Concurrent request of unique values












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I am building an application where usernames must be unique.
How do I manage two users that are trying to register the same username?



I was thinking to create a table of temporary blocked usernames.
And as soon as the text area goes onBlur to record the value as a blocked username, until the user completes the registration process or releases it.



Is there a more convenient way to manage this case?










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    0















    I am building an application where usernames must be unique.
    How do I manage two users that are trying to register the same username?



    I was thinking to create a table of temporary blocked usernames.
    And as soon as the text area goes onBlur to record the value as a blocked username, until the user completes the registration process or releases it.



    Is there a more convenient way to manage this case?










    share|improve this question

























      0












      0








      0








      I am building an application where usernames must be unique.
      How do I manage two users that are trying to register the same username?



      I was thinking to create a table of temporary blocked usernames.
      And as soon as the text area goes onBlur to record the value as a blocked username, until the user completes the registration process or releases it.



      Is there a more convenient way to manage this case?










      share|improve this question














      I am building an application where usernames must be unique.
      How do I manage two users that are trying to register the same username?



      I was thinking to create a table of temporary blocked usernames.
      And as soon as the text area goes onBlur to record the value as a blocked username, until the user completes the registration process or releases it.



      Is there a more convenient way to manage this case?







      concurrency username unique-constraint unique-key






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 23 '18 at 10:13









      user10523399user10523399

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