Usercontrol viewmodel wpf mvvm
0
I have a user control called AddUserControl which is used in MainWindow as a edit screen and there is add button in ribbon control, so the same AddUserControl should open. so i have created a AddWindow and plugged that usercontrol in AddWindow.
so should i make a viewmodel for AddUserControl cause same code is being repeated in both MainScreen and AddWindow? But usercontrol should not have its viewmodel. It will be really helpful if anyone will explain it?
c# wpf mvvm
asked Nov 20 '18 at 11:36
Ravi Solanki
5916
add a comment |
0
I have a user control called AddUserControl which is used in MainWindow as a edit screen and there is add button in ribbon control, so the same AddUserControl should open. so i have created a AddWindow and plugged that usercontrol in AddWindow.
so should i make a viewmodel for AddUserControl cause same code is being repeated in both MainScreen and AddWindow? But usercontrol should not have its viewmodel. It will be really helpful if anyone will explain it?
c# wpf mvvm
asked Nov 20 '18 at 11:36
Ravi Solanki
5916
1
If the UserControl is supposed to be independent of a specific view model, it has to expose dependency properties that can be bound to properties of any view model object in the current DataContext, like<local:YourUserControl UcProperty="{Binding VmProperty}"/>. If you put such a UserControl in a DataTemplate for a certain view model type (by setting the DataTemplate'sDataTypeproperty), it will be created automatically when you assign an instance of the view model type to theContentproperty of a ContentControl.
– Clemens
Nov 20 '18 at 12:00
The view model of theMainWindowmay have aUserproperty which returns anAddUserViewModelthat theAddUserControlbinds to. And you can set theDataContextof theAddWindowto another instance ofAddUserViewModel. Then theUserControlwill be reusable in both windows. The other option is to add dependency properties to theUserControland bind these individually.
– mm8
Nov 20 '18 at 12:16
In my AddUserControl, i have some methods like upload files and perform some action like edit and save. There is like more than 10+ properties, so making dependency properties is a difficult task i guess. still can you please explain further or maybe different approach?
– Ravi Solanki
Nov 20 '18 at 12:50
1
Can you post a visual like a UML or the code (View, any code behind, and ViewModel)?
– Michael Puckett II
Nov 20 '18 at 13:14
add a comment |
0
0
0
I have a user control called AddUserControl which is used in MainWindow as a edit screen and there is add button in ribbon control, so the same AddUserControl should open. so i have created a AddWindow and plugged that usercontrol in AddWindow.
so should i make a viewmodel for AddUserControl cause same code is being repeated in both MainScreen and AddWindow? But usercontrol should not have its viewmodel. It will be really helpful if anyone will explain it?
c# wpf mvvm
asked Nov 20 '18 at 11:36
Ravi Solanki
5916
I have a user control called AddUserControl which is used in MainWindow as a edit screen and there is add button in ribbon control, so the same AddUserControl should open. so i have created a AddWindow and plugged that usercontrol in AddWindow.
so should i make a viewmodel for AddUserControl cause same code is being repeated in both MainScreen and AddWindow? But usercontrol should not have its viewmodel. It will be really helpful if anyone will explain it?
c# wpf mvvm
c# wpf mvvm
asked Nov 20 '18 at 11:36
Ravi Solanki
5916
asked Nov 20 '18 at 11:36
Ravi Solanki
5916
asked Nov 20 '18 at 11:36
Ravi Solanki
5916
asked Nov 20 '18 at 11:36
Ravi Solanki
5916
asked Nov 20 '18 at 11:36
Ravi Solanki
5916
5916
1
If the UserControl is supposed to be independent of a specific view model, it has to expose dependency properties that can be bound to properties of any view model object in the current DataContext, like<local:YourUserControl UcProperty="{Binding VmProperty}"/>. If you put such a UserControl in a DataTemplate for a certain view model type (by setting the DataTemplate'sDataTypeproperty), it will be created automatically when you assign an instance of the view model type to theContentproperty of a ContentControl.
– Clemens
Nov 20 '18 at 12:00
The view model of theMainWindowmay have aUserproperty which returns anAddUserViewModelthat theAddUserControlbinds to. And you can set theDataContextof theAddWindowto another instance ofAddUserViewModel. Then theUserControlwill be reusable in both windows. The other option is to add dependency properties to theUserControland bind these individually.
– mm8
Nov 20 '18 at 12:16
In my AddUserControl, i have some methods like upload files and perform some action like edit and save. There is like more than 10+ properties, so making dependency properties is a difficult task i guess. still can you please explain further or maybe different approach?
– Ravi Solanki
Nov 20 '18 at 12:50
1
Can you post a visual like a UML or the code (View, any code behind, and ViewModel)?
