Create the numbers 1 - 30 using the digits 2, 0, 1, 9 in this particular order!
Inspired by the last year's "2018 four 4s challenge", I thought it's time to welcome 2019 by a similar challenge. This time you have to use the digits 2, 0, 1, 9 in this particular order to create the numbers 1 - 30.
The rules haven't changed:
- Use all four digits exactly once in the order 2-0-1-9.
- Allowed operations: $+, -, cdot, div, !$ (factorial), $!!$ (double factorial), square root, exponentiation.
- Parentheses and grouping (e.g. "19") are also allowed.
- Squaring uses the digit 2, so expressions using multiple 2's, e. g. $2^2$ or $1^2+2^9$, are not allowed.
- The modulus operator $(%, mod)$ is not allowed.
- Rounding (e.g. 201/9=22) is not allowed.
I'm curious to see your creative solutions!
May each day of 2019 bring happiness, good cheer, and sweet surprises to you and all your dear ones!
Happy New Year and greetings from Germany!
André
formation-of-numbers number-theory
add a comment |
Inspired by the last year's "2018 four 4s challenge", I thought it's time to welcome 2019 by a similar challenge. This time you have to use the digits 2, 0, 1, 9 in this particular order to create the numbers 1 - 30.
The rules haven't changed:
- Use all four digits exactly once in the order 2-0-1-9.
- Allowed operations: $+, -, cdot, div, !$ (factorial), $!!$ (double factorial), square root, exponentiation.
- Parentheses and grouping (e.g. "19") are also allowed.
- Squaring uses the digit 2, so expressions using multiple 2's, e. g. $2^2$ or $1^2+2^9$, are not allowed.
- The modulus operator $(%, mod)$ is not allowed.
- Rounding (e.g. 201/9=22) is not allowed.
I'm curious to see your creative solutions!
May each day of 2019 bring happiness, good cheer, and sweet surprises to you and all your dear ones!
Happy New Year and greetings from Germany!
André
formation-of-numbers number-theory
Will you be giving a green check to someone?
– flashstorm
2 days ago
Of course I'll do.
– André
2 days ago
add a comment |
Inspired by the last year's "2018 four 4s challenge", I thought it's time to welcome 2019 by a similar challenge. This time you have to use the digits 2, 0, 1, 9 in this particular order to create the numbers 1 - 30.
The rules haven't changed:
- Use all four digits exactly once in the order 2-0-1-9.
- Allowed operations: $+, -, cdot, div, !$ (factorial), $!!$ (double factorial), square root, exponentiation.
- Parentheses and grouping (e.g. "19") are also allowed.
- Squaring uses the digit 2, so expressions using multiple 2's, e. g. $2^2$ or $1^2+2^9$, are not allowed.
- The modulus operator $(%, mod)$ is not allowed.
- Rounding (e.g. 201/9=22) is not allowed.
I'm curious to see your creative solutions!
May each day of 2019 bring happiness, good cheer, and sweet surprises to you and all your dear ones!
Happy New Year and greetings from Germany!
André
formation-of-numbers number-theory
Inspired by the last year's "2018 four 4s challenge", I thought it's time to welcome 2019 by a similar challenge. This time you have to use the digits 2, 0, 1, 9 in this particular order to create the numbers 1 - 30.
The rules haven't changed:
- Use all four digits exactly once in the order 2-0-1-9.
- Allowed operations: $+, -, cdot, div, !$ (factorial), $!!$ (double factorial), square root, exponentiation.
- Parentheses and grouping (e.g. "19") are also allowed.
- Squaring uses the digit 2, so expressions using multiple 2's, e. g. $2^2$ or $1^2+2^9$, are not allowed.
- The modulus operator $(%, mod)$ is not allowed.
- Rounding (e.g. 201/9=22) is not allowed.
I'm curious to see your creative solutions!
May each day of 2019 bring happiness, good cheer, and sweet surprises to you and all your dear ones!
Happy New Year and greetings from Germany!
André
formation-of-numbers number-theory
formation-of-numbers number-theory
asked Dec 31 '18 at 18:28
André
1,183716
1,183716
Will you be giving a green check to someone?
– flashstorm
2 days ago
Of course I'll do.
– André
2 days ago
add a comment |
Will you be giving a green check to someone?
– flashstorm
2 days ago
Of course I'll do.
– André
2 days ago
Will you be giving a green check to someone?
– flashstorm
2 days ago
Will you be giving a green check to someone?
– flashstorm
2 days ago
Of course I'll do.
– André
2 days ago
Of course I'll do.
– André
2 days ago
add a comment |
5 Answers
5
active
oldest
votes
1
1 = 2^(0*19)
2
2 = 2 + (0*19)
3
3 = 2 + 0!^19
4
4 = 2 ^ (0! + 1 ^ 9)
5
-((2 + 0! + 1) - 9)
6
-((2 + 0 + 1) - 9))
7
-((2 + 0*1 - 9))
8
-((2 - 01) - 9)
9
2*0*1 + 9
10
2*0 + 1 + 9
11
2 + 0*1 + 9
12
2 + 0 + 1 + 9
13
2 + 0! + 1 + 9
14
(2 + 0!)! - 1 + 9
15
(2 + 0 + 1)! + 9
16
(2 + 0!)! + 1 + 9
17
20 - (1 * sqrt(9))
18
(2 + (0 * 1)) * 9
19
20 - 1^9
20
20 * 1^9
21
20 + 1^9
22
2 + 0! + 19
23
20 + 1 * sqrt(9)
24
20 + 1 + sqrt(9)
25
2 || (0! + 1 + sqrt (9))
explained:
Ok, this one needs explanation. The operation for "grouping" is known as concatenation and represented by ||. Basically this means push the digits together: 2 || 0 = 20. However, just like any operation, you can represent either side not by a number but by an equation on its own. So 0! + 1 + sqrt(9) = 5, meaning the above represents 2 || 5, qed.
26
2 || ((0! + 1) * sqrt(9))
27
(2 + 0 + 1) * 9
28
((2 + 0!) || 1) - sqrt(9)
29
(2 + (0 * 1)) || 9
30
20 + 1 + 9
edited for clarity
– flashstorm
Dec 31 '18 at 18:59
@flashstorm Um... $3ne 2+0^{19}$
– Frpzzd
Dec 31 '18 at 19:13
1
was missing an !
– flashstorm
Dec 31 '18 at 19:19
Ding! Fries are done :)
– flashstorm
Dec 31 '18 at 19:31
add a comment |
$$1=20-19$$
$$2=2+0cdot 19=20div(1+9)$$
$$3=2cdot 0cdot 1+sqrt{9}=-(2+0+1)!+9$$
$$4=2^{0-1+sqrt{9}}$$
$$5=20div (1+sqrt{9})$$
$$6=(2cdot 0cdot 1+sqrt{9})!$$
$$7=-2-0cdot 1+9$$
$$8=2^{0cdot 1+sqrt{9}}$$
$$9=2cdot 0cdot 1+9$$
$$10=2cdot 0+1+9=20-1-9$$
$$11=2+0cdot 1+9=20-1cdot 9=2^0+1+9$$
$$12=2+0+1+9=20+1-9$$
$$13=2+0!+1+9=2^{0!+1}+9$$
$$14=(2+0!)!-1+9$$
$$15=(2+0+1)!+9$$
$$16=2^{0+1+sqrt{9}}$$
$$17=20-sqrt{1cdot 9}$$
$$18=20+1-sqrt{9}$$
$$19=2cdot 0+19$$
$$20=2^0+19$$
$$21=20+1^9$$
$$22=2cdot (0!+1+9)$$
$$23=20+sqrt{1cdot 9}$$
$$24=2^{0-1+sqrt{9}}!=20+1+sqrt{9}$$
$$25=(2+0!)!+19$$
$$26=2+0+(1+sqrt{9})!$$
$$27=(2+0+1)^{sqrt{9}}$$
$$28=20-1+9$$
$$29=20+1cdot 9=20cdot 1+9$$
$$30=20+1+9$$
DONE!
All finished now! :D
– Frpzzd
Dec 31 '18 at 19:48
Great :) But Spoiler-Tags would be nice ;)
– André
Dec 31 '18 at 21:23
@André Oh, sorry! I can't figure out how to get the mathjax to work inside of a spoiler tag. D:<
– Frpzzd
Dec 31 '18 at 21:26
1
@André Also: I've been trying to do 31, but it actually seems to be much harder than any of the previous ones! Looks like you picked just the right number to stop on! XD
– Frpzzd
Dec 31 '18 at 21:27
1
Your answer for 6 is incorrect; that expression comes out to 2. However, adding parentheses around part and another factorial will make it work.
– user1207177
Dec 31 '18 at 21:41
|
show 2 more comments
1-16 were done as of the time I started this, so I wanted to focus only on 17-30, using answers different from ones that I've already seen. Others will be included if I find solutions that I like.
8:
$8 = sqrt{(2^{0!+1}!!)!! / (sqrt9)!}$
16:
$16 = ((2 + 0 + 1)!)!! / sqrt9 = 20 - 1 - sqrt9$
17:
$17 = (2 + 0! + 1)!! + 9$
18:
$18 = (2^0 + 1) cdot 9 = 2 cdot (0+1)cdot 9 = 2^{0+1} cdot 9$
19:
$19 = 2 cdot 0 + 19$
20:
$20 = 2^0 + 19 = 20! / 19!$
21:
$21 = 20 + 1^9$
22:
$22 = 20 - 1 + sqrt9$
23:
$23 = 20 + 1 cdot sqrt9$
24:
$24 = 2^{0! + 1} cdot (sqrt9)! = 2^{0! + 1}!! cdot sqrt9 = (2+0!+1)!! cdot sqrt9 = ((2 + 0!)! - 1)!! + 9$
25:
$25 = (2 + 0!)! + 19$
26:
$26 = 20 + 1 cdot (sqrt9)!$
27:
$27 = 2^{0! + 1}! + sqrt9$
28: Can't get one different from what I've already seen in other answers. Will maybe try later.
