From long to wide formats just based on two columns Rstudio












0















This is my data frame:
My data frame



I have a data frame of six columns and last columns contains the values . The Column 'code' includes s and d. column 'Sex' includes M and F. And I have two thousand offsprings in the column offspring.



seq parent code Sex offspring                     Value 

1 49032 s M J44010_CCG7YANXX_2_661_X4 -0.38455056

2 48741 s M J44010_CCG7YANXX_2_661_X4 0.10574340

3 48757 s M J44010_CCG7YANXX_2_661_X4 0.39572906

4 48465 d f J44010_CCG7YANXX_2_661_X4 0.43409006

5 48521 d f J44010_CCG7YANXX_2_661_X4 0.40337447

6 48703 d f J44010_CCG7YANXX_2_661_X4 -0.38148980


The column parent includes ids for both males and females.
I want to keep the female/dam id ,female/dam code and female/dam sex just beside the male/sire as a column and also keep the sire value and dam value seperately . So, the 'value' will be seprated in two parts .



The data frame will look like the below:



'seq''parent1''sirecode''Sex''parent2''damcode''Sex''offspring''sireValue' 'damvalue'

1 49032 s M 48465 d f J44010 -0.38455056 0.43409006

2 48741 s M 48521 d f J44010 0.10574340 0.40337447

3 48757 s M 48703 d f J44010 0.39572906 -0.38148980


So, each offspring will have 3 or 4 pair of parents.

I tried to use dcast function on it.










share|improve this question




















  • 1





    How do we know what male parent to match to what female parents? All the offspring are identical as far as I can tell.

    – iod
    Nov 23 '18 at 1:20











  • I just given the example of one offspring. There are other offspring just like it . And male parent (sire1) and female parent (dam1) are in pair. So, they are sequenced . For example, 1. Sire 1 2. Sire 2 3. Sire 3. 4. Dam1 5. Dam2 6. Dam3

    – Koushik Das
    Nov 23 '18 at 1:40


















0















This is my data frame:
My data frame



I have a data frame of six columns and last columns contains the values . The Column 'code' includes s and d. column 'Sex' includes M and F. And I have two thousand offsprings in the column offspring.



seq parent code Sex offspring                     Value 

1 49032 s M J44010_CCG7YANXX_2_661_X4 -0.38455056

2 48741 s M J44010_CCG7YANXX_2_661_X4 0.10574340

3 48757 s M J44010_CCG7YANXX_2_661_X4 0.39572906

4 48465 d f J44010_CCG7YANXX_2_661_X4 0.43409006

5 48521 d f J44010_CCG7YANXX_2_661_X4 0.40337447

6 48703 d f J44010_CCG7YANXX_2_661_X4 -0.38148980


The column parent includes ids for both males and females.
I want to keep the female/dam id ,female/dam code and female/dam sex just beside the male/sire as a column and also keep the sire value and dam value seperately . So, the 'value' will be seprated in two parts .



The data frame will look like the below:



'seq''parent1''sirecode''Sex''parent2''damcode''Sex''offspring''sireValue' 'damvalue'

1 49032 s M 48465 d f J44010 -0.38455056 0.43409006

2 48741 s M 48521 d f J44010 0.10574340 0.40337447

3 48757 s M 48703 d f J44010 0.39572906 -0.38148980


So, each offspring will have 3 or 4 pair of parents.

I tried to use dcast function on it.










share|improve this question




















  • 1





    How do we know what male parent to match to what female parents? All the offspring are identical as far as I can tell.

    – iod
    Nov 23 '18 at 1:20











  • I just given the example of one offspring. There are other offspring just like it . And male parent (sire1) and female parent (dam1) are in pair. So, they are sequenced . For example, 1. Sire 1 2. Sire 2 3. Sire 3. 4. Dam1 5. Dam2 6. Dam3

    – Koushik Das
    Nov 23 '18 at 1:40
















0












0








0








This is my data frame:
My data frame



I have a data frame of six columns and last columns contains the values . The Column 'code' includes s and d. column 'Sex' includes M and F. And I have two thousand offsprings in the column offspring.



seq parent code Sex offspring                     Value 

1 49032 s M J44010_CCG7YANXX_2_661_X4 -0.38455056

2 48741 s M J44010_CCG7YANXX_2_661_X4 0.10574340

3 48757 s M J44010_CCG7YANXX_2_661_X4 0.39572906

4 48465 d f J44010_CCG7YANXX_2_661_X4 0.43409006

5 48521 d f J44010_CCG7YANXX_2_661_X4 0.40337447

6 48703 d f J44010_CCG7YANXX_2_661_X4 -0.38148980


The column parent includes ids for both males and females.
I want to keep the female/dam id ,female/dam code and female/dam sex just beside the male/sire as a column and also keep the sire value and dam value seperately . So, the 'value' will be seprated in two parts .



