions...

asked Nov 24 at 20:03

Suite401

959312

add a comment |

up vote
4
down vote

favorite

Obviously I am missing something obvious.

I have:

lis = {"a"}|{"b"}|{"c"}

but I want:

lis2 = "a"|"b"|"c"

Thanks as always for suggestions...

asked Nov 24 at 20:03

Suite401

959312

add a comment |

up vote
4
down vote

favorite

Obviously I am missing something obvious.

I have:

lis = {"a"}|{"b"}|{"c"}

but I want:

lis2 = "a"|"b"|"c"

Thanks as always for suggestions...

asked Nov 24 at 20:03

Suite401

959312

Obviously I am missing something obvious.

I have:

lis = {"a"}|{"b"}|{"c"}

but I want:

lis2 = "a"|"b"|"c"

Thanks as always for suggestions...

list-manipulation

asked Nov 24 at 20:03

Suite401

959312

asked Nov 24 at 20:03

Suite401

959312

asked Nov 24 at 20:03

Suite401

959312

asked Nov 24 at 20:03

Suite401

959312

asked Nov 24 at 20:03

Suite401

959312

add a comment |

2 Answers
2

active

oldest

votes

up vote
6
down vote

accepted

Use lis[[All, 1]] or First /@ list. See Part and First.

answered Nov 24 at 20:06

Szabolcs

157k13430918

add a comment |

up vote
6
down vote

You can also Apply (@@@) Sequence at level 1:

Sequence @@@ lis

Also

## & @@@ lis

Alternatively, use ReplaceAll to replace List with Sequence:

lis /. List -> Sequence

Additional methods:

MapAt[Sequence &, lis, {All, 0}]

ReplacePart[lis, {_, 0} :> Sequence]

lis[[All, 0]] = Sequence; lis

all give "a" | "b" | "c".

edited Nov 25 at 8:20

answered Nov 24 at 20:22

kglr

174k8196401

add a comment |

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

up vote
6
down vote

accepted

Use lis[[All, 1]] or First /@ list. See Part and First.

answered Nov 24 at 20:06

Szabolcs

157k13430918

add a comment |

up vote
6
down vote

accepted

Use lis[[All, 1]] or First /@ list. See Part and First.

answered Nov 24 at 20:06

Szabolcs

157k13430918

add a comment |

up vote
6
down vote

accepted

Use lis[[All, 1]] or First /@ list. See Part and First.

answered Nov 24 at 20:06

Szabolcs

157k13430918

Use lis[[All, 1]] or First /@ list. See Part and First.

answered Nov 24 at 20:06

Szabolcs

157k13430918

answered Nov 24 at 20:06

Szabolcs

157k13430918

answered Nov 24 at 20:06

Szabolcs

157k13430918

answered Nov 24 at 20:06

Szabolcs

157k13430918

add a comment |

up vote
6
down vote

You can also Apply (@@@) Sequence at level 1:

Sequence @@@ lis

Also

## & @@@ lis

Alternatively, use ReplaceAll to replace List with Sequence:

lis /. List -> Sequence

Additional methods:

MapAt[Sequence &, lis, {All, 0}]

ReplacePart[lis, {_, 0} :> Sequence]

lis[[All, 0]] = Sequence; lis

all give "a" | "b" | "c".

edited Nov 25 at 8:20

answered Nov 24 at 20:22

kglr

174k8196401

add a comment |

up vote
6
down vote

You can also Apply (@@@) Sequence at level 1:

Sequence @@@ lis

Also

## & @@@ lis

Alternatively, use ReplaceAll to replace List with Sequence:

lis /. List -> Sequence

Additional methods:

MapAt[Sequence &, lis, {All, 0}]

ReplacePart[lis, {_, 0} :> Sequence]

lis[[All, 0]] = Sequence; lis

all give "a" | "b" | "c".

edited Nov 25 at 8:20

answered Nov 24 at 20:22

kglr

174k8196401

add a comment |

up vote
6
down vote

You can also Apply (@@@) Sequence at level 1:

Sequence @@@ lis

Also

## & @@@ lis

Alternatively, use ReplaceAll to replace List with Sequence:

lis /. List -> Sequence

Additional methods:

MapAt[Sequence &, lis, {All, 0}]

ReplacePart[lis, {_, 0} :> Sequence]

lis[[All, 0]] = Sequence; lis

all give "a" | "b" | "c".

edited Nov 25 at 8:20

answered Nov 24 at 20:22

kglr

174k8196401

You can also Apply (@@@) Sequence at level 1:

Sequence @@@ lis

Also

## & @@@ lis

Alternatively, use ReplaceAll to replace List with Sequence:

lis /. List -> Sequence

Additional methods:

MapAt[Sequence &, lis, {All, 0}]

ReplacePart[lis, {_, 0} :> Sequence]

lis[[All, 0]] = Sequence; lis

all give "a" | "b" | "c".

edited Nov 25 at 8:20

answered Nov 24 at 20:22

kglr

174k8196401

edited Nov 25 at 8:20

answered Nov 24 at 20:22

kglr

174k8196401

answered Nov 24 at 20:22

kglr

174k8196401

answered Nov 24 at 20:22

kglr

174k8196401

add a comment |

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