Unable to list relative elements XSLT 2.0












0















I am trying to learn XSLT 2.0. In the example below, I am trying to list languages and books available in each language. Can you please help me understand how the context works?



<?xml version="1.0" encoding="utf-8"?>
<?xml-stylesheet type="text/xsl" href="Library.xsl"?>
<Library>
<Books>
<Book>
<Language code="English">English</Language>
<code>1</code>
<Title>History</Title>
</Book>
<Book>
<Language code="Spanish">Spanish</Language>
<code>2</code>
<Title>Math</Title>
</Book>
</Books>
<Languages>
<Language code="English">English</Language>
<Language code="Spanish">Spanish</Language>
</Languages>
</Library>


// Stylesheet



<?xml version="1.0"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<html>
<body>
<table>
<xsl:for-each select="/Library/Languages/Language">
<tr>
<td style="border:1px solid red;">
<xsl:value-of select="@code" /><br /><br />
<xsl:variable name="key" select="@code" />
</td>
</tr>
<xsl:for-each select="/Library/Books/Book">
<xsl:if test="Language[@code=string($key)]">
<tr>
<td style="border:1px solid red;">
<xsl:value-of select="@code" />
</td>
</tr>
</xsl:if>
</xsl:for-each>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>


// Desired output:



Language: English
Title: English Book

Language: Spanish
Title: Spanish Book









share|improve this question

























  • You haven't used any XSLT 2 specific code. Furthermore, does that code run at all? How do you try to use XSLT 2? You have declared the xsl:variable inside of a td element, it will not be available outside of the td. You can simply use the current() function in a predicate of the inner xsl:for-each: <xsl:for-each select="/Library/Books/Book[Language/@code = current()/@code]">. Not sure about the output you want, show us the HTML with the sample data matching the input, I don't see any title "English book" or "Spanish book" in the input sample.

    – Martin Honnen
    Nov 22 '18 at 19:59











  • I would suggest you learn about keys, which were designed for tasks like this.

    – michael.hor257k
    Nov 23 '18 at 9:29


















0















I am trying to learn XSLT 2.0. In the example below, I am trying to list languages and books available in each language. Can you please help me understand how the context works?



<?xml version="1.0" encoding="utf-8"?>
<?xml-stylesheet type="text/xsl" href="Library.xsl"?>
<Library>
<Books>
<Book>
<Language code="English">English</Language>
<code>1</code>
<Title>History</Title>
</Book>
<Book>
<Language code="Spanish">Spanish</Language>
<code>2</code>
<Title>Math</Title>
</Book>
</Books>
<Languages>
<Language code="English">English</Language>
<Language code="Spanish">Spanish</Language>
</Languages>
</Library>


// Stylesheet



<?xml version="1.0"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<html>
<body>
<table>
<xsl:for-each select="/Library/Languages/Language">
<tr>
<td style="border:1px solid red;">
<xsl:value-of select="@code" /><br /><br />
<xsl:variable name="key" select="@code" />
</td>
</tr>
<xsl:for-each select="/Library/Books/Book">
<xsl:if test="Language[@code=string($key)]">
<tr>
<td style="border:1px solid red;">
<xsl:value-of select="@code" />
</td>
</tr>
</xsl:if>
</xsl:for-each>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>


// Desired output:



Language: English
Title: English Book

Language: Spanish
Title: Spanish Book









share|improve this question

























  • You haven't used any XSLT 2 specific code. Furthermore, does that code run at all? How do you try to use XSLT 2? You have declared the xsl:variable inside of a td element, it will not be available outside of the td. You can simply use the current() function in a predicate of the inner xsl:for-each: <xsl:for-each select="/Library/Books/Book[Language/@code = current()/@code]">. Not sure about the output you want, show us the HTML with the sample data matching the input, I don't see any title "English book" or "Spanish book" in the input sample.

    – Martin Honnen
    Nov 22 '18 at 19:59











  • I would suggest you learn about keys, which were designed for tasks like this.

    – michael.hor257k
    Nov 23 '18 at 9:29
















0












0








0








I am trying to learn XSLT 2.0. In the example below, I am trying to list languages and books available in each language. Can you please help me understand how the context works?



