[JS][AJAX] second ajax does not work. Why?
0
I have little problem :) The first ajax returns the correct value.
Then I extract the text from the first answer and I want to send this text to another ajax file. but the second one sends an empty value. Why?
So this is my code:
var fileName = "record.wav";
var formdata = new FormData();
formdata.append('file', blob);
$.ajax({
url: "sendFileAudio.php",
type: 'POST',
data: formdata,
// async: true,
cache: false,
contentType: false,
processData: false,
beforeSend: function() {
$("#loaderStt").show();
},
success: function(data) {
console.log(data);
var messagesContainerOther = $(".messages");
messagesContainerOther.append(
data
);
var audioRsp = $(data).text();
var pytanie = audioRsp.valueOf();
// alert(typeof audioRsp);
document.getElementById("wiadomosc").innerHTML = pytanie;
// var pytanie = $("#wiadomosc").text();
$.ajax({
url: "sendMessageSamara.php",
type: 'POST',
data: pytanie,
beforeSend: function() {
$("#loader").show();
},
success: function(data) {
// console.log(data);
// alert("2"+ref);
console.log("poszło");
console.log(pytanie);
var messagesContainerOther = $(".messages");
messagesContainerOther.append(
data
);
messagesContainerOther.finish().animate({
scrollTop: messagesContainerOther.prop("scrollHeight")
},
250
);
},
complete: function(data) {
$("#loader").hide();
},
});
},
complete: function(data) {
$("#loaderStt").hide();
},
});
javascript jquery ajax
edited Nov 19 at 22:28
charlietfl
138k1286118
asked Nov 19 at 22:25
Michal Robak
31
add a comment |
0
I have little problem :) The first ajax returns the correct value.
Then I extract the text from the first answer and I want to send this text to another ajax file. but the second one sends an empty value. Why?
So this is my code:
var fileName = "record.wav";
var formdata = new FormData();
formdata.append('file', blob);
$.ajax({
url: "sendFileAudio.php",
type: 'POST',
data: formdata,
// async: true,
cache: false,
contentType: false,
processData: false,
beforeSend: function() {
$("#loaderStt").show();
},
success: function(data) {
console.log(data);
var messagesContainerOther = $(".messages");
messagesContainerOther.append(
data
);
var audioRsp = $(data).text();
var pytanie = audioRsp.valueOf();
// alert(typeof audioRsp);
document.getElementById("wiadomosc").innerHTML = pytanie;
// var pytanie = $("#wiadomosc").text();
$.ajax({
url: "sendMessageSamara.php",
type: 'POST',
data: pytanie,
beforeSend: function() {
$("#loader").show();
},
success: function(data) {
// console.log(data);
// alert("2"+ref);
console.log("poszło");
console.log(pytanie);
var messagesContainerOther = $(".messages");
messagesContainerOther.append(
data
);
messagesContainerOther.finish().animate({
scrollTop: messagesContainerOther.prop("scrollHeight")
},
250
);
},
complete: function(data) {
$("#loader").hide();
},
});
},
complete: function(data) {
$("#loaderStt").hide();
},
});
javascript jquery ajax
edited Nov 19 at 22:28
charlietfl
138k1286118
asked Nov 19 at 22:25
Michal Robak
31
add a comment |
0
0
0
I have little problem :) The first ajax returns the correct value.
Then I extract the text from the first answer and I want to send this text to another ajax file. but the second one sends an empty value. Why?
So this is my code:
var fileName = "record.wav";
var formdata = new FormData();
formdata.append('file', blob);
$.ajax({
url: "sendFileAudio.php",
type: 'POST',
data: formdata,
// async: true,
cache: false,
contentType: false,
processData: false,
beforeSend: function() {
$("#loaderStt").show();
},
success: function(data) {
console.log(data);
var messagesContainerOther = $(".messages");
messagesContainerOther.append(
data
);
var audioRsp = $(data).text();
var pytanie = audioRsp.valueOf();
// alert(typeof audioRsp);
document.getElementById("wiadomosc").innerHTML = pytanie;
// var pytanie = $("#wiadomosc").text();
$.ajax({
url: "sendMessageSamara.php",
type: 'POST',
data: pytanie,
beforeSend: function() {
$("#loader").show();
},
success: function(data) {
// console.log(data);
// alert("2"+ref);
console.log("poszło");
console.log(pytanie);
var messagesContainerOther = $(".messages");
messagesContainerOther.append(
data
);
messagesContainerOther.finish().animate({
scrollTop: messagesContainerOther.prop("scrollHeight")
},
250
);
},
complete: function(data) {
$("#loader").hide();
},
});
},
complete: function(data) {
$("#loaderStt").hide();
},
});
javascript jquery ajax
edited Nov 19 at 22:28
charlietfl
138k1286118
asked Nov 19 at 22:25
Michal Robak
31
I have little problem :) The first ajax returns the correct value.
Then I extract the text from the first answer and I want to send this text to another ajax file. but the second one sends an empty value. Why?
