Search similar value in another table using IN (SQLite)
I'm using SQLite to deal with tons of data (like 100gb of data).
I need to seach the value of one column in other table in the fastest way possible.
For example, I need to find the following values of Table 1
[COD]
C62
K801
And then find them in Table 2:
[COD_2]
C60-C63
K80-K81
My desired result is something like:
[COD_1] [COD_2]
C62 C60-C63
K801 K80-K81
Since I have a lot of data, it is inefficient to do something like:
SELECT *
FROM TABLE_1, TABLE_2
WHERE COD_1 LIKE '%' || COD_2 || '%';
Instead, I was trying to do this:
SELECT *
FROM TABLE_1
WHERE COD_1 IN (SELECT COD_2 FROM TABLE_2);
Of course that this doesn't result because the codes are not exactly the sames. Is there a way to search for similar values of one column (something like the LIKE operator) in other table by using IN? Or other way that doesn't cross TABLE_1 and TABLE_2?
Thank you!!!
useful to me.
sqlite
asked Nov 22 '18 at 20:19
Valeria Lobos OssandónValeria Lobos Ossandón
7629
add a comment |
I'm using SQLite to deal with tons of data (like 100gb of data).
I need to seach the value of one column in other table in the fastest way possible.
For example, I need to find the following values of Table 1
[COD]
C62
K801
And then find them in Table 2:
[COD_2]
C60-C63
K80-K81
My desired result is something like:
[COD_1] [COD_2]
C62 C60-C63
K801 K80-K81
Since I have a lot of data, it is inefficient to do something like:
SELECT *
FROM TABLE_1, TABLE_2
WHERE COD_1 LIKE '%' || COD_2 || '%';
Instead, I was trying to do this:
SELECT *
FROM TABLE_1
WHERE COD_1 IN (SELECT COD_2 FROM TABLE_2);
Of course that this doesn't result because the codes are not exactly the sames. Is there a way to search for similar values of one column (something like the LIKE operator) in other table by using IN? Or other way that doesn't cross TABLE_1 and TABLE_2?
Thank you!!!
useful to me.
sqlite
asked Nov 22 '18 at 20:19
Valeria Lobos OssandónValeria Lobos Ossandón
7629
Are you trying to store a range in a single value (Bad idea, btw)? If so, how isK801inK80-K81?
– Shawn
Nov 22 '18 at 21:32
add a comment |
I'm using SQLite to deal with tons of data (like 100gb of data).
I need to seach the value of one column in other table in the fastest way possible.
For example, I need to find the following values of Table 1
[COD]
C62
K801
And then find them in Table 2:
[COD_2]
C60-C63
K80-K81
My desired result is something like:
[COD_1] [COD_2]
C62 C60-C63
K801 K80-K81
Since I have a lot of data, it is inefficient to do something like:
SELECT *
FROM TABLE_1, TABLE_2
WHERE COD_1 LIKE '%' || COD_2 || '%';
Instead, I was trying to do this:
SELECT *
FROM TABLE_1
WHERE COD_1 IN (SELECT COD_2 FROM TABLE_2);
Of course that this doesn't result because the codes are not exactly the sames. Is there a way to search for similar values of one column (something like the LIKE operator) in other table by using IN? Or other way that doesn't cross TABLE_1 and TABLE_2?
Thank you!!!
useful to me.
sqlite
asked Nov 22 '18 at 20:19
Valeria Lobos OssandónValeria Lobos Ossandón
7629
I'm using SQLite to deal with tons of data (like 100gb of data).
I need to seach the value of one column in other table in the fastest way possible.
For example, I need to find the following values of Table 1
[COD]
C62
K801
And then find them in Table 2:
[COD_2]
C60-C63
K80-K81
My desired result is something like:
[COD_1] [COD_2]
C62 C60-C63
K801 K80-K81
Since I have a lot of data, it is inefficient to do something like:
SELECT *
FROM TABLE_1, TABLE_2
WHERE COD_1 LIKE '%' || COD_2 || '%';
Instead, I was trying to do this:
SELECT *
FROM TABLE_1
WHERE COD_1 IN (SELECT COD_2 FROM TABLE_2);
Of course that this doesn't result because the codes are not exactly the sames. Is there a way to search for similar values of one column (something like the LIKE operator) in other table by using IN? Or other way that doesn't cross TABLE_1 and TABLE_2?
Thank you!!!
useful to me.
sqlite
sqlite
asked Nov 22 '18 at 20:19
Valeria Lobos OssandónValeria Lobos Ossandón
7629
asked Nov 22 '18 at 20:19
Valeria Lobos OssandónValeria Lobos Ossandón
7629
asked Nov 22 '18 at 20:19
Valeria Lobos OssandónValeria Lobos Ossandón
7629
asked Nov 22 '18 at 20:19
Valeria Lobos OssandónValeria Lobos Ossandón
7629
asked Nov 22 '18 at 20:19
Valeria Lobos OssandónValeria Lobos Ossandón
7629
7629
Are you trying to store a range in a single value (Bad idea, btw)? If so, how isK801inK80-K81?
