Regular expression with full match only
I know that this hackneyed theme and I read related answers...
However, I will ask...
I have input string in next format:
3#0.01, 2#0.5, 1#-10, -2#~
So this is a list of values splitted by comma.
I can catch all values with next expression:
(([-+]?d+)#([-+]?d*.?d+|~))+
It's working fine.
But I want to have no matching if any mistake is presenting in input string, for example:
MISTAKE3#0.01, 2#0.5, 1#-10, -2#~AND_HERE_MISTAKE_TOO
Unfortunately ^ and $ symbols are not helping here.
So my question: how can I stop matching if some part of input string is invalid.
Thanks.
Here is snippet: https://regex101.com/r/Xih0Qk/2
.net regex lookahead lookbehind
edited Nov 21 '18 at 18:52
Poul Bak
5,46831232
asked Nov 21 '18 at 17:12
Sergey AlikinSergey Alikin
305
|
show 7 more comments
I know that this hackneyed theme and I read related answers...
However, I will ask...
I have input string in next format:
3#0.01, 2#0.5, 1#-10, -2#~
So this is a list of values splitted by comma.
I can catch all values with next expression:
(([-+]?d+)#([-+]?d*.?d+|~))+
It's working fine.
But I want to have no matching if any mistake is presenting in input string, for example:
MISTAKE3#0.01, 2#0.5, 1#-10, -2#~AND_HERE_MISTAKE_TOO
Unfortunately ^ and $ symbols are not helping here.
So my question: how can I stop matching if some part of input string is invalid.
Thanks.
Here is snippet: https://regex101.com/r/Xih0Qk/2
.net regex lookahead lookbehind
edited Nov 21 '18 at 18:52
Poul Bak
5,46831232
asked Nov 21 '18 at 17:12
Sergey AlikinSergey Alikin
305
Try(([-+]?bd+)#([-+]?d*.?d+|~B))+
– Wiktor Stribiżew
Nov 21 '18 at 17:13
Wiktor, thanks for your attempt. But, unfortunately, no.
– Sergey Alikin
Nov 21 '18 at 17:49
So, you want to match them all only after validating the whole string? Something like regex101.com/r/Xih0Qk/3?
– Wiktor Stribiżew
Nov 21 '18 at 17:59
Wiktor, that's exactly what I want.
– Sergey Alikin
Nov 21 '18 at 18:13
Wiktor, wielkie dzięki, if I have guessed ;)
– Sergey Alikin
Nov 21 '18 at 18:14
|
show 7 more comments
I know that this hackneyed theme and I read related answers...
However, I will ask...
I have input string in next format:
3#0.01, 2#0.5, 1#-10, -2#~
So this is a list of values splitted by comma.
I can catch all values with next expression:
(([-+]?d+)#([-+]?d*.?d+|~))+
It's working fine.
But I want to have no matching if any mistake is presenting in input string, for example:
MISTAKE3#0.01, 2#0.5, 1#-10, -2#~AND_HERE_MISTAKE_TOO
Unfortunately ^ and $ symbols are not helping here.
So my question: how can I stop matching if some part of input string is invalid.
Thanks.
Here is snippet: https://regex101.com/r/Xih0Qk/2
.net regex lookahead lookbehind
edited Nov 21 '18 at 18:52
Poul Bak
5,46831232
asked Nov 21 '18 at 17:12
Sergey AlikinSergey Alikin
305
I know that this hackneyed theme and I read related answers...
However, I will ask...
I have input string in next format:
3#0.01, 2#0.5, 1#-10, -2#~
So this is a list of values splitted by comma.
I can catch all values with next expression:
(([-+]?d+)#([-+]?d*.?d+|~))+
It's working fine.
But I want to have no matching if any mistake is presenting in input string, for example:
MISTAKE3#0.01, 2#0.5, 1#-10, -2#~AND_HERE_MISTAKE_TOO
Unfortunately ^ and $ symbols are not helping here.
