Capturing repeating groups in GO
I'm trying to create a function that can parse strings which consist of an uppercase word followed by zero or more arguments which are encapsulated in double quotes.
For example, each of the following lines:
COPY "filename one" "filename two"
REMOVE "filename"
LIST "x" "y" "z"
DISCONNECT
The result should be a string (the command) followed by a string (the arguments inside the quotes). I created the following regular expression:
re1, _ := regexp.Compile(`([A-Z]+)(?: "([^"]+)")*`)
results := re1.FindAllStringSubmatch(input, -1)
However, no-matter what I try, only the last argument gets captured.
An example of my problem: https://play.golang.org/p/W1rE1X4SWf5
"arg1" is not captured in this example. What am I missing?
regex go
edited Nov 22 '18 at 16:21
mrzasa
10.6k104078
asked Nov 22 '18 at 15:40
XatooXatoo
2,2962144
add a comment |
I'm trying to create a function that can parse strings which consist of an uppercase word followed by zero or more arguments which are encapsulated in double quotes.
For example, each of the following lines:
COPY "filename one" "filename two"
REMOVE "filename"
LIST "x" "y" "z"
DISCONNECT
The result should be a string (the command) followed by a string (the arguments inside the quotes). I created the following regular expression:
re1, _ := regexp.Compile(`([A-Z]+)(?: "([^"]+)")*`)
results := re1.FindAllStringSubmatch(input, -1)
However, no-matter what I try, only the last argument gets captured.
An example of my problem: https://play.golang.org/p/W1rE1X4SWf5
"arg1" is not captured in this example. What am I missing?
regex go
edited Nov 22 '18 at 16:21
mrzasa
10.6k104078
asked Nov 22 '18 at 15:40
XatooXatoo
2,2962144
Could a command (without considering args) contain white space?
– Ehsan.Saradar
Nov 22 '18 at 15:57
add a comment |
I'm trying to create a function that can parse strings which consist of an uppercase word followed by zero or more arguments which are encapsulated in double quotes.
For example, each of the following lines:
COPY "filename one" "filename two"
REMOVE "filename"
LIST "x" "y" "z"
DISCONNECT
The result should be a string (the command) followed by a string (the arguments inside the quotes). I created the following regular expression:
re1, _ := regexp.Compile(`([A-Z]+)(?: "([^"]+)")*`)
results := re1.FindAllStringSubmatch(input, -1)
However, no-matter what I try, only the last argument gets captured.
An example of my problem: https://play.golang.org/p/W1rE1X4SWf5
"arg1" is not captured in this example. What am I missing?
regex go
edited Nov 22 '18 at 16:21
mrzasa
10.6k104078
asked Nov 22 '18 at 15:40
XatooXatoo
2,2962144
I'm trying to create a function that can parse strings which consist of an uppercase word followed by zero or more arguments which are encapsulated in double quotes.
For example, each of the following lines:
COPY "filename one" "filename two"
REMOVE "filename"
LIST "x" "y" "z"
DISCONNECT
The result should be a string (the command) followed by a string (the arguments inside the quotes). I created the following regular expression:
re1, _ := regexp.Compile(`([A-Z]+)(?: "([^"]+)")*`)
results := re1.FindAllStringSubmatch(input, -1)
However, no-matter what I try, only the last argument gets captured.
An example of my problem: https://play.golang.org/p/W1rE1X4SWf5
"arg1" is not captured in this example. What am I missing?
regex go
regex go
edited Nov 22 '18 at 16:21
mrzasa
10.6k104078
asked Nov 22 '18 at 15:40
XatooXatoo
2,2962144
edited Nov 22 '18 at 16:21
mrzasa
10.6k104078
asked Nov 22 '18 at 15:40
XatooXatoo
2,2962144
edited Nov 22 '18 at 16:21
mrzasa
10.6k104078
edited Nov 22 '18 at 16:21
mrzasa
10.6k104078
edited Nov 22 '18 at 16:21
mrzasa
10.6k104078
10.6k104078
asked Nov 22 '18 at 15:40
XatooXatoo
2,2962144
asked Nov 22 '18 at 15:40
XatooXatoo
2,2962144
asked Nov 22 '18 at 15:40
XatooXatoo
2,2962144
2,2962144
Could a command (without considering args) contain white space?
– Ehsan.Saradar
Nov 22 '18 at 15:57
add a comment |
Could a command (without considering args) contain white space?
– Ehsan.Saradar
Nov 22 '18 at 15:57
Could a command (without considering args) contain white space?
– Ehsan.Saradar
Nov 22 '18 at 15:57
Could a command (without considering args) contain white space?
