jQuery: How to add div with a dynamic id that increments when button is clicked?












0















I have this problem in jQuery:



I have a button that when clicked calls a function to create a div with an incremental id, equal to the number of clicks made. Here's my simplified solution:



$(document).ready(function() {
var count = 0;
});

$("#button").click(function() {
count = count + 1;
addDiv(count);
});


But, if I define the function click here, the id on my div is NaN while if I put the function of click in document.ready(), it creates two divs. I only want to create a div with incremental Id for each click!










share|improve this question

























  • Have a look at what var does and how variables defined with var work: developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…

    – Andreas
    Nov 22 '18 at 18:45













  • I think the problem is that you have to change the elements attribute and not just a javascript variable

    – tobifasc
    Nov 22 '18 at 18:53











  • The problem is in variable scope check jsfiddle.net/f9ug1dyv

    – Mohammad
    Nov 22 '18 at 18:57
















0















I have this problem in jQuery:



I have a button that when clicked calls a function to create a div with an incremental id, equal to the number of clicks made. Here's my simplified solution:



$(document).ready(function() {
var count = 0;
});

$("#button").click(function() {
count = count + 1;
addDiv(count);
});


But, if I define the function click here, the id on my div is NaN while if I put the function of click in document.ready(), it creates two divs. I only want to create a div with incremental Id for each click!










share|improve this question

























  • Have a look at what var does and how variables defined with var work: developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…

    – Andreas
    Nov 22 '18 at 18:45













  • I think the problem is that you have to change the elements attribute and not just a javascript variable

    – tobifasc
    Nov 22 '18 at 18:53











  • The problem is in variable scope check jsfiddle.net/f9ug1dyv

    – Mohammad
    Nov 22 '18 at 18:57














0












0








0








I have this problem in jQuery:



I have a button that when clicked calls a function to create a div with an incremental id, equal to the number of clicks made. Here's my simplified solution:



$(document).ready(function() {
var count = 0;
});

$("#button").click(function() {
count = count + 1;
addDiv(count);
});


But, if I define the function click here, the id on my div is NaN while if I put the function of click in document.ready(), it creates two divs. I only want to create a div with incremental Id for each click!










share|improve this question
















I have this problem in jQuery:



I have a button that when clicked calls a function to create a div with an incremental id, equal to the number of clicks made. Here's my simplified solution:



$(document).ready(function() {
var count = 0;
});

$("#button").click(function() {
count = count + 1;
addDiv(count);
});


But, if I define the function click here, the id on my div is NaN while if I put the function of click in document.ready(), it creates two divs. I only want to create a div with incremental Id for each click!







javascript jquery html






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 22 '18 at 19:42









Roy Scheffers

2,248101927




2,248101927










asked Nov 22 '18 at 18:42









user10276822user10276822

43




43













  • Have a look at what var does and how variables defined with var work: developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…

    – Andreas
    Nov 22 '18 at 18:45













  • I think the problem is that you have to change the elements attribute and not just a javascript variable

    – tobifasc
    Nov 22 '18 at 18:53











  • The problem is in variable scope check jsfiddle.net/f9ug1dyv

    – Mohammad
    Nov 22 '18 at 18:57



















  • Have a look at what var does and how variables defined with var work: developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…

    – Andreas
    Nov 22 '18 at 18:45













  • I think the problem is that you have to change the elements attribute and not just a javascript variable

    – tobifasc
    Nov 22 '18 at 18:53











  • The problem is in variable scope check jsfiddle.net/f9ug1dyv

    – Mohammad
    Nov 22 '18 at 18:57

















Have a look at what var does and how variables defined with var work: developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…

– Andreas
Nov 22 '18 at 18:45







Have a look at what var does and how variables defined with var work: developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…

– Andreas
Nov 22 '18 at 18:45















I think the problem is that you have to change the elements attribute and not just a javascript variable