– Shawn
Nov 22 '18 at 21:32
add a comment |
Are you trying to store a range in a single value (Bad idea, btw)? If so, how isK801inK80-K81?
– Shawn
Nov 22 '18 at 21:32
Are you trying to store a range in a single value (Bad idea, btw)? If so, how is
K801 in K80-K81?– Shawn
Nov 22 '18 at 21:32
Are you trying to store a range in a single value (Bad idea, btw)? If so, how is
K801 in K80-K81?– Shawn
Nov 22 '18 at 21:32
add a comment |
1 Answer
1
active
oldest
votes
Based on the small data set shown, and my presumed answer to @Shawn's question (K801 is a typo and is meant to be K80 or K81) I assume the following problem description:
Find a row in COD_2 such that the value in COD_1 is between {value1}-{value2} in COD_2; the - being significant and dependable.
I cannot speak to speed, but I would approach it this way:
SELECT value1, value2
from COD_1,COD_2
where value1 between substr(value2,1,instr(value2,'-')-1) and substr(value2,instr(value2,'-')+1)
The thought being: split the value from COD-2 into a "start" and an "end" value.
answered Nov 23 '18 at 22:25
DinoCoderSaurusDinoCoderSaurus
1,014158
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53437582%2fsearch-similar-value-in-another-table-using-in-sqlite%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Based on the small data set shown, and my presumed answer to @Shawn's question (K801 is a typo and is meant to be K80 or K81) I assume the following problem description:
Find a row in COD_2 such that the value in COD_1 is between {value1}-{value2} in COD_2; the - being significant and dependable.
I cannot speak to speed, but I would approach it this way:
SELECT value1, value2
from COD_1,COD_2
where value1 between substr(value2,1,instr(value2,'-')-1) and substr(value2,instr(value2,'-')+1)
The thought being: split the value from COD-2 into a "start" and an "end" value.
answered Nov 23 '18 at 22:25
DinoCoderSaurusDinoCoderSaurus
1,014158
add a comment |
Based on the small data set shown, and my presumed answer to @Shawn's question (K801 is a typo and is meant to be K80 or K81) I assume the following problem description:
Find a row in COD_2 such that the value in COD_1 is between {value1}-{value2} in COD_2; the - being significant and dependable.
I cannot speak to speed, but I would approach it this way:
SELECT value1, value2
from COD_1,COD_2
where value1 between substr(value2,1,instr(value2,'-')-1) and substr(value2,instr(value2,'-')+1)
The thought being: split the value from COD-2 into a "start" and an "end" value.
answered Nov 23 '18 at 22:25
DinoCoderSaurusDinoCoderSaurus
1,014158
add a comment |
Based on the small data set shown, and my presumed answer to @Shawn's question (K801 is a typo and is meant to be K80 or K81) I assume the following problem description:
Find a row in COD_2 such that the value in COD_1 is between {value1}-{value2} in COD_2; the - being significant and dependable.
I cannot speak to speed, but I would approach it this way:
SELECT value1, value2
from COD_1,COD_2
where value1 between substr(value2,1,instr(value2,'-')-1) and substr(value2,instr(value2,'-')+1)
The thought being: split the value from COD-2 into a "start" and an "end" value.
answered Nov 23 '18 at 22:25
DinoCoderSaurusDinoCoderSaurus
1,014158
Based on the small data set shown, and my presumed answer to @Shawn's question (K801 is a typo and is meant to be K80 or K81) I assume the following problem description:
Find a row in COD_2 such that the value in COD_1 is between {value1}-{value2} in COD_2; the - being significant and dependable.
I cannot speak to speed, but I would approach it this way:
SELECT value1, value2
from COD_1,COD_2
where value1 between substr(value2,1,instr(value2,'-')-1) and substr(value2,instr(value2,'-')+1)
The thought being: split the value from COD-2 into a "start" and an "end" value.
answered Nov 23 '18 at 22:25
DinoCoderSaurusDinoCoderSaurus
1,014158
answered Nov 23 '18 at 22:25
DinoCoderSaurusDinoCoderSaurus
1,014158
answered Nov 23 '18 at 22:25
DinoCoderSaurusDinoCoderSaurus
1,014158
answered Nov 23 '18 at 22:25
DinoCoderSaurusDinoCoderSaurus
1,014158
1,014158
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53437582%2fsearch-similar-value-in-another-table-using-in-sqlite%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Are you trying to store a range in a single value (Bad idea, btw)? If so, how is
K801inK80-K81?– Shawn
Nov 22 '18 at 21:32