Sorting a list while keeping its correspondence to another list











up vote
5
down vote

favorite
1












I have the following two lists:



ids = {5, 11, 17, 24, 31, 37, 40, 39, 38, 33, 32, 25}



values = {0.0351563, 0.131836, 0.086792, 0.0637894, 0.065752, 0.191388, 0.063796, 0.173784, 0.0503769, 0.0875244, 0.0146484, 0.0351563}


where entries in values correspond to entries in ids.



I now wish to sort ids in ascending order while maintaining the correspondence to values, such that elements in values must be changed according to the changes made to ids.



How can that be achieved?






list-manipulation







share|improve this question
























  • values[[Ordering@ids]] and SortBy[Transpose[{ids, values}], First] == Transpose[{Sort@ids, values[[Ordering@ids]]}]
    – user1066
    Dec 2 at 17:53















up vote
5
down vote

favorite
1












I have the following two lists:



ids = {5, 11, 17, 24, 31, 37, 40, 39, 38, 33, 32, 25}



values = {0.0351563, 0.131836, 0.086792, 0.0637894, 0.065752, 0.191388, 0.063796, 0.173784, 0.0503769, 0.0875244, 0.0146484, 0.0351563}


where entries in values correspond to entries in ids.



I now wish to sort ids in ascending order while maintaining the correspondence to values, such that elements in values must be changed according to the changes made to ids.



How can that be achieved?






list-manipulation







share|improve this question
























  • values[[Ordering@ids]] and SortBy[Transpose[{ids, values}], First] == Transpose[{Sort@ids, values[[Ordering@ids]]}]
    – user1066
    Dec 2 at 17:53













up vote
5
down vote

favorite
1









up vote
5
down vote

favorite
1






1





I have the following two lists:



ids = {5, 11, 17, 24, 31, 37, 40, 39, 38, 33, 32, 25}



values = {0.0351563, 0.131836, 0.086792, 0.0637894, 0.065752, 0.191388, 0.063796, 0.173784, 0.0503769, 0.0875244, 0.0146484, 0.0351563}


where entries in values correspond to entries in ids.



I now wish to sort ids in ascending order while maintaining the correspondence to values, such that elements in values must be changed according to the changes made to ids.



How can that be achieved?






list-manipulation







share|improve this question















I have the following two lists:



ids = {5, 11, 17, 24, 31, 37, 40, 39, 38, 33, 32, 25}



values = {0.0351563, 0.131836, 0.086792, 0.0637894, 0.065752, 0.191388, 0.063796, 0.173784, 0.0503769, 0.0875244, 0.0146484, 0.0351563}


where entries in values correspond to entries in ids.



I now wish to sort ids in ascending order while maintaining the correspondence to values, such that elements in values must be changed according to the changes made to ids.



How can that be achieved?






list-manipulation




list-manipulation






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Dec 2 at 16:49

























asked Dec 2 at 16:40









user120911

54318




54318












  • values[[Ordering@ids]] and SortBy[Transpose[{ids, values}], First] == Transpose[{Sort@ids, values[[Ordering@ids]]}]
    – user1066
    Dec 2 at 17:53


















  • values[[Ordering@ids]] and SortBy[Transpose[{ids, values}], First] == Transpose[{Sort@ids, values[[Ordering@ids]]}]
    – user1066
    Dec 2 at 17:53
















values[[Ordering@ids]] and SortBy[Transpose[{ids, values}], First] == Transpose[{Sort@ids, values[[Ordering@ids]]}]
– user1066
Dec 2 at 17:53




values[[Ordering@ids]] and SortBy[Transpose[{ids, values}], First] == Transpose[{Sort@ids, values[[Ordering@ids]]}]
– user1066
Dec 2 at 17:53










4 Answers
4






active

oldest

votes

















up vote
5
down vote



accepted










With[{p = Ordering[ids]},

 idsnew = ids[[p]];

 valuesnew = values[[p]];