– tobifasc
Nov 22 '18 at 18:53





I think the problem is that you have to change the elements attribute and not just a javascript variable

– tobifasc
Nov 22 '18 at 18:53













The problem is in variable scope check jsfiddle.net/f9ug1dyv

– Mohammad
Nov 22 '18 at 18:57





The problem is in variable scope check jsfiddle.net/f9ug1dyv

– Mohammad
Nov 22 '18 at 18:57












5 Answers
5






active

oldest

votes


















1














try this






var count=0;
$(document).ready(function(){
$("#add-div").click(function(){
count++;
$("body").append('<div id="'+count+'">div number '+count+'</div>');
});
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<body>
<button id="add-div">add div</button>
<br>
<br>
</body>








share|improve this answer
























  • Please, Don't just "Try this". Explain in a couple of paragraph why this works.

    – Roko C. Buljan
    Nov 22 '18 at 19:02











  • thanks, but this is a simple code, he will know the error

    – abdulsattar-alkhalaf
    Nov 22 '18 at 19:04



















1














This was due to scope issue.
Try this code:



  $( document ).ready(function() {
var count =0;
console.log(count);
$( "#button" ).click(function() {
count=count+1;
addDiv(count);
});
});





share|improve this answer
























  • You can remove console.log statement I used this for debugging purpose.

    – Jahanzeb Awan
    Nov 22 '18 at 19:11



















0














This is because of the scoping issue of count variable. Please note that JavaScript variables are accessible in scoping scenarios (block level scoping or function level scoping). More info here
What's wrong with your code is you have declared the count variable in one function and you are accessing it outside of it which is not allowed. Only to fix your code, I have made the count variable as global and now it will work as expected.



Note: Please note that global variables can be accessed anywhere in the execution context, so can be used with utmost care.






  $( document ).ready(function() 
{
//var count =0;
});

var count=0;
$('#button').on('click', function(){
count = count + 1;
alert(count);
});


//$( "#button" ).click(function() {
// count=count+1;
// addDiv(count);
//});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<button id='button'>Click Me</button>








share|improve this answer































    0














    if you define a variable within a function, it is restricted only to this function, if you set it to a global scope, which is what you need in this case, the variable becomes available for all functions that are under this scope, look:






    //global scope
    var count = 0;
    $( "#button" ).click(function() {
    //function restrict scope
    $('#increment').append(`<div>${count}</div>`)
    count++;
    });

        <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
    <body>
    <button id="button">Click Me!</button>
    <div id="increment">
    </body>





    See more at this page






    share|improve this answer































      0














      It's a scope problem.
      If you don't want to expose variables to the outer scope, you can use a closure.



      let addDiv = function(){
      let counter = 0;
      return function(){
      counter++;
      let wrapper = $("#someDiv");
      wrapper.append(`<div> id: ${counter}</div>`)
      }
      }();
      button.on("click", function(){
      addDiv();
      });





      share|improve this answer























        Your Answer






        StackExchange.ifUsing("editor", function () {
        StackExchange.using("externalEditor", function () {
        StackExchange.using("snippets", function () {
        StackExchange.snippets.init();
        });
        });
        }, "code-snippets");

        StackExchange.ready(function() {
        var channelOptions = {
        tags: "".split(" "),
        id: "1"
        };
        initTagRenderer("".split(" "), "".split(" "), channelOptions);

        StackExchange.using("externalEditor", function() {
        // Have to fire editor after snippets, if snippets enabled
        if (StackExchange.settings.snippets.snippetsEnabled) {
        StackExchange.using("snippets", function() {
        createEditor();
        });
        }
        else {
        createEditor();
        }
        });

        function createEditor() {
        StackExchange.prepareEditor({
        heartbeatType: 'answer',
        autoActivateHeartbeat: false,
        convertImagesToLinks: true,
        noModals: true,
        showLowRepImageUploadWarning: true,
        reputationToPostImages: 10,
        bindNavPrevention: true,
        postfix: "",
        imageUploader: {
        brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
        contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
        allowUrls: true
        },
        onDemand: true,
        discardSelector: ".discard-answer"
        ,immediatelyShowMarkdownHelp:true
        });