29:
$29 = 20 + 1 cdot 9$
30:
$30 = 2^{0! + 1}! + (sqrt9)!$
I know we're supposed to stop at 30, but I accidentally found this fun one:
32:
$32 = sqrt{20!! / (1 + 9)!}$
Well, there's a way to construct the number 31 satisfying the rules above (at least if we allow the subfactorial) :)
– André
20 hours ago
@André do you mean without concatenation?
– tilper
20 hours ago
Yes, without concatenation! Hint: Try using the "!!! faculty".
– André
19 hours ago
add a comment |
I wrote a program to determine all representable numbers between 1 and 1,000,000 following the rules, so this should be a comprehensive list.
0 through 30:
$$0 = 2times0timesleft(1+9right)$$
$$1 = 20-19$$
$$2 = 2+0timesleft(1+9right)$$
$$3 = 2+0+1^{9}$$
$$4 = 2-left(0+1-sqrt{9}right)$$
$$5 = frac{20}{1+sqrt{9}}$$
$$6 = -2-left(0+1-9right)$$
$$7 = 2timesleft(0-1right)+9$$
$$8 = 2times0-left(1-9right)$$
$$9 = 2times0+1times9$$
$$10 = 2-left(0+1-9right)$$
$$11 = 2+0+1times9$$
$$12 = 2+0+1+9$$
$$13 = 20-left(1+left(sqrt{9}right)!right)$$
$$14 = 20-1timesleft(sqrt{9}right)!$$
$$15 = 20+1-left(sqrt{9}right)!$$
$$16 = 2timesleft(0-left(1-9right)right)$$
$$17 = -2+0+19$$
$$18 = 2timesleft(0+1times9right)$$
$$19 = 2times0+19$$
$$20 = 2timesleft(0+1+9right)$$
$$21 = 2+0+19$$
$$22 = 20-left(1-sqrt{9}right)$$
$$23 = 20+1timessqrt{9}$$
$$24 = 20+1+sqrt{9}$$
$$25 = 20-left(1-left(sqrt{9}right)!right)$$
$$26 = 20+1timesleft(sqrt{9}right)!$$
$$27 = left(2+0+1right)times9$$
$$28 = 20-left(1-9right)$$
$$29 = 20+1times9$$
$$30 = 20+1+9$$
31 through 100. Concatenation of expressions (denoted with ||) is only used when necessary. Interestingly enough, 31 is the smallest number that cannot be done without concatenation of expressions, and 75 is the smallest number that cannot be done in general.
$$31 = 2+left(left(0!+1right)||9right)$$
$$32 = sqrt{2^{0+1+9}}$$
$$33 = left(2+0!+1right)!+9$$
$$34 = left(2+0!right)||left(1+sqrt{9}right)$$
$$35 = 20+left(-1+left(sqrt{9}right)!right)!!$$
$$36 = 2timesleft(-0!+19right)$$
$$37 = left(2+0!right)||left(1+left(sqrt{9}right)!right)$$
$$38 = 2timesleft(0+19right)$$
$$39 = 20+19$$
$$40 = 20timesleft(-1+sqrt{9}right)$$
$$41 = left(left(2+0!right)!right)!!-left(1+left(sqrt{9}right)!right)$$
$$42 = left(2+0!right)!timesleft(1+left(sqrt{9}right)!right)$$
$$43 = left(left(2+0!right)!right)!!+1-left(sqrt{9}right)!$$
$$44 = 20+left(1+sqrt{9}right)!$$
$$45 = left(left(2+0!right)!-1right)times9$$
$$46 = 2timesleft(-0!+left(1+sqrt{9}right)!right)$$
$$47 = 2times0-left(1-left(left(sqrt{9}right)!right)!!right)$$
$$48 = 2timesleft(0+left(1+sqrt{9}right)!right)$$
$$49 = 2-left(0+1-left(left(sqrt{9}right)!right)!!right)$$
$$50 = 2timesleft(0!+left(1+sqrt{9}right)!right)$$
$$51 = 2+0+1+left(left(sqrt{9}right)!right)!!$$
$$52 = 2+0!+1+left(left(sqrt{9}right)!right)!!$$
$$53 = left(2+0!right)!-left(1-left(left(sqrt{9}right)!right)!!right)$$
$$54 = left(2+0!right)!times1times9$$
$$55 = left(2+0!right)!+1+left(left(sqrt{9}right)!right)!!$$
$$56 = left(left(2+0!right)!right)!!-left(1-9right)$$
$$57 = left(20-1right)timessqrt{9}$$
$$58 = left(left(2+0!right)!right)!!+1+9$$
$$59 = left(left(2+0!right)!-1right)||9$$
$$60 = 20times1timessqrt{9}$$
$$61 = left(2+0!right)!||left(1^{9}right)$$
$$62 = -2+left(0!+1right)^{left(sqrt{9}right)!}$$
$$63 = left(20+1right)timessqrt{9}$$
$$64 = 2^{0+1timesleft(sqrt{9}right)!}$$
$$65 = left(2+0!right)!||left(-1+left(sqrt{9}right)!right)$$
$$66 = 2+left(0!+1right)^{left(sqrt{9}right)!}$$
$$67 = frac{201}{sqrt{9}}$$
$$68 = 20+1timesleft(left(sqrt{9}right)!right)!!$$
$$69 = -2+sqrt{0!+left(1+left(sqrt{9}right)!right)!}$$
$$70 = left(left(2+0!right)!||1right)+9$$
$$71 = sqrt{2^{0}+left(1+left(sqrt{9}right)!right)!}$$
$$72 = left(2+0!right)timesleft(1+sqrt{9}right)!$$
$$73 = 2+sqrt{0!+left(1+left(sqrt{9}right)!right)!}$$
$$74 = 2timesleft(left(-0!||1right)+left(left(sqrt{9}right)!right)!!right)$$
$$76 = left(left(2+0!right)!+1right)||left(sqrt{9}right)!$$
$$78 = left(2+0!right)!timesleft(1||sqrt{9}right)$$
$$79 = left(left(2+0!right)!+1right)||9$$
$$80 = 20timesleft(1+sqrt{9}right)$$
$$81 = left(2+0!right)^{1+sqrt{9}}$$
$$83 = left(2+0!+1right)!!||sqrt{9}$$
$$84 = left(2||0!right)timesleft(1+sqrt{9}right)$$
$$85 = -20+left(1+left(sqrt{9}right)!right)!!$$
$$86 = left(2+0!+1right)!!||left(sqrt{9}right)!$$
$$89 = left(2+0!+1right)!!||9$$
$$90 = frac{left(left(2+0!right)!right)!}{-1+9}$$
$$92 = 2timesleft(-0!-left(1-left(left(sqrt{9}right)!right)!!right)right)$$
$$93 = left(left(2+0!right)||1right)timessqrt{9}$$
$$94 = 2timesleft(0-left(1-left(left(sqrt{9}right)!right)!!right)right)$$
$$95 = left(left(2+0!right)!right)!!-left(1-left(left(sqrt{9}right)!right)!!right)$$
$$96 = 2timesleft(0+1timesleft(left(sqrt{9}right)!right)!!right)$$
$$97 = left(left(2+0!right)!right)!!+1+left(left(sqrt{9}right)!right)!!$$
$$98 = 2timesleft(0+1+left(left(sqrt{9}right)!right)!!right)$$
$$99 = left(left(2+0!right)!+1right)!!-left(sqrt{9}right)!$$
$$100 = 20timesleft(-1+left(sqrt{9}right)!right)$$
The rest of the numbers from 101 to 1,000,000 can be found here.
New contributor
Nice. I'm curious whether your program finds anything for 28 other than $20 - (1-9)$ and $20 - 1 +9$, etc.
– tilper
yesterday
add a comment |
Disagree about 31, does not need concatenation : 29+1+0! = 31
New contributor
This does not provide an answer to the question. Once you have sufficient reputation you will be able to comment on any post; instead, provide answers that don't require clarification from the asker. - From Review
– A. P.
30 mins ago
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "559"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fpuzzling.stackexchange.com%2fquestions%2f77961%2fcreate-the-numbers-1-30-using-the-digits-2-0-1-9-in-this-particular-order%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
5 Answers
5
active
oldest
votes
5 Answers
5
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
1 = 2^(0*19)
2
2 = 2 + (0*19)
3
3 = 2 + 0!^19
4
4 = 2 ^ (0! + 1 ^ 9)
5
-((2 + 0! + 1) - 9)
6
-((2 + 0 + 1) - 9))
7
-((2 + 0*1 - 9))
8
-((2 - 01) - 9)
9
2*0*1 + 9
10
2*0 + 1 + 9
11
2 + 0*1 + 9
12
2 + 0 + 1 + 9
13
2 + 0! + 1 + 9
14
(2 + 0!)! - 1 + 9
15
(2 + 0 + 1)! + 9
16
(2 + 0!)! + 1 + 9
17
20 - (1 * sqrt(9))
18
(2 + (0 * 1)) * 9
19
20 - 1^9
20
20 * 1^9
21
20 + 1^9
22
2 + 0! + 19
23
20 + 1 * sqrt(9)
24
20 + 1 + sqrt(9)
25
2 || (0! + 1 + sqrt (9))
explained:
Ok, this one needs explanation. The operation for "grouping" is known as concatenation and represented by ||. Basically this means push the digits together: 2 || 0 = 20. However, just like any operation, you can represent either side not by a number but by an equation on its own. So 0! + 1 + sqrt(9) = 5, meaning the above represents 2 || 5, qed.