– Ehsan.Saradar
Nov 22 '18 at 15:57
add a comment |
4 Answers
4
active
oldest
votes
If your commands are well defined, e.i. command names are always upper-case and arguments are always after the command then a looser regex might just fit your use case:
re1, _ := regexp.Compile(`([A-Z]+)|(?: "([^"]+)")`)
results := re1.FindAllStringSubmatch(`COMMAND "arg1" "arg2" "arg3"`, -1)
fmt.Println("Command:", results[0][1])
for _, arg := range results[1:] {
fmt.Println("Arg:", arg[2])
}
Playground
answered Nov 22 '18 at 16:15
ssemillassemilla
3,097524
Awesome, this implementation works for me!
– Xatoo
Nov 22 '18 at 17:00
Probably,regexp.Compile(`^([A-Z]+)| "([^"]+)"`)will be more precise as it matches the command at the start of string only.
– Wiktor Stribiżew
Nov 22 '18 at 17:25
add a comment |
When you try to capture repeated match, only the last one is captured.
I'd try to do it in two steps: first split commmand and arguments, then parse the arguments.
Splitting to command and arguments can be done with ([A-Z]+)((?: "[^"]+")*) (demo):
([A-Z]+)in first group, you get the command
((?: "[^"]+")*)in the second group, you'll get arguments in quotes, separated by spaces
Then you can use FindAllString with "([^"]+)" to extract arguments (demo).
answered Nov 22 '18 at 16:05
mrzasamrzasa
10.6k104078
add a comment |
I think this may solve your problem
re1, _ := regexp.Compile(`([A-Z]+)(?: *)`)
commandText:=`COPY "filename one" "filename two"`
if re1.Match(byte(commandText)){
index:=re1.FindIndex(byte(commandText))[1]
commandArgs:=commandText[index:]
commandArgsRegex,_:=regexp.Compile(`"([^"]+)"`)
fmt.Println("Command= " , commandText[0:index])
for i,arg:=range commandArgsRegex.FindAllString(commandArgs,-1){
fmt.Println("args ", i,"= " , arg)
}
}else{
fmt.Println("Failed")
}
answered Nov 22 '18 at 16:10
Ehsan.SaradarEhsan.Saradar
46337
add a comment |
Add an extra capture group. If you make it optional extra data will be empty but the match will work
re1, _ := regexp.Compile(`^([A-Z]+)(s"[^"]+")(s"[^"]+")?(s"[^"]+")?$`)
Add more (s"[^"]+")? expressions up to the maximum you need. I put in two as there is an expression with 3 parameters in your examples
answered Nov 22 '18 at 16:25
VorsprungVorsprung
23.2k32144
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
If your commands are well defined, e.i. command names are always upper-case and arguments are always after the command then a looser regex might just fit your use case:
re1, _ := regexp.Compile(`([A-Z]+)|(?: "([^"]+)")`)
results := re1.FindAllStringSubmatch(`COMMAND "arg1" "arg2" "arg3"`, -1)
fmt.Println("Command:", results[0][1])
for _, arg := range results[1:] {
fmt.Println("Arg:", arg[2])
}
Playground
answered Nov 22 '18 at 16:15
ssemillassemilla
3,097524
Awesome, this implementation works for me!
– Xatoo
Nov 22 '18 at 17:00
Probably,regexp.Compile(`^([A-Z]+)| "([^"]+)"`)will be more precise as it matches the command at the start of string only.
– Wiktor Stribiżew
Nov 22 '18 at 17:25
add a comment |
If your commands are well defined, e.i. command names are always upper-case and arguments are always after the command then a looser regex might just fit your use case:
re1, _ := regexp.Compile(`([A-Z]+)|(?: "([^"]+)")`)
results := re1.FindAllStringSubmatch(`COMMAND "arg1" "arg2" "arg3"`, -1)
fmt.Println("Command:", results[0][1])
for _, arg := range results[1:] {
fmt.Println("Arg:", arg[2])
}
Playground
answered Nov 22 '18 at 16:15
ssemillassemilla
3,097524
Awesome, this implementation works for me!
– Xatoo
Nov 22 '18 at 17:00
Probably,regexp.Compile(`^([A-Z]+)| "([^"]+)"`)will be more precise as it matches the command at the start of string only.
– Wiktor Stribiżew
Nov 22 '18 at 17:25
add a comment |
If your commands are well defined, e.i. command names are always upper-case and arguments are always after the command then a looser regex might just fit your use case:
re1, _ := regexp.Compile(`([A-Z]+)|(?: "([^"]+)")`)
results := re1.FindAllStringSubmatch(`COMMAND "arg1" "arg2" "arg3"`, -1)
fmt.Println("Command:", results[0][1])
for _, arg := range results[1:] {
fmt.Println("Arg:", arg[2])
}
Playground
answered Nov 22 '18 at 16:15
ssemillassemilla
3,097524
If your commands are well defined, e.i. command names are always upper-case and arguments are always after the command then a looser regex might just fit your use case:
re1, _ := regexp.Compile(`([A-Z]+)|(?: "([^"]+)")`)
results := re1.FindAllStringSubmatch(`COMMAND "arg1" "arg2" "arg3"`, -1)
fmt.Println("Command:", results[0][1])
for _, arg := range results[1:] {
fmt.Println("Arg:", arg[2])
}
Playground
answered Nov 22 '18 at 16:15
ssemillassemilla
3,097524
edited Nov 22 '18 at 16:23
answered Nov 22 '18 at 16:15
ssemillassemilla
3,097524
answered Nov 22 '18 at 16:15
ssemillassemilla
3,097524
answered Nov 22 '18 at 16:15
ssemillassemilla
3,097524
3,097524
Awesome, this implementation works for me!