        }
        });














        draft saved

        draft discarded


















        StackExchange.ready(
        function () {
        StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53436628%2fjquery-how-to-add-div-with-a-dynamic-id-that-increments-when-button-is-clicked%23new-answer', 'question_page');
        }
        );

        Post as a guest















        Required, but never shown

























        5 Answers
        5






        active

        oldest

        votes








        5 Answers
        5






        active

        oldest

        votes









        active

        oldest

        votes






        active

        oldest

        votes









        1














        try this






        var count=0;
        $(document).ready(function(){
        $("#add-div").click(function(){
        count++;
        $("body").append('<div id="'+count+'">div number '+count+'</div>');
        });
        });

        <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
        <body>
        <button id="add-div">add div</button>
        <br>
        <br>
        </body>








        share|improve this answer
























        • Please, Don't just "Try this". Explain in a couple of paragraph why this works.

          – Roko C. Buljan
          Nov 22 '18 at 19:02











        • thanks, but this is a simple code, he will know the error

          – abdulsattar-alkhalaf
          Nov 22 '18 at 19:04
















        1














        try this






        var count=0;
        $(document).ready(function(){
        $("#add-div").click(function(){
        count++;
        $("body").append('<div id="'+count+'">div number '+count+'</div>');
        });
        });

        <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
        <body>
        <button id="add-div">add div</button>
        <br>
        <br>
        </body>








        share|improve this answer
























        • Please, Don't just "Try this". Explain in a couple of paragraph why this works.

          – Roko C. Buljan
          Nov 22 '18 at 19:02











        • thanks, but this is a simple code, he will know the error

          – abdulsattar-alkhalaf
          Nov 22 '18 at 19:04














        1












        1








        1







        try this






        var count=0;
        $(document).ready(function(){
        $("#add-div").click(function(){
        count++;
        $("body").append('<div id="'+count+'">div number '+count+'</div>');
        });
        });

        <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
        <body>
        <button id="add-div">add div</button>
        <br>
        <br>
        </body>








        share|improve this answer













        try this






        var count=0;
        $(document).ready(function(){
        $("#add-div").click(function(){
        count++;
        $("body").append('<div id="'+count+'">div number '+count+'</div>');
        });
        });

        <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
        <body>
        <button id="add-div">add div</button>
        <br>
        <br>
        </body>








        var count=0;
        $(document).ready(function(){
        $("#add-div").click(function(){
        count++;
        $("body").append('<div id="'+count+'">div number '+count+'</div>');
        });
        });

        <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
        <body>
        <button id="add-div">add div</button>
        <br>
        <br>
        </body>





        var count=0;
        $(document).ready(function(){
        $("#add-div").click(function(){
        count++;
        $("body").append('<div id="'+count+'">div number '+count+'</div>');
        });
        });

        <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
        <body>
        <button id="add-div">add div</button>
        <br>
        <br>
        </body>






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 22 '18 at 18:57









        abdulsattar-alkhalafabdulsattar-alkhalaf

        33215




        33215













        • Please, Don't just "Try this". Explain in a couple of paragraph why this works.

          – Roko C. Buljan
          Nov 22 '18 at 19:02











        • thanks, but this is a simple code, he will know the error

          – abdulsattar-alkhalaf
          Nov 22 '18 at 19:04



















        • Please, Don't just "Try this". Explain in a couple of paragraph why this works.

          – Roko C. Buljan
          Nov 22 '18 at 19:02











        • thanks, but this is a simple code, he will know the error

          – abdulsattar-alkhalaf
          Nov 22 '18 at 19:04

















        Please, Don't just "Try this". Explain in a couple of paragraph why this works.