 ]

idsnew

valuesnew



{5, 11, 17, 24, 25, 31, 32, 33, 37, 38, 39, 40}



{0.0351563, 0.131836, 0.086792, 0.0637894, 0.0351563, 0.065752, 0.0146484, 0.0875244, 0.191388, 0.0503769, 0.173784, 0.063796}







share|improve this answer























  • This generates an error for me: Set::write: Tag Times in valuesnew {5,11,17,24,25,31,32,33,37,38,39,40} is Protected.
    – user120911
    Dec 2 at 16:59










  • Sorry, I missed a semicolon that was necessary after wrapping everything with With. Please try again.
    – Henrik Schumacher
    Dec 2 at 17:07


















up vote
4
down vote













I would keep them together while sorting.



SortBy[Transpose[{ids, values}], First]





{{5, 0.0351563}, {11, 0.131836}, {17, 0.086792}, {24, 0.0637894}, {25,

   0.0351563}, {31, 0.065752}, {32, 0.0146484}, {33, 0.0875244}, {37, 

  0.191388}, {38, 0.0503769}, {39, 0.173784}, {40, 0.063796}}






share|improve this answer





















  • See also my remark under Okke's post.
    – Henrik Schumacher
    Dec 2 at 18:17


















up vote
4
down vote













AssociationThread[ids, values] // KeySort


Edit
To extract keys and values



sorted = AssociationThread[ids, values] // KeySort

sortedIds = Keys[sorted]

sortedValues = Values[sorted]





share|improve this answer























  • This looks simple, but how do I work with these afterwards?
    – user120911
    Dec 2 at 17:00










  • @user120911 Added sorted key / value extraction.
    – Rohit Namjoshi
    Dec 2 at 17:24


















up vote
2
down vote













Since Sort sort it by the first entry by default 



Sort@Transpose@{ids, values}



{{5, 0.0351563}, {11, 0.131836}, {17, 0.086792}, {24, 0.0637894}, {25,
0.0351563}, {31, 0.065752}, {32, 0.0146484}, {33, 0.0875244}, {37,
0.191388}, {38, 0.0503769}, {39, 0.173784}, {40, 0.063796}}







share|improve this answer

















  • 1




    A problem that arises here with Transpose is is that it unpacks arrays: ids is a list of integers and values is a list of machine reals. So both can be packed separately; but not Transpose@{ids, values} as it has mixed data types. This may become important when processing large datasets.
    – Henrik Schumacher
    Dec 2 at 18:16











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4 Answers
4






active

oldest

votes








4 Answers
4






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
5
down vote



accepted










With[{p = Ordering[ids]},

 idsnew = ids[[p]];

 valuesnew = values[[p]];

 ]

idsnew

valuesnew



{5, 11, 17, 24, 25, 31, 32, 33, 37, 38, 39, 40}



{0.0351563, 0.131836, 0.086792, 0.0637894, 0.0351563, 0.065752, 0.0146484, 0.0875244, 0.191388, 0.0503769, 0.173784, 0.063796}







share|improve this answer























  • This generates an error for me: Set::write: Tag Times in valuesnew {5,11,17,24,25,31,32,33,37,38,39,40} is Protected.
    – user120911
    Dec 2 at 16:59










  • Sorry, I missed a semicolon that was necessary after wrapping everything with With. Please try again.
    – Henrik Schumacher
    Dec 2 at 17:07















up vote
5
down vote



accepted










With[{p = Ordering[ids]},

 idsnew = ids[[p]];

 valuesnew = values[[p]];

 ]

idsnew

valuesnew



{5, 11, 17, 24, 25, 31, 32, 33, 37, 38, 39, 40}



{0.0351563, 0.131836, 0.086792, 0.0637894, 0.0351563, 0.065752, 0.0146484, 0.0875244, 0.191388, 0.0503769, 0.173784, 0.063796}







share|improve this answer























  • This generates an error for me: Set::write: Tag Times in valuesnew {5,11,17,24,25,31,32,33,37,38,39,40} is Protected.
    – user120911
    Dec 2 at 16:59










