XCTest: Tap “Done” button in SFSafariViewController
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I'm opening a SFSafariViewController and can't find the "Done" Button to leave Safari again.
Also if I try to solve it with a swipeRight XCode creates code that it can't use in a test afterwards
let element = app.children(matching: .window).element(boundBy: 0).children(matching: .other).element.children(matching: .other).element.children(matching: .other).element(boundBy: 2)
element.swipeRight()
Any idea how to dismiss SFSafariViewController? (I don't need access to elements in the browser).
xcode xctest xcuitest uitest
edited Nov 19 at 23:40
Jon Reid
15.7k24878
asked Nov 19 at 8:02
netshark1000
3,48543867
add a comment |
up vote
0
down vote
favorite
I'm opening a SFSafariViewController and can't find the "Done" Button to leave Safari again.
Also if I try to solve it with a swipeRight XCode creates code that it can't use in a test afterwards
let element = app.children(matching: .window).element(boundBy: 0).children(matching: .other).element.children(matching: .other).element.children(matching: .other).element(boundBy: 2)
element.swipeRight()
Any idea how to dismiss SFSafariViewController? (I don't need access to elements in the browser).
xcode xctest xcuitest uitest
edited Nov 19 at 23:40
Jon Reid
15.7k24878
asked Nov 19 at 8:02
netshark1000
3,48543867
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I'm opening a SFSafariViewController and can't find the "Done" Button to leave Safari again.
Also if I try to solve it with a swipeRight XCode creates code that it can't use in a test afterwards
let element = app.children(matching: .window).element(boundBy: 0).children(matching: .other).element.children(matching: .other).element.children(matching: .other).element(boundBy: 2)
element.swipeRight()
Any idea how to dismiss SFSafariViewController? (I don't need access to elements in the browser).
xcode xctest xcuitest uitest
edited Nov 19 at 23:40
Jon Reid
15.7k24878
asked Nov 19 at 8:02
netshark1000
3,48543867
I'm opening a SFSafariViewController and can't find the "Done" Button to leave Safari again.
Also if I try to solve it with a swipeRight XCode creates code that it can't use in a test afterwards
let element = app.children(matching: .window).element(boundBy: 0).children(matching: .other).element.children(matching: .other).element.children(matching: .other).element(boundBy: 2)
element.swipeRight()
Any idea how to dismiss SFSafariViewController? (I don't need access to elements in the browser).
xcode xctest xcuitest uitest
xcode xctest xcuitest uitest
edited Nov 19 at 23:40
Jon Reid
15.7k24878
asked Nov 19 at 8:02
netshark1000
3,48543867
edited Nov 19 at 23:40
Jon Reid
15.7k24878
asked Nov 19 at 8:02
netshark1000
3,48543867
edited Nov 19 at 23:40
Jon Reid
15.7k24878
edited Nov 19 at 23:40
Jon Reid
15.7k24878
edited Nov 19 at 23:40
Jon Reid
15.7k24878
15.7k24878
asked Nov 19 at 8:02
netshark1000
3,48543867
asked Nov 19 at 8:02
netshark1000
3,48543867
asked Nov 19 at 8:02
netshark1000
3,48543867
3,48543867
add a comment |
add a comment |
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