– Xatoo
Nov 22 '18 at 17:00
Probably,regexp.Compile(`^([A-Z]+)| "([^"]+)"`)will be more precise as it matches the command at the start of string only.
– Wiktor Stribiżew
Nov 22 '18 at 17:25
add a comment |
Awesome, this implementation works for me!
– Xatoo
Nov 22 '18 at 17:00
Probably,regexp.Compile(`^([A-Z]+)| "([^"]+)"`)will be more precise as it matches the command at the start of string only.
– Wiktor Stribiżew
Nov 22 '18 at 17:25
Awesome, this implementation works for me!
– Xatoo
Nov 22 '18 at 17:00
Awesome, this implementation works for me!
– Xatoo
Nov 22 '18 at 17:00
Probably,
regexp.Compile(`^([A-Z]+)| "([^"]+)"`) will be more precise as it matches the command at the start of string only.– Wiktor Stribiżew
Nov 22 '18 at 17:25
Probably,
regexp.Compile(`^([A-Z]+)| "([^"]+)"`) will be more precise as it matches the command at the start of string only.– Wiktor Stribiżew
Nov 22 '18 at 17:25
add a comment |
When you try to capture repeated match, only the last one is captured.
I'd try to do it in two steps: first split commmand and arguments, then parse the arguments.
Splitting to command and arguments can be done with ([A-Z]+)((?: "[^"]+")*) (demo):
([A-Z]+)in first group, you get the command
((?: "[^"]+")*)in the second group, you'll get arguments in quotes, separated by spaces
Then you can use FindAllString with "([^"]+)" to extract arguments (demo).
answered Nov 22 '18 at 16:05
mrzasamrzasa
10.6k104078
add a comment |
When you try to capture repeated match, only the last one is captured.
I'd try to do it in two steps: first split commmand and arguments, then parse the arguments.
Splitting to command and arguments can be done with ([A-Z]+)((?: "[^"]+")*) (demo):
([A-Z]+)in first group, you get the command
((?: "[^"]+")*)in the second group, you'll get arguments in quotes, separated by spaces
Then you can use FindAllString with "([^"]+)" to extract arguments (demo).
answered Nov 22 '18 at 16:05
mrzasamrzasa
10.6k104078
add a comment |
When you try to capture repeated match, only the last one is captured.
I'd try to do it in two steps: first split commmand and arguments, then parse the arguments.
Splitting to command and arguments can be done with ([A-Z]+)((?: "[^"]+")*) (demo):
([A-Z]+)in first group, you get the command
((?: "[^"]+")*)in the second group, you'll get arguments in quotes, separated by spaces
Then you can use FindAllString with "([^"]+)" to extract arguments (demo).
answered Nov 22 '18 at 16:05
mrzasamrzasa
10.6k104078
When you try to capture repeated match, only the last one is captured.
I'd try to do it in two steps: first split commmand and arguments, then parse the arguments.
Splitting to command and arguments can be done with ([A-Z]+)((?: "[^"]+")*) (demo):
([A-Z]+)in first group, you get the command
((?: "[^"]+")*)in the second group, you'll get arguments in quotes, separated by spaces
Then you can use FindAllString with "([^"]+)" to extract arguments (demo).