  • Sorry, I missed a semicolon that was necessary after wrapping everything with With. Please try again.
    – Henrik Schumacher
    Dec 2 at 17:07













up vote
5
down vote



accepted







up vote
5
down vote



accepted






With[{p = Ordering[ids]},

 idsnew = ids[[p]];

 valuesnew = values[[p]];

 ]

idsnew

valuesnew



{5, 11, 17, 24, 25, 31, 32, 33, 37, 38, 39, 40}



{0.0351563, 0.131836, 0.086792, 0.0637894, 0.0351563, 0.065752, 0.0146484, 0.0875244, 0.191388, 0.0503769, 0.173784, 0.063796}







share|improve this answer














With[{p = Ordering[ids]},

 idsnew = ids[[p]];

 valuesnew = values[[p]];

 ]

idsnew

valuesnew



{5, 11, 17, 24, 25, 31, 32, 33, 37, 38, 39, 40}



{0.0351563, 0.131836, 0.086792, 0.0637894, 0.0351563, 0.065752, 0.0146484, 0.0875244, 0.191388, 0.0503769, 0.173784, 0.063796}








share|improve this answer














share|improve this answer



share|improve this answer








edited Dec 2 at 17:06

























answered Dec 2 at 16:48









Henrik Schumacher

47.4k466134




47.4k466134












  • This generates an error for me: Set::write: Tag Times in valuesnew {5,11,17,24,25,31,32,33,37,38,39,40} is Protected.
    – user120911
    Dec 2 at 16:59










  • Sorry, I missed a semicolon that was necessary after wrapping everything with With. Please try again.
    – Henrik Schumacher
    Dec 2 at 17:07


















  • This generates an error for me: Set::write: Tag Times in valuesnew {5,11,17,24,25,31,32,33,37,38,39,40} is Protected.
    – user120911
    Dec 2 at 16:59










  • Sorry, I missed a semicolon that was necessary after wrapping everything with With. Please try again.
    – Henrik Schumacher
    Dec 2 at 17:07
















This generates an error for me: Set::write: Tag Times in valuesnew {5,11,17,24,25,31,32,33,37,38,39,40} is Protected.
– user120911
Dec 2 at 16:59




This generates an error for me: Set::write: Tag Times in valuesnew {5,11,17,24,25,31,32,33,37,38,39,40} is Protected.
– user120911
Dec 2 at 16:59












Sorry, I missed a semicolon that was necessary after wrapping everything with With. Please try again.
– Henrik Schumacher
Dec 2 at 17:07




Sorry, I missed a semicolon that was necessary after wrapping everything with With. Please try again.
– Henrik Schumacher
Dec 2 at 17:07










up vote
4
down vote













I would keep them together while sorting.



SortBy[Transpose[{ids, values}], First]





{{5, 0.0351563}, {11, 0.131836}, {17, 0.086792}, {24, 0.0637894}, {25,

   0.0351563}, {31, 0.065752}, {32, 0.0146484}, {33, 0.0875244}, {37, 

  0.191388}, {38, 0.0503769}, {39, 0.173784}, {40, 0.063796}}






share|improve this answer





















  • See also my remark under Okke's post.
    – Henrik Schumacher
    Dec 2 at 18:17















up vote
4
down vote













I would keep them together while sorting.



SortBy[Transpose[{ids, values}], First]





{{5, 0.0351563}, {11, 0.131836}, {17, 0.086792}, {24, 0.0637894}, {25,

   0.0351563}, {31, 0.065752}, {32, 0.0146484}, {33, 0.0875244}, {37, 

  0.191388}, {38, 0.0503769}, {39, 0.173784}, {40, 0.063796}}






share|improve this answer





















  • See also my remark under Okke's post.
    – Henrik Schumacher
    Dec 2 at 18:17













up vote
4
down vote










up vote
4
down vote









I would keep them together while sorting.