<?xml version="1.0" encoding="utf-8"?>
<?xml-stylesheet type="text/xsl" href="Library.xsl"?>
<Library>
<Books>
<Book>
<Language code="English">English</Language>
<code>1</code>
<Title>History</Title>
</Book>
<Book>
<Language code="Spanish">Spanish</Language>
<code>2</code>
<Title>Math</Title>
</Book>
</Books>
<Languages>
<Language code="English">English</Language>
<Language code="Spanish">Spanish</Language>
</Languages>
</Library>


// Stylesheet



<?xml version="1.0"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<html>
<body>
<table>
<xsl:for-each select="/Library/Languages/Language">
<tr>
<td style="border:1px solid red;">
<xsl:value-of select="@code" /><br /><br />
<xsl:variable name="key" select="@code" />
</td>
</tr>
<xsl:for-each select="/Library/Books/Book">
<xsl:if test="Language[@code=string($key)]">
<tr>
<td style="border:1px solid red;">
<xsl:value-of select="@code" />
</td>
</tr>
</xsl:if>
</xsl:for-each>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>


// Desired output:



Language: English
Title: English Book

Language: Spanish
Title: Spanish Book









share|improve this question
















I am trying to learn XSLT 2.0. In the example below, I am trying to list languages and books available in each language. Can you please help me understand how the context works?



<?xml version="1.0" encoding="utf-8"?>
<?xml-stylesheet type="text/xsl" href="Library.xsl"?>
<Library>
<Books>
<Book>
<Language code="English">English</Language>
<code>1</code>
<Title>History</Title>
</Book>
<Book>
<Language code="Spanish">Spanish</Language>
<code>2</code>
<Title>Math</Title>
</Book>
</Books>
<Languages>
<Language code="English">English</Language>
<Language code="Spanish">Spanish</Language>
</Languages>
</Library>


// Stylesheet



<?xml version="1.0"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<html>
<body>
<table>
<xsl:for-each select="/Library/Languages/Language">
<tr>
<td style="border:1px solid red;">
<xsl:value-of select="@code" /><br /><br />
<xsl:variable name="key" select="@code" />
</td>
</tr>
<xsl:for-each select="/Library/Books/Book">
<xsl:if test="Language[@code=string($key)]">
<tr>
<td style="border:1px solid red;">
<xsl:value-of select="@code" />
</td>
</tr>
</xsl:if>
</xsl:for-each>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>


// Desired output:



Language: English
Title: English Book

Language: Spanish
Title: Spanish Book






xml xslt stylesheet






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 22 '18 at 20:58









zx485

14.8k133048




14.8k133048










asked Nov 22 '18 at 19:32









Surinder SinghSurinder Singh

32




32













  • You haven't used any XSLT 2 specific code. Furthermore, does that code run at all? How do you try to use XSLT 2? You have declared the xsl:variable inside of a td element, it will not be available outside of the td. You can simply use the current() function in a predicate of the inner xsl:for-each: <xsl:for-each select="/Library/Books/Book[Language/@code = current()/@code]">. Not sure about the output you want, show us the HTML with the sample data matching the input, I don't see any title "English book" or "Spanish book" in the input sample.

    – Martin Honnen
    Nov 22 '18 at 19:59











  • I would suggest you learn about keys, which were designed for tasks like this.

    – michael.hor257k
    Nov 23 '18 at 9:29





















  • You haven't used any XSLT 2 specific code. Furthermore, does that code run at all? How do you try to use XSLT 2? You have declared the xsl:variable inside of a td element, it will not be available outside of the td. You can simply use the current() function in a predicate of the inner xsl:for-each: <xsl:for-each select="/Library/Books/Book[Language/@code = current()/@code]">. Not sure about the output you want, show us the HTML with the sample data matching the input, I don't see any title "English book" or "Spanish book" in the input sample.

    – Martin Honnen
    Nov 22 '18 at 19:59











  • I would suggest you learn about keys, which were designed for tasks like this.

    – michael.hor257k
    Nov 23 '18 at 9:29



















You haven't used any XSLT 2 specific code. Furthermore, does that code run at all? How do you try to use XSLT 2? You have declared the xsl:variable inside of a td element, it will not be available outside of the td. You can simply use the current() function in a predicate of the inner xsl:for-each: <xsl:for-each select="/Library/Books/Book[Language/@code = current()/@code]">. Not sure about the output you want, show us the HTML with the sample data matching the input, I don't see any title "English book" or "Spanish book" in the input sample.