The data frame will look like the below:



'seq''parent1''sirecode''Sex''parent2''damcode''Sex''offspring''sireValue' 'damvalue'

1 49032 s M 48465 d f J44010 -0.38455056 0.43409006

2 48741 s M 48521 d f J44010 0.10574340 0.40337447

3 48757 s M 48703 d f J44010 0.39572906 -0.38148980


So, each offspring will have 3 or 4 pair of parents.

I tried to use dcast function on it.










share|improve this question
















This is my data frame:
My data frame



I have a data frame of six columns and last columns contains the values . The Column 'code' includes s and d. column 'Sex' includes M and F. And I have two thousand offsprings in the column offspring.



seq parent code Sex offspring                     Value 

1 49032 s M J44010_CCG7YANXX_2_661_X4 -0.38455056

2 48741 s M J44010_CCG7YANXX_2_661_X4 0.10574340

3 48757 s M J44010_CCG7YANXX_2_661_X4 0.39572906

4 48465 d f J44010_CCG7YANXX_2_661_X4 0.43409006

5 48521 d f J44010_CCG7YANXX_2_661_X4 0.40337447

6 48703 d f J44010_CCG7YANXX_2_661_X4 -0.38148980


The column parent includes ids for both males and females.
I want to keep the female/dam id ,female/dam code and female/dam sex just beside the male/sire as a column and also keep the sire value and dam value seperately . So, the 'value' will be seprated in two parts .



The data frame will look like the below:



'seq''parent1''sirecode''Sex''parent2''damcode''Sex''offspring''sireValue' 'damvalue'

1 49032 s M 48465 d f J44010 -0.38455056 0.43409006

2 48741 s M 48521 d f J44010 0.10574340 0.40337447

3 48757 s M 48703 d f J44010 0.39572906 -0.38148980


So, each offspring will have 3 or 4 pair of parents.

I tried to use dcast function on it.







r






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 23 '18 at 2:19









kit

1,1063817




1,1063817










asked Nov 23 '18 at 1:04









Koushik DasKoushik Das

12




12








  • 1





    How do we know what male parent to match to what female parents? All the offspring are identical as far as I can tell.

    – iod
    Nov 23 '18 at 1:20











  • I just given the example of one offspring. There are other offspring just like it . And male parent (sire1) and female parent (dam1) are in pair. So, they are sequenced . For example, 1. Sire 1 2. Sire 2 3. Sire 3. 4. Dam1 5. Dam2 6. Dam3

    – Koushik Das
    Nov 23 '18 at 1:40
















  • 1





    How do we know what male parent to match to what female parents? All the offspring are identical as far as I can tell.

    – iod
    Nov 23 '18 at 1:20











  • I just given the example of one offspring. There are other offspring just like it . And male parent (sire1) and female parent (dam1) are in pair. So, they are sequenced . For example, 1. Sire 1 2. Sire 2 3. Sire 3. 4. Dam1 5. Dam2 6. Dam3

    – Koushik Das
    Nov 23 '18 at 1:40










1




1





How do we know what male parent to match to what female parents? All the offspring are identical as far as I can tell.

– iod
Nov 23 '18 at 1:20





How do we know what male parent to match to what female parents? All the offspring are identical as far as I can tell.

– iod
Nov 23 '18 at 1:20













I just given the example of one offspring. There are other offspring just like it . And male parent (sire1) and female parent (dam1) are in pair. So, they are sequenced . For example, 1. Sire 1 2. Sire 2 3. Sire 3. 4. Dam1 5. Dam2 6. Dam3

– Koushik Das
Nov 23 '18 at 1:40







I just given the example of one offspring. There are other offspring just like it . And male parent (sire1) and female parent (dam1) are in pair. So, they are sequenced . For example, 1. Sire 1 2. Sire 2 3. Sire 3. 4. Dam1 5. Dam2 6. Dam3

– Koushik Das
Nov 23 '18 at 1:40














1 Answer
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oldest

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0














We could use dcast after creating a sequence column



library(data.table)
setDT(df1)[, n := seq_len(.N), .(code, Sex)]
dcast(df1, n + offspring ~ rowid(n), value.var = c('parent', 'code', 'Sex', 'Value'), sep = "")
# n offspring parent1 parent2 code1 code2 Sex1 Sex2 Value1 Value2
#1: 1 J44010_CCG7YANXX_2_661_X4 49032 48465 s d M f -0.3845506 0.4340901
#2: 2 J44010_CCG7YANXX_2_661_X4 48741 48521 s d M f 0.1057434 0.4033745
#3: 3 J44010_CCG7YANXX_2_661_X4 48757 48703 s d M f 0.3957291 -0.3814898