So my question: how can I stop matching if some part of input string is invalid.
Thanks.
Here is snippet: https://regex101.com/r/Xih0Qk/2
.net regex lookahead lookbehind
.net regex lookahead lookbehind
edited Nov 21 '18 at 18:52
Poul Bak
5,46831232
asked Nov 21 '18 at 17:12
Sergey AlikinSergey Alikin
305
edited Nov 21 '18 at 18:52
Poul Bak
5,46831232
asked Nov 21 '18 at 17:12
Sergey AlikinSergey Alikin
305
edited Nov 21 '18 at 18:52
Poul Bak
5,46831232
edited Nov 21 '18 at 18:52
Poul Bak
5,46831232
edited Nov 21 '18 at 18:52
Poul Bak
5,46831232
5,46831232
asked Nov 21 '18 at 17:12
Sergey AlikinSergey Alikin
305
asked Nov 21 '18 at 17:12
Sergey AlikinSergey Alikin
305
asked Nov 21 '18 at 17:12
Sergey AlikinSergey Alikin
305
305
Try(([-+]?bd+)#([-+]?d*.?d+|~B))+
– Wiktor Stribiżew
Nov 21 '18 at 17:13
Wiktor, thanks for your attempt. But, unfortunately, no.
– Sergey Alikin
Nov 21 '18 at 17:49
So, you want to match them all only after validating the whole string? Something like regex101.com/r/Xih0Qk/3?
– Wiktor Stribiżew
Nov 21 '18 at 17:59
Wiktor, that's exactly what I want.
– Sergey Alikin
Nov 21 '18 at 18:13
Wiktor, wielkie dzięki, if I have guessed ;)
– Sergey Alikin
Nov 21 '18 at 18:14
|
show 7 more comments
Try(([-+]?bd+)#([-+]?d*.?d+|~B))+
– Wiktor Stribiżew
Nov 21 '18 at 17:13
Wiktor, thanks for your attempt. But, unfortunately, no.
– Sergey Alikin
Nov 21 '18 at 17:49
So, you want to match them all only after validating the whole string? Something like regex101.com/r/Xih0Qk/3?
– Wiktor Stribiżew
Nov 21 '18 at 17:59
Wiktor, that's exactly what I want.
– Sergey Alikin
Nov 21 '18 at 18:13
Wiktor, wielkie dzięki, if I have guessed ;)
– Sergey Alikin
Nov 21 '18 at 18:14
Try
(([-+]?bd+)#([-+]?d*.?d+|~B))+– Wiktor Stribiżew
Nov 21 '18 at 17:13
Try
(([-+]?bd+)#([-+]?d*.?d+|~B))+– Wiktor Stribiżew
Nov 21 '18 at 17:13
Wiktor, thanks for your attempt. But, unfortunately, no.
– Sergey Alikin
Nov 21 '18 at 17:49
Wiktor, thanks for your attempt. But, unfortunately, no.
– Sergey Alikin
Nov 21 '18 at 17:49
So, you want to match them all only after validating the whole string? Something like regex101.com/r/Xih0Qk/3?
– Wiktor Stribiżew
Nov 21 '18 at 17:59
So, you want to match them all only after validating the whole string? Something like regex101.com/r/Xih0Qk/3?
– Wiktor Stribiżew
Nov 21 '18 at 17:59
Wiktor, that's exactly what I want.
– Sergey Alikin
Nov 21 '18 at 18:13
Wiktor, that's exactly what I want.
