How to count words in a line












3















I have a text file called "shoplist.txt" which one have:



drinks water cola fanta

fruit banana orange


And I want to get how many items per line I have. I'm able to extract drinks and fruit with function "cut" but how can I count how many words I have in each line?



My actually code is:



fileLine=`cat file.txt`

#Here I get each line saving it to fileLine

for line in $fileLine; do

 echo

((aux++))

done


But this code dosen't work because it save to %fileLine each work (drinks, then water,then cola,...)



How can I get the first line and then count the words on that line?






bash shell-script







share|improve this question





























    3















    I have a text file called "shoplist.txt" which one have:



    drinks water cola fanta
    
fruit banana orange


    And I want to get how many items per line I have. I'm able to extract drinks and fruit with function "cut" but how can I count how many words I have in each line?



    My actually code is:



    fileLine=`cat file.txt`
    
#Here I get each line saving it to fileLine
    
for line in $fileLine; do
    
 echo
    
((aux++))
    
done


    But this code dosen't work because it save to %fileLine each work (drinks, then water,then cola,...)



    How can I get the first line and then count the words on that line?






    bash shell-script







    share|improve this question



























      3












      3








      3








      I have a text file called "shoplist.txt" which one have:



      drinks water cola fanta
      
fruit banana orange


      And I want to get how many items per line I have. I'm able to extract drinks and fruit with function "cut" but how can I count how many words I have in each line?



      My actually code is:



      fileLine=`cat file.txt`
      
#Here I get each line saving it to fileLine
      
for line in $fileLine; do
      
 echo
      
((aux++))
      
done


      But this code dosen't work because it save to %fileLine each work (drinks, then water,then cola,...)



      How can I get the first line and then count the words on that line?






      bash shell-script







      share|improve this question
















      I have a text file called "shoplist.txt" which one have:



      drinks water cola fanta
      
fruit banana orange


      And I want to get how many items per line I have. I'm able to extract drinks and fruit with function "cut" but how can I count how many words I have in each line?



      My actually code is:



      fileLine=`cat file.txt`
      
#Here I get each line saving it to fileLine
      
for line in $fileLine; do
      
 echo
      
((aux++))
      
done


      But this code dosen't work because it save to %fileLine each work (drinks, then water,then cola,...)



      How can I get the first line and then count the words on that line?






      bash shell-script




      bash shell-script






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 10 hours ago









      Rui F Ribeiro

      41k1479137




      41k1479137










      asked 10 hours ago









      Multi17Multi17

      182




      182






















          2 Answers
          2






          active

          oldest

          votes


















          13














          If you can use awk, NF is the number of fields in the current line (by default, a field is a word delimited by any amount of whitespace).



          Use



          awk '{ print NF, $0 }' inputfile


          With your sample input, this will print



          4 drinks water cola fanta
          
3 fruit banana orange





          share|improve this answer


























          • The more cryptic awk '$0=NF" "$0' inputfile is a shorter solution.

            – Isaac
            1 hour ago



















          2














          In Bash and wc:



          IFS=$'n'
          
while read line; do
          
    wc -w <<< "$line"
          
done < file.txt


          wc counts lines, words, bytes in files. With a shell loop you can make it count words in a line.






          share|improve this answer





















          • 1





            @Stobor thanks, fixed.

            – sborsky
            7 hours ago











          Your Answer








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          2 Answers
          2






          active

          oldest

          votes








          2 Answers
          2






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          13














          If you can use awk, NF is the number of fields in the current line (by default, a field is a word delimited by any amount of whitespace).



          Use



          awk '{ print NF, $0 }' inputfile


          With your sample input, this will print



          4 drinks water cola fanta
          
3 fruit banana orange





          share|improve this answer


























          • The more cryptic awk '$0=NF" "$0' inputfile is a shorter solution.

            – Isaac
            1 hour ago
















          13














          If you can use awk, NF is the number of fields in the current line (by default, a field is a word delimited by any amount of whitespace).



          Use



          awk '{ print NF, $0 }' inputfile


          With your sample input, this will print



          4 drinks water cola fanta
          
3 fruit banana orange





          share|improve this answer


























          • The more cryptic awk '$0=NF" "$0' inputfile is a shorter solution.

            – Isaac
            1 hour ago














          13












          13








          13







          If you can use awk, NF is the number of fields in the current line (by default, a field is a word delimited by any amount of whitespace).



          Use



          awk '{ print NF, $0 }' inputfile


          With your sample input, this will print



          4 drinks water cola fanta
          
3 fruit banana orange





          share|improve this answer















          If you can use awk, NF is the number of fields in the current line (by default, a field is a word delimited by any amount of whitespace).



          Use



          awk '{ print NF, $0 }' inputfile


          With your sample input, this will print



          4 drinks water cola fanta
          
3 fruit banana orange






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited 7 hours ago









          Kusalananda

          133k17254417




          133k17254417










          answered 10 hours ago









          BodoBodo

          1,993314




          1,993314













          • The more cryptic awk '$0=NF" "$0' inputfile is a shorter solution.

            – Isaac
            1 hour ago



















          • The more cryptic awk '$0=NF" "$0' inputfile is a shorter solution.

            – Isaac
            1 hour ago

















          The more cryptic awk '$0=NF" "$0' inputfile is a shorter solution.

          – Isaac
          1 hour ago





          The more cryptic awk '$0=NF" "$0' inputfile is a shorter solution.

          – Isaac
          1 hour ago













          2














          In Bash and wc:



          IFS=$'n'
          
while read line; do
          
    wc -w <<< "$line"
          
done < file.txt


          wc counts lines, words, bytes in files. With a shell loop you can make it count words in a line.






          share|improve this answer





















          • 1





            @Stobor thanks, fixed.

            – sborsky
            7 hours ago
















          2














          In Bash and wc:



          IFS=$'n'
          
while read line; do
          
    wc -w <<< "$line"
          
done < file.txt


          wc counts lines, words, bytes in files. With a shell loop you can make it count words in a line.






          share|improve this answer





















          • 1





            @Stobor thanks, fixed.

            – sborsky
            7 hours ago














          2












          2








          2







          In Bash and wc:



          IFS=$'n'
          
while read line; do
          
    wc -w <<< "$line"
          
done < file.txt


          wc counts lines, words, bytes in files. With a shell loop you can make it count words in a line.






          share|improve this answer















          In Bash and wc:



          IFS=$'n'
          
while read line; do
          
    wc -w <<< "$line"
          
done < file.txt


          wc counts lines, words, bytes in files. With a shell loop you can make it count words in a line.







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited 7 hours ago

























          answered 9 hours ago









          sborskysborsky

          789511




          789511








          • 1





            @Stobor thanks, fixed.

            – sborsky
            7 hours ago














          • 1





            @Stobor thanks, fixed.

            – sborsky
            7 hours ago








          1




          1





          @Stobor thanks, fixed.

          – sborsky
          7 hours ago





          @Stobor thanks, fixed.

          – sborsky
          7 hours ago


















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