In base R, we can use reshape



df1$n <- with(df1, ave(seq_along(Sex), Sex, FUN = seq_along))
df1$n1 <- with(df1, ave(n, n, FUN = seq_along))
reshape(df1[-1], idvar = c('n', 'offspring'), timevar = 'n1', direction = 'wide' )


data



df1 <- structure(list(seq = 1:6, parent = c(49032L, 48741L, 48757L, 
48465L, 48521L, 48703L), code = c("s", "s", "s", "d", "d", "d"
), Sex = c("M", "M", "M", "f", "f", "f"),
offspring = c("J44010_CCG7YANXX_2_661_X4",
"J44010_CCG7YANXX_2_661_X4", "J44010_CCG7YANXX_2_661_X4",
"J44010_CCG7YANXX_2_661_X4",
"J44010_CCG7YANXX_2_661_X4", "J44010_CCG7YANXX_2_661_X4"),
Value = c(-0.38455056,
0.1057434, 0.39572906, 0.43409006, 0.40337447, -0.3814898)),
class = "data.frame", row.names = c(NA, -6L))





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    0














    We could use dcast after creating a sequence column



    library(data.table)
    setDT(df1)[, n := seq_len(.N), .(code, Sex)]
    dcast(df1, n + offspring ~ rowid(n), value.var = c('parent', 'code', 'Sex', 'Value'), sep = "")
    # n offspring parent1 parent2 code1 code2 Sex1 Sex2 Value1 Value2
    #1: 1 J44010_CCG7YANXX_2_661_X4 49032 48465 s d M f -0.3845506 0.4340901
    #2: 2 J44010_CCG7YANXX_2_661_X4 48741 48521 s d M f 0.1057434 0.4033745
    #3: 3 J44010_CCG7YANXX_2_661_X4 48757 48703 s d M f 0.3957291 -0.3814898




    In base R, we can use reshape



    df1$n <- with(df1, ave(seq_along(Sex), Sex, FUN = seq_along))
    df1$n1 <- with(df1, ave(n, n, FUN = seq_along))
    reshape(df1[-1], idvar = c('n', 'offspring'), timevar = 'n1', direction = 'wide' )


    data



    df1 <- structure(list(seq = 1:6, parent = c(49032L, 48741L, 48757L, 
    48465L, 48521L, 48703L), code = c("s", "s", "s", "d", "d", "d"
    ), Sex = c("M", "M", "M", "f", "f", "f"),
    offspring = c("J44010_CCG7YANXX_2_661_X4",
    "J44010_CCG7YANXX_2_661_X4", "J44010_CCG7YANXX_2_661_X4",
    "J44010_CCG7YANXX_2_661_X4",
    "J44010_CCG7YANXX_2_661_X4", "J44010_CCG7YANXX_2_661_X4"),
    Value = c(-0.38455056,
    0.1057434, 0.39572906, 0.43409006, 0.40337447, -0.3814898)),
    class = "data.frame", row.names = c(NA, -6L))





    share|improve this answer






























      0














      We could use dcast after creating a sequence column



      library(data.table)
      setDT(df1)[, n := seq_len(.N), .(code, Sex)]
      dcast(df1, n + offspring ~ rowid(n), value.var = c('parent', 'code', 'Sex', 'Value'), sep = "")
      # n offspring parent1 parent2 code1 code2 Sex1 Sex2 Value1 Value2
      #1: 1 J44010_CCG7YANXX_2_661_X4 49032 48465 s d M f -0.3845506 0.4340901
      #2: 2 J44010_CCG7YANXX_2_661_X4 48741 48521 s d M f 0.1057434 0.4033745
      #3: 3 J44010_CCG7YANXX_2_661_X4 48757 48703 s d M f 0.3957291 -0.3814898