– Sergey Alikin
Nov 21 '18 at 18:13
Wiktor, wielkie dzięki, if I have guessed ;)
– Sergey Alikin
Nov 21 '18 at 18:14
Wiktor, wielkie dzięki, if I have guessed ;)
– Sergey Alikin
Nov 21 '18 at 18:14
|
show 7 more comments
1 Answer
1
active
oldest
votes
In .NET, you may use a regex with inifinite width lookbehinds (it is also supported in the latest ECMAScript 2018 powered JavaScript environments, if you need to port the same solution there). The regex will look like
(?<=^(?:[-+]?d+#(?:[-+]?d*.?d+|~),s)*)[-+]?d+#(?:[-+]?d*.?d+|~)(?=(?:,s[-+]?d+#(?:[-+]?d*.?d+|~))*$)
See the online regex demo
In code, it is easier to build the pattern from a variable:
var block = @"[-+]?d+#(?:[-+]?d*.?d+|~)"; // Block/unit pattern
var pattern = $@"(?<=^(?:{block},s)*){block}(?=(?:,s{block})*$)";
var results1 = Regex.Matches("3#0.01, 2#0.5, 1#-10, -2#~", pattern)
.Cast<Match>().Select(x => x.Value);
if (results1.Count() > 0)
Console.WriteLine(string.Join(", ", results1));
var results2 = Regex.Matches("MISTAKE3#0.01, 2#0.5, 1#-10, -2#~AND_HERE_MISTAKE_TOO", pattern)
.Cast<Match>().Select(x => x.Value);
if (results2.Count() > 0)
Console.WriteLine(string.Join(", ", results2));
See the C# demo online. Output (only the right string matched):
3#0.01, 2#0.5, 1#-10, -2#~
Pattern explanation
(?<=^(?:{block},s)*)- a positive lookbehind that only matches a location immediately preceded with 0+ occurrences of a{block}pattern at the start of the string followed with a,and 1 whitespace
{block}- your block/unit pattern to match
(?=(?:,s{block})*$)- a positive lookahead that matches a location immediately followed with 0+ occurrences of a,, a whitespace and a{block}pattern up to the end of the string.
answered Nov 21 '18 at 18:48
Wiktor StribiżewWiktor Stribiżew
315k16133213
Wiktor, thanks! You are the best. Can I ask about small detail: how can I match only WRONG patterns. MISTAKE3#0.01, 2#0.5, 1#-10, -2#~AND_HERE_MISTAKE_TOO. First and last in this line, for example.
– Sergey Alikin
Nov 21 '18 at 19:00
@SergeyAlikin Probably, if you remove all the valid ones,Regex.Replace(s, @"(?:^|,s)[-+]?d+#(?:[-+]?d*.?d+|~)(?=,s|$)", "").Split(new {", "}, StringSplitOptions.None)
– Wiktor Stribiżew
Nov 21 '18 at 19:05
Wiktor, thank you very very much. I will not disturb you more.
– Sergey Alikin
Nov 21 '18 at 19:17
add a comment |
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In .NET, you may use a regex with inifinite width lookbehinds (it is also supported in the latest ECMAScript 2018 powered JavaScript environments, if you need to port the same solution there). The regex will look like
(?<=^(?:[-+]?d+#(?:[-+]?d*.?d+|~),s)*)[-+]?d+#(?:[-+]?d*.?d+|~)(?=(?:,s[-+]?d+#(?:[-+]?d*.?d+|~))*$)
See the online regex demo
In code, it is easier to build the pattern from a variable:
var block = @"[-+]?d+#(?:[-+]?d*.?d+|~)"; // Block/unit pattern
var pattern = $@"(?<=^(?:{block},s)*){block}(?=(?:,s{block})*$)";
var results1 = Regex.Matches("3#0.01, 2#0.5, 1#-10, -2#~", pattern)
.Cast<Match>().Select(x => x.Value);
if (results1.Count() > 0)
Console.WriteLine(string.Join(", ", results1));
var results2 = Regex.Matches("MISTAKE3#0.01, 2#0.5, 1#-10, -2#~AND_HERE_MISTAKE_TOO", pattern)
.Cast<Match>().Select(x => x.Value);
if (results2.Count() > 0)
Console.WriteLine(string.Join(", ", results2));
See the C# demo online. Output (only the right string matched):
3#0.01, 2#0.5, 1#-10, -2#~
Pattern explanation
(?<=^(?:{block},s)*)- a positive lookbehind that only matches a location immediately preceded with 0+ occurrences of a{block}pattern at the start of the string followed with a,and 1 whitespace
{block}- your block/unit pattern to match
(?=(?:,s{block})*$)- a positive lookahead that matches a location immediately followed with 0+ occurrences of a,, a whitespace and a{block}pattern up to the end of the string.