26
2 || ((0! + 1) * sqrt(9))
27
(2 + 0 + 1) * 9
28
((2 + 0!) || 1) - sqrt(9)
29
(2 + (0 * 1)) || 9
30
20 + 1 + 9
edited for clarity
– flashstorm
Dec 31 '18 at 18:59
@flashstorm Um... $3ne 2+0^{19}$
– Frpzzd
Dec 31 '18 at 19:13
1
was missing an !
– flashstorm
Dec 31 '18 at 19:19
Ding! Fries are done :)
– flashstorm
Dec 31 '18 at 19:31
add a comment |
1
1 = 2^(0*19)
2
2 = 2 + (0*19)
3
3 = 2 + 0!^19
4
4 = 2 ^ (0! + 1 ^ 9)
5
-((2 + 0! + 1) - 9)
6
-((2 + 0 + 1) - 9))
7
-((2 + 0*1 - 9))
8
-((2 - 01) - 9)
9
2*0*1 + 9
10
2*0 + 1 + 9
11
2 + 0*1 + 9
12
2 + 0 + 1 + 9
13
2 + 0! + 1 + 9
14
(2 + 0!)! - 1 + 9
15
(2 + 0 + 1)! + 9
16
(2 + 0!)! + 1 + 9
17
20 - (1 * sqrt(9))
18
(2 + (0 * 1)) * 9
19
20 - 1^9
20
20 * 1^9
21
20 + 1^9
22
2 + 0! + 19
23
20 + 1 * sqrt(9)
24
20 + 1 + sqrt(9)
25
2 || (0! + 1 + sqrt (9))
explained:
Ok, this one needs explanation. The operation for "grouping" is known as concatenation and represented by ||. Basically this means push the digits together: 2 || 0 = 20. However, just like any operation, you can represent either side not by a number but by an equation on its own. So 0! + 1 + sqrt(9) = 5, meaning the above represents 2 || 5, qed.
26
2 || ((0! + 1) * sqrt(9))
27
(2 + 0 + 1) * 9
28
((2 + 0!) || 1) - sqrt(9)
29
(2 + (0 * 1)) || 9
30
20 + 1 + 9
edited for clarity
– flashstorm
Dec 31 '18 at 18:59
@flashstorm Um... $3ne 2+0^{19}$
– Frpzzd
Dec 31 '18 at 19:13
1
was missing an !
– flashstorm
Dec 31 '18 at 19:19
Ding! Fries are done :)
– flashstorm
Dec 31 '18 at 19:31
add a comment |
1
1 = 2^(0*19)
2
2 = 2 + (0*19)
3
3 = 2 + 0!^19
4
4 = 2 ^ (0! + 1 ^ 9)
5
-((2 + 0! + 1) - 9)
6
-((2 + 0 + 1) - 9))
7
-((2 + 0*1 - 9))
8
-((2 - 01) - 9)
9
2*0*1 + 9
10
2*0 + 1 + 9
11
2 + 0*1 + 9
12
2 + 0 + 1 + 9
13
2 + 0! + 1 + 9
14
(2 + 0!)! - 1 + 9
15
(2 + 0 + 1)! + 9
16
(2 + 0!)! + 1 + 9
17
20 - (1 * sqrt(9))
18
(2 + (0 * 1)) * 9
19
20 - 1^9
20
20 * 1^9
21
20 + 1^9
22
2 + 0! + 19
23
20 + 1 * sqrt(9)
24
20 + 1 + sqrt(9)
25
2 || (0! + 1 + sqrt (9))
explained:
Ok, this one needs explanation. The operation for "grouping" is known as concatenation and represented by ||. Basically this means push the digits together: 2 || 0 = 20. However, just like any operation, you can represent either side not by a number but by an equation on its own. So 0! + 1 + sqrt(9) = 5, meaning the above represents 2 || 5, qed.
26
2 || ((0! + 1) * sqrt(9))
27
(2 + 0 + 1) * 9
28
((2 + 0!) || 1) - sqrt(9)
29
(2 + (0 * 1)) || 9
30
20 + 1 + 9
1
1 = 2^(0*19)
2
2 = 2 + (0*19)
3
3 = 2 + 0!^19
4
4 = 2 ^ (0! + 1 ^ 9)
5
-((2 + 0! + 1) - 9)
6
-((2 + 0 + 1) - 9))
7
-((2 + 0*1 - 9))
8
-((2 - 01) - 9)
9
2*0*1 + 9
10
2*0 + 1 + 9
11
2 + 0*1 + 9
12
2 + 0 + 1 + 9
13
2 + 0! + 1 + 9
14
(2 + 0!)! - 1 + 9
15
(2 + 0 + 1)! + 9
16
(2 + 0!)! + 1 + 9
17
20 - (1 * sqrt(9))
18
(2 + (0 * 1)) * 9
19
20 - 1^9
20
20 * 1^9
21
20 + 1^9
22
2 + 0! + 19
23
20 + 1 * sqrt(9)
24
20 + 1 + sqrt(9)
25
2 || (0! + 1 + sqrt (9))
explained:
Ok, this one needs explanation. The operation for "grouping" is known as concatenation and represented by ||. Basically this means push the digits together: 2 || 0 = 20. However, just like any operation, you can represent either side not by a number but by an equation on its own. So 0! + 1 + sqrt(9) = 5, meaning the above represents 2 || 5, qed.
26
2 || ((0! + 1) * sqrt(9))
27
(2 + 0 + 1) * 9
28
((2 + 0!) || 1) - sqrt(9)
29
(2 + (0 * 1)) || 9
30
20 + 1 + 9
edited Dec 31 '18 at 19:39
answered Dec 31 '18 at 18:40
flashstorm
7729
7729
edited for clarity
– flashstorm
Dec 31 '18 at 18:59
@flashstorm Um... $3ne 2+0^{19}$
– Frpzzd
Dec 31 '18 at 19:13
1
was missing an !
– flashstorm
Dec 31 '18 at 19:19
Ding! Fries are done :)
– flashstorm
Dec 31 '18 at 19:31
add a comment |
edited for clarity
– flashstorm
Dec 31 '18 at 18:59
@flashstorm Um... $3ne 2+0^{19}$
– Frpzzd
Dec 31 '18 at 19:13
1
was missing an !
– flashstorm
Dec 31 '18 at 19:19
Ding! Fries are done :)
– flashstorm
Dec 31 '18 at 19:31
edited for clarity
– flashstorm
Dec 31 '18 at 18:59
edited for clarity
– flashstorm
Dec 31 '18 at 18:59
@flashstorm Um... $3ne 2+0^{19}$
– Frpzzd
Dec 31 '18 at 19:13
@flashstorm Um... $3ne 2+0^{19}$
– Frpzzd
Dec 31 '18 at 19:13
1
1
was missing an !
– flashstorm
Dec 31 '18 at 19:19
was missing an !
– flashstorm
Dec 31 '18 at 19:19
Ding! Fries are done :)
– flashstorm
Dec 31 '18 at 19:31
Ding! Fries are done :)
– flashstorm
Dec 31 '18 at 19:31
add a comment |
$$1=20-19$$
$$2=2+0cdot 19=20div(1+9)$$
$$3=2cdot 0cdot 1+sqrt{9}=-(2+0+1)!+9$$
$$4=2^{0-1+sqrt{9}}$$
$$5=20div (1+sqrt{9})$$
$$6=(2cdot 0cdot 1+sqrt{9})!$$
$$7=-2-0cdot 1+9$$
$$8=2^{0cdot 1+sqrt{9}}$$
$$9=2cdot 0cdot 1+9$$
$$10=2cdot 0+1+9=20-1-9$$
$$11=2+0cdot 1+9=20-1cdot 9=2^0+1+9$$
$$12=2+0+1+9=20+1-9$$
$$13=2+0!+1+9=2^{0!+1}+9$$
$$14=(2+0!)!-1+9$$
$$15=(2+0+1)!+9$$
$$16=2^{0+1+sqrt{9}}$$
$$17=20-sqrt{1cdot 9}$$
$$18=20+1-sqrt{9}$$
$$19=2cdot 0+19$$
$$20=2^0+19$$
$$21=20+1^9$$
$$22=2cdot (0!+1+9)$$
$$23=20+sqrt{1cdot 9}$$
$$24=2^{0-1+sqrt{9}}!=20+1+sqrt{9}$$
$$25=(2+0!)!+19$$
$$26=2+0+(1+sqrt{9})!$$
$$27=(2+0+1)^{sqrt{9}}$$
$$28=20-1+9$$
$$29=20+1cdot 9=20cdot 1+9$$
$$30=20+1+9$$
DONE!
All finished now! :D
– Frpzzd
Dec 31 '18 at 19:48
Great :) But Spoiler-Tags would be nice ;)
– André
Dec 31 '18 at 21:23
@André Oh, sorry! I can't figure out how to get the mathjax to work inside of a spoiler tag. D:<
– Frpzzd
Dec 31 '18 at 21:26
1
@André Also: I've been trying to do 31, but it actually seems to be much harder than any of the previous ones! Looks like you picked just the right number to stop on! XD
– Frpzzd
Dec 31 '18 at 21:27
1
Your answer for 6 is incorrect; that expression comes out to 2. However, adding parentheses around part and another factorial will make it work.
