Pandas Dataframe selecting groups with minimal cardinality
I have a problem where I need to take groups of rows from a data frame where the number of items in a group exceeds a certain number (cutoff). For those groups, I need to take some head rows and the tail row.
I am using the code below
train = train[train.groupby('id').id.transform(len) > headRows]
groups = pd.concat([train.groupby('id').head(headRows),train.groupby('id').tail(1)]).sort_index()
This works. But the first line, it is very slow :(. 30 minutes or more.
Is there any way to make the first line faster ? If I do not use the first line, there are duplicate indices from the result of the second line, which messes up things.
Thanks in advance
Regards
Note:
My train data frame has around 70,000 groups of varying group size over around 700,000 rows . It actually follows from my other question as can be seen here Data processing with adding columns dynamically in Python Pandas Dataframe.
Jeff gave a great answer there, but it fails if the group size is less or equal to parameter I pass in head(parameter) when concatenating my rows as in Jeffs answer : In [31]: groups = concat.....
python pandas dataframe data-processing
edited May 23 '17 at 10:28
Community♦
11
asked May 18 '14 at 6:28
Run2
9721226
add a comment |
I have a problem where I need to take groups of rows from a data frame where the number of items in a group exceeds a certain number (cutoff). For those groups, I need to take some head rows and the tail row.
I am using the code below
train = train[train.groupby('id').id.transform(len) > headRows]
groups = pd.concat([train.groupby('id').head(headRows),train.groupby('id').tail(1)]).sort_index()
This works. But the first line, it is very slow :(. 30 minutes or more.
Is there any way to make the first line faster ? If I do not use the first line, there are duplicate indices from the result of the second line, which messes up things.
Thanks in advance
Regards
Note:
My train data frame has around 70,000 groups of varying group size over around 700,000 rows . It actually follows from my other question as can be seen here Data processing with adding columns dynamically in Python Pandas Dataframe.
Jeff gave a great answer there, but it fails if the group size is less or equal to parameter I pass in head(parameter) when concatenating my rows as in Jeffs answer : In [31]: groups = concat.....
python pandas dataframe data-processing
edited May 23 '17 at 10:28
Community♦
11
asked May 18 '14 at 6:28
Run2
9721226
add a comment |
I have a problem where I need to take groups of rows from a data frame where the number of items in a group exceeds a certain number (cutoff). For those groups, I need to take some head rows and the tail row.
I am using the code below
train = train[train.groupby('id').id.transform(len) > headRows]
groups = pd.concat([train.groupby('id').head(headRows),train.groupby('id').tail(1)]).sort_index()
This works. But the first line, it is very slow :(. 30 minutes or more.
Is there any way to make the first line faster ? If I do not use the first line, there are duplicate indices from the result of the second line, which messes up things.
Thanks in advance
Regards
Note:
My train data frame has around 70,000 groups of varying group size over around 700,000 rows . It actually follows from my other question as can be seen here Data processing with adding columns dynamically in Python Pandas Dataframe.
Jeff gave a great answer there, but it fails if the group size is less or equal to parameter I pass in head(parameter) when concatenating my rows as in Jeffs answer : In [31]: groups = concat.....
python pandas dataframe data-processing
edited May 23 '17 at 10:28
Community♦
11
asked May 18 '14 at 6:28
Run2
9721226
I have a problem where I need to take groups of rows from a data frame where the number of items in a group exceeds a certain number (cutoff). For those groups, I need to take some head rows and the tail row.
I am using the code below
train = train[train.groupby('id').id.transform(len) > headRows]
groups = pd.concat([train.groupby('id').head(headRows),train.groupby('id').tail(1)]).sort_index()
This works. But the first line, it is very slow :(. 30 minutes or more.
Is there any way to make the first line faster ? If I do not use the first line, there are duplicate indices from the result of the second line, which messes up things.
Thanks in advance
Regards
Note:
My train data frame has around 70,000 groups of varying group size over around 700,000 rows . It actually follows from my other question as can be seen here Data processing with adding columns dynamically in Python Pandas Dataframe.
Jeff gave a great answer there, but it fails if the group size is less or equal to parameter I pass in head(parameter) when concatenating my rows as in Jeffs answer : In [31]: groups = concat.....
python pandas dataframe data-processing
python pandas dataframe data-processing
edited May 23 '17 at 10:28
Community♦
11
asked May 18 '14 at 6:28
Run2
9721226
edited May 23 '17 at 10:28
Community♦
11
asked May 18 '14 at 6:28
Run2
9721226
edited May 23 '17 at 10:28
Community♦
11
edited May 23 '17 at 10:28
Community♦
11
edited May 23 '17 at 10:28
Community♦
11
11
asked May 18 '14 at 6:28
Run2
9721226
asked May 18 '14 at 6:28
Run2
9721226
asked May 18 '14 at 6:28
Run2
9721226
9721226
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Use groupby/filter:
>>> df.groupby('id').filter(lambda x: len(x) > cutoff)
This will just return the rows of your dataframe where the size of the group is greater than your cutoff. Also, it should perform quite a bit better. I timed filter here with a dataframe with 30,039 'id' groups and a little over 4 million observations:
In [9]: %timeit df.groupby('id').filter(lambda x: len(x) > 12)
1 loops, best of 3: 12.6 s per loop
answered May 18 '14 at 6:51
Karl D.
7,0512827
Hey thanks Karl. Let me evaluate that. I will get back. Thanks
– Run2
May 18 '14 at 6:54
1
Hey Karl, worked. 4 mins now. Thanks.
