Django change Models relations depending on condition (if is staff or not)












0















I have 2 Moles, User and Account. The User can be staff or normal User.
In general a User can have just one Account.



This is what I have now:



class User(AbstractBaseUser):
account = models.OneToOneField(Account, null=True, on_delete=models.CASCADE)


but in special cases an User can have multiple or no Account, only if the User is_staff.



The logic is to have now a ForeignKey:



class User(AbstractBaseUser):
account = models.ForeignKey(Account, on_delete=models.CASCADE)


But in this case, how do I stop in Django Admin or else, for a User to have multiple Foreign keys if is not staff, and force it for normal users to have a simulated OneToOne Relation.










share|improve this question


















  • 2





    Why don't you handle this validation in User.save()? There you know if the the user is_staff=True and you can raise ValidationError if it doesn't match your rules.

    – Alex
    Nov 22 '18 at 20:33
















0















I have 2 Moles, User and Account. The User can be staff or normal User.
In general a User can have just one Account.



This is what I have now:



class User(AbstractBaseUser):
account = models.OneToOneField(Account, null=True, on_delete=models.CASCADE)


but in special cases an User can have multiple or no Account, only if the User is_staff.



The logic is to have now a ForeignKey:



class User(AbstractBaseUser):
account = models.ForeignKey(Account, on_delete=models.CASCADE)


But in this case, how do I stop in Django Admin or else, for a User to have multiple Foreign keys if is not staff, and force it for normal users to have a simulated OneToOne Relation.










share|improve this question


















  • 2





    Why don't you handle this validation in User.save()? There you know if the the user is_staff=True and you can raise ValidationError if it doesn't match your rules.

    – Alex
    Nov 22 '18 at 20:33














0












0








0








I have 2 Moles, User and Account. The User can be staff or normal User.
In general a User can have just one Account.



This is what I have now:



class User(AbstractBaseUser):
account = models.OneToOneField(Account, null=True, on_delete=models.CASCADE)


but in special cases an User can have multiple or no Account, only if the User is_staff.



The logic is to have now a ForeignKey:



class User(AbstractBaseUser):
account = models.ForeignKey(Account, on_delete=models.CASCADE)


But in this case, how do I stop in Django Admin or else, for a User to have multiple Foreign keys if is not staff, and force it for normal users to have a simulated OneToOne Relation.










share|improve this question














I have 2 Moles, User and Account. The User can be staff or normal User.
In general a User can have just one Account.



This is what I have now:



class User(AbstractBaseUser):
account = models.OneToOneField(Account, null=True, on_delete=models.CASCADE)


but in special cases an User can have multiple or no Account, only if the User is_staff.



The logic is to have now a ForeignKey:



class User(AbstractBaseUser):
account = models.ForeignKey(Account, on_delete=models.CASCADE)


But in this case, how do I stop in Django Admin or else, for a User to have multiple Foreign keys if is not staff, and force it for normal users to have a simulated OneToOne Relation.







django django-models






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asked Nov 22 '18 at 20:21









user3541631user3541631

1,17621634




1,17621634








  • 2





    Why don't you handle this validation in User.save()? There you know if the the user is_staff=True and you can raise ValidationError if it doesn't match your rules.

    – Alex
    Nov 22 '18 at 20:33














  • 2





    Why don't you handle this validation in User.save()? There you know if the the user is_staff=True and you can raise ValidationError if it doesn't match your rules.

    – Alex
    Nov 22 '18 at 20:33








2




2





Why don't you handle this validation in User.save()? There you know if the the user is_staff=True and you can raise ValidationError if it doesn't match your rules.

– Alex
Nov 22 '18 at 20:33





Why don't you handle this validation in User.save()? There you know if the the user is_staff=True and you can raise ValidationError if it doesn't match your rules.

– Alex
Nov 22 '18 at 20:33












1 Answer
1






active

oldest

votes


















0














If you want to do a Many-to-one relation where one staff User can have multiple accounts, is your Account model that should contain your foreign key. Also, you can override your Account's save model to reinforce your condition using a code similar to this:



class Account(...):
user = models.ForeignKey(User, on_delete=models.CASCADE)

def save(self, *args, **kwargs):
user = self.user
if user and user.set_account.count() > 0 and not user.is_staff:
raise ValidationError(_('You cannot add another account to user {}'.format(user.username)))
super(Account, self).save(*args, **kwargs)





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    1 Answer
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    1 Answer
    1






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    active

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    0














    If you want to do a Many-to-one relation where one staff User can have multiple accounts, is your Account model that should contain your foreign key. Also, you can override your Account's save model to reinforce your condition using a code similar to this:



    class Account(...):
    user = models.ForeignKey(User, on_delete=models.CASCADE)

    def save(self, *args, **kwargs):
    user = self.user
    if user and user.set_account.count() > 0 and not user.is_staff:
    raise ValidationError(_('You cannot add another account to user {}'.format(user.username)))
    super(Account, self).save(*args, **kwargs)





    share|improve this answer




























      0














      If you want to do a Many-to-one relation where one staff User can have multiple accounts, is your Account model that should contain your foreign key. Also, you can override your Account's save model to reinforce your condition using a code similar to this:



      class Account(...):
      user = models.ForeignKey(User, on_delete=models.CASCADE)

      def save(self, *args, **kwargs):
      user = self.user
      if user and user.set_account.count() > 0 and not user.is_staff:
      raise ValidationError(_('You cannot add another account to user {}'.format(user.username)))
      super(Account, self).save(*args, **kwargs)





      share|improve this answer


























        0












        0








        0







        If you want to do a Many-to-one relation where one staff User can have multiple accounts, is your Account model that should contain your foreign key. Also, you can override your Account's save model to reinforce your condition using a code similar to this:



        class Account(...):
        user = models.ForeignKey(User, on_delete=models.CASCADE)

        def save(self, *args, **kwargs):
        user = self.user
        if user and user.set_account.count() > 0 and not user.is_staff:
        raise ValidationError(_('You cannot add another account to user {}'.format(user.username)))
        super(Account, self).save(*args, **kwargs)





        share|improve this answer













        If you want to do a Many-to-one relation where one staff User can have multiple accounts, is your Account model that should contain your foreign key. Also, you can override your Account's save model to reinforce your condition using a code similar to this:



        class Account(...):
        user = models.ForeignKey(User, on_delete=models.CASCADE)

        def save(self, *args, **kwargs):
        user = self.user
        if user and user.set_account.count() > 0 and not user.is_staff:
        raise ValidationError(_('You cannot add another account to user {}'.format(user.username)))
        super(Account, self).save(*args, **kwargs)






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 22 '18 at 21:33









        Aurora WangAurora Wang

        733316




        733316
































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