– user1207177
Dec 31 '18 at 21:41
|
show 2 more comments
$$1=20-19$$
$$2=2+0cdot 19=20div(1+9)$$
$$3=2cdot 0cdot 1+sqrt{9}=-(2+0+1)!+9$$
$$4=2^{0-1+sqrt{9}}$$
$$5=20div (1+sqrt{9})$$
$$6=(2cdot 0cdot 1+sqrt{9})!$$
$$7=-2-0cdot 1+9$$
$$8=2^{0cdot 1+sqrt{9}}$$
$$9=2cdot 0cdot 1+9$$
$$10=2cdot 0+1+9=20-1-9$$
$$11=2+0cdot 1+9=20-1cdot 9=2^0+1+9$$
$$12=2+0+1+9=20+1-9$$
$$13=2+0!+1+9=2^{0!+1}+9$$
$$14=(2+0!)!-1+9$$
$$15=(2+0+1)!+9$$
$$16=2^{0+1+sqrt{9}}$$
$$17=20-sqrt{1cdot 9}$$
$$18=20+1-sqrt{9}$$
$$19=2cdot 0+19$$
$$20=2^0+19$$
$$21=20+1^9$$
$$22=2cdot (0!+1+9)$$
$$23=20+sqrt{1cdot 9}$$
$$24=2^{0-1+sqrt{9}}!=20+1+sqrt{9}$$
$$25=(2+0!)!+19$$
$$26=2+0+(1+sqrt{9})!$$
$$27=(2+0+1)^{sqrt{9}}$$
$$28=20-1+9$$
$$29=20+1cdot 9=20cdot 1+9$$
$$30=20+1+9$$
DONE!
All finished now! :D
– Frpzzd
Dec 31 '18 at 19:48
Great :) But Spoiler-Tags would be nice ;)
– André
Dec 31 '18 at 21:23
@André Oh, sorry! I can't figure out how to get the mathjax to work inside of a spoiler tag. D:<
– Frpzzd
Dec 31 '18 at 21:26
1
@André Also: I've been trying to do 31, but it actually seems to be much harder than any of the previous ones! Looks like you picked just the right number to stop on! XD
– Frpzzd
Dec 31 '18 at 21:27
1
Your answer for 6 is incorrect; that expression comes out to 2. However, adding parentheses around part and another factorial will make it work.
– user1207177
Dec 31 '18 at 21:41
|
show 2 more comments
$$1=20-19$$
$$2=2+0cdot 19=20div(1+9)$$
$$3=2cdot 0cdot 1+sqrt{9}=-(2+0+1)!+9$$
$$4=2^{0-1+sqrt{9}}$$
$$5=20div (1+sqrt{9})$$
$$6=(2cdot 0cdot 1+sqrt{9})!$$
$$7=-2-0cdot 1+9$$
$$8=2^{0cdot 1+sqrt{9}}$$
$$9=2cdot 0cdot 1+9$$
$$10=2cdot 0+1+9=20-1-9$$
$$11=2+0cdot 1+9=20-1cdot 9=2^0+1+9$$
$$12=2+0+1+9=20+1-9$$
$$13=2+0!+1+9=2^{0!+1}+9$$
$$14=(2+0!)!-1+9$$
$$15=(2+0+1)!+9$$
$$16=2^{0+1+sqrt{9}}$$
$$17=20-sqrt{1cdot 9}$$
$$18=20+1-sqrt{9}$$
$$19=2cdot 0+19$$
$$20=2^0+19$$
$$21=20+1^9$$
$$22=2cdot (0!+1+9)$$
$$23=20+sqrt{1cdot 9}$$
$$24=2^{0-1+sqrt{9}}!=20+1+sqrt{9}$$
$$25=(2+0!)!+19$$
$$26=2+0+(1+sqrt{9})!$$
$$27=(2+0+1)^{sqrt{9}}$$
$$28=20-1+9$$
$$29=20+1cdot 9=20cdot 1+9$$
$$30=20+1+9$$
DONE!
$$1=20-19$$
$$2=2+0cdot 19=20div(1+9)$$
$$3=2cdot 0cdot 1+sqrt{9}=-(2+0+1)!+9$$
$$4=2^{0-1+sqrt{9}}$$
$$5=20div (1+sqrt{9})$$
$$6=(2cdot 0cdot 1+sqrt{9})!$$
$$7=-2-0cdot 1+9$$
$$8=2^{0cdot 1+sqrt{9}}$$
$$9=2cdot 0cdot 1+9$$
$$10=2cdot 0+1+9=20-1-9$$
$$11=2+0cdot 1+9=20-1cdot 9=2^0+1+9$$
$$12=2+0+1+9=20+1-9$$
$$13=2+0!+1+9=2^{0!+1}+9$$
$$14=(2+0!)!-1+9$$
$$15=(2+0+1)!+9$$
$$16=2^{0+1+sqrt{9}}$$
$$17=20-sqrt{1cdot 9}$$
$$18=20+1-sqrt{9}$$
$$19=2cdot 0+19$$
$$20=2^0+19$$
$$21=20+1^9$$
$$22=2cdot (0!+1+9)$$
$$23=20+sqrt{1cdot 9}$$
$$24=2^{0-1+sqrt{9}}!=20+1+sqrt{9}$$
$$25=(2+0!)!+19$$
$$26=2+0+(1+sqrt{9})!$$
$$27=(2+0+1)^{sqrt{9}}$$
$$28=20-1+9$$
$$29=20+1cdot 9=20cdot 1+9$$
$$30=20+1+9$$
DONE!
edited 2 days ago
Hugh
1,4681617
1,4681617
answered Dec 31 '18 at 19:21
Frpzzd
871120
871120
All finished now! :D
– Frpzzd
Dec 31 '18 at 19:48
Great :) But Spoiler-Tags would be nice ;)
– André
Dec 31 '18 at 21:23
@André Oh, sorry! I can't figure out how to get the mathjax to work inside of a spoiler tag. D:<
– Frpzzd
Dec 31 '18 at 21:26
1
@André Also: I've been trying to do 31, but it actually seems to be much harder than any of the previous ones! Looks like you picked just the right number to stop on! XD
– Frpzzd
Dec 31 '18 at 21:27
1
Your answer for 6 is incorrect; that expression comes out to 2. However, adding parentheses around part and another factorial will make it work.
– user1207177
Dec 31 '18 at 21:41
|
show 2 more comments
All finished now! :D
– Frpzzd
Dec 31 '18 at 19:48
Great :) But Spoiler-Tags would be nice ;)
– André
Dec 31 '18 at 21:23
@André Oh, sorry! I can't figure out how to get the mathjax to work inside of a spoiler tag. D:<
– Frpzzd
Dec 31 '18 at 21:26
1
@André Also: I've been trying to do 31, but it actually seems to be much harder than any of the previous ones! Looks like you picked just the right number to stop on! XD
– Frpzzd
Dec 31 '18 at 21:27
1
Your answer for 6 is incorrect; that expression comes out to 2. However, adding parentheses around part and another factorial will make it work.
– user1207177
Dec 31 '18 at 21:41
All finished now! :D
– Frpzzd
Dec 31 '18 at 19:48
All finished now! :D
– Frpzzd
Dec 31 '18 at 19:48
Great :) But Spoiler-Tags would be nice ;)
– André
Dec 31 '18 at 21:23
Great :) But Spoiler-Tags would be nice ;)
– André
Dec 31 '18 at 21:23
@André Oh, sorry! I can't figure out how to get the mathjax to work inside of a spoiler tag. D:<
– Frpzzd
Dec 31 '18 at 21:26
@André Oh, sorry! I can't figure out how to get the mathjax to work inside of a spoiler tag. D:<
– Frpzzd
Dec 31 '18 at 21:26
1
1
@André Also: I've been trying to do 31, but it actually seems to be much harder than any of the previous ones! Looks like you picked just the right number to stop on! XD
– Frpzzd
Dec 31 '18 at 21:27
@André Also: I've been trying to do 31, but it actually seems to be much harder than any of the previous ones! Looks like you picked just the right number to stop on! XD
– Frpzzd
Dec 31 '18 at 21:27
1
1
Your answer for 6 is incorrect; that expression comes out to 2. However, adding parentheses around part and another factorial will make it work.
– user1207177
Dec 31 '18 at 21:41
Your answer for 6 is incorrect; that expression comes out to 2. However, adding parentheses around part and another factorial will make it work.
– user1207177
Dec 31 '18 at 21:41
|
show 2 more comments
1-16 were done as of the time I started this, so I wanted to focus only on 17-30, using answers different from ones that I've already seen. Others will be included if I find solutions that I like.
8:
$8 = sqrt{(2^{0!+1}!!)!! / (sqrt9)!}$
16:
$16 = ((2 + 0 + 1)!)!! / sqrt9 = 20 - 1 - sqrt9$
17:
$17 = (2 + 0! + 1)!! + 9$
18:
$18 = (2^0 + 1) cdot 9 = 2 cdot (0+1)cdot 9 = 2^{0+1} cdot 9$
19:
$19 = 2 cdot 0 + 19$
20:
$20 = 2^0 + 19 = 20! / 19!$
21:
$21 = 20 + 1^9$
22:
$22 = 20 - 1 + sqrt9$
23:
$23 = 20 + 1 cdot sqrt9$
24:
$24 = 2^{0! + 1} cdot (sqrt9)! = 2^{0! + 1}!! cdot sqrt9 = (2+0!+1)!! cdot sqrt9 = ((2 + 0!)! - 1)!! + 9$
25:
$25 = (2 + 0!)! + 19$
26:
$26 = 20 + 1 cdot (sqrt9)!$
27:
$27 = 2^{0! + 1}! + sqrt9$
28: Can't get one different from what I've already seen in other answers. Will maybe try later.