– Run2
May 18 '14 at 7:04
@Karl D If u your take this question (and the original) and make a combined entry for the cookbook would be great (maybe add a little explanation of the problem). thanks
– Jeff
May 18 '14 at 10:57
Yeah, I can do that @Jeff.
– Karl D.
May 18 '14 at 18:35
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Use groupby/filter:
>>> df.groupby('id').filter(lambda x: len(x) > cutoff)
This will just return the rows of your dataframe where the size of the group is greater than your cutoff. Also, it should perform quite a bit better. I timed filter here with a dataframe with 30,039 'id' groups and a little over 4 million observations:
In [9]: %timeit df.groupby('id').filter(lambda x: len(x) > 12)
1 loops, best of 3: 12.6 s per loop
answered May 18 '14 at 6:51
Karl D.
7,0512827
Hey thanks Karl. Let me evaluate that. I will get back. Thanks
– Run2
May 18 '14 at 6:54
1
Hey Karl, worked. 4 mins now. Thanks.
– Run2
May 18 '14 at 7:04
@Karl D If u your take this question (and the original) and make a combined entry for the cookbook would be great (maybe add a little explanation of the problem). thanks
– Jeff
May 18 '14 at 10:57
Yeah, I can do that @Jeff.
– Karl D.
May 18 '14 at 18:35
add a comment |
Use groupby/filter:
>>> df.groupby('id').filter(lambda x: len(x) > cutoff)
This will just return the rows of your dataframe where the size of the group is greater than your cutoff. Also, it should perform quite a bit better. I timed filter here with a dataframe with 30,039 'id' groups and a little over 4 million observations:
In [9]: %timeit df.groupby('id').filter(lambda x: len(x) > 12)
1 loops, best of 3: 12.6 s per loop
answered May 18 '14 at 6:51
Karl D.
7,0512827
Hey thanks Karl. Let me evaluate that. I will get back. Thanks
– Run2
May 18 '14 at 6:54
1
Hey Karl, worked. 4 mins now. Thanks.
– Run2
May 18 '14 at 7:04
@Karl D If u your take this question (and the original) and make a combined entry for the cookbook would be great (maybe add a little explanation of the problem). thanks
– Jeff
May 18 '14 at 10:57
Yeah, I can do that @Jeff.
– Karl D.
May 18 '14 at 18:35
add a comment |
Use groupby/filter:
>>> df.groupby('id').filter(lambda x: len(x) > cutoff)
This will just return the rows of your dataframe where the size of the group is greater than your cutoff. Also, it should perform quite a bit better. I timed filter here with a dataframe with 30,039 'id' groups and a little over 4 million observations:
In [9]: %timeit df.groupby('id').filter(lambda x: len(x) > 12)
1 loops, best of 3: 12.6 s per loop
answered May 18 '14 at 6:51
Karl D.
7,0512827
Use groupby/filter:
>>> df.groupby('id').filter(lambda x: len(x) > cutoff)
This will just return the rows of your dataframe where the size of the group is greater than your cutoff. Also, it should perform quite a bit better. I timed filter here with a dataframe with 30,039 'id' groups and a little over 4 million observations:
In [9]: %timeit df.groupby('id').filter(lambda x: len(x) > 12)
1 loops, best of 3: 12.6 s per loop
answered May 18 '14 at 6:51
Karl D.
7,0512827
edited May 18 '14 at 7:07
answered May 18 '14 at 6:51
Karl D.
7,0512827
answered May 18 '14 at 6:51
Karl D.
7,0512827
answered May 18 '14 at 6:51
Karl D.
7,0512827
7,0512827
Hey thanks Karl. Let me evaluate that. I will get back. Thanks
– Run2
May 18 '14 at 6:54
1
Hey Karl, worked. 4 mins now. Thanks.
– Run2
May 18 '14 at 7:04
@Karl D If u your take this question (and the original) and make a combined entry for the cookbook would be great (maybe add a little explanation of the problem). thanks
– Jeff
May 18 '14 at 10:57
Yeah, I can do that @Jeff.
– Karl D.
May 18 '14 at 18:35
add a comment |
Hey thanks Karl. Let me evaluate that. I will get back. Thanks
– Run2
May 18 '14 at 6:54
1
Hey Karl, worked. 4 mins now. Thanks.
– Run2
May 18 '14 at 7:04
@Karl D If u your take this question (and the original) and make a combined entry for the cookbook would be great (maybe add a little explanation of the problem). thanks
– Jeff
May 18 '14 at 10:57
Yeah, I can do that @Jeff.
– Karl D.
May 18 '14 at 18:35
Hey thanks Karl. Let me evaluate that. I will get back. Thanks
– Run2
May 18 '14 at 6:54
Hey thanks Karl. Let me evaluate that. I will get back. Thanks
– Run2
May 18 '14 at 6:54
1
1
Hey Karl, worked. 4 mins now. Thanks.
– Run2
May 18 '14 at 7:04
Hey Karl, worked. 4 mins now. Thanks.
– Run2
May 18 '14 at 7:04
@Karl D If u your take this question (and the original) and make a combined entry for the cookbook would be great (maybe add a little explanation of the problem). thanks
– Jeff
May 18 '14 at 10:57
@Karl D If u your take this question (and the original) and make a combined entry for the cookbook would be great (maybe add a little explanation of the problem). thanks
– Jeff
May 18 '14 at 10:57
Yeah, I can do that @Jeff.
– Karl D.
May 18 '14 at 18:35
Yeah, I can do that @Jeff.
– Karl D.
May 18 '14 at 18:35
add a comment |
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