SortBy[Transpose[{ids, values}], First]





{{5, 0.0351563}, {11, 0.131836}, {17, 0.086792}, {24, 0.0637894}, {25,

   0.0351563}, {31, 0.065752}, {32, 0.0146484}, {33, 0.0875244}, {37, 

  0.191388}, {38, 0.0503769}, {39, 0.173784}, {40, 0.063796}}






share|improve this answer












I would keep them together while sorting.



SortBy[Transpose[{ids, values}], First]





{{5, 0.0351563}, {11, 0.131836}, {17, 0.086792}, {24, 0.0637894}, {25,

   0.0351563}, {31, 0.065752}, {32, 0.0146484}, {33, 0.0875244}, {37, 

  0.191388}, {38, 0.0503769}, {39, 0.173784}, {40, 0.063796}}







share|improve this answer












share|improve this answer



share|improve this answer










answered Dec 2 at 16:45









Johu

3,6531037




3,6531037












  • See also my remark under Okke's post.
    – Henrik Schumacher
    Dec 2 at 18:17


















  • See also my remark under Okke's post.
    – Henrik Schumacher
    Dec 2 at 18:17
















See also my remark under Okke's post.
– Henrik Schumacher
Dec 2 at 18:17




See also my remark under Okke's post.
– Henrik Schumacher
Dec 2 at 18:17










up vote
4
down vote













AssociationThread[ids, values] // KeySort


Edit
To extract keys and values



sorted = AssociationThread[ids, values] // KeySort

sortedIds = Keys[sorted]

sortedValues = Values[sorted]





share|improve this answer























  • This looks simple, but how do I work with these afterwards?
    – user120911
    Dec 2 at 17:00










  • @user120911 Added sorted key / value extraction.
    – Rohit Namjoshi
    Dec 2 at 17:24















up vote
4
down vote













AssociationThread[ids, values] // KeySort


Edit
To extract keys and values



sorted = AssociationThread[ids, values] // KeySort

sortedIds = Keys[sorted]

sortedValues = Values[sorted]





share|improve this answer























  • This looks simple, but how do I work with these afterwards?
    – user120911
    Dec 2 at 17:00










  • @user120911 Added sorted key / value extraction.
    – Rohit Namjoshi
    Dec 2 at 17:24













up vote
4
down vote










up vote
4
down vote









AssociationThread[ids, values] // KeySort


Edit
To extract keys and values



sorted = AssociationThread[ids, values] // KeySort

sortedIds = Keys[sorted]

sortedValues = Values[sorted]





share|improve this answer














AssociationThread[ids, values] // KeySort


Edit
To extract keys and values



sorted = AssociationThread[ids, values] // KeySort

sortedIds = Keys[sorted]

sortedValues = Values[sorted]






share|improve this answer














share|improve this answer



share|improve this answer








edited Dec 2 at 17:24

























answered Dec 2 at 16:46









Rohit Namjoshi

7031110




7031110












  • This looks simple, but how do I work with these afterwards?
    – user120911
    Dec 2 at 17:00










  • @user120911 Added sorted key / value extraction.
    – Rohit Namjoshi
    Dec 2 at 17:24


















  • This looks simple, but how do I work with these afterwards?
    – user120911
    Dec 2 at 17:00










  • @user120911 Added sorted key / value extraction.
    – Rohit Namjoshi
    Dec 2 at 17:24
















This looks simple, but how do I work with these afterwards?
– user120911
Dec 2 at 17:00




This looks simple, but how do I work with these afterwards?
– user120911
Dec 2 at 17:00