answered Nov 21 '18 at 18:48
Wiktor StribiżewWiktor Stribiżew
315k16133213
Wiktor, thanks! You are the best. Can I ask about small detail: how can I match only WRONG patterns. MISTAKE3#0.01, 2#0.5, 1#-10, -2#~AND_HERE_MISTAKE_TOO. First and last in this line, for example.
– Sergey Alikin
Nov 21 '18 at 19:00
@SergeyAlikin Probably, if you remove all the valid ones,Regex.Replace(s, @"(?:^|,s)[-+]?d+#(?:[-+]?d*.?d+|~)(?=,s|$)", "").Split(new {", "}, StringSplitOptions.None)
– Wiktor Stribiżew
Nov 21 '18 at 19:05
Wiktor, thank you very very much. I will not disturb you more.
– Sergey Alikin
Nov 21 '18 at 19:17
add a comment |
In .NET, you may use a regex with inifinite width lookbehinds (it is also supported in the latest ECMAScript 2018 powered JavaScript environments, if you need to port the same solution there). The regex will look like
(?<=^(?:[-+]?d+#(?:[-+]?d*.?d+|~),s)*)[-+]?d+#(?:[-+]?d*.?d+|~)(?=(?:,s[-+]?d+#(?:[-+]?d*.?d+|~))*$)
See the online regex demo
In code, it is easier to build the pattern from a variable:
var block = @"[-+]?d+#(?:[-+]?d*.?d+|~)"; // Block/unit pattern
var pattern = $@"(?<=^(?:{block},s)*){block}(?=(?:,s{block})*$)";
var results1 = Regex.Matches("3#0.01, 2#0.5, 1#-10, -2#~", pattern)
.Cast<Match>().Select(x => x.Value);
if (results1.Count() > 0)
Console.WriteLine(string.Join(", ", results1));
var results2 = Regex.Matches("MISTAKE3#0.01, 2#0.5, 1#-10, -2#~AND_HERE_MISTAKE_TOO", pattern)
.Cast<Match>().Select(x => x.Value);
if (results2.Count() > 0)
Console.WriteLine(string.Join(", ", results2));
See the C# demo online. Output (only the right string matched):
3#0.01, 2#0.5, 1#-10, -2#~
Pattern explanation
(?<=^(?:{block},s)*)- a positive lookbehind that only matches a location immediately preceded with 0+ occurrences of a{block}pattern at the start of the string followed with a,and 1 whitespace
{block}- your block/unit pattern to match
(?=(?:,s{block})*$)- a positive lookahead that matches a location immediately followed with 0+ occurrences of a,, a whitespace and a{block}pattern up to the end of the string.
answered Nov 21 '18 at 18:48
Wiktor StribiżewWiktor Stribiżew
315k16133213
Wiktor, thanks! You are the best. Can I ask about small detail: how can I match only WRONG patterns. MISTAKE3#0.01, 2#0.5, 1#-10, -2#~AND_HERE_MISTAKE_TOO. First and last in this line, for example.
– Sergey Alikin
Nov 21 '18 at 19:00
@SergeyAlikin Probably, if you remove all the valid ones,Regex.Replace(s, @"(?:^|,s)[-+]?d+#(?:[-+]?d*.?d+|~)(?=,s|$)", "").Split(new {", "}, StringSplitOptions.None)
– Wiktor Stribiżew
Nov 21 '18 at 19:05
Wiktor, thank you very very much. I will not disturb you more.