answered Nov 22 '18 at 16:05
mrzasamrzasa
10.6k104078
answered Nov 22 '18 at 16:05
mrzasamrzasa
10.6k104078
answered Nov 22 '18 at 16:05
mrzasamrzasa
10.6k104078
answered Nov 22 '18 at 16:05
mrzasamrzasa
10.6k104078
10.6k104078
add a comment |
add a comment |
I think this may solve your problem
re1, _ := regexp.Compile(`([A-Z]+)(?: *)`)
commandText:=`COPY "filename one" "filename two"`
if re1.Match(byte(commandText)){
index:=re1.FindIndex(byte(commandText))[1]
commandArgs:=commandText[index:]
commandArgsRegex,_:=regexp.Compile(`"([^"]+)"`)
fmt.Println("Command= " , commandText[0:index])
for i,arg:=range commandArgsRegex.FindAllString(commandArgs,-1){
fmt.Println("args ", i,"= " , arg)
}
}else{
fmt.Println("Failed")
}
answered Nov 22 '18 at 16:10
Ehsan.SaradarEhsan.Saradar
46337
add a comment |
I think this may solve your problem
re1, _ := regexp.Compile(`([A-Z]+)(?: *)`)
commandText:=`COPY "filename one" "filename two"`
if re1.Match(byte(commandText)){
index:=re1.FindIndex(byte(commandText))[1]
commandArgs:=commandText[index:]
commandArgsRegex,_:=regexp.Compile(`"([^"]+)"`)
fmt.Println("Command= " , commandText[0:index])
for i,arg:=range commandArgsRegex.FindAllString(commandArgs,-1){
fmt.Println("args ", i,"= " , arg)
}
}else{
fmt.Println("Failed")
}
answered Nov 22 '18 at 16:10
Ehsan.SaradarEhsan.Saradar
46337
add a comment |
I think this may solve your problem
re1, _ := regexp.Compile(`([A-Z]+)(?: *)`)
commandText:=`COPY "filename one" "filename two"`
if re1.Match(byte(commandText)){
index:=re1.FindIndex(byte(commandText))[1]
commandArgs:=commandText[index:]
commandArgsRegex,_:=regexp.Compile(`"([^"]+)"`)
fmt.Println("Command= " , commandText[0:index])
for i,arg:=range commandArgsRegex.FindAllString(commandArgs,-1){
fmt.Println("args ", i,"= " , arg)
}
}else{
fmt.Println("Failed")
}
answered Nov 22 '18 at 16:10
Ehsan.SaradarEhsan.Saradar
46337
I think this may solve your problem
re1, _ := regexp.Compile(`([A-Z]+)(?: *)`)
commandText:=`COPY "filename one" "filename two"`
if re1.Match(byte(commandText)){
index:=re1.FindIndex(byte(commandText))[1]
commandArgs:=commandText[index:]
commandArgsRegex,_:=regexp.Compile(`"([^"]+)"`)
fmt.Println("Command= " , commandText[0:index])
for i,arg:=range commandArgsRegex.FindAllString(commandArgs,-1){
fmt.Println("args ", i,"= " , arg)
}
}else{
fmt.Println("Failed")
}
answered Nov 22 '18 at 16:10
Ehsan.SaradarEhsan.Saradar
46337
answered Nov 22 '18 at 16:10
Ehsan.SaradarEhsan.Saradar
46337
answered Nov 22 '18 at 16:10
Ehsan.SaradarEhsan.Saradar
46337
answered Nov 22 '18 at 16:10
Ehsan.SaradarEhsan.Saradar
46337
46337
add a comment |
add a comment |
Add an extra capture group. If you make it optional extra data will be empty but the match will work
re1, _ := regexp.Compile(`^([A-Z]+)(s"[^"]+")(s"[^"]+")?(s"[^"]+")?$`)
Add more (s"[^"]+")? expressions up to the maximum you need. I put in two as there is an expression with 3 parameters in your examples
answered Nov 22 '18 at 16:25
VorsprungVorsprung
23.2k32144
add a comment |
Add an extra capture group. If you make it optional extra data will be empty but the match will work
re1, _ := regexp.Compile(`^([A-Z]+)(s"[^"]+")(s"[^"]+")?(s"[^"]+")?$`)
Add more (s"[^"]+")? expressions up to the maximum you need. I put in two as there is an expression with 3 parameters in your examples
answered Nov 22 '18 at 16:25
VorsprungVorsprung
23.2k32144
add a comment |
Add an extra capture group. If you make it optional extra data will be empty but the match will work
re1, _ := regexp.Compile(`^([A-Z]+)(s"[^"]+")(s"[^"]+")?(s"[^"]+")?$`)
Add more (s"[^"]+")? expressions up to the maximum you need. I put in two as there is an expression with 3 parameters in your examples
answered Nov 22 '18 at 16:25
VorsprungVorsprung
23.2k32144
Add an extra capture group. If you make it optional extra data will be empty but the match will work
re1, _ := regexp.Compile(`^([A-Z]+)(s"[^"]+")(s"[^"]+")?(s"[^"]+")?$`)
Add more (s"[^"]+")? expressions up to the maximum you need. I put in two as there is an expression with 3 parameters in your examples
answered Nov 22 '18 at 16:25
VorsprungVorsprung
23.2k32144
answered Nov 22 '18 at 16:25
VorsprungVorsprung
23.2k32144
answered Nov 22 '18 at 16:25
VorsprungVorsprung
23.2k32144
answered Nov 22 '18 at 16:25
VorsprungVorsprung
23.2k32144
23.2k32144
add a comment |
add a comment |
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Could a command (without considering args) contain white space?
– Ehsan.Saradar
Nov 22 '18 at 15:57