29:
$29 = 20 + 1 cdot 9$
30:
$30 = 2^{0! + 1}! + (sqrt9)!$
I know we're supposed to stop at 30, but I accidentally found this fun one:
32:
$32 = sqrt{20!! / (1 + 9)!}$
Well, there's a way to construct the number 31 satisfying the rules above (at least if we allow the subfactorial) :)
– André
20 hours ago
@André do you mean without concatenation?
– tilper
20 hours ago
Yes, without concatenation! Hint: Try using the "!!! faculty".
– André
19 hours ago
add a comment |
1-16 were done as of the time I started this, so I wanted to focus only on 17-30, using answers different from ones that I've already seen. Others will be included if I find solutions that I like.
8:
$8 = sqrt{(2^{0!+1}!!)!! / (sqrt9)!}$
16:
$16 = ((2 + 0 + 1)!)!! / sqrt9 = 20 - 1 - sqrt9$
17:
$17 = (2 + 0! + 1)!! + 9$
18:
$18 = (2^0 + 1) cdot 9 = 2 cdot (0+1)cdot 9 = 2^{0+1} cdot 9$
19:
$19 = 2 cdot 0 + 19$
20:
$20 = 2^0 + 19 = 20! / 19!$
21:
$21 = 20 + 1^9$
22:
$22 = 20 - 1 + sqrt9$
23:
$23 = 20 + 1 cdot sqrt9$
24:
$24 = 2^{0! + 1} cdot (sqrt9)! = 2^{0! + 1}!! cdot sqrt9 = (2+0!+1)!! cdot sqrt9 = ((2 + 0!)! - 1)!! + 9$
25:
$25 = (2 + 0!)! + 19$
26:
$26 = 20 + 1 cdot (sqrt9)!$
27:
$27 = 2^{0! + 1}! + sqrt9$
28: Can't get one different from what I've already seen in other answers. Will maybe try later.
29:
$29 = 20 + 1 cdot 9$
30:
$30 = 2^{0! + 1}! + (sqrt9)!$
I know we're supposed to stop at 30, but I accidentally found this fun one:
32:
$32 = sqrt{20!! / (1 + 9)!}$
Well, there's a way to construct the number 31 satisfying the rules above (at least if we allow the subfactorial) :)
– André
20 hours ago
@André do you mean without concatenation?
– tilper
20 hours ago
Yes, without concatenation! Hint: Try using the "!!! faculty".
– André
19 hours ago
add a comment |
1-16 were done as of the time I started this, so I wanted to focus only on 17-30, using answers different from ones that I've already seen. Others will be included if I find solutions that I like.
8:
$8 = sqrt{(2^{0!+1}!!)!! / (sqrt9)!}$
16:
$16 = ((2 + 0 + 1)!)!! / sqrt9 = 20 - 1 - sqrt9$
17:
$17 = (2 + 0! + 1)!! + 9$
18:
$18 = (2^0 + 1) cdot 9 = 2 cdot (0+1)cdot 9 = 2^{0+1} cdot 9$
19:
$19 = 2 cdot 0 + 19$
20:
$20 = 2^0 + 19 = 20! / 19!$
21:
$21 = 20 + 1^9$
22:
$22 = 20 - 1 + sqrt9$
23:
$23 = 20 + 1 cdot sqrt9$
24:
$24 = 2^{0! + 1} cdot (sqrt9)! = 2^{0! + 1}!! cdot sqrt9 = (2+0!+1)!! cdot sqrt9 = ((2 + 0!)! - 1)!! + 9$
25:
$25 = (2 + 0!)! + 19$
26:
$26 = 20 + 1 cdot (sqrt9)!$
27:
$27 = 2^{0! + 1}! + sqrt9$
28: Can't get one different from what I've already seen in other answers. Will maybe try later.
29:
$29 = 20 + 1 cdot 9$
30:
$30 = 2^{0! + 1}! + (sqrt9)!$
I know we're supposed to stop at 30, but I accidentally found this fun one:
32:
$32 = sqrt{20!! / (1 + 9)!}$
1-16 were done as of the time I started this, so I wanted to focus only on 17-30, using answers different from ones that I've already seen. Others will be included if I find solutions that I like.
8:
$8 = sqrt{(2^{0!+1}!!)!! / (sqrt9)!}$
16:
$16 = ((2 + 0 + 1)!)!! / sqrt9 = 20 - 1 - sqrt9$
17:
$17 = (2 + 0! + 1)!! + 9$
18:
$18 = (2^0 + 1) cdot 9 = 2 cdot (0+1)cdot 9 = 2^{0+1} cdot 9$
19:
$19 = 2 cdot 0 + 19$
20:
$20 = 2^0 + 19 = 20! / 19!$
21:
$21 = 20 + 1^9$
22:
$22 = 20 - 1 + sqrt9$
23:
$23 = 20 + 1 cdot sqrt9$
24:
$24 = 2^{0! + 1} cdot (sqrt9)! = 2^{0! + 1}!! cdot sqrt9 = (2+0!+1)!! cdot sqrt9 = ((2 + 0!)! - 1)!! + 9$
25:
$25 = (2 + 0!)! + 19$
26:
$26 = 20 + 1 cdot (sqrt9)!$
27:
$27 = 2^{0! + 1}! + sqrt9$
28: Can't get one different from what I've already seen in other answers. Will maybe try later.
29:
$29 = 20 + 1 cdot 9$
30:
$30 = 2^{0! + 1}! + (sqrt9)!$
I know we're supposed to stop at 30, but I accidentally found this fun one:
32:
$32 = sqrt{20!! / (1 + 9)!}$
edited Dec 31 '18 at 20:48
answered Dec 31 '18 at 19:13
tilper
892514
892514
Well, there's a way to construct the number 31 satisfying the rules above (at least if we allow the subfactorial) :)
– André
20 hours ago
@André do you mean without concatenation?
– tilper
20 hours ago
Yes, without concatenation! Hint: Try using the "!!! faculty".
– André
19 hours ago
add a comment |
Well, there's a way to construct the number 31 satisfying the rules above (at least if we allow the subfactorial) :)
– André
20 hours ago
@André do you mean without concatenation?
– tilper
20 hours ago
Yes, without concatenation! Hint: Try using the "!!! faculty".
– André
19 hours ago
Well, there's a way to construct the number 31 satisfying the rules above (at least if we allow the subfactorial) :)
– André
20 hours ago
Well, there's a way to construct the number 31 satisfying the rules above (at least if we allow the subfactorial) :)
– André
20 hours ago
@André do you mean without concatenation?
– tilper
20 hours ago
@André do you mean without concatenation?
– tilper
20 hours ago
Yes, without concatenation! Hint: Try using the "!!! faculty".
– André
19 hours ago
Yes, without concatenation! Hint: Try using the "!!! faculty".
– André
19 hours ago
add a comment |
I wrote a program to determine all representable numbers between 1 and 1,000,000 following the rules, so this should be a comprehensive list.
0 through 30:
$$0 = 2times0timesleft(1+9right)$$
$$1 = 20-19$$
$$2 = 2+0timesleft(1+9right)$$
$$3 = 2+0+1^{9}$$
$$4 = 2-left(0+1-sqrt{9}right)$$
$$5 = frac{20}{1+sqrt{9}}$$
$$6 = -2-left(0+1-9right)$$
$$7 = 2timesleft(0-1right)+9$$
$$8 = 2times0-left(1-9right)$$
$$9 = 2times0+1times9$$
$$10 = 2-left(0+1-9right)$$
$$11 = 2+0+1times9$$
$$12 = 2+0+1+9$$
$$13 = 20-left(1+left(sqrt{9}right)!right)$$
$$14 = 20-1timesleft(sqrt{9}right)!$$
$$15 = 20+1-left(sqrt{9}right)!$$
$$16 = 2timesleft(0-left(1-9right)right)$$
$$17 = -2+0+19$$
$$18 = 2timesleft(0+1times9right)$$
$$19 = 2times0+19$$
$$20 = 2timesleft(0+1+9right)$$
$$21 = 2+0+19$$
$$22 = 20-left(1-sqrt{9}right)$$
$$23 = 20+1timessqrt{9}$$
$$24 = 20+1+sqrt{9}$$
$$25 = 20-left(1-left(sqrt{9}right)!right)$$
$$26 = 20+1timesleft(sqrt{9}right)!$$
$$27 = left(2+0+1right)times9$$
$$28 = 20-left(1-9right)$$
$$29 = 20+1times9$$
$$30 = 20+1+9$$
31 through 100. Concatenation of expressions (denoted with ||) is only used when necessary. Interestingly enough, 31 is the smallest number that cannot be done without concatenation of expressions, and 75 is the smallest number that cannot be done in general.