– Sergey Alikin
Nov 21 '18 at 19:17
add a comment |
In .NET, you may use a regex with inifinite width lookbehinds (it is also supported in the latest ECMAScript 2018 powered JavaScript environments, if you need to port the same solution there). The regex will look like
(?<=^(?:[-+]?d+#(?:[-+]?d*.?d+|~),s)*)[-+]?d+#(?:[-+]?d*.?d+|~)(?=(?:,s[-+]?d+#(?:[-+]?d*.?d+|~))*$)
See the online regex demo
In code, it is easier to build the pattern from a variable:
var block = @"[-+]?d+#(?:[-+]?d*.?d+|~)"; // Block/unit pattern
var pattern = $@"(?<=^(?:{block},s)*){block}(?=(?:,s{block})*$)";
var results1 = Regex.Matches("3#0.01, 2#0.5, 1#-10, -2#~", pattern)
.Cast<Match>().Select(x => x.Value);
if (results1.Count() > 0)
Console.WriteLine(string.Join(", ", results1));
var results2 = Regex.Matches("MISTAKE3#0.01, 2#0.5, 1#-10, -2#~AND_HERE_MISTAKE_TOO", pattern)
.Cast<Match>().Select(x => x.Value);
if (results2.Count() > 0)
Console.WriteLine(string.Join(", ", results2));
See the C# demo online. Output (only the right string matched):
3#0.01, 2#0.5, 1#-10, -2#~
Pattern explanation
(?<=^(?:{block},s)*)- a positive lookbehind that only matches a location immediately preceded with 0+ occurrences of a{block}pattern at the start of the string followed with a,and 1 whitespace
{block}- your block/unit pattern to match
(?=(?:,s{block})*$)- a positive lookahead that matches a location immediately followed with 0+ occurrences of a,, a whitespace and a{block}pattern up to the end of the string.
answered Nov 21 '18 at 18:48
Wiktor StribiżewWiktor Stribiżew
315k16133213
In .NET, you may use a regex with inifinite width lookbehinds (it is also supported in the latest ECMAScript 2018 powered JavaScript environments, if you need to port the same solution there). The regex will look like
(?<=^(?:[-+]?d+#(?:[-+]?d*.?d+|~),s)*)[-+]?d+#(?:[-+]?d*.?d+|~)(?=(?:,s[-+]?d+#(?:[-+]?d*.?d+|~))*$)
See the online regex demo
In code, it is easier to build the pattern from a variable:
var block = @"[-+]?d+#(?:[-+]?d*.?d+|~)"; // Block/unit pattern
var pattern = $@"(?<=^(?:{block},s)*){block}(?=(?:,s{block})*$)";
var results1 = Regex.Matches("3#0.01, 2#0.5, 1#-10, -2#~", pattern)
.Cast<Match>().Select(x => x.Value);
if (results1.Count() > 0)
Console.WriteLine(string.Join(", ", results1));
var results2 = Regex.Matches("MISTAKE3#0.01, 2#0.5, 1#-10, -2#~AND_HERE_MISTAKE_TOO", pattern)
.Cast<Match>().Select(x => x.Value);
if (results2.Count() > 0)
Console.WriteLine(string.Join(", ", results2));
See the C# demo online. Output (only the right string matched):
3#0.01, 2#0.5, 1#-10, -2#~
Pattern explanation
(?<=^(?:{block},s)*)- a positive lookbehind that only matches a location immediately preceded with 0+ occurrences of a{block}pattern at the start of the string followed with a,and 1 whitespace
{block}- your block/unit pattern to match
(?=(?:,s{block})*$)- a positive lookahead that matches a location immediately followed with 0+ occurrences of a,, a whitespace and a{block}pattern up to the end of the string.
answered Nov 21 '18 at 18:48
Wiktor StribiżewWiktor Stribiżew
315k16133213
answered Nov 21 '18 at 18:48
Wiktor StribiżewWiktor Stribiżew
315k16133213
answered Nov 21 '18 at 18:48
Wiktor StribiżewWiktor Stribiżew
315k16133213
answered Nov 21 '18 at 18:48
Wiktor StribiżewWiktor Stribiżew
315k16133213
315k16133213
Wiktor, thanks! You are the best. Can I ask about small detail: how can I match only WRONG patterns. MISTAKE3#0.01, 2#0.5, 1#-10, -2#~AND_HERE_MISTAKE_TOO. First and last in this line, for example.