      In base R, we can use reshape



      df1$n <- with(df1, ave(seq_along(Sex), Sex, FUN = seq_along))
      df1$n1 <- with(df1, ave(n, n, FUN = seq_along))
      reshape(df1[-1], idvar = c('n', 'offspring'), timevar = 'n1', direction = 'wide' )


      data



      df1 <- structure(list(seq = 1:6, parent = c(49032L, 48741L, 48757L, 
      48465L, 48521L, 48703L), code = c("s", "s", "s", "d", "d", "d"
      ), Sex = c("M", "M", "M", "f", "f", "f"),
      offspring = c("J44010_CCG7YANXX_2_661_X4",
      "J44010_CCG7YANXX_2_661_X4", "J44010_CCG7YANXX_2_661_X4",
      "J44010_CCG7YANXX_2_661_X4",
      "J44010_CCG7YANXX_2_661_X4", "J44010_CCG7YANXX_2_661_X4"),
      Value = c(-0.38455056,
      0.1057434, 0.39572906, 0.43409006, 0.40337447, -0.3814898)),
      class = "data.frame", row.names = c(NA, -6L))





      share|improve this answer




























        0












        0








        0







        We could use dcast after creating a sequence column



        library(data.table)
        setDT(df1)[, n := seq_len(.N), .(code, Sex)]
        dcast(df1, n + offspring ~ rowid(n), value.var = c('parent', 'code', 'Sex', 'Value'), sep = "")
        # n offspring parent1 parent2 code1 code2 Sex1 Sex2 Value1 Value2
        #1: 1 J44010_CCG7YANXX_2_661_X4 49032 48465 s d M f -0.3845506 0.4340901
        #2: 2 J44010_CCG7YANXX_2_661_X4 48741 48521 s d M f 0.1057434 0.4033745
        #3: 3 J44010_CCG7YANXX_2_661_X4 48757 48703 s d M f 0.3957291 -0.3814898




        In base R, we can use reshape



        df1$n <- with(df1, ave(seq_along(Sex), Sex, FUN = seq_along))
        df1$n1 <- with(df1, ave(n, n, FUN = seq_along))
        reshape(df1[-1], idvar = c('n', 'offspring'), timevar = 'n1', direction = 'wide' )


        data



        df1 <- structure(list(seq = 1:6, parent = c(49032L, 48741L, 48757L, 
        48465L, 48521L, 48703L), code = c("s", "s", "s", "d", "d", "d"
        ), Sex = c("M", "M", "M", "f", "f", "f"),
        offspring = c("J44010_CCG7YANXX_2_661_X4",
        "J44010_CCG7YANXX_2_661_X4", "J44010_CCG7YANXX_2_661_X4",
        "J44010_CCG7YANXX_2_661_X4",
        "J44010_CCG7YANXX_2_661_X4", "J44010_CCG7YANXX_2_661_X4"),
        Value = c(-0.38455056,
        0.1057434, 0.39572906, 0.43409006, 0.40337447, -0.3814898)),
        class = "data.frame", row.names = c(NA, -6L))





        share|improve this answer















        We could use dcast after creating a sequence column



        library(data.table)
        setDT(df1)[, n := seq_len(.N), .(code, Sex)]
        dcast(df1, n + offspring ~ rowid(n), value.var = c('parent', 'code', 'Sex', 'Value'), sep = "")
        # n offspring parent1 parent2 code1 code2 Sex1 Sex2 Value1 Value2
        #1: 1 J44010_CCG7YANXX_2_661_X4 49032 48465 s d M f -0.3845506 0.4340901
        #2: 2 J44010_CCG7YANXX_2_661_X4 48741 48521 s d M f 0.1057434 0.4033745
        #3: 3 J44010_CCG7YANXX_2_661_X4 48757 48703 s d M f 0.3957291 -0.3814898




        In base R, we can use reshape



        df1$n <- with(df1, ave(seq_along(Sex), Sex, FUN = seq_along))
        df1$n1 <- with(df1, ave(n, n, FUN = seq_along))
        reshape(df1[-1], idvar = c('n', 'offspring'), timevar = 'n1', direction = 'wide' )


        data



        df1 <- structure(list(seq = 1:6, parent = c(49032L, 48741L, 48757L, 
        48465L, 48521L, 48703L), code = c("s", "s", "s", "d", "d", "d"
        ), Sex = c("M", "M", "M", "f", "f", "f"),
        offspring = c("J44010_CCG7YANXX_2_661_X4",
        "J44010_CCG7YANXX_2_661_X4", "J44010_CCG7YANXX_2_661_X4",
        "J44010_CCG7YANXX_2_661_X4",
        "J44010_CCG7YANXX_2_661_X4", "J44010_CCG7YANXX_2_661_X4"),
        Value = c(-0.38455056,
        0.1057434, 0.39572906, 0.43409006, 0.40337447, -0.3814898)),
        class = "data.frame", row.names = c(NA, -6L))






        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Nov 23 '18 at 1:43

























        answered Nov 23 '18 at 1:25









        akrunakrun

        414k13202275




        414k13202275
































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