$$31 = 2+left(left(0!+1right)||9right)$$
$$32 = sqrt{2^{0+1+9}}$$
$$33 = left(2+0!+1right)!+9$$
$$34 = left(2+0!right)||left(1+sqrt{9}right)$$
$$35 = 20+left(-1+left(sqrt{9}right)!right)!!$$
$$36 = 2timesleft(-0!+19right)$$
$$37 = left(2+0!right)||left(1+left(sqrt{9}right)!right)$$
$$38 = 2timesleft(0+19right)$$
$$39 = 20+19$$
$$40 = 20timesleft(-1+sqrt{9}right)$$
$$41 = left(left(2+0!right)!right)!!-left(1+left(sqrt{9}right)!right)$$
$$42 = left(2+0!right)!timesleft(1+left(sqrt{9}right)!right)$$
$$43 = left(left(2+0!right)!right)!!+1-left(sqrt{9}right)!$$
$$44 = 20+left(1+sqrt{9}right)!$$
$$45 = left(left(2+0!right)!-1right)times9$$
$$46 = 2timesleft(-0!+left(1+sqrt{9}right)!right)$$
$$47 = 2times0-left(1-left(left(sqrt{9}right)!right)!!right)$$
$$48 = 2timesleft(0+left(1+sqrt{9}right)!right)$$
$$49 = 2-left(0+1-left(left(sqrt{9}right)!right)!!right)$$
$$50 = 2timesleft(0!+left(1+sqrt{9}right)!right)$$
$$51 = 2+0+1+left(left(sqrt{9}right)!right)!!$$
$$52 = 2+0!+1+left(left(sqrt{9}right)!right)!!$$
$$53 = left(2+0!right)!-left(1-left(left(sqrt{9}right)!right)!!right)$$
$$54 = left(2+0!right)!times1times9$$
$$55 = left(2+0!right)!+1+left(left(sqrt{9}right)!right)!!$$
$$56 = left(left(2+0!right)!right)!!-left(1-9right)$$
$$57 = left(20-1right)timessqrt{9}$$
$$58 = left(left(2+0!right)!right)!!+1+9$$
$$59 = left(left(2+0!right)!-1right)||9$$
$$60 = 20times1timessqrt{9}$$
$$61 = left(2+0!right)!||left(1^{9}right)$$
$$62 = -2+left(0!+1right)^{left(sqrt{9}right)!}$$
$$63 = left(20+1right)timessqrt{9}$$
$$64 = 2^{0+1timesleft(sqrt{9}right)!}$$
$$65 = left(2+0!right)!||left(-1+left(sqrt{9}right)!right)$$
$$66 = 2+left(0!+1right)^{left(sqrt{9}right)!}$$
$$67 = frac{201}{sqrt{9}}$$
$$68 = 20+1timesleft(left(sqrt{9}right)!right)!!$$
$$69 = -2+sqrt{0!+left(1+left(sqrt{9}right)!right)!}$$
$$70 = left(left(2+0!right)!||1right)+9$$
$$71 = sqrt{2^{0}+left(1+left(sqrt{9}right)!right)!}$$
$$72 = left(2+0!right)timesleft(1+sqrt{9}right)!$$
$$73 = 2+sqrt{0!+left(1+left(sqrt{9}right)!right)!}$$
$$74 = 2timesleft(left(-0!||1right)+left(left(sqrt{9}right)!right)!!right)$$
$$76 = left(left(2+0!right)!+1right)||left(sqrt{9}right)!$$
$$78 = left(2+0!right)!timesleft(1||sqrt{9}right)$$
$$79 = left(left(2+0!right)!+1right)||9$$
$$80 = 20timesleft(1+sqrt{9}right)$$
$$81 = left(2+0!right)^{1+sqrt{9}}$$
$$83 = left(2+0!+1right)!!||sqrt{9}$$
$$84 = left(2||0!right)timesleft(1+sqrt{9}right)$$
$$85 = -20+left(1+left(sqrt{9}right)!right)!!$$
$$86 = left(2+0!+1right)!!||left(sqrt{9}right)!$$
$$89 = left(2+0!+1right)!!||9$$
$$90 = frac{left(left(2+0!right)!right)!}{-1+9}$$
$$92 = 2timesleft(-0!-left(1-left(left(sqrt{9}right)!right)!!right)right)$$
$$93 = left(left(2+0!right)||1right)timessqrt{9}$$
$$94 = 2timesleft(0-left(1-left(left(sqrt{9}right)!right)!!right)right)$$
$$95 = left(left(2+0!right)!right)!!-left(1-left(left(sqrt{9}right)!right)!!right)$$
$$96 = 2timesleft(0+1timesleft(left(sqrt{9}right)!right)!!right)$$
$$97 = left(left(2+0!right)!right)!!+1+left(left(sqrt{9}right)!right)!!$$
$$98 = 2timesleft(0+1+left(left(sqrt{9}right)!right)!!right)$$
$$99 = left(left(2+0!right)!+1right)!!-left(sqrt{9}right)!$$
$$100 = 20timesleft(-1+left(sqrt{9}right)!right)$$
The rest of the numbers from 101 to 1,000,000 can be found here.
New contributor
Nice. I'm curious whether your program finds anything for 28 other than $20 - (1-9)$ and $20 - 1 +9$, etc.
– tilper
yesterday
add a comment |
I wrote a program to determine all representable numbers between 1 and 1,000,000 following the rules, so this should be a comprehensive list.
0 through 30:
$$0 = 2times0timesleft(1+9right)$$
$$1 = 20-19$$
$$2 = 2+0timesleft(1+9right)$$
$$3 = 2+0+1^{9}$$
$$4 = 2-left(0+1-sqrt{9}right)$$
$$5 = frac{20}{1+sqrt{9}}$$
$$6 = -2-left(0+1-9right)$$
$$7 = 2timesleft(0-1right)+9$$
$$8 = 2times0-left(1-9right)$$
$$9 = 2times0+1times9$$
$$10 = 2-left(0+1-9right)$$
$$11 = 2+0+1times9$$
$$12 = 2+0+1+9$$
$$13 = 20-left(1+left(sqrt{9}right)!right)$$
$$14 = 20-1timesleft(sqrt{9}right)!$$
$$15 = 20+1-left(sqrt{9}right)!$$
$$16 = 2timesleft(0-left(1-9right)right)$$
$$17 = -2+0+19$$
$$18 = 2timesleft(0+1times9right)$$
$$19 = 2times0+19$$
$$20 = 2timesleft(0+1+9right)$$
$$21 = 2+0+19$$
$$22 = 20-left(1-sqrt{9}right)$$
$$23 = 20+1timessqrt{9}$$
$$24 = 20+1+sqrt{9}$$
$$25 = 20-left(1-left(sqrt{9}right)!right)$$
$$26 = 20+1timesleft(sqrt{9}right)!$$
$$27 = left(2+0+1right)times9$$
$$28 = 20-left(1-9right)$$
$$29 = 20+1times9$$
$$30 = 20+1+9$$
31 through 100. Concatenation of expressions (denoted with ||) is only used when necessary. Interestingly enough, 31 is the smallest number that cannot be done without concatenation of expressions, and 75 is the smallest number that cannot be done in general.
$$31 = 2+left(left(0!+1right)||9right)$$
$$32 = sqrt{2^{0+1+9}}$$
$$33 = left(2+0!+1right)!+9$$
$$34 = left(2+0!right)||left(1+sqrt{9}right)$$
$$35 = 20+left(-1+left(sqrt{9}right)!right)!!$$
$$36 = 2timesleft(-0!+19right)$$
$$37 = left(2+0!right)||left(1+left(sqrt{9}right)!right)$$
$$38 = 2timesleft(0+19right)$$
$$39 = 20+19$$
$$40 = 20timesleft(-1+sqrt{9}right)$$
$$41 = left(left(2+0!right)!right)!!-left(1+left(sqrt{9}right)!right)$$
$$42 = left(2+0!right)!timesleft(1+left(sqrt{9}right)!right)$$
$$43 = left(left(2+0!right)!right)!!+1-left(sqrt{9}right)!$$
$$44 = 20+left(1+sqrt{9}right)!$$
$$45 = left(left(2+0!right)!-1right)times9$$
$$46 = 2timesleft(-0!+left(1+sqrt{9}right)!right)$$
$$47 = 2times0-left(1-left(left(sqrt{9}right)!right)!!right)$$
$$48 = 2timesleft(0+left(1+sqrt{9}right)!right)$$
$$49 = 2-left(0+1-left(left(sqrt{9}right)!right)!!right)$$
$$50 = 2timesleft(0!+left(1+sqrt{9}right)!right)$$
$$51 = 2+0+1+left(left(sqrt{9}right)!right)!!$$
$$52 = 2+0!+1+left(left(sqrt{9}right)!right)!!$$
$$53 = left(2+0!right)!-left(1-left(left(sqrt{9}right)!right)!!right)$$
$$54 = left(2+0!right)!times1times9$$
$$55 = left(2+0!right)!+1+left(left(sqrt{9}right)!right)!!$$
$$56 = left(left(2+0!right)!right)!!-left(1-9right)$$
$$57 = left(20-1right)timessqrt{9}$$
$$58 = left(left(2+0!right)!right)!!+1+9$$
$$59 = left(left(2+0!right)!-1right)||9$$
$$60 = 20times1timessqrt{9}$$
$$61 = left(2+0!right)!||left(1^{9}right)$$
$$62 = -2+left(0!+1right)^{left(sqrt{9}right)!}$$
$$63 = left(20+1right)timessqrt{9}$$
$$64 = 2^{0+1timesleft(sqrt{9}right)!}$$
$$65 = left(2+0!right)!||left(-1+left(sqrt{9}right)!right)$$
$$66 = 2+left(0!+1right)^{left(sqrt{9}right)!}$$
$$67 = frac{201}{sqrt{9}}$$
$$68 = 20+1timesleft(left(sqrt{9}right)!right)!!$$
$$69 = -2+sqrt{0!+left(1+left(sqrt{9}right)!right)!}$$
$$70 = left(left(2+0!right)!||1right)+9$$
$$71 = sqrt{2^{0}+left(1+left(sqrt{9}right)!right)!}$$
$$72 = left(2+0!right)timesleft(1+sqrt{9}right)!$$
$$73 = 2+sqrt{0!+left(1+left(sqrt{9}right)!right)!}$$
$$74 = 2timesleft(left(-0!||1right)+left(left(sqrt{9}right)!right)!!right)$$
$$76 = left(left(2+0!right)!+1right)||left(sqrt{9}right)!$$
$$78 = left(2+0!right)!timesleft(1||sqrt{9}right)$$
$$79 = left(left(2+0!right)!+1right)||9$$
$$80 = 20timesleft(1+sqrt{9}right)$$
$$81 = left(2+0!right)^{1+sqrt{9}}$$
$$83 = left(2+0!+1right)!!||sqrt{9}$$
$$84 = left(2||0!right)timesleft(1+sqrt{9}right)$$
$$85 = -20+left(1+left(sqrt{9}right)!right)!!$$
$$86 = left(2+0!+1right)!!||left(sqrt{9}right)!$$
$$89 = left(2+0!+1right)!!||9$$
$$90 = frac{left(left(2+0!right)!right)!}{-1+9}$$
$$92 = 2timesleft(-0!-left(1-left(left(sqrt{9}right)!right)!!right)right)$$
$$93 = left(left(2+0!right)||1right)timessqrt{9}$$
$$94 = 2timesleft(0-left(1-left(left(sqrt{9}right)!right)!!right)right)$$
$$95 = left(left(2+0!right)!right)!!-left(1-left(left(sqrt{9}right)!right)!!right)$$
$$96 = 2timesleft(0+1timesleft(left(sqrt{9}right)!right)!!right)$$
$$97 = left(left(2+0!right)!right)!!+1+left(left(sqrt{9}right)!right)!!$$
$$98 = 2timesleft(0+1+left(left(sqrt{9}right)!right)!!right)$$
$$99 = left(left(2+0!right)!+1right)!!-left(sqrt{9}right)!$$
$$100 = 20timesleft(-1+left(sqrt{9}right)!right)$$
The rest of the numbers from 101 to 1,000,000 can be found here.