        – Roko C. Buljan
        Nov 22 '18 at 19:02





        Please, Don't just "Try this". Explain in a couple of paragraph why this works.

        – Roko C. Buljan
        Nov 22 '18 at 19:02













        thanks, but this is a simple code, he will know the error

        – abdulsattar-alkhalaf
        Nov 22 '18 at 19:04





        thanks, but this is a simple code, he will know the error

        – abdulsattar-alkhalaf
        Nov 22 '18 at 19:04













        1














        This was due to scope issue.
        Try this code:



          $( document ).ready(function() {
        var count =0;
        console.log(count);
        $( "#button" ).click(function() {
        count=count+1;
        addDiv(count);
        });
        });





        share|improve this answer
























        • You can remove console.log statement I used this for debugging purpose.

          – Jahanzeb Awan
          Nov 22 '18 at 19:11
















        1














        This was due to scope issue.
        Try this code:



          $( document ).ready(function() {
        var count =0;
        console.log(count);
        $( "#button" ).click(function() {
        count=count+1;
        addDiv(count);
        });
        });





        share|improve this answer
























        • You can remove console.log statement I used this for debugging purpose.

          – Jahanzeb Awan
          Nov 22 '18 at 19:11














        1












        1








        1







        This was due to scope issue.
        Try this code:



          $( document ).ready(function() {
        var count =0;
        console.log(count);
        $( "#button" ).click(function() {
        count=count+1;
        addDiv(count);
        });
        });





        share|improve this answer













        This was due to scope issue.
        Try this code:



          $( document ).ready(function() {
        var count =0;
        console.log(count);
        $( "#button" ).click(function() {
        count=count+1;
        addDiv(count);
        });
        });






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 22 '18 at 19:09









        Jahanzeb AwanJahanzeb Awan

        6310




        6310













        • You can remove console.log statement I used this for debugging purpose.

          – Jahanzeb Awan
          Nov 22 '18 at 19:11



















        • You can remove console.log statement I used this for debugging purpose.

          – Jahanzeb Awan
          Nov 22 '18 at 19:11

















        You can remove console.log statement I used this for debugging purpose.

        – Jahanzeb Awan
        Nov 22 '18 at 19:11





        You can remove console.log statement I used this for debugging purpose.

        – Jahanzeb Awan
        Nov 22 '18 at 19:11











        0














        This is because of the scoping issue of count variable. Please note that JavaScript variables are accessible in scoping scenarios (block level scoping or function level scoping). More info here
        What's wrong with your code is you have declared the count variable in one function and you are accessing it outside of it which is not allowed. Only to fix your code, I have made the count variable as global and now it will work as expected.



        Note: Please note that global variables can be accessed anywhere in the execution context, so can be used with utmost care.






          $( document ).ready(function() 
        {
        //var count =0;
        });

        var count=0;
        $('#button').on('click', function(){
        count = count + 1;
        alert(count);
        });


        //$( "#button" ).click(function() {
        // count=count+1;
        // addDiv(count);
        //});

        <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

        <button id='button'>Click Me</button>








        share|improve this answer




























          0














          This is because of the scoping issue of count variable. Please note that JavaScript variables are accessible in scoping scenarios (block level scoping or function level scoping). More info here
          What's wrong with your code is you have declared the count variable in one function and you are accessing it outside of it which is not allowed. Only to fix your code, I have made the count variable as global and now it will work as expected.



          Note: Please note that global variables can be accessed anywhere in the execution context, so can be used with utmost care.






            $( document ).ready(function() 
          {
          //var count =0;
          });

          var count=0;
          $('#button').on('click', function(){
          count = count + 1;
          alert(count);
          });


          //$( "#button" ).click(function() {
          // count=count+1;
          // addDiv(count);
          //});

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

          <button id='button'>Click Me</button>








          share|improve this answer


























            0












            0








            0







            This is because of the scoping issue of count variable. Please note that JavaScript variables are accessible in scoping scenarios (block level scoping or function level scoping). More info here
            What's wrong with your code is you have declared the count variable in one function and you are accessing it outside of it which is not allowed. Only to fix your code, I have made the count variable as global and now it will work as expected.