@user120911 Added sorted key / value extraction.
– Rohit Namjoshi
Dec 2 at 17:24




@user120911 Added sorted key / value extraction.
– Rohit Namjoshi
Dec 2 at 17:24










up vote
2
down vote













Since Sort sort it by the first entry by default 



Sort@Transpose@{ids, values}



{{5, 0.0351563}, {11, 0.131836}, {17, 0.086792}, {24, 0.0637894}, {25,
0.0351563}, {31, 0.065752}, {32, 0.0146484}, {33, 0.0875244}, {37,
0.191388}, {38, 0.0503769}, {39, 0.173784}, {40, 0.063796}}







share|improve this answer

















  • 1




    A problem that arises here with Transpose is is that it unpacks arrays: ids is a list of integers and values is a list of machine reals. So both can be packed separately; but not Transpose@{ids, values} as it has mixed data types. This may become important when processing large datasets.
    – Henrik Schumacher
    Dec 2 at 18:16















up vote
2
down vote













Since Sort sort it by the first entry by default 



Sort@Transpose@{ids, values}



{{5, 0.0351563}, {11, 0.131836}, {17, 0.086792}, {24, 0.0637894}, {25,
0.0351563}, {31, 0.065752}, {32, 0.0146484}, {33, 0.0875244}, {37,
0.191388}, {38, 0.0503769}, {39, 0.173784}, {40, 0.063796}}







share|improve this answer

















  • 1




    A problem that arises here with Transpose is is that it unpacks arrays: ids is a list of integers and values is a list of machine reals. So both can be packed separately; but not Transpose@{ids, values} as it has mixed data types. This may become important when processing large datasets.
    – Henrik Schumacher
    Dec 2 at 18:16













up vote
2
down vote










up vote
2
down vote









Since Sort sort it by the first entry by default 



Sort@Transpose@{ids, values}



{{5, 0.0351563}, {11, 0.131836}, {17, 0.086792}, {24, 0.0637894}, {25,
0.0351563}, {31, 0.065752}, {32, 0.0146484}, {33, 0.0875244}, {37,
0.191388}, {38, 0.0503769}, {39, 0.173784}, {40, 0.063796}}







share|improve this answer












Since Sort sort it by the first entry by default 



Sort@Transpose@{ids, values}



{{5, 0.0351563}, {11, 0.131836}, {17, 0.086792}, {24, 0.0637894}, {25,
0.0351563}, {31, 0.065752}, {32, 0.0146484}, {33, 0.0875244}, {37,
0.191388}, {38, 0.0503769}, {39, 0.173784}, {40, 0.063796}}








share|improve this answer












share|improve this answer



share|improve this answer










answered Dec 2 at 18:07









Okkes Dulgerci

3,7851716




3,7851716








  • 1




    A problem that arises here with Transpose is is that it unpacks arrays: ids is a list of integers and values is a list of machine reals. So both can be packed separately; but not Transpose@{ids, values} as it has mixed data types. This may become important when processing large datasets.
    – Henrik Schumacher
    Dec 2 at 18:16














  • 1




    A problem that arises here with Transpose is is that it unpacks arrays: ids is a list of integers and values is a list of machine reals. So both can be packed separately; but not Transpose@{ids, values} as it has mixed data types. This may become important when processing large datasets.
    – Henrik Schumacher
    Dec 2 at 18:16








1




1




A problem that arises here with Transpose is is that it unpacks arrays: ids is a list of integers and values is a list of machine reals. So both can be packed separately; but not Transpose@{ids, values} as it has mixed data types. This may become important when processing large datasets.
– Henrik Schumacher
Dec 2 at 18:16




A problem that arises here with Transpose is is that it unpacks arrays: ids is a list of integers and values is a list of machine reals. So both can be packed separately; but not Transpose@{ids, values} as it has mixed data types. This may become important when processing large datasets.
– Henrik Schumacher
Dec 2 at 18:16


















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Origin of the phrase “under your belt”?

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.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ margin-bottom:0; } 17 1 Today, I found myself discussing what students should have "under their belts" during a lecture, and I wondered to myself if there was some inappropriate undertone here that I might be unaware of. Question : What is the origin of the phrase "under your belt"? A google search revealed some webpages (e.g. [1]) that assert its origin is related to consumption of food -- once a meal has been eaten, it's under your belt (which is a relief). However, with such websites, I have no way to determine fact from "random guy on the internet making stuff up". etymology idioms ...
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