Argthtjtr

As far as I know, all numbers have a root of 4. What I mean by this is as follows:

Starting with any number, for example 384, I take the number of letters in that number. Then I repeat this process until it infinitely repeats the number 4.

Three Hundred Eighty Four = 22

Twenty Two = 9

Nine = 4

Four = 4

So I challenge you to find any number which does not follow this rule.

There are some trick solutions

For example, in Spanish, 4 and 6 are cuatro and seis respectively, so starting at either one of those will lead to an infinite cycle of 4-6-4-6-4... Thus, I'll begin with the assumption we are just using English.

With that in mind

Negative number and decimals both have a positive, whole number of letters, so after one iteration, every number is a positive, whole integer. Every number below ten has, at most, 5 letters within it. Thus, numbers from 20-29 will contain no more that 6+5=11 letters, below the lower bound for this range. A similar argument can be applied for every other number above 29. Every number from 10-19 has, at most, 9 letters in it. This is also below the lower bound of 10. With this, it is easy to see any number above ten will quickly drop below ten.

So, for the final step

One, two, six and ten lead to three.
Three, seven, eight lead to five.
Zero, four, five and nine lead to four.
This accounts for all of the numbers. We have shown every number reaches below ten, and every number up to ten reaches four within its third step. Thus, every number will eventually reach four.

To answer your question

There is no number that does not follow this rule.

There's no such number. Sooner or later you'll end up with a positive integer equal to its own number of letters, which can only be 4; or a loop where it regularly increases and decreases. Only the non-negative integers 0, 1, 2 and 3 are less than the number of their letters due to the way all integers are written, and even they end up giving 4, so a loop is impossible.

Since the OP asks for any number, we can extend the definition to constant numbers like pi or e (Euler's Constant)

Both these cannot be counted (till infinity??)

So technically they do not end with four??

Technically you could say

'Seven billion billionths' (always add those last two words)

The last two words make certain that you won't get to 4.

There's also:

'times one' 'not the number four' 'is a silly solution'

and many more!

   Wikipedia says this is an unsolved problem in mathematics, so yeah.

   I realized 'eight billion billionths' might be the second number alphabetically...