New contributor
Nice. I'm curious whether your program finds anything for 28 other than $20 - (1-9)$ and $20 - 1 +9$, etc.
– tilper
yesterday
add a comment |
I wrote a program to determine all representable numbers between 1 and 1,000,000 following the rules, so this should be a comprehensive list.
0 through 30:
$$0 = 2times0timesleft(1+9right)$$
$$1 = 20-19$$
$$2 = 2+0timesleft(1+9right)$$
$$3 = 2+0+1^{9}$$
$$4 = 2-left(0+1-sqrt{9}right)$$
$$5 = frac{20}{1+sqrt{9}}$$
$$6 = -2-left(0+1-9right)$$
$$7 = 2timesleft(0-1right)+9$$
$$8 = 2times0-left(1-9right)$$
$$9 = 2times0+1times9$$
$$10 = 2-left(0+1-9right)$$
$$11 = 2+0+1times9$$
$$12 = 2+0+1+9$$
$$13 = 20-left(1+left(sqrt{9}right)!right)$$
$$14 = 20-1timesleft(sqrt{9}right)!$$
$$15 = 20+1-left(sqrt{9}right)!$$
$$16 = 2timesleft(0-left(1-9right)right)$$
$$17 = -2+0+19$$
$$18 = 2timesleft(0+1times9right)$$
$$19 = 2times0+19$$
$$20 = 2timesleft(0+1+9right)$$
$$21 = 2+0+19$$
$$22 = 20-left(1-sqrt{9}right)$$
$$23 = 20+1timessqrt{9}$$
$$24 = 20+1+sqrt{9}$$
$$25 = 20-left(1-left(sqrt{9}right)!right)$$
$$26 = 20+1timesleft(sqrt{9}right)!$$
$$27 = left(2+0+1right)times9$$
$$28 = 20-left(1-9right)$$
$$29 = 20+1times9$$
$$30 = 20+1+9$$
31 through 100. Concatenation of expressions (denoted with ||) is only used when necessary. Interestingly enough, 31 is the smallest number that cannot be done without concatenation of expressions, and 75 is the smallest number that cannot be done in general.
$$31 = 2+left(left(0!+1right)||9right)$$
$$32 = sqrt{2^{0+1+9}}$$
$$33 = left(2+0!+1right)!+9$$
$$34 = left(2+0!right)||left(1+sqrt{9}right)$$
$$35 = 20+left(-1+left(sqrt{9}right)!right)!!$$
$$36 = 2timesleft(-0!+19right)$$
$$37 = left(2+0!right)||left(1+left(sqrt{9}right)!right)$$
$$38 = 2timesleft(0+19right)$$
$$39 = 20+19$$
$$40 = 20timesleft(-1+sqrt{9}right)$$
$$41 = left(left(2+0!right)!right)!!-left(1+left(sqrt{9}right)!right)$$
$$42 = left(2+0!right)!timesleft(1+left(sqrt{9}right)!right)$$
$$43 = left(left(2+0!right)!right)!!+1-left(sqrt{9}right)!$$
$$44 = 20+left(1+sqrt{9}right)!$$
$$45 = left(left(2+0!right)!-1right)times9$$
$$46 = 2timesleft(-0!+left(1+sqrt{9}right)!right)$$
$$47 = 2times0-left(1-left(left(sqrt{9}right)!right)!!right)$$
$$48 = 2timesleft(0+left(1+sqrt{9}right)!right)$$
$$49 = 2-left(0+1-left(left(sqrt{9}right)!right)!!right)$$
$$50 = 2timesleft(0!+left(1+sqrt{9}right)!right)$$
$$51 = 2+0+1+left(left(sqrt{9}right)!right)!!$$
$$52 = 2+0!+1+left(left(sqrt{9}right)!right)!!$$
$$53 = left(2+0!right)!-left(1-left(left(sqrt{9}right)!right)!!right)$$
$$54 = left(2+0!right)!times1times9$$
$$55 = left(2+0!right)!+1+left(left(sqrt{9}right)!right)!!$$
$$56 = left(left(2+0!right)!right)!!-left(1-9right)$$
$$57 = left(20-1right)timessqrt{9}$$
$$58 = left(left(2+0!right)!right)!!+1+9$$
$$59 = left(left(2+0!right)!-1right)||9$$
$$60 = 20times1timessqrt{9}$$
$$61 = left(2+0!right)!||left(1^{9}right)$$
$$62 = -2+left(0!+1right)^{left(sqrt{9}right)!}$$
$$63 = left(20+1right)timessqrt{9}$$
$$64 = 2^{0+1timesleft(sqrt{9}right)!}$$
$$65 = left(2+0!right)!||left(-1+left(sqrt{9}right)!right)$$
$$66 = 2+left(0!+1right)^{left(sqrt{9}right)!}$$
$$67 = frac{201}{sqrt{9}}$$
$$68 = 20+1timesleft(left(sqrt{9}right)!right)!!$$
$$69 = -2+sqrt{0!+left(1+left(sqrt{9}right)!right)!}$$
$$70 = left(left(2+0!right)!||1right)+9$$
$$71 = sqrt{2^{0}+left(1+left(sqrt{9}right)!right)!}$$
$$72 = left(2+0!right)timesleft(1+sqrt{9}right)!$$
$$73 = 2+sqrt{0!+left(1+left(sqrt{9}right)!right)!}$$
$$74 = 2timesleft(left(-0!||1right)+left(left(sqrt{9}right)!right)!!right)$$
$$76 = left(left(2+0!right)!+1right)||left(sqrt{9}right)!$$
$$78 = left(2+0!right)!timesleft(1||sqrt{9}right)$$
$$79 = left(left(2+0!right)!+1right)||9$$
$$80 = 20timesleft(1+sqrt{9}right)$$
$$81 = left(2+0!right)^{1+sqrt{9}}$$
$$83 = left(2+0!+1right)!!||sqrt{9}$$
$$84 = left(2||0!right)timesleft(1+sqrt{9}right)$$
$$85 = -20+left(1+left(sqrt{9}right)!right)!!$$
$$86 = left(2+0!+1right)!!||left(sqrt{9}right)!$$
$$89 = left(2+0!+1right)!!||9$$
$$90 = frac{left(left(2+0!right)!right)!}{-1+9}$$
$$92 = 2timesleft(-0!-left(1-left(left(sqrt{9}right)!right)!!right)right)$$
$$93 = left(left(2+0!right)||1right)timessqrt{9}$$
$$94 = 2timesleft(0-left(1-left(left(sqrt{9}right)!right)!!right)right)$$
$$95 = left(left(2+0!right)!right)!!-left(1-left(left(sqrt{9}right)!right)!!right)$$
$$96 = 2timesleft(0+1timesleft(left(sqrt{9}right)!right)!!right)$$
$$97 = left(left(2+0!right)!right)!!+1+left(left(sqrt{9}right)!right)!!$$
$$98 = 2timesleft(0+1+left(left(sqrt{9}right)!right)!!right)$$
$$99 = left(left(2+0!right)!+1right)!!-left(sqrt{9}right)!$$
$$100 = 20timesleft(-1+left(sqrt{9}right)!right)$$
The rest of the numbers from 101 to 1,000,000 can be found here.