– Martin Honnen
Nov 22 '18 at 19:59





You haven't used any XSLT 2 specific code. Furthermore, does that code run at all? How do you try to use XSLT 2? You have declared the xsl:variable inside of a td element, it will not be available outside of the td. You can simply use the current() function in a predicate of the inner xsl:for-each: <xsl:for-each select="/Library/Books/Book[Language/@code = current()/@code]">. Not sure about the output you want, show us the HTML with the sample data matching the input, I don't see any title "English book" or "Spanish book" in the input sample.

– Martin Honnen
Nov 22 '18 at 19:59













I would suggest you learn about keys, which were designed for tasks like this.

– michael.hor257k
Nov 23 '18 at 9:29







I would suggest you learn about keys, which were designed for tasks like this.

– michael.hor257k
Nov 23 '18 at 9:29














1 Answer
1






active

oldest

votes


















0














To get your desired output, you can change your XSLT-1.0 file to the following (XSLT-2.0 does not seem to be necessary). One crucial aspect was moving the <xsl:variable name="key" select="@code" /> out of the tdelement up two layers, so that it can be accessed in the xsl:for-each.



<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<html>
<body>
<table>
<xsl:for-each select="/Library/Languages/Language">
<xsl:variable name="key" select="@code" />
<tr>
<td style="border:1px solid red;">
<xsl:value-of select="concat('Language: ', @code)" /><br /><br />
</td>
</tr>
<xsl:for-each select="/Library/Books/Book[Language[@code=$key]]">
<tr>
<td style="border:1px solid red;">
<xsl:value-of select="concat('Title: ', $key,' Book')" />
</td>
</tr>
</xsl:for-each>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>


The output is:



<html>
<body>
<table>
<tr>
<td style="border:1px solid red;">Language: English</td>
</tr>
<tr>
<td style="border:1px solid red;">Title: English Book</td>
</tr>
<tr>
<td style="border:1px solid red;">Language: Spanish</td>
</tr>
<tr>
<td style="border:1px solid red;">Title: Spanish Book</td>
</tr>
</table>
</body>
</html>





share|improve this answer
























  • Thank you so much! Works just as expected. Happy Thanksgiving and good luck with your Black Friday shopping!

    – Surinder Singh
    Nov 23 '18 at 15:29











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









0














To get your desired output, you can change your XSLT-1.0 file to the following (XSLT-2.0 does not seem to be necessary). One crucial aspect was moving the <xsl:variable name="key" select="@code" /> out of the tdelement up two layers, so that it can be accessed in the xsl:for-each.



<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<html>
<body>
<table>
<xsl:for-each select="/Library/Languages/Language">
<xsl:variable name="key" select="@code" />
<tr>
<td style="border:1px solid red;">
<xsl:value-of select="concat('Language: ', @code)" /><br /><br />
</td>
</tr>
<xsl:for-each select="/Library/Books/Book[Language[@code=$key]]">
<tr>
<td style="border:1px solid red;">
<xsl:value-of select="concat('Title: ', $key,' Book')" />
</td>
</tr>
</xsl:for-each>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>


The output is:



<html>
<body>
<table>
<tr>
<td style="border:1px solid red;">Language: English</td>
</tr>
<tr>
<td style="border:1px solid red;">Title: English Book</td>
</tr>
<tr>
<td style="border:1px solid red;">Language: Spanish</td>
</tr>
<tr>
<td style="border:1px solid red;">Title: Spanish Book</td>
</tr>
</table>
</body>
</html>





share|improve this answer
























  • Thank you so much! Works just as expected. Happy Thanksgiving and good luck with your Black Friday shopping!

    – Surinder Singh
    Nov 23 '18 at 15:29
















0














To get your desired output, you can change your XSLT-1.0 file to the following (XSLT-2.0 does not seem to be necessary). One crucial aspect was moving the <xsl:variable name="key" select="@code" /> out of the tdelement up two layers, so that it can be accessed in the xsl:for-each.