– Michael Puckett II
Nov 20 '18 at 13:14
add a comment |
1
If the UserControl is supposed to be independent of a specific view model, it has to expose dependency properties that can be bound to properties of any view model object in the current DataContext, like<local:YourUserControl UcProperty="{Binding VmProperty}"/>. If you put such a UserControl in a DataTemplate for a certain view model type (by setting the DataTemplate'sDataTypeproperty), it will be created automatically when you assign an instance of the view model type to theContentproperty of a ContentControl.
– Clemens
Nov 20 '18 at 12:00
The view model of theMainWindowmay have aUserproperty which returns anAddUserViewModelthat theAddUserControlbinds to. And you can set theDataContextof theAddWindowto another instance ofAddUserViewModel. Then theUserControlwill be reusable in both windows. The other option is to add dependency properties to theUserControland bind these individually.
– mm8
Nov 20 '18 at 12:16
In my AddUserControl, i have some methods like upload files and perform some action like edit and save. There is like more than 10+ properties, so making dependency properties is a difficult task i guess. still can you please explain further or maybe different approach?
– Ravi Solanki
Nov 20 '18 at 12:50
1
Can you post a visual like a UML or the code (View, any code behind, and ViewModel)?
– Michael Puckett II
Nov 20 '18 at 13:14
1
1
If the UserControl is supposed to be independent of a specific view model, it has to expose dependency properties that can be bound to properties of any view model object in the current DataContext, like
<local:YourUserControl UcProperty="{Binding VmProperty}"/>. If you put such a UserControl in a DataTemplate for a certain view model type (by setting the DataTemplate's DataType property), it will be created automatically when you assign an instance of the view model type to the Content property of a ContentControl.– Clemens
Nov 20 '18 at 12:00
If the UserControl is supposed to be independent of a specific view model, it has to expose dependency properties that can be bound to properties of any view model object in the current DataContext, like
<local:YourUserControl UcProperty="{Binding VmProperty}"/>. If you put such a UserControl in a DataTemplate for a certain view model type (by setting the DataTemplate's DataType property), it will be created automatically when you assign an instance of the view model type to the Content property of a ContentControl.– Clemens
Nov 20 '18 at 12:00
The view model of the
MainWindow may have a User property which returns an AddUserViewModel that the AddUserControl binds to. And you can set the DataContext of the AddWindow to another instance of AddUserViewModel. Then the UserControl will be reusable in both windows. The other option is to add dependency properties to the UserControl and bind these individually.– mm8
Nov 20 '18 at 12:16
The view model of the
MainWindow may have a User property which returns an AddUserViewModel that the AddUserControl binds to. And you can set the DataContext of the AddWindow to another instance of AddUserViewModel. Then the UserControl will be reusable in both windows. The other option is to add dependency properties to the UserControl and bind these individually.– mm8
Nov 20 '18 at 12:16
In my AddUserControl, i have some methods like upload files and perform some action like edit and save. There is like more than 10+ properties, so making dependency properties is a difficult task i guess. still can you please explain further or maybe different approach?
– Ravi Solanki
Nov 20 '18 at 12:50
In my AddUserControl, i have some methods like upload files and perform some action like edit and save. There is like more than 10+ properties, so making dependency properties is a difficult task i guess. still can you please explain further or maybe different approach?
– Ravi Solanki
Nov 20 '18 at 12:50
1
1
Can you post a visual like a UML or the code (View, any code behind, and ViewModel)?
– Michael Puckett II
Nov 20 '18 at 13:14
Can you post a visual like a UML or the code (View, any code behind, and ViewModel)?
– Michael Puckett II
Nov 20 '18 at 13:14
add a comment |
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1
If the UserControl is supposed to be independent of a specific view model, it has to expose dependency properties that can be bound to properties of any view model object in the current DataContext, like
<local:YourUserControl UcProperty="{Binding VmProperty}"/>. If you put such a UserControl in a DataTemplate for a certain view model type (by setting the DataTemplate'sDataTypeproperty), it will be created automatically when you assign an instance of the view model type to theContentproperty of a ContentControl.– Clemens
Nov 20 '18 at 12:00
The view model of the
MainWindowmay have aUserproperty which returns anAddUserViewModelthat theAddUserControlbinds to. And you can set theDataContextof theAddWindowto another instance ofAddUserViewModel. Then theUserControlwill be reusable in both windows. The other option is to add dependency properties to theUserControland bind these individually.– mm8
Nov 20 '18 at 12:16
In my AddUserControl, i have some methods like upload files and perform some action like edit and save. There is like more than 10+ properties, so making dependency properties is a difficult task i guess. still can you please explain further or maybe different approach?
– Ravi Solanki
Nov 20 '18 at 12:50
1
Can you post a visual like a UML or the code (View, any code behind, and ViewModel)?
– Michael Puckett II
Nov 20 '18 at 13:14