New contributor
I wrote a program to determine all representable numbers between 1 and 1,000,000 following the rules, so this should be a comprehensive list.
0 through 30:
$$0 = 2times0timesleft(1+9right)$$
$$1 = 20-19$$
$$2 = 2+0timesleft(1+9right)$$
$$3 = 2+0+1^{9}$$
$$4 = 2-left(0+1-sqrt{9}right)$$
$$5 = frac{20}{1+sqrt{9}}$$
$$6 = -2-left(0+1-9right)$$
$$7 = 2timesleft(0-1right)+9$$
$$8 = 2times0-left(1-9right)$$
$$9 = 2times0+1times9$$
$$10 = 2-left(0+1-9right)$$
$$11 = 2+0+1times9$$
$$12 = 2+0+1+9$$
$$13 = 20-left(1+left(sqrt{9}right)!right)$$
$$14 = 20-1timesleft(sqrt{9}right)!$$
$$15 = 20+1-left(sqrt{9}right)!$$
$$16 = 2timesleft(0-left(1-9right)right)$$
$$17 = -2+0+19$$
$$18 = 2timesleft(0+1times9right)$$
$$19 = 2times0+19$$
$$20 = 2timesleft(0+1+9right)$$
$$21 = 2+0+19$$
$$22 = 20-left(1-sqrt{9}right)$$
$$23 = 20+1timessqrt{9}$$
$$24 = 20+1+sqrt{9}$$
$$25 = 20-left(1-left(sqrt{9}right)!right)$$
$$26 = 20+1timesleft(sqrt{9}right)!$$
$$27 = left(2+0+1right)times9$$
$$28 = 20-left(1-9right)$$
$$29 = 20+1times9$$
$$30 = 20+1+9$$
31 through 100. Concatenation of expressions (denoted with ||) is only used when necessary. Interestingly enough, 31 is the smallest number that cannot be done without concatenation of expressions, and 75 is the smallest number that cannot be done in general.
$$31 = 2+left(left(0!+1right)||9right)$$
$$32 = sqrt{2^{0+1+9}}$$
$$33 = left(2+0!+1right)!+9$$
$$34 = left(2+0!right)||left(1+sqrt{9}right)$$
$$35 = 20+left(-1+left(sqrt{9}right)!right)!!$$
$$36 = 2timesleft(-0!+19right)$$
$$37 = left(2+0!right)||left(1+left(sqrt{9}right)!right)$$
$$38 = 2timesleft(0+19right)$$
$$39 = 20+19$$
$$40 = 20timesleft(-1+sqrt{9}right)$$
$$41 = left(left(2+0!right)!right)!!-left(1+left(sqrt{9}right)!right)$$
$$42 = left(2+0!right)!timesleft(1+left(sqrt{9}right)!right)$$
$$43 = left(left(2+0!right)!right)!!+1-left(sqrt{9}right)!$$
$$44 = 20+left(1+sqrt{9}right)!$$
$$45 = left(left(2+0!right)!-1right)times9$$
$$46 = 2timesleft(-0!+left(1+sqrt{9}right)!right)$$
$$47 = 2times0-left(1-left(left(sqrt{9}right)!right)!!right)$$
$$48 = 2timesleft(0+left(1+sqrt{9}right)!right)$$
$$49 = 2-left(0+1-left(left(sqrt{9}right)!right)!!right)$$
$$50 = 2timesleft(0!+left(1+sqrt{9}right)!right)$$
$$51 = 2+0+1+left(left(sqrt{9}right)!right)!!$$
$$52 = 2+0!+1+left(left(sqrt{9}right)!right)!!$$
$$53 = left(2+0!right)!-left(1-left(left(sqrt{9}right)!right)!!right)$$
$$54 = left(2+0!right)!times1times9$$
$$55 = left(2+0!right)!+1+left(left(sqrt{9}right)!right)!!$$
$$56 = left(left(2+0!right)!right)!!-left(1-9right)$$
$$57 = left(20-1right)timessqrt{9}$$
$$58 = left(left(2+0!right)!right)!!+1+9$$
$$59 = left(left(2+0!right)!-1right)||9$$
$$60 = 20times1timessqrt{9}$$
$$61 = left(2+0!right)!||left(1^{9}right)$$
$$62 = -2+left(0!+1right)^{left(sqrt{9}right)!}$$
$$63 = left(20+1right)timessqrt{9}$$
$$64 = 2^{0+1timesleft(sqrt{9}right)!}$$
$$65 = left(2+0!right)!||left(-1+left(sqrt{9}right)!right)$$
$$66 = 2+left(0!+1right)^{left(sqrt{9}right)!}$$
$$67 = frac{201}{sqrt{9}}$$
$$68 = 20+1timesleft(left(sqrt{9}right)!right)!!$$
$$69 = -2+sqrt{0!+left(1+left(sqrt{9}right)!right)!}$$
$$70 = left(left(2+0!right)!||1right)+9$$
$$71 = sqrt{2^{0}+left(1+left(sqrt{9}right)!right)!}$$
$$72 = left(2+0!right)timesleft(1+sqrt{9}right)!$$
$$73 = 2+sqrt{0!+left(1+left(sqrt{9}right)!right)!}$$
$$74 = 2timesleft(left(-0!||1right)+left(left(sqrt{9}right)!right)!!right)$$
$$76 = left(left(2+0!right)!+1right)||left(sqrt{9}right)!$$
$$78 = left(2+0!right)!timesleft(1||sqrt{9}right)$$
$$79 = left(left(2+0!right)!+1right)||9$$
$$80 = 20timesleft(1+sqrt{9}right)$$
$$81 = left(2+0!right)^{1+sqrt{9}}$$
$$83 = left(2+0!+1right)!!||sqrt{9}$$
$$84 = left(2||0!right)timesleft(1+sqrt{9}right)$$
$$85 = -20+left(1+left(sqrt{9}right)!right)!!$$
$$86 = left(2+0!+1right)!!||left(sqrt{9}right)!$$
$$89 = left(2+0!+1right)!!||9$$
$$90 = frac{left(left(2+0!right)!right)!}{-1+9}$$
$$92 = 2timesleft(-0!-left(1-left(left(sqrt{9}right)!right)!!right)right)$$
$$93 = left(left(2+0!right)||1right)timessqrt{9}$$
$$94 = 2timesleft(0-left(1-left(left(sqrt{9}right)!right)!!right)right)$$
$$95 = left(left(2+0!right)!right)!!-left(1-left(left(sqrt{9}right)!right)!!right)$$
$$96 = 2timesleft(0+1timesleft(left(sqrt{9}right)!right)!!right)$$
$$97 = left(left(2+0!right)!right)!!+1+left(left(sqrt{9}right)!right)!!$$
$$98 = 2timesleft(0+1+left(left(sqrt{9}right)!right)!!right)$$
$$99 = left(left(2+0!right)!+1right)!!-left(sqrt{9}right)!$$
$$100 = 20timesleft(-1+left(sqrt{9}right)!right)$$
The rest of the numbers from 101 to 1,000,000 can be found here.
New contributor
edited 2 days ago
New contributor
answered 2 days ago
The Turtle
1314
1314
New contributor
New contributor
Nice. I'm curious whether your program finds anything for 28 other than $20 - (1-9)$ and $20 - 1 +9$, etc.
– tilper
yesterday
add a comment |
Nice. I'm curious whether your program finds anything for 28 other than $20 - (1-9)$ and $20 - 1 +9$, etc.
– tilper
yesterday
Nice. I'm curious whether your program finds anything for 28 other than $20 - (1-9)$ and $20 - 1 +9$, etc.
– tilper
yesterday
Nice. I'm curious whether your program finds anything for 28 other than $20 - (1-9)$ and $20 - 1 +9$, etc.
– tilper
yesterday
add a comment |
Disagree about 31, does not need concatenation : 29+1+0! = 31
New contributor
This does not provide an answer to the question. Once you have sufficient reputation you will be able to comment on any post; instead, provide answers that don't require clarification from the asker. - From Review
– A. P.
30 mins ago
add a comment |
Disagree about 31, does not need concatenation : 29+1+0! = 31
New contributor
This does not provide an answer to the question. Once you have sufficient reputation you will be able to comment on any post; instead, provide answers that don't require clarification from the asker. - From Review
– A. P.
30 mins ago
add a comment |
Disagree about 31, does not need concatenation : 29+1+0! = 31
New contributor
Disagree about 31, does not need concatenation : 29+1+0! = 31
New contributor
New contributor
answered 48 mins ago
olivier
1
1
New contributor
New contributor
This does not provide an answer to the question. Once you have sufficient reputation you will be able to comment on any post; instead, provide answers that don't require clarification from the asker. - From Review
– A. P.
30 mins ago
add a comment |
This does not provide an answer to the question. Once you have sufficient reputation you will be able to comment on any post; instead, provide answers that don't require clarification from the asker. - From Review
– A. P.
30 mins ago
This does not provide an answer to the question. Once you have sufficient reputation you will be able to comment on any post; instead, provide answers that don't require clarification from the asker. - From Review
– A. P.
30 mins ago
This does not provide an answer to the question. Once you have sufficient reputation you will be able to comment on any post; instead, provide answers that don't require clarification from the asker. - From Review
– A. P.
30 mins ago
add a comment |
Thanks for contributing an answer to Puzzling Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fpuzzling.stackexchange.com%2fquestions%2f77961%2fcreate-the-numbers-1-30-using-the-digits-2-0-1-9-in-this-particular-order%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Will you be giving a green check to someone?
– flashstorm
2 days ago
Of course I'll do.
– André
2 days ago