<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<html>
<body>
<table>
<xsl:for-each select="/Library/Languages/Language">
<xsl:variable name="key" select="@code" />
<tr>
<td style="border:1px solid red;">
<xsl:value-of select="concat('Language: ', @code)" /><br /><br />
</td>
</tr>
<xsl:for-each select="/Library/Books/Book[Language[@code=$key]]">
<tr>
<td style="border:1px solid red;">
<xsl:value-of select="concat('Title: ', $key,' Book')" />
</td>
</tr>
</xsl:for-each>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>


The output is:



<html>
<body>
<table>
<tr>
<td style="border:1px solid red;">Language: English</td>
</tr>
<tr>
<td style="border:1px solid red;">Title: English Book</td>
</tr>
<tr>
<td style="border:1px solid red;">Language: Spanish</td>
</tr>
<tr>
<td style="border:1px solid red;">Title: Spanish Book</td>
</tr>
</table>
</body>
</html>





share|improve this answer
























  • Thank you so much! Works just as expected. Happy Thanksgiving and good luck with your Black Friday shopping!

    – Surinder Singh
    Nov 23 '18 at 15:29














0












0








0







To get your desired output, you can change your XSLT-1.0 file to the following (XSLT-2.0 does not seem to be necessary). One crucial aspect was moving the <xsl:variable name="key" select="@code" /> out of the tdelement up two layers, so that it can be accessed in the xsl:for-each.



<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<html>
<body>
<table>
<xsl:for-each select="/Library/Languages/Language">
<xsl:variable name="key" select="@code" />
<tr>
<td style="border:1px solid red;">
<xsl:value-of select="concat('Language: ', @code)" /><br /><br />
</td>
</tr>
<xsl:for-each select="/Library/Books/Book[Language[@code=$key]]">
<tr>
<td style="border:1px solid red;">
<xsl:value-of select="concat('Title: ', $key,' Book')" />
</td>
</tr>
</xsl:for-each>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>


The output is:



<html>
<body>
<table>
<tr>
<td style="border:1px solid red;">Language: English</td>
</tr>
<tr>
<td style="border:1px solid red;">Title: English Book</td>
</tr>
<tr>
<td style="border:1px solid red;">Language: Spanish</td>
</tr>
<tr>
<td style="border:1px solid red;">Title: Spanish Book</td>
</tr>
</table>
</body>
</html>





share|improve this answer













To get your desired output, you can change your XSLT-1.0 file to the following (XSLT-2.0 does not seem to be necessary). One crucial aspect was moving the <xsl:variable name="key" select="@code" /> out of the tdelement up two layers, so that it can be accessed in the xsl:for-each.



<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<html>
<body>
<table>
<xsl:for-each select="/Library/Languages/Language">
<xsl:variable name="key" select="@code" />
<tr>
<td style="border:1px solid red;">
<xsl:value-of select="concat('Language: ', @code)" /><br /><br />
</td>
</tr>
<xsl:for-each select="/Library/Books/Book[Language[@code=$key]]">
<tr>
<td style="border:1px solid red;">
<xsl:value-of select="concat('Title: ', $key,' Book')" />
</td>
</tr>
</xsl:for-each>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>


The output is:



<html>
<body>
<table>
<tr>
<td style="border:1px solid red;">Language: English</td>
</tr>
<tr>
<td style="border:1px solid red;">Title: English Book</td>
</tr>
<tr>
<td style="border:1px solid red;">Language: Spanish</td>
</tr>
<tr>
<td style="border:1px solid red;">Title: Spanish Book</td>
</tr>
</table>
</body>
</html>






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 22 '18 at 21:02









zx485zx485

14.8k133048




14.8k133048













  • Thank you so much! Works just as expected. Happy Thanksgiving and good luck with your Black Friday shopping!

    – Surinder Singh
    Nov 23 '18 at 15:29



















  • Thank you so much! Works just as expected. Happy Thanksgiving and good luck with your Black Friday shopping!

    – Surinder Singh
    Nov 23 '18 at 15:29

















Thank you so much! Works just as expected. Happy Thanksgiving and good luck with your Black Friday shopping!

– Surinder Singh
Nov 23 '18 at 15:29





Thank you so much! Works just as expected. Happy Thanksgiving and good luck with your Black Friday shopping!

– Surinder Singh
Nov 23 '18 at 15:29




















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