So this is my code:
var fileName = "record.wav";
var formdata = new FormData();
formdata.append('file', blob);
$.ajax({
url: "sendFileAudio.php",
type: 'POST',
data: formdata,
// async: true,
cache: false,
contentType: false,
processData: false,
beforeSend: function() {
$("#loaderStt").show();
},
success: function(data) {
console.log(data);
var messagesContainerOther = $(".messages");
messagesContainerOther.append(
data
);
var audioRsp = $(data).text();
var pytanie = audioRsp.valueOf();
// alert(typeof audioRsp);
document.getElementById("wiadomosc").innerHTML = pytanie;
// var pytanie = $("#wiadomosc").text();
$.ajax({
url: "sendMessageSamara.php",
type: 'POST',
data: pytanie,
beforeSend: function() {
$("#loader").show();
},
success: function(data) {
// console.log(data);
// alert("2"+ref);
console.log("poszło");
console.log(pytanie);
var messagesContainerOther = $(".messages");
messagesContainerOther.append(
data
);
messagesContainerOther.finish().animate({
scrollTop: messagesContainerOther.prop("scrollHeight")
},
250
);
},
complete: function(data) {
$("#loader").hide();
},
});
},
complete: function(data) {
$("#loaderStt").hide();
},
});
javascript jquery ajax
javascript jquery ajax
edited Nov 19 at 22:28
charlietfl
138k1286118
asked Nov 19 at 22:25
Michal Robak
31
edited Nov 19 at 22:28
charlietfl
138k1286118
asked Nov 19 at 22:25
Michal Robak
31
edited Nov 19 at 22:28
charlietfl
138k1286118
edited Nov 19 at 22:28
charlietfl
138k1286118
edited Nov 19 at 22:28
charlietfl
138k1286118
138k1286118
asked Nov 19 at 22:25
Michal Robak
31
asked Nov 19 at 22:25
Michal Robak
31
asked Nov 19 at 22:25
Michal Robak
31
31
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
0
You aren't sending a key/value pair in the second request, only a value
Change
data: pytanie
to
data: {somePropertyName: pytanie}
And receive that in php with:
$_POST['somePropertyName'];
answered Nov 19 at 22:33
charlietfl
138k1286118
What exactly isn't working? Is request being made? inspect it in browser dev tools network and see what is sent is what you expect, status etc
– charlietfl
Nov 19 at 22:50
i add before: contentType: 'text/plain', haha :)
– Michal Robak
Nov 19 at 22:51
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
You aren't sending a key/value pair in the second request, only a value
Change
data: pytanie
to
data: {somePropertyName: pytanie}
And receive that in php with:
$_POST['somePropertyName'];
answered Nov 19 at 22:33
charlietfl
138k1286118
What exactly isn't working? Is request being made? inspect it in browser dev tools network and see what is sent is what you expect, status etc
– charlietfl
Nov 19 at 22:50
i add before: contentType: 'text/plain', haha :)
– Michal Robak
Nov 19 at 22:51
add a comment |
0
You aren't sending a key/value pair in the second request, only a value
Change
data: pytanie
to
data: {somePropertyName: pytanie}
And receive that in php with:
$_POST['somePropertyName'];
answered Nov 19 at 22:33
charlietfl
138k1286118
What exactly isn't working? Is request being made? inspect it in browser dev tools network and see what is sent is what you expect, status etc
– charlietfl
Nov 19 at 22:50
i add before: contentType: 'text/plain', haha :)
– Michal Robak
Nov 19 at 22:51
add a comment |
0
0
0
You aren't sending a key/value pair in the second request, only a value
Change
data: pytanie
to
data: {somePropertyName: pytanie}
And receive that in php with:
$_POST['somePropertyName'];
answered Nov 19 at 22:33
charlietfl
138k1286118
You aren't sending a key/value pair in the second request, only a value
Change
data: pytanie
to
data: {somePropertyName: pytanie}
And receive that in php with:
$_POST['somePropertyName'];
answered Nov 19 at 22:33
charlietfl
138k1286118
answered Nov 19 at 22:33
charlietfl
138k1286118
answered Nov 19 at 22:33
charlietfl
138k1286118
answered Nov 19 at 22:33
charlietfl
138k1286118
138k1286118
What exactly isn't working? Is request being made? inspect it in browser dev tools network and see what is sent is what you expect, status etc
– charlietfl
Nov 19 at 22:50
i add before: contentType: 'text/plain', haha :)
– Michal Robak
Nov 19 at 22:51
add a comment |
What exactly isn't working? Is request being made? inspect it in browser dev tools network and see what is sent is what you expect, status etc
– charlietfl
Nov 19 at 22:50
i add before: contentType: 'text/plain', haha :)
– Michal Robak
Nov 19 at 22:51
What exactly isn't working? Is request being made? inspect it in browser dev tools network and see what is sent is what you expect, status etc
– charlietfl
Nov 19 at 22:50
What exactly isn't working? Is request being made? inspect it in browser dev tools network and see what is sent is what you expect, status etc
– charlietfl
Nov 19 at 22:50
i add before: contentType: 'text/plain', haha :)
– Michal Robak
Nov 19 at 22:51
i add before: contentType: 'text/plain', haha :)
– Michal Robak
Nov 19 at 22:51
add a comment |
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