– Sergey Alikin
Nov 21 '18 at 19:00
@SergeyAlikin Probably, if you remove all the valid ones,Regex.Replace(s, @"(?:^|,s)[-+]?d+#(?:[-+]?d*.?d+|~)(?=,s|$)", "").Split(new {", "}, StringSplitOptions.None)
– Wiktor Stribiżew
Nov 21 '18 at 19:05
Wiktor, thank you very very much. I will not disturb you more.
– Sergey Alikin
Nov 21 '18 at 19:17
add a comment |
Wiktor, thanks! You are the best. Can I ask about small detail: how can I match only WRONG patterns. MISTAKE3#0.01, 2#0.5, 1#-10, -2#~AND_HERE_MISTAKE_TOO. First and last in this line, for example.
– Sergey Alikin
Nov 21 '18 at 19:00
@SergeyAlikin Probably, if you remove all the valid ones,Regex.Replace(s, @"(?:^|,s)[-+]?d+#(?:[-+]?d*.?d+|~)(?=,s|$)", "").Split(new {", "}, StringSplitOptions.None)
– Wiktor Stribiżew
Nov 21 '18 at 19:05
Wiktor, thank you very very much. I will not disturb you more.
– Sergey Alikin
Nov 21 '18 at 19:17
Wiktor, thanks! You are the best. Can I ask about small detail: how can I match only WRONG patterns. MISTAKE3#0.01, 2#0.5, 1#-10, -2#~AND_HERE_MISTAKE_TOO. First and last in this line, for example.
– Sergey Alikin
Nov 21 '18 at 19:00
Wiktor, thanks! You are the best. Can I ask about small detail: how can I match only WRONG patterns. MISTAKE3#0.01, 2#0.5, 1#-10, -2#~AND_HERE_MISTAKE_TOO. First and last in this line, for example.
– Sergey Alikin
Nov 21 '18 at 19:00
@SergeyAlikin Probably, if you remove all the valid ones,
Regex.Replace(s, @"(?:^|,s)[-+]?d+#(?:[-+]?d*.?d+|~)(?=,s|$)", "").Split(new {", "}, StringSplitOptions.None)– Wiktor Stribiżew
Nov 21 '18 at 19:05
@SergeyAlikin Probably, if you remove all the valid ones,
Regex.Replace(s, @"(?:^|,s)[-+]?d+#(?:[-+]?d*.?d+|~)(?=,s|$)", "").Split(new {", "}, StringSplitOptions.None)– Wiktor Stribiżew
Nov 21 '18 at 19:05
Wiktor, thank you very very much. I will not disturb you more.
– Sergey Alikin
Nov 21 '18 at 19:17
Wiktor, thank you very very much. I will not disturb you more.
– Sergey Alikin
Nov 21 '18 at 19:17
add a comment |
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(([-+]?bd+)#([-+]?d*.?d+|~B))+– Wiktor Stribiżew
Nov 21 '18 at 17:13
Wiktor, thanks for your attempt. But, unfortunately, no.
– Sergey Alikin
Nov 21 '18 at 17:49
So, you want to match them all only after validating the whole string? Something like regex101.com/r/Xih0Qk/3?
– Wiktor Stribiżew
Nov 21 '18 at 17:59
Wiktor, that's exactly what I want.
– Sergey Alikin
Nov 21 '18 at 18:13
Wiktor, wielkie dzięki, if I have guessed ;)
– Sergey Alikin
Nov 21 '18 at 18:14