            Note: Please note that global variables can be accessed anywhere in the execution context, so can be used with utmost care.






              $( document ).ready(function() 
            {
            //var count =0;
            });

            var count=0;
            $('#button').on('click', function(){
            count = count + 1;
            alert(count);
            });


            //$( "#button" ).click(function() {
            // count=count+1;
            // addDiv(count);
            //});

            <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

            <button id='button'>Click Me</button>








            share|improve this answer













            This is because of the scoping issue of count variable. Please note that JavaScript variables are accessible in scoping scenarios (block level scoping or function level scoping). More info here
            What's wrong with your code is you have declared the count variable in one function and you are accessing it outside of it which is not allowed. Only to fix your code, I have made the count variable as global and now it will work as expected.



            Note: Please note that global variables can be accessed anywhere in the execution context, so can be used with utmost care.






              $( document ).ready(function() 
            {
            //var count =0;
            });

            var count=0;
            $('#button').on('click', function(){
            count = count + 1;
            alert(count);
            });


            //$( "#button" ).click(function() {
            // count=count+1;
            // addDiv(count);
            //});

            <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

            <button id='button'>Click Me</button>








              $( document ).ready(function() 
            {
            //var count =0;
            });

            var count=0;
            $('#button').on('click', function(){
            count = count + 1;
            alert(count);
            });


            //$( "#button" ).click(function() {
            // count=count+1;
            // addDiv(count);
            //});

            <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

            <button id='button'>Click Me</button>





              $( document ).ready(function() 
            {
            //var count =0;
            });

            var count=0;
            $('#button').on('click', function(){
            count = count + 1;
            alert(count);
            });


            //$( "#button" ).click(function() {
            // count=count+1;
            // addDiv(count);
            //});

            <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

            <button id='button'>Click Me</button>






            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Nov 22 '18 at 19:00









            iSahilSharmaiSahilSharma

            1,025620




            1,025620























                0














                if you define a variable within a function, it is restricted only to this function, if you set it to a global scope, which is what you need in this case, the variable becomes available for all functions that are under this scope, look:






                //global scope
                var count = 0;
                $( "#button" ).click(function() {
                //function restrict scope
                $('#increment').append(`<div>${count}</div>`)
                count++;
                });

                    <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
                <body>
                <button id="button">Click Me!</button>
                <div id="increment">
                </body>





                See more at this page






                share|improve this answer




























                  0














                  if you define a variable within a function, it is restricted only to this function, if you set it to a global scope, which is what you need in this case, the variable becomes available for all functions that are under this scope, look:






                  //global scope
                  var count = 0;
                  $( "#button" ).click(function() {
                  //function restrict scope
                  $('#increment').append(`<div>${count}</div>`)
                  count++;
                  });

                      <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
                  <body>
                  <button id="button">Click Me!</button>
                  <div id="increment">
                  </body>





                  See more at this page






                  share|improve this answer


























                    0












                    0








                    0







                    if you define a variable within a function, it is restricted only to this function, if you set it to a global scope, which is what you need in this case, the variable becomes available for all functions that are under this scope, look:






                    //global scope
                    var count = 0;
                    $( "#button" ).click(function() {
                    //function restrict scope
                    $('#increment').append(`<div>${count}</div>`)
                    count++;
                    });

                        <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
                    <body>
                    <button id="button">Click Me!</button>
                    <div id="increment">
                    </body>





                    See more at this page






                    share|improve this answer













                    if you define a variable within a function, it is restricted only to this function, if you set it to a global scope, which is what you need in this case, the variable becomes available for all functions that are under this scope, look:






                    //global scope
                    var count = 0;
                    $( "#button" ).click(function() {
                    //function restrict scope
                    $('#increment').append(`<div>${count}</div>`)
                    count++;
                    });

                        <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
                    <body>
                    <button id="button">Click Me!</button>
                    <div id="increment">
                    </body>





                    See more at this page






                    //global scope
                    var count = 0;
                    $( "#button" ).click(function() {
                    //function restrict scope
                    $('#increment').append(`<div>${count}</div>`)
                    count++;
                    });

                        <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
                    <body>
                    <button id="button">Click Me!</button>
                    <div id="increment">
                    </body>





                    //global scope
                    var count = 0;
                    $( "#button" ).click(function() {
                    //function restrict scope
                    $('#increment').append(`<div>${count}</div>`)
                    count++;
                    });

                        <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
                    <body>
                    <button id="button">Click Me!</button>
                    <div id="increment">
                    </body>






                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered Nov 22 '18 at 19:05









                    Demian BibianoDemian Bibiano

                    1789




                    1789























                        0














                        It's a scope problem.
                        If you don't want to expose variables to the outer scope, you can use a closure.



                        let addDiv = function(){
                        let counter = 0;
                        return function(){
                        counter++;
                        let wrapper = $("#someDiv");
                        wrapper.append(`<div> id: ${counter}</div>`)
                        }
                        }();
                        button.on("click", function(){
                        addDiv();
                        });





                        share|improve this answer




























                          0














                          It's a scope problem.
                          If you don't want to expose variables to the outer scope, you can use a closure.



                          let addDiv = function(){
                          let counter = 0;
                          return function(){
                          counter++;
                          let wrapper = $("#someDiv");
                          wrapper.append(`<div> id: ${counter}</div>`)
                          }
                          }();
                          button.on("click", function(){
                          addDiv();
                          });





                          share|improve this answer


























                            0












                            0








                            0







                            It's a scope problem.
                            If you don't want to expose variables to the outer scope, you can use a closure.



                            let addDiv = function(){
                            let counter = 0;
                            return function(){
                            counter++;
                            let wrapper = $("#someDiv");
                            wrapper.append(`<div> id: ${counter}</div>`)
                            }
                            }();
                            button.on("click", function(){
                            addDiv();
                            });





                            share|improve this answer













                            It's a scope problem.
                            If you don't want to expose variables to the outer scope, you can use a closure.



                            let addDiv = function(){
                            let counter = 0;
                            return function(){
                            counter++;
                            let wrapper = $("#someDiv");
                            wrapper.append(`<div> id: ${counter}</div>`)
                            }
                            }();
                            button.on("click", function(){
                            addDiv();
                            });






                            share|improve this answer












                            share|improve this answer



                            share|improve this answer










                            answered Nov 22 '18 at 19:22









                            Dmitry ShevchenkoDmitry Shevchenko

                            1




                            1






























                                draft saved

                                draft discarded




















































                                Thanks for contributing an answer to Stack Overflow!


                                • Please be sure to answer the question. Provide details and share your research!

                                But avoid



                                • Asking for help, clarification, or responding to other answers.

                                • Making statements based on opinion; back them up with references or personal experience.


                                To learn more, see our tips on writing great answers.




                                draft saved


                                draft discarded














                                StackExchange.ready(
                                function () {
                                StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53436628%2fjquery-how-to-add-div-with-a-dynamic-id-that-increments-when-button-is-clicked%23new-answer', 'question_page');
                                }
                                );

                                Post as a guest















                                Required, but never shown





















































                                Required, but never shown














                                Required, but never shown












                                Required, but never shown







                                Required, but never shown

































                                Required, but never shown














                                Required, but never shown












                                Required, but never shown







                                Required, but never shown







                                Popular posts from this blog

                                If I really need a card on my start hand, how many mulligans make sense? [duplicate]

                                Alcedinidae

                                Can an atomic nucleus contain both particles and